1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua ([tex]v[/tex]), en metros por segundo:
[tex]v = \sqrt{\frac{K}{\rho} }[/tex] (1)
Donde:
[tex]K[/tex] - Módulo de compresibilidad, en newtons por metro cuadrado.[tex]\rho[/tex] - Densidad del agua, en kilogramos por metro cúbico.Si sabemos que [tex]\rho = 1\times 10^{3}\,\frac{kg}{m^{3}}[/tex] y [tex]K = 2,16\times 10^{9}\,\frac{N}{m^{2}}[/tex], entonces la velocidad de las ondas sonoras es:
[tex]v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }[/tex]
[tex]v\approx 1469,694\,\frac{m}{s}[/tex]
La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.
2) Luego, determinamos la longitud de onda ([tex]\lambda[/tex]), en metros, mediante la siguiente fórmula:
[tex]\lambda = \frac{v}{f}[/tex] (2)
Donde [tex]f[/tex] es la frecuencia de las ondas sonoras, en hertz.
Si sabemos que [tex]v\approx 1469,694\,\frac{m}{s}[/tex] y [tex]f = 1000\,hz[/tex], entonces la longitud de onda de las ondas sonoras es:
[tex]\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}[/tex]
[tex]\lambda = 1,470\,m[/tex]
La longitud de onda de las ondas sonoras es 1,470 metros.
Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: https://brainly.com/question/1070238
A race car accelerates uniformly from 18.5 m/s in 2.47 seconds m. Determine the acceleration of the car in m/sec^2 and the distance
The change of velocity is from 18.5 to 46.1 m/s or 46.1 - 18.5 = 27.6 m/s. The time of change is 2.47 s. So the acceleration is 27.6 m/s / 2.47 s = 11.17 m/s^2. The distance traveled is average velocity times time of travel.
what is the second longest wavelength for a standing wave on a wire with one fixed end and one open end that is 3.0 m long?
What is the boiling point of water?
Group of answer choices
373.15 degrees Fahrenheit
373.15 degrees Celsius
373.15 Kelvin
Answer:
373.15 Kelvin
Explanation:
Boiling Point of water
= 100 degree Celsius
= (100 + 273.15) Kelvin
= 373.15 Kelvin
how to prove the first linear motion
Answer:
Then solve for v as a function of t. This is the first equation of motion . It's written like a polynomial — a constant term (v0) followed by a first order term (at). Since the highest order is 1, it's more correct to call it a linear function.
Explanation:
A passenger of mass 90kg is involved in a minor car crash. The car approaches a solid barrier at 32m/s. It crashes into the barrer and stops in 0.2s. Determine the impulse that must be applied to the car to bring it to rest
Answer:
I hope this helps:)
Explanation:
good luck:)
about conserving and protecting our coral reefs. 3. Punch a hole and put ribbon or string on it. Rubrics will serve as your guide in creating your bookmark. (SAMPLE BELOW) Protect Keep it our clean! Corals! de Questions: 1. What was your awareness message all about in your bookmark? 5. Do you believe there is a need to protect our coral reefs after doing this activity? Why? The Tubbataha Reef in Palawan is our country's pride. It is one of UNESCO World Heritage Sites. What would you suggest our government do to protect this?
The above question requires a personal answer about your perception of corals, environmental conservation, and the activity you did in the classroom. In that case, I can't answer your question, but I'll show you how to answer it.
Please consider the following information to answer your questions:
The awareness message about corals refers to their preservation, due to their environmental and economic importance.After doing your activity you should be able to understand the importance of preserving corals. That's because they are important for fish spawning and habitat, blocking wave erosion, and protecting coastal communities.To protect coral reefs, the government must map reef areas, reduce marine pollution, monitor fish exploitation, protect coral areas and encourage environmental education and awareness of nature conservation.In summary, coral reefs must be protected so that the natural marine balance is maintained.
