12. Find m<1 and m<2 for a//t
0
please help

12. Find M&lt;1 And M&lt;2 For A//t 0please Help

Answers

Answer 1

Answer:

Angle 1 & 2 are both 100 degrees

Step-by-step explanation:

In the picture,

angles on the same side of the line must add up to 180degrees.

Angles directly opposite of each other(same vertices) must be equal.

with parallel lines, angles that are made by the same intersecting line are also equal.

image really helps :( sry its hard to explain in words

12. Find M&lt;1 And M&lt;2 For A//t 0please Help

Related Questions

rewrite cos^4 2x in terms of the first power of cosine.

Answers

cos2x = (1+cos(2x))/2

What is meant by first power of cosine?

The cosine power is odd (n odd): u = sin x and du = cos x dx should be used. d u = cos ⁡ To create an even number of cosine powers, replace dx with (a), canceling one power of cos x by substituting du. The Power Factor is the sine of the angle formed by Current and Voltage.

P = VI Cosθ OR.Cosθ = P ÷ V I OR.Cosθ = kW ÷ kVA OR.Cosθ = True Power ÷ Apparent Power.

The ratio of the length of the side next to the angle to the length of the hypotenuse is known as the cosine, sometimes abbreviated as "cos." The ratio of the length of the side across from the angle to the length of the side next to it is called the tangent, which is frequently abbreviated as "tan."

cos2(2x) = (1+cos(4x))/2

cos4(2x)= [(1+cos(4x))/2]²

[tex]cos^{4}[/tex](2x) = [(1+cos(4x))/2]²

[tex]cos^{4}[/tex] (2x) = (1/4) × [1 + cos(4x)]²

[tex]cos^{4}[/tex](2x) = (1/4) × (1 + 2cos(4x) + cos²(4x))

[tex]cos^{4}[/tex](2x) = (1/4)*[1 + 2cos(4x) + (1 + cos(2x))/2]

[tex]cos^{4}[/tex](2x) = (1/4)*[1 + 2cos(4x) + (1/2)*(1 + cos(2x))]

[tex]cos^{4}[/tex](2x) = (1/8)*[2 + 4cos(4x) + 1 + cos(2x)]  

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a frog is at the bottom of a 25 foot well. each day he climbs up 3 feet, and each night he slips down 2 feet. how many days will it take him to reach the top of the well?

Answers

25. he goes up by one foot (3 minus 2) each day and night, so 25.


A group is planning a trip to the local amusement park and needs to make sure everyone has a ticket. Up to 8 people can attend the trip, and the tickets cost $17.50 each. This scenario
is modeled by the function y-17.50x where x is the number of people attending and y is the total cost of the trip. Determine the domain and range for this situation.
DOMAIN:
RANGE:

Answers

Answer:

8x17.50

Step-by-step explanation:

True or false

-5/-1 = 5?
(0/-4) = 0?
-3/1 = -3?
- 8/0 = 0?

Answers

Checking if the results of the following divisions are true or false.

a) -5/-1 = 5 ↔ True

The fraction, (remembering that it is a division), -5/-1can be simplified to 5 by removing the negative sign from the numerator and denominator.

b) (0/-4) = 0 ↔ True

We know that any number divided by zero, the result will always be zero.

c) -3/1 = -3 ↔ True

Any number divided by one equals the same number.

d) -8/0 = 0 ↔ False

A normal number simply cannot be divided by 0.

The three previous divisions are true, that is, your answers are correct. While the last one can't, since it can't be divided by 0, this one is false.

Use the rational zeros theorem to list all possible rational zeros of the following.

Answers

The given function is:

[tex]g(x)=-25x^3-5x^2-2x-1[/tex]

The theorem states that the factors are p/q where p is the factors of the last term (constant term) and q is the factors of the leading coefficient.

Here the leading coefficient is -25 and the constant term is -1.

The factors are listed below:

[tex]\begin{gathered} -25\Rightarrow\pm25,\pm5,\pm1\Rightarrow q \\ -1=\pm1\Rightarrow p \end{gathered}[/tex]

So the value of p/q can be the values shown below:

[tex]\frac{p}{q}\Rightarrow\pm\frac{1}{25},\pm\frac{1}{5},\pm1[/tex]

Hence the possible zeroes of the given function are:

[tex]\pm\frac{1}{25},\pm\frac{1}{5},\pm1[/tex]

Need some help with this, thanks! (And quick thank you! I'd also like an explanation on how these problems get solved , please!)

