1. Which of the following shows the process of freezing?'
A.candle wax cooling on the table
B.pouring cola over ice
C.heating a cup of water
D.particles are speeding-up and colliding more

Answer:

6.022 × 1023

Explanation:

1 mole of H:

The definition of Avogadro's number of 6.022 × 1023/mole is the number of atoms or molecules per one gram atomic weight. For one gram atomic weight of hydrogen with an atomic weight of one gram, one mole of hydrogen contains 6.022 × 1023 hydrogen atoms. 1.45⋅6.02⋅1023≈8.73⋅1023 hydrogen atoms.

1 mole:

The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).

in an H:

H: 2×2×4=16 atoms of hydrogen. C: It only appears once and without a subscript, so 1×4=4 .  O : Like carbon, it's 1×4=4 .

1.00 mole:

One mole is equal to 6.02214179×1023 atoms, or other elementary units such as molecules.

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Answer:

objects thaty release 0H+ and H- ions when dissociated

Explanation:

in chemistry

please mark brainliest

Explanation:

conjugated base is substance formed when an acid loses

a hydrogen ion.

conjugated acid is a type of acid that is formed when a base accepts a proton in solution

Answer:

huh

Explanation:

Answer:

d took the test

Explanation:

Electrolysis is a technique that separates natural elements. It is commercially used to obtain important materials (e.g., pure metals) for construction.

Electrolysis refers to the use of an electric current to trigger non-spontaneous chemical reactions.

This technology (electrolysis) is commercially important in industry, construction and therefore also in architecture in order to extract metals and minerals from the ground.

Electrolysis uses particular electrolytic cells in order to extract highly pure metals from ores.

Learn more about electrolysis here:

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Answer: Electrolysis is a technique that separates natural elements. It is commercially used to obtain important materials (e.g., pure metals) for construction.

Electrolysis refers to the use of an electric current to trigger non-spontaneous chemical reactions.

This technology (electrolysis) is commercially important in industry, construction and therefore also in architecture in order to extract metals and minerals from the ground.

Electrolysis uses particular electrolytic cells in order to extract highly pure metals from ores.

Learn more about electrolysis here:

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Answer:

c

Explanation:

Answer:

it indicates that the lower orbitals are filled first and they have the maximum number of electrons compared to the higher orbitals

The Coriolis Effect (Core-nol-e-us)

Answer:

2.00n2g

Explanation:

hope its attachments

Answer:

5-3. Ice water 0 "C. A steel tank contains carbon dioxide at 27 "C and a pressure of 12.0 atm.

Explanation:

Answer: 1 more of hydrogen =22.4dm3

X moles of hydrogen =4.48dm3

22.4dm3x = 4.48dm3

4.48dm3\22.4dm3

X=0.2 moles

Explanation: 1 volume of hydrogen at STP is 22.4dm3

Answer:

I hope it help you the wavelength is 1.9130E-28

Answer:

About 58%.

Explanation:

We first need to write the balanced chemical equation:

[tex]\displaystyle \text{CH$_4$(g)} + 2\text{O$_2$(g)} \longrightarrow \text{CO$_2$(g)} + 2\text{H$_2$O(g)}[/tex]

We are given that 0.809 g of carbon dioxide was produced from the reaction of 0.80 g of methane and 2.1 g of oxygen gas. We want to calculate the percent yield of carbon dioxide.

First, determine the limiting reagent. We can convert each initial mass to the mass of carbon dioxide using stoichiometry. The molar mass of methane is 16.05 g/mol and the molar mass of carbon dioxie is 44.01 g/mol. From the equation, every one mole of carbon dioxide is produced from every one mole of methane and every two moles of oxygen gas.

0.80 g of methane will (theoretically) produce:

[tex]\displaystyle \begin{aligned} 0.80 \text{ g CH$_4$} &\cdot \frac{1 \text{ mol CH$_4$}}{16.05 \text{ g CH$_4$}} \cdot \frac{1 \text{ mol CO$_2$}}{1 \text{ mol CH$_4$}} \cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} \\ \\ & = 2.2 \text{ g CO$_2$}\end{aligned}[/tex]

2.1 g of oxygen gas will (theoretically) produce:

[tex]\displaystyle \begin{aligned} 2.1 \text{ g O$_2$} & \cdot \frac{ 1 \text{ mol O$_2$}}{32.00 \text{ g O$_2$}} \cdot \frac{1 \text{ mol CO$_2$}}{2 \text{ mol O$_2$}}\cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} \\ \\ & = 1.4 \text{ g CO$_2$} \end{aligned}[/tex]

Hence, oxygen gas is the limiting reagent. A maximum of 1.4 g of carbon dioxide can be produced.