More information about coral reefs at:
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assume that the hubble constant is 72 km/s/mpc. if a galaxy is 100mpc away, how fast is it moving away from us?
The galaxy is 7200 km/s moving away from us.
A Hubble is a large telescope in space.
The question can be solved using the formula below
⇒ Formula
v = Cd........................ Equation 1⇒ Where:
v = Speed of the galaxyC = Hubble constantd = Galaxy's distance⇒ Given:
C = 72 km/s/mpcd = 100 mpc⇒ Substitute these values into equation 1
v = 72(100)v = 7200 km/s.Hence, the galaxy is 7200 km/s moving away from us.
Learn more about Hubble here: https://brainly.com/question/14615983
5. A ball is shot directly into the air vertically with an
initial velocity of 49.7 m/s. What is the velocity of the
ball after 3 seconds?
a. 3.4 m/s
b. 20.3 m/s
c. 12.4 m/s
d. 202.0 m/s
2.
A swimmer swims 1 m/s due north against a current of 3 m/s due south. What is the resultant velocity of
the boat?
The resultant velocity of the boat is equal to 2 m/s due south.
Given the following data:
Swimmer's speed = 1 m/s due northOcean current speed = 3 m/s due south.To determine the resultant velocity of the boat:
Resultant velocity can be defined as the sum (addition) of each of the vector velocity acting on a physical or an object. Thus, it is simply a combination of two or more single vector velocity.
Note: When the velocities are acting in the same direction, you will add them up while you will subtract when the velocities are acting in opposite directions.
In this scenario, the velocities are acting in opposite directions. Thus, we would subtract as follows:
[tex]V = 3 - 1[/tex]
V = 2 m/s due south.
Read more on resultant velocity here: https://brainly.com/question/11182174
advantages of writing very large and very small numbers in the terms of power of ten
Answer:
Large numbers might create fuse, be confusing and if you miss even one of the zeros it is a very big deal in a situation when you are making a spaceship. Hope this answers your questions :) Merry Christmas. Have fun.
Explanation:
2
Explanation:
for saving space in large numbers
and small numbers for multiplying easily
Samantha's teacher asks her to describe motion in one dimension. This type of motion is always
A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.
Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.
In Science, the motion of an object or physical body is described in terms of the following parameters:
SpeedForceAccelerationDistanceTimeFurthermore, there are three (3) forms of motion based on dimension and these include:
1. Motion in one dimension
2. Motion in two dimension
3. Motion in three dimension
A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.
Read more on motion here: https://brainly.com/question/17675825
The decomposition of dinitrogen pentoxide is described by the reaction: 2N2O5(g)→4NO2(g)+O2(g). If O2 is being formed at a rate of 2.40 mol/min, what is the rate at which N2O5 is being used up?
Answer:
4.80 mol N2O5/min
Explanation:
The balanced equation tells us that 2 moles of N2O5 are required for every 1 mole of O2. Therefore:
(2.40 mol O2/min)*(2 mol N2O5/mol O2) = 4.80 mol N2O5/min
Which statement describes ionic compounds?
A) ionic compounds are positively charged
B) ionic compounds are neutral
C) ionic compounds are negatively charged
Answer:the answer is b
Explanation:
This is because in an ionic bond negative and positive bonds are present
how does gravitational lensing tell us about the mass of a galaxy cluster?
Answer:
Newton's universal law of gravitation predicts how mass can distort light, so we can apply Newton's law to determine the mass of the cluster. ... The lensing allows us to determine the orbital speeds of galaxies in the cluster, so that we can determine the mass of the cluster from the orbital velocity law.
Explanation:
what depth would a submarine have to submerge so that it would not be swayed by surface waves wwith a wavelength of 30 meters
Answer:
Explanation:
ello
according to newton's third law, of a sledgehammer hits a wall with a force of 1000 n, how much force does the wall hit the sledgehammer? a - 1000 n b 1000 n c 0 n d 500 n
The correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
Newton's third lawNewton's third law of motion states that for every action or force, there is an equal but oppositely directed force.