Answers

Answer:

9.38%

Step-by-step explanation:

First this is the solution I used:

Percentage change = actual change/original amount x 100

Hope this helps.

a mail carrier randomly inspects every 20th letter being mailed. out of 600 letters in the sample, 3 were open. there were 18,000 letters being mailed. make an inference about the number of all the letters being mailed that were open

Answers

90 letters out of the inspected sample of 900 letters will be found to be open

Inspection is done by mail carrier for every 20th letter

Inspection rate = 1/20*100 = 5%

It is a form of inspection where a sample of the same unit's manufactured goods, produced using the same procedures, is taken and examined, as opposed to the entire unit being examined. In general, the unit relates to the lot, and the lot determines whether the things are acceptable or rejectable.

Number of letters found open in 600 letters = 3 letters

Rate of letter found open = 3/600*100 = 0.5%

The sample being mailed = 18000 letters

Number of letters that were inspected for being open = 5% of 18000 = 900

letters

The number of letters found open = 0.5% of 18000 = 90

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-Determine the equation of the line that passes through the point (9, -42)and is parallel to the line y = -5x + 1.Enter your answer in slope-intercept form.Pls see picture

Answers

Two parallel lines have the same slope. Given the equation of one of the lines, you can determine the slope of the other line:

[tex]y=-5x+1[/tex]

The slope of the line is the coefficient of the x-term, in this case, that coefficient is -5. Then the slope of both parallel lines is m= -5.

The line you have to find must cross through the point (9,-42). Using the point-slope form you can determine the equation of the parallel line:

[tex]y-y_1=m(x-x_1)[/tex]

Where

m is the slope of the line

(x₁,y₁) are the coordinates of one point of the line:

[tex]\begin{gathered} y-(-42)=-5(x-9) \\ y+42=-5(x-9) \end{gathered}[/tex]

To write the equation in slope-intercept form, the first step is to distribute the multiplication on the parentheses term:

[tex]\begin{gathered} y+42=(-5)\cdot x+(-5)\cdot(-9) \\ y+42=-5x+45 \end{gathered}[/tex]

Subtract 42 to both sides of the expression to pass the term to the right side of the equal sign:

[tex]\begin{gathered} y+42-42=-5x+45-42 \\ y=-5x+3 \end{gathered}[/tex]

The equation of the line is y= -5x + 3

Erica prepared 13 flower
arrangements after working 2 hours. How many hours did Erica work if she prepared 26 flower arrangements?

Answers

Erica worked 4 hours  to prepare 26 flower arrangements.

Erica prepared 13 flower arrangements after working 2 hours.

Time Erica took to prepare 1 flower arrangement = 2 / 13 hours.

Therefore time Erica took to prepare 26 flower arrangement = 2/13 x 26 hours.

=4 hours.

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Use the distributive property to write an equivalent expression.
9(7r−3s+10)

Thanks!

Answers

Answer:

63r-27s+90

Step-by-step explanation:

9 times 7 is 63

9 times -3 is -27

9 times 10 is 90

Please help me out with questions 20.-24.

Answers

Answer:

answers are in the photo

A sculpture is formed from a cylinder resting on top of a cuboid...
The cylinder has radius 40 cm and height 70 cm.
The cuboid measures 80 cm by 80 cm by 140 cm.
The sculpture is made of steel.
The steel has a density of 8.05 g/cm³.
Calculate the total mass of the sculpture in tonnes.

Answers

The most appropriate choice for volume of cuboid and cylinder will be given by-

Total mass of sculpture is 10.0464 tonnes

What is volume of cuboid and cylinder?

Cuboid is a three dimensional figure that has 6 faces, 12 edges and 8 vertices.