To calculate the percent yield, we divide the actual yield by the theoretical yield. The actual yield was 0.809 g and the theoretical yield is 1.4 g. Hence:

[tex]\displaystyle \begin{aligned} \%\text{Yield} & = \frac{\text{Actual}}{\text{Theoretical}} \times 100\% \\ \\ & = \frac{(0.809\text{ g CO$_2$})}{(1.4\text{ g CO$_2$})} \times 100\% \\ \\ & = 58\%\end{aligned}[/tex]

In conclusion, the percent yield of carbon dioxide is about 58%.

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[tex] \rule{999pt}{66646pt}[/tex]

Answer:

109.5°

Explanation:

Pls Cross Check It, If It Correct

Answer:it's b hope that help

The molar mass of water is 18 g. Given that there are 0.23 teaspoon for every 1 g. Thus , for 18 g there would be 4.14 teaspoons.

Any substance that contains  6.022 × 10²³ number of atoms is called one mole of that substance. The mass of a compound or molecule containing these much atoms is called its molar mass.

Molar mass of water is 18 g. Thus, it means that one mole of water weighs 18 g. Given that for every 1 g of water there are 0.23 teaspoon. Thus, number of teaspoons for one mole or 18 g of water is:

number of teaspoons = 18 g × 0.23  /1 g

                                    = 4.14 teaspoons.

Therefore, 4.14 teaspoons are required for one mole of water.

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Answer:

B. crest

Explanation:

The highest part of a wavelength is called the crest, meanwhile, the lowest part is the trough.

Answer:

b

Explanation:

it's highest because it have the most higher wave

Answer:

ZH² + O² = ZH²O I think this may help you I don't really know how to explain

The charge on iron (Fe) in iron sulfate (FeSO₄) is equal to +2. Therefore, option (D) is correct.

The ionic charge can be described as the oxidation number of the chemical species. The cation carries a positive ionic charge while Anion carries a negative ionic charge. The number of electrons gained or lost by an atom decides the charge carried by ions.

In the modern periodic table, the elements placed on the left side are electropositive and act as metals because they can donate one or more electrons. The elements placed on the right side are electronegative as they can accept one or more electrons and get a negative charge on their ions.

Considering that the charge on the iron is x, We know that charge on the sulfate ion is -2.

x - 2 = 0

x = +2

Therefore, the charge on iron (Fe) in iron sulfate (FeSO₄) is +2.

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This is my answer

Explanation:

p=m/v

where:. p=density

m=mass

v=volume

p=F/A = Lim ∆F / ∆A

1 ATM=14.7 psi

= 1.013x10⁶ d/cm²

1 bar=10⁶ d/cm²

=10⁵ N/m2

Hope it helps to you goodluck

I'm not sure but that's the answer of my notebook like my answer please

Answer:

d) Non-polar solvents

Answer:

Explanation:

Glycolysis

Pyruvic acid oxidation

Curbs cycle or citric acid cycle.

Respiratory chain.

Have a great night!

Answer:

plastic,palstic bottle,balloon,cap of water bottle,plastic slippers and plastic comb.

Explanation:

hope it helps :D

Answer:

good day philipines

Explanation:

Answer:

hello

Explanation:

Answer:

A. 4,6-dimethyloct-1,4,6-yne

B. deconic acid

C. 3-ethyl-4-methyl-7-bromocyclohexene

D. 2,2,3-trimethyl-4-butyl-heptane

E. 3-methylhexane

F. ethyl hexanoate

G. butanal

H. propyne

J. 2,4-dimethyl-pent-2-ene

Explanation:

sorry i didn't have time to do I

Answer:

nm, dm, km, m

Explanation:

1 nanometer = 1e-12 (0.000000000001) kilometers

1 decimeter = 1e-4 (0.0001) kilometers

1 kilometer = 1 kilometer

Regardless of whether 'm' stands for mile or meter, it's still larger than all of these being approx. 1.61 and 1e-3 (0.001) kilometers respectively.

in the future, please provide the exact units.

Such as:

nanometers, decimeters, kilometers, meters