Application of the newton's third lawForce with which the sledgehammer hits the wall = 1000 N
From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.Thus, the force exerted by the sledgehammer on the wall = -1000 N
The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.Thus, the correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
Learn more about Newton's third law and force at: https://brainly.com/question/13874955
Determine the kinetic energy of a 1500 kg roller coaster that is moving with a
speed of 35 m/s.
A) 200,000 J
B) 25,000
C) O 918,750
D) 920,000J
Answer:
918,750 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass in kg
v is the velocity in m/s
From the question
m = 1500 kg
v = 35 m/s
We have
[tex]k = \frac{1}{2} \times 1500 \times {35}^{2} \\ = 750 \times 1225 \\ = 918750[/tex]
We have the final answer as
918,750 JHope this helps you
A current of 2.0 A flows through a flashlight bulb when it is connected
across the terminals of a 5 V battery. What is the energy dissipated by this
bulb during 1 hour of continuous working?*
Using Joules law
[tex]\\ \sf\Rrightarrow H=VIt[/tex]
[tex]\\ \sf\Rrightarrow H=5(2)(1)[/tex]
[tex]\\ \sf\Rrightarrow H=10Kwh[/tex]
Stacey runs around a 400 meter track 2 times in 5 minutes. How does her displacement differ from her distance? *
Answer:
Distance is 800 m and Displacement is 0 m
Explanation:
Total Distance
= 400(2)
= 800 m
Total Displacement
= 0 m since she returns to the same spot
The gravitational force between two asteroids is 6.2 × 108 N. Asteroid Y has three times the mass of asteroid Z.
If the distance between the asteroids is 2100 kilometers, what is the mass of asteroid Y?
Answer:
1.1x10¹⁶ kg
Explanation:
Let m = mass of asteroid y.
Because asteroid y has three times the mass of asteroid z, the mass of asteroid z is m/3.
Given:
F = 6.2x10⁸ N
d = 2100 km = 2.1x10⁶ m
Note that
G = 6.67408x10⁻¹¹ m³/(kg-s²)
The gravitational force between the asteroids is
F = (G*m*(m/3))/d² = (Gm²)/(3d²)
or
m² = (3Fd²)/G
= [(3*(6.2x10⁸ N)*(2.1x10⁶ m)²]/(6.67408x10⁻¹¹ m³/(kg-s²))
= 1.229x10³² kg²
m = 1.1086x10¹⁶ kg = 1.1x10¹⁶ kg (approx)
please help me! i’ll mark brainliest if you’re correct!
The answer is that the resultant force is the vector sum of the component forces. In your simple example, where the component forces (F1 and F2) are at right angles to one another, as illustrated below, then the resultant force (r) is given by:
[tex]r= \sqrt{(f_{1}) {}^{2} +( f_{2})^{2} + 2f_{1}f_{2}. cos \: Θ, } \\ where \\ \: Θ, = angle \: between \: f_{1} \: and \: f_{2} \\ r = \sqrt{(2) {}^{2} + (5) {}^{2} + 2 \times 2 \times 5 \times cos90 } \\ \sqrt{4 + 25} = \sqrt{29} = 5.385 \\ nearest \: hundred = 5.39[/tex]
Answer: 3N to the right
Explanation: 2N- 5N= 3N
What does the Area under a Speed-time graph represent?
A. acceleration
B. average speed
C. deceleration
D. distance travelled
Answer:
d. distance travelled
Explanation:
answer
please help me !! i’ll mark brainliest if you’re right!
"PLS HELP ME WITH THIS QUESTION!" Two factors that affect climate patterns on Earth are the tilt of Earth on its axis and the topography of Earth. Describe how these two factors affect the climate patterns of Earth.
Answer:
The tilt of the Earth causes some places to be hit more by the sun's rays, while the topography affects wind travel.
