Answer:
7/8 desserts he can make.
Step-by-step explanation:
factorise the following: x*2-2x-3
What is the equation of the line shown in this graph?
Answer:
y = 1
hope that helps you
Can someone Please help me?
should i use dy\dx (normal differentiation) or d²y\dx² (differentiation of the differentiation)?
Use both!
You want to minimize P, so differentiate P with respect to x and set the derivative equal to 0 and solve for any critical points.
P = 8/x + 2x
dP/dx = -8/x² + 2 = 0
8/x² = 2
x² = 8/2 = 4
x = ± √4 = ± 2
You can then use the second derivative to determine the concavity of P, and its sign at a given critical point decides whether it is a minimum or a maximum.
We have
d²P/dx² = 16/x³
When x = -2, the second derivative is negative, which means there's a relative maximum here.
When x = 2, the second derivative is positive, which means there's a relative minimum here.
So, P has a relative maximum value of 8/(-2) + 2(-2) = -8 when x = -2.
PQR is an isosceles triangle in which PQ=PR
M and N are points on PQ and PR such that angle MRQ=angle NQR
Prove that triangles QNR and RMQ are congruent
9514 1404 393
Explanation:
∠MRQ ≅ ∠NQR . . . . given
QR ≅ RQ . . . . reflexive property
∠PQR ≅ ∠PRQ . . . . property of isosceles triangle PQR
ΔQNR ≅ Δ RMQ . . . . ASA postulate
I need help on this thx
Abigail wants to attend a community college. Suppose x represents the number of credits she takes and y represents her total fees in dollars. Which of these statements are correct? Select all that apply.
A.
If tuition amounts to $125 plus $150 per credit, the function that would model this situation is y = 150x + 125.
B.
If tuition amounts to $200 plus $175 per credit, the function that would model this situation is x = 175y + 200.
C.
If tuition amounts to $175 plus $150 per credit, the function that would model this situation is y = 175x + 150.
D.
If tuition amounts to $250 plus $275 per credit, the function that would model this situation is x = 250y + 275.
E.
If tuition amounts to $225 plus $200 per credit, the function that would model this situation is y = 200x + 225.
F.
If tuition amounts to $100 plus $125 per credit, the function that would model this situation is y = 125x + 100.
Answer:
ddddddddddxdddxsddddddddD
Step-by-step explanation:
i hope it helps you
Solve for x -1 + 18x 16x + 9
Answer:
[tex]288 {x}^{2} + x + 18[/tex]
Step-by-step explanation:
Ayan po ang answer sana po makatulong
Paki heart nalang po kung nakatulong
#carrying learning
How do I solve this equation and check the solutions?
Answer:
{-6}
Step-by-step explanation:
Step 1 Raise both sides of the equation to the index of the radical in the case 2
[tex](\sqrt{2x+13} )^{2} =(x+7)^{2}[/tex]
[tex]2x + 13 = (x+7)(x+7)[/tex]
[tex]2x +13 = x^{2} + 14x + 49\\0=x^{2} +12x+36[/tex]
Step 2 Factor
(x + 6)(x + 6) = 0
x + 6 = 0
x = - 6
Step 3 Check -6
[tex]\sqrt{2(-6)+13} = -6 + 7\\\sqrt{-12+13} = 1\\\sqrt{1} = 1\\1 = 1[/tex]
which series has a sum of 20?
Answer:
the first option has a sum of 20
Step-by-step explanation:
Answer:
the first one has a sum of 20
Step-by-step explanation:
Solve 3/5k-5=7/10k by eliminating the fraction. Explain how you determine what to multiply each term by and all the steps to solving the equation.
9514 1404 393
Answer:
k = -50
Step-by-step explanation:
The fraction denominators are 5 and 10. The least common multiple of those values is 10. This means we can eliminate fractions by multiplying both sides of the equation by 10:
6k -50 = 7k
Subtracting 6k from both sides of the equation leaves you with the solution:
-50 = k
A cheetah ran 60/4 and a gazelle ran 100/8 which won is higher
Answer:
The cheeta is slow, the gazelle
Step-by-step explanation:
The cheeta x2 is 120/8 making the gazelle higher
Answer:
Cheetah
Step-by-step explanation:
One: Cheetah's have always been known as the fastest animals on earth.
Mathematically:
60 / 4 = 15 (cheetah)
100 / 8 = 12.5 (gazelle)
15 is higher than 12.5
Given z = 4 (cos (pi/ 2) + i sin (pi/2 ) ) , what is z3?
a)12 (cosine (StartFraction pi Over 2 EndFraction) + I sine (StartFraction pi Over 2 EndFraction) )
b)64 (cosine (StartFraction pi Over 2 EndFraction) + I sine (StartFraction pi Over 2 EndFraction) )
c)12 (cosine (StartFraction 3 pi Over 2 EndFraction) + I sine (StartFraction 3 pi Over 2 EndFraction) )
d)64 (cosine (StartFraction 3 pi Over 2 EndFraction) + I sine (StartFraction 3 pi Over 2 EndFraction) )
Answer:
D
Step-by-step explanation:
The value of z^3 is option (D) [tex]z^{3}=64 (cos(\frac{3\pi }{2} ) + isin (\frac{3\pi }{2} ) )[/tex] is the correct answer.