Volume of cuboid is given by the formula length [tex]\times[/tex] breadth [tex]\times[/tex] height

Cylinder is a three dimensional round figure that has two circular bases at the end

If r is the radius of the cylinder and h is the height of the cylinder, volume of the cylinder is given by the formula

V = [tex]\pi \times r^2 \times h[/tex]

Here,

Radius of cylinder = 40 cm

Height of cylinder = 70 cm

Volume of cylinder = [tex]\pi \times r^2 \times h[/tex]

                                = [tex]\frac{22}{7} \times (40)^2 \times 70\\[/tex]

                                = 352000 [tex]cm^3[/tex]

Length of cuboid = 80 cm

Breadth of cuboid = 80 cm

Height of cuboid = 140 m

Volume of cuboid = [tex]80 \times 80 \times 140[/tex]

                              = 896000 [tex]cm^3[/tex]

Total volume of sculpture = (352000 + 896000) [tex]cm^3[/tex]

                                           = 1248000 [tex]cm^3[/tex]

Density of sculpture = 8.05 [tex]g / cm^3[/tex]

Mass of sculpture  = [tex]1248000 \times 8.05[/tex]

                               = 10046400 g

                               = 10046.4 kg

                                = 10.0464 tonnes

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Passes to the point( -5, 6) and has a slope equal to 3

Help due tomorrow !!

Answers

The equation of a line that passes through the point ( -5, 6) and has a slope equal to 3 is  y = 3x + 21

How to find equation of a line using slope?

The equation of the line passes through the point (-5, 6) and has a slope equal to 3.

Therefore, the equation of a line can be represented as follows;

y = mx + b

where

m = slopeb = y-intercept

Therefore,

y = 3x + b

slope = 3

using (-5, 6), let's find the y-intercept

6 = 3(-5) + b

6 = - 15 + b

b = 6 + 15

b = 21

Therefore, the equation of the line is y = 3x + 21

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x/x+2 - 4/x-2 algeriac equation

Answers

The solution of the given equation in quadratic form will be; (x^{2} -6x - 8)/(x^{2} -4 )

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

WE have been given an algebric equation as;

x/x+2 - 4/x-2

Solving it;

[tex]\dfrac{x}{x+2 }- \dfrac{4}{x-2}\\\\\\\dfrac{x(x-2)}{x+2 }- \dfrac{4(x+2 )}{x-2}\\\\\\\dfrac{x(x-2)- 4(x+2 )}{(x+2 )(x-2)}\\\\\\\dfrac{x^{2} -2x- 4x - 8}{x^{2} -2^{2} }\\\\\\\dfrac{x^{2} -6x - 8}{x^{2} -4 }[/tex]

Hence, the solution of the given equation in quadratic form will be;

(x^{2} -6x - 8)/(x^{2} -4 )

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You get paid ​​
$10.75​ an hour at your job and the newest video game costs ​
$60.00 Find the inequality that represents the number of hours you will need to work in order to afford the video game. Use x as a variable

Answers

The inequality that represents the number of hours you will need to work in order to afford the video game is x ≥ 5.58.

What is an inequality?

Inequalities are created through the connection of two expressions. It should be noted that two expressions in an inequality aren't always equal. They are denoted by the symbols ≥ < > ≤ 

Let the number of hours be represented as x.

The person is paid $10.75 an hour at your job and the newest video game costs $60.00. This will be illustrated as:

10.75x ≥ 60

Divide

x ≥ 60 / 10.75

x ≥ 5.58

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April is arranging place cards for a wedding reception on a table the brides fa

Answers

Using the greatest common factor, it is found that the greatest number of cards that she can place in a row is of 14.

How to find the greatest number of cards that she can place in a row?

The number of cards for each family is given as follows:

April's family: 154.Groom's family: 140.

We want to find a way to distribute them having the same number of cards in each row, hence this is possible finding the greatest common factor (GCF) of the numbers of 154 and 140.

The GCF is found factoring both numbers 154 and 140 simultaneously by prime factors, as follows:

154 - 140|2 (both 154 and 140 are divisible by 2).

77 - 70|7 (both 77 and 70 are divisible by 11).

11 - 7

There are no numbers for which both 11 and 7 are divisible by, hence the greatest number of cards that she can place in a row is:

gcf(154, 140) = 2 x 7 = 14.

Missing information


The complete problem is:

April is arranging place cards for a wedding reception on a table. The bride's family has 154 cards and the groom's family has 140 cards. She wants the arrangements for the two families to have the same number of cards in each row. What is the greatest number of cards that she can place in a row?