Explanation:
Because of the way the Earth is tilted on its axis, some parts receive more heat due to being hit more directly by the sun's rays. This is the reason why the North pole is very cold since it doesn't get directly hit by the sun's rays. As for the topography, the way the wind travels is affected by mountains, and the temperature of winds are affected by the places the wind originated from. Also, high altitude places such as mountain summits are colder, while low altitude places are warmer. So, when an area is under direct sunlight, it causes warm climate, and when an area receives warm air because of its topography, it causes further heat.
Help it’s multiple choice 11 through 15 please!
1. • Here, force of gravity on the block = 20 N.
• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]
• The coefficient
[tex] u_{k} = 0.4[/tex]
• Force of friction =
[tex]u_{k} \times \: normal \: \: \: force \\ = 0.4 \times 20N \\ = 8N[/tex]
• Hence, the force of sliding friction between the block and the ground is 8 N.
• So, it is option c. 8 N
2. The answer is option d. continue in the same direction with no change in speed.
We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.
3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.
Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.
So, 1 N = 1 Kg × 1 m/s^2.
4. It is d. not zero.
Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.
5. Force = 2 N
Acceleration of the object A = 2 m/s^2.
Acceleration of the object B = 1 m/s^2.
Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg
And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg
So, the mass of object B is greater than that of object A.
Hence, the answer is option c. Object B has more mass.
Hope you could get an idea from here.
Doubt clarification - use comment section.
how much force would be needed to push a box weighing 30 N up a ramp that ahas an ideal mechanical advantage of 3
Answer:
60n would be the needed force
The force needed to push a box weighing 30 N up a ramp that has an ideal mechanical advantage of 3 is equal to 10 N.
What is the mechanical advantage?The mechanical advantage can be described as the ratio of the input force to the output force. The mechanical advantage of any machine can be determined by the ratio of the forces involved to do the work.
The ratio of the resistance force to the effort is called the actual mechanical advantage which will be comparatively less. The efficiency of a machine is always determined by equating the ratio of its output to its input.
The efficiency of the machine is equal to the ratio of the actual mechanical advantage (M.A.) and theoretical mechanical advantage. Mechanical advantage can be defined as the force produced by a machine to the force applied to it.
Given the load = 30 N and the ideal mechanical advantage = 3
Mechanical advantage = Load/ Effort
Input force or effort = Load/ M.A.
Force = 30/3
Input Force = 10 N
Learn more about the Mechanical advantage, here:
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A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the speed of the train in m/s.
Answer:
0.236 m/s² (rounded)
Explanation:
A hockey player hits a rubber puck from one side of the rink to the other. It has a mass of .170 kg, and is hit at an initial speed of 6 m/s. If the rink is 61 meters long, how fast is the puck moving when it hits the far wall?
By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s
Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:
mass m = 0.170 kg
initial speed u = 6 m/s.
Distance covered s = 61 m
To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V
To do this, let us first calculate the kinetic energy at which the ball move.
K.E = 1/2m[tex]U^{2}[/tex]
K.E = 1/2 x 0.17 x [tex]6^{2}[/tex]
K.E = 3.06 J
The work done on the ball is equal to the kinetic energy. That is,
W = K.E
But work done = Force x distance
F x S = K.E
F x 61 = 3.06
F = 3.06/61
F = 0.05 N
From here, we can calculate the acceleration of the ball from Newton second law
F = ma
0.05 = 0.17a
a = 0.05/0.17
a = 0.3 m/[tex]s^{2}[/tex]
To calculate the final velocity, let us use third equation of motion.
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2as
[tex]V^{2}[/tex] = [tex]6^{2}[/tex] + 2 x 0.3 x 61
[tex]V^{2}[/tex] = 36 + 36
[tex]V^{2}[/tex] = 72
V = [tex]\sqrt{72}[/tex]
V = 8.485 m/s
Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.
Learn more about dynamics here: https://brainly.com/question/402617
a plane mirror forms a virtual image why
how can I make a square fit in a triangle hole
cut the square and make it a triangle