What is a complex number?A complex number is characterized by an ordered pair of numbers, the real and imaginary parts. It can be represented in multiple ways such as Standard form(rectangular form), Polar form, Exponential form.
For the given situation,
The complex number, z = 4 (cos (pi/ 2) + i sin (pi/2 ) )
[tex]z=4(cos(\frac{\pi }{2} ) + isin (\frac{\pi }{2} ) )[/tex]
⇒ [tex]z^{3}=4^{3} (cos(\frac{\pi }{2} ) + isin (\frac{\pi }{2} ) )^{3}[/tex]
By De Moivre's theorem,
[tex]{\displaystyle {\big (}\cos x+i\sin x{\big )}^{n}=\cos nx+i\sin nx}[/tex]
Thus, [tex]z^{3}=64 (cos(\frac{3\pi }{2} ) + isin (\frac{3\pi }{2} ) )[/tex]
Hence we can conclude that the value of z^3 is option (D) [tex]z^{3}=64 (cos(\frac{3\pi }{2} ) + isin (\frac{3\pi }{2} ) )[/tex] is the correct answer.
Learn more about complex numbers here
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Of all the items on the pizza, enter the fraction that is mushrooms.
---------------
Answer:
2/3
Step-by-step explanation:
In GHJ, GH = 21 inches, HJ = 24 inches, and GJ = 9 inches. Which statement is true? A. G is smallest B. J is smallest C. H is largest D. G is largest
Answer:
G is the smallest
H is the largest
Step-by-step explanation:
Given
[tex]GH = 21[/tex]
[tex]HJ = 24[/tex]
[tex]GJ = 9[/tex]
Required
Which of the statements is true
First, we need to solve for G, H and J as follows:
[tex]G + H = 21[/tex] --- (1)
[tex]H + J = 24[/tex] --- (2)
[tex]G + J = 9[/tex] --- (3)
Make G the subject in (1)
[tex]G = 21 - H[/tex]
Substitute 21 - H for G in (3)
[tex]21 - H + J = 9[/tex]
Collect Like Terms
[tex]-H + J = 9 - 21[/tex]
[tex]-H + J = -12[/tex]
Make J the subject
[tex]J = H - 12[/tex]
Substitute H - 12 for J in (2)
[tex]H + H - 12 = 24[/tex]
[tex]2H - 12 = 24[/tex]
Collect Like Terms
[tex]2H = 24 + 12[/tex]
[tex]2H = 36[/tex]
Solve for H
[tex]H = 18[/tex]
Substitute 18 for H in [tex]J = H - 12[/tex]
[tex]J = 18 - 12[/tex]
[tex]J = 6[/tex]
Substitute 18 for H in [tex]G = 21 - H[/tex]
[tex]G = 21 - 18[/tex]
[tex]G = 3[/tex]
So, we have that:
[tex]G = 3[/tex] [tex]J = 6[/tex] [tex]H = 18[/tex]
Hence, we can conclude that:
G is the smallest
H is the largest
Factorise fully : 12x-8
please help :(
Answer:
-96 :)
Step-by-step explanation:
12 x (-8) = -96
if there is one negative in the problem the answer will be negative.
What is the annual interest for a principle of $3,500 at a simple annual interest rate of 2.3%?
Answer:
80.5
Step-by-step explanation:
PLEASE ANSWER ASAP For the Christmas and holiday season, every student in Mrs. Perri’s class decided to send a card to each student in the class and to Mrs. Perri. There are 31 students in the class. How many cards were sent that day?
What is the slope of this line?
Enter your answer as a fraction in simplest term in the box.
Can someone help me with this pls?
Answer:
1/4 is the simplest form
Step-by-step explanation:
Answer:
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What are the vertical asymptotes of 10/X-1
Answer:
Enter a problem...
Algebra Examples
Popular Problems Algebra Find the Asymptotes f(x)=10/(x^2-1)
f
(
x
)
=
10
x
2
−
1
Find where the expression
10
x
2
−
1
is undefined.
x
=
−
1
,
x
=
1
Since
10
x
2
−
1
→
∞
as
x
→
−
1
from the left and
10
x
2
−
1
→
−
∞
as
x
→
−
1
from the right, then
x
=
−
1
is a vertical asymptote.
x
=
−
1
Since
10
x
2
−
1
→
−
∞
as
x
→
1
from the left and
10
x
2
−
1
→
∞
as
x
→
1
from the right, then
x
=
1
is a vertical asymptote.
x
=
1
List all of the vertical asymptotes:
x
=
−
1
,
1
Consider the rational function
R
(
x
)
=
a
x
n
b
x
m
where
n
is the degree of the numerator and
m
is the degree of the denominator.
1. If
n
<
m
, then the x-axis,
y
=
0
, is the horizontal asymptote.
2. If
n
=
m
, then the horizontal asymptote is the line
y
=
a
b
.
3. If
n
>
m
, then there is no horizontal asymptote (there is an oblique asymptote).
Find
n
and
m
.
n
=
0
m
=
2
Since
n
<
m
, the x-axis,
y
=
0
, is the horizontal asymptote.
y
=
0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x
=
−
1
,
1
Horizontal Asymptotes:
y
=
0
No Oblique Asymptotes
image of graph
The vertical asymptotes of the given function are x = 1 and x = -1,
We have given the rational function is 10/(x²-1).
We need to find the vertical asymptotes of