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2. The admission fee at a small fair is $2.50 for children and $4.00 for adults. On a certain day, 2400 people enter the fair and $7140 is collected. How many children and how many adults attended?

Answers

Given:

a.) The admission fee at a small fair is $2.50 for children and $4.00 for adults.

b.) On a certain day, 2400 people enter the fair and $7140 is collected.

Let,

x = total number of children

y = total number of adults

Let's generate two equations based on the given scenario:

EQUATION 1: Total number of children and adults entered the fair.

[tex]\text{ x + y = }2400[/tex]

EQUATION 2: Total money collected from the admission.

[tex]\text{ 2.5x + 4y = }$7140$[/tex]

We will be using the substitution method. We get,

[tex]\text{ x + y = }2400[/tex][tex]\text{ y = }2400\text{ - x}[/tex]

Substitute to Equation 2:

[tex]\text{ 2.5x + 4y = }$7140$[/tex][tex]\text{ 2.5x + 4(}2400\text{ - x) = }$7140$[/tex][tex]\text{ 2.5x + 9600 - 4x = }$7140$[/tex][tex]\text{ 2.5x - 4x = }$7140$\text{ - 9600 }[/tex][tex]\text{ -1.5x }=\text{ }-2,460[/tex][tex]\text{ }\frac{\text{-1.5x}}{-1.5}\text{ }=\text{ }\frac{-2,460}{-1.5}[/tex][tex]\text{ x }=\text{ }1,640\text{ children}[/tex]

Therefore, 1,640 children went to the fair.

For the adults,

x + y = 2400

1,640 + y = 2400

y = 2400 - 1,640

y = 760 adults

In summary: 1,640 children and 760 adults went to the fair.

Cody biked a total of 22 kilometers
by making 11 trips to work. How
many trips will Cody have to make to
bike a total of 30 kilometers?

Answers

Answer: 15

Step-by-step explanation:

This is the answer because 22 divided by 11 equals 2 kilometer each trip to work so 30 kilometer divided by 2 is 15.

In the designers proposal, they state that the paths EC and DB each measure 100 feet. They also state that the garden will require 140 feet of hedges. Are their numbers reasonable?

Answers

We are given a circle whose diamter is 100 feet. To find out if 140 feet of hedges will fit into it given all the oother dimensions, we will have to calculate the lengths of the chords that correspond to the hedges.

First, let us solve for AE.

[tex]\begin{gathered} chord=2r\sin\theta \\ \\ AE=100\sin50 \\ AE=76.6 \end{gathered}[/tex]

We used θ = 50 degrees because we know that the measurement of the arc is equal to the measurement of the central angle.

Now, to solve for the length of ED, we need to find out the measurement of the central angle that subtend it.

Segments AD and EC intersect, thus the following equation must be true for the angles that they form and the arcs that they subtend:

[tex]\begin{gathered} m\angle EXA=\frac{1}{2}(m\hat{AE}+m\hat{DC}) \\ \\ 70=\frac{1}{2}(50+m\hat{DC}) \\ \\ 140=(50+m\hat{DC}) \\ \\ 90=m\hat{DC} \end{gathered}[/tex]

Again, using the formula for finding the length of a chord, we can now solve for the length of ED.

[tex]\begin{gathered} chord=2r\sin(\theta) \\ \\ ED=100\sin90 \\ ED=100 \end{gathered}[/tex]

Finally, we need to calculate the length of BC. But we know that BC = ED because the diameters meet at a 90-degree angle and so the chords that they subtend are all congruent. You may also think of ∠BYC as being vertical to ∠EYD. So BC should be equal to ED either way. BC = 100

So the total length of the hedges is:

[tex]\begin{gathered} AE+ED+BC \\ =76.6+100+100 \\ =276.6ft \end{gathered}[/tex]

Therefore, the numbers given by the designers are not reasonable. 140 feet is too short for the hedges.

2x-6y=-3
Determine if the given ordered pair. (3, 7/2)
satisfies the given equation.
O YES O No

Answers

Answer:

No, it doesn't satisfy.

Step-by-step explanation:

2x - 6y = -3

let us post the ordered pair in the equation and solve it

2(3) - 6(7/2) = -3

6 - 21 = -3

-15 = -3  ......  which isn't equal

so we conclude that the given ordered pair doesn't satisfy the equation.

Find the area of the triangle described below. Round to the nearest hundredth.b = 20, a = 29, c = 21

Answers

Solution

We want to find the area of the triangle given te sides

b = 20

a = 29

c = 21

Note: Hero formula for calculating the Area of a Triangle

We will first find S

[tex]\begin{gathered} S=\frac{a+b+c}{2} \\ S=\frac{29+20+21}{2} \\ S=35 \end{gathered}[/tex]

To find the Area

[tex]\begin{gathered} Area=\sqrt[]{S(S-a)(S-b)(S-c)} \\ Area=\sqrt[]{35(35-29)(35-20)(35-21)} \\ Area=\sqrt[]{35\times6\times15\times14} \\ Area=\sqrt[]{44100} \\ Area=210 \end{gathered}[/tex]

Therefore, the area is

[tex]Area=210[/tex]

Convert repeating decimals to fractions.
Rewrite as a simplified fraction.
3.83 =?

Answers

As a fraction 3.83 (3 repeating )is 3x 83/99

what is repeating decimals ?

Repeating decimal values are created by fraction that  do not divide evenly. when converting a repeating decimal to a fraction we can ignore the units in the start as the units remain unchanged ,which allows us to  convert our decimal values and then the units back in afterward.

so ,

To convert the 3.83 to a fraction , we ignore the units as they will remain units.

we then set up one equation of our unknown x being equal to 0.83333......and another that is 100 times greater , 100x = 83.33333....

by subtracting these two equation from each other we can then divide by the coefficient of x to create our fraction .

10x=83.3333...

    x= 0.83333...

  99x = 82.5

we now divide both sides by 99 to isolate x:

99x=82.5

99x/99=82.5/99

x= 82.5/99

x = 82.5 x10/99x10

x = 825/990

x = 165/198

we cannot simplify this fraction any more

finally we add back the 3 units we set aside at the beginning ,making our fraction 3x165/198

so , the fraction 3.83 is 3x 83/99

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Which equation has a graph that is parallel to the graph 2x-y = -1

Answers

The equation whose graph is parallel to that of line 2x - y = - 1 is →

y = - 2x - 1

What is the general equation of straight line?

The general equation of straight line is -

y = mx + c

Given is an equation of line as → 2x - y = - 1

The equation of the line whose graph will be parallel to that of the graph of line 2x - y = -1, will have same slope as that of given line itself.

2x - y = - 1

y = -2x - 1

m = -2

The equation whose graph is parallel to that of 2x - y = -1 is -

y = - 2x - 1

Therefore, the equation whose graph is parallel to that of line 2x - y = - 1 is → y = - 2x - 1

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consider the dihedral point group constructed from two generators express a 3d matrix representation for the two generators of the group in the hexagonal basis

Answers

the groups generated by two elements of order 2 are K4  and dihedral group.

We are given that G be  a finite group with  x, y belong to G have two elements of order two.

We have to prove that <x,y> is either abelian or isomorphic  to a dihedral group.

<x,y> means the group generated by two elements of order 2.

We know that  Zn is a cyclic group and  number of elements of order 2 is always odd in number and generated by one element  .So , given group is not isomorphic to Zn

But we are given that two elements of order 2 in given group

Therefore, group G can be K4 or dihedral group

Because the groups generated by two elements of order 2 are K4  and dihedral group.

We know that  is abelian group of order 4 and every element of K4  is of order 2 except identity element and generated by 2 elements of order 2 and dihedral group can be  also generated by two elements of order 2

Hence, <x,y> is isomorphic to K4 or D2.

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Simplify the expression √9x^3/25y^2 and please be sure to explain your steps! Thank you!

Answers

The value of the expression given as√9x^3/25y^2 is 3x^3/25y^2

What are expressions?

Expressions are mathematical statements that are represented by variables, coefficients and operators

How to simplify the expression?

The expression is given as

√9x^3/25y^2

Evaluate the square root of 9

So, we have the following equation

√9x^3/25y^2 = 3x^3/25y^2

The above expression cannot be further simplified

Hence, the solution to the expression is 3x^3/25y^2

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HELP PLEASE!!!!!!!!!!!
What is the dimensions of a rectangle that is 32ft by 8ft after it is dilated by a scale factor of 7/8

Answers

Dimensions of rectangle after dilation of scale factor 7/8 will be

[tex] (\frac{7}{2},14),  (\frac{-7}{2},14),  (\frac{-7}{2},-14),  (\frac{7}{2},-14) [/tex]

Dilation of rectangle :-

Dilation means the area of any rectangle increases or decreases due to change in it's dimensions but the shape of that rectangle will remain same.

Now Consider the point of dilation as the center of rectangle and assume that the center of given rectangle is at the origin.

As given the length and width of rectangle is 32ft and 8ft respectively.

∴ The Dimensions of rectangle will be (4,16), (-4,16), (-4,-16) and (4,-16).

Now As the rectangle is diluted by the factor of 7/8.

So Now New Dimensions are Calculated by simply multiplying the available dimensions with the scale factor of dilation.

∴ new Dimension after dilation will be

[tex] (4(\frac{7}{8}),16(\frac{7}{8})), (-4(\frac{7}{8}),16(\frac{7}{8})), (-4(\frac{7}{8}),-16(\frac{7}{8})), (4(\frac{7}{8}),-16(\frac{7}{8})) [/tex]

∴ Dimension after dilution will be ;

[tex] (\frac{7}{2},14),  (\frac{-7}{2},14),  (\frac{-7}{2},-14),  (\frac{7}{2},-14) [/tex]

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alpha writes the infinite arithmetic sequence \[10, 8, 6, 4, 2, 0 ,\ldots.\]beta writes the infinite geometric sequence \[9, 6, 4, \frac{8}{3}, \frac{16}{9}, \ldots.\]gamma makes a sequence whose $n^{\text{th}}$ term is the product of the $n^{\text{th}}$ term of alpha's sequence and the $n^{\text{th}}$ term of beta's sequence: \[10\cdot 9 \quad,\quad 8\cdot 6\quad ,\quad 6\cdot 4\quad,\quad 4\cdot \frac83\quad,\quad 2\cdot \frac{16}{9}\quad,\quad \ldots.\]what is the sum of gamma's entire sequence?

Answers

Consecutive terms in the α sequence have a common difference of

8 - 10 = 6 - 8 = 4 - 6 = … = -2

so they are given recursively by

[tex]\begin{cases} \alpha_1 = 10 \\ \alpha_n = \alpha_{n-1} - 2 & \text{for } n\ge2 \end{cases}[/tex]

By substitution, we have

[tex]\alpha_n = \alpha_{n-1} - 2 \\\\ \alpha_n = \alpha_{n-2} - 2\cdot2 \\\\ \alpha_n = \alpha_{n-3} - 3\cdot2 \\\\ \vdots \\\\ \alpha_n = \alpha_{n-(n-1)} - (n-1)\cdot 2 = \alpha_1 - 2(n-1) = 12-2n[/tex]

Consecutive terms in the β sequence have a common ratio of

6/9 = 4/6 = (8/3)/4 = … = 2/3

so the recurrence for these terms is

[tex]\begin{cases} \beta_1 = 9 \\\\ \beta_n = \frac23 \beta_{n-1} & \text{for } n\ge2 \end{cases}[/tex]

We can solve for [tex]\beta_n[/tex] similarly:

[tex]\beta_n = \dfrac23 \beta_{n-1} \\\\ \beta_n = \left(\dfrac23\right)^2 \beta_{n-2} \\\\ \beta_n = \left(\dfrac23\right)^3 \beta_{n-3} \\\\ \vdots \\\\ \beta_n = \left(\dfrac23\right)^{n-1} \beta_{n-(n-1)} = \left(\dfrac23\right)^{n-1} \beta_1 = \dfrac{2^{n-1}}{3^{n-1}} \cdot 3^2 = \dfrac{2^{n-1}}{3^{n-3}}[/tex]

The γ sequence has [tex]n[/tex]-th term

[tex]\gamma_n = \alpha_n \beta_n = (12-2n) \dfrac{2^{n-1}}{3^{n-3}} = (108-18n) \left(\dfrac23\right)^{n-1}[/tex]

and we want to compute

[tex]\displaystyle \sum_{n=1}^\infty \gamma_n = 108 \sum_{n=1}^\infty \left(\frac23\right)^{n-1} - 18 \sum_{n=1}^\infty n \left(\frac23\right)^{n-1}[/tex]

Recall the sum of an infinite geometric series with common ratio [tex]|r|<1[/tex] converges to

[tex]\displaystyle \sum_{n=1}^\infty r^{n-1} = \frac1{1-r}[/tex]

so that

[tex]\displaystyle \sum_{n=1}^\infty \left(\frac23\right)^{n-1} = \frac1{1-\frac23} = 3[/tex]

For the remaining sum, we can use the method shown in question [24494877] to compute

[tex]\displaystyle \sum_{n=1}^\infty nr^{n-1} = \frac1{(1-r)^2}[/tex]

which gives

[tex]\displaystyle \sum_{n=1}^\infty n \left(\frac23\right)^{n-1} = \frac1{\left(1-\frac23\right)^2} = 9[/tex]

Then the infinite sum of the terms of γ converges to

[tex]\displaystyle \sum_{n=1}^\infty \gamma_n = 108 \cdot 3 - 18 \cdot 9 = \boxed{162}[/tex]

Give the circumference of a circle with a radius of 17 m.

Answers

Answer:106.81

Step-by-step explanation:

To find the Circumference of a circle you have to do is 2×[tex]\pi[/tex]×17 which would give you 106.81.

The circumference is the outline of the circle, it is the edge; in other words it is the perimeter of the circle.

To calculate the circumference of the circle, we apply the following formula:

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{C=2\pi r} \end{gathered}$}}[/tex]

We have that the radius is 17 meters, and the value of pi is 3.14, we substitute these data in the formula and solve:

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{C=2\cdot(3.14)\cdot(17 \ m)} \end{gathered}$}}[/tex][tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{C=106.76 \ m} \end{gathered}$}}}[/tex] The circumference of the circle is: 106.76 meters.


For a certain airline, flight attendants need to be between 63 and 73 inches tall. Which of the following absolute value equations can be used to represent these minimum and maximum heights

Answers

Flight attendants for one carrier must be between 63 and 73 inches tall. The absolute value equations from the list below can be used to express these minimum and maximum heights is |x+68|<5.

Given that,

Flight attendants for one carrier must be between 63 and 73 inches tall.

We have to find what absolute value equations from the list below can be used to express these minimum and maximum heights.

In algebra, an absolute value function is a function where the variable is inside the bars denoting absolute values. The absolute value function is also known as the modulus function, and its most popular representation is function of x = |x|, where x is a real number. The absolute value function is typically written as function of x = a |x - h| + k, where a denotes the vertical stretch of the graph, h denotes the horizontal shift, and k denotes the vertical shift from the graph of function of x = |x|.

Therefore, The absolute value equations from the list below can be used to express these minimum and maximum heights is |x+68|<5.

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can someone explain functions to me please I don't get it.

Answers

Functions are special relaionships that connect an element of one set of numbers, with one element in another set of numbers.

The most comon way to represent functions is connecting elements of a set of Real numbers called the "Domain", to another number in a set called the Range (and whose elements are identified with the letter "y")

Using math operations one can relate x values with y values via an equation of the type:

y = 2 x - 5

where you have a mathematical form of that relationship, that allows you to know given the value of one member (x) of the Domain what number is associated with it in the Range.

For example, try the number x = 0

and see which y number connects with it:

y = 2 (0) - 5 = 0 - 5 = -5

Then you say that the number 0 in the Domain connects with the number -5 in the Range.

This relationship can also be given with coordinate pairs of the form:

(x, y) mentioning in the first position (where the x is), the number in the Domain that connects to the "y" number of the Range). The y goes in the second place. so for example in the relationship we found above, x = 0 connects with y=-5, you would have a shortcut way to write it as the pair: (0, -5) that tells you which x connects with which y.

The functions can also be given in graph form by plotting the relationship between members of the Domain and the Range on the plane. Graphing a point in the plane location that corresponds to the connected x and y values (like you do in the game "battlefield" when you locate ships on the board.

I know this is very general, but hopefully you got the idea ofa function as a special relationship between numbers, and that they can be expressed in different fashions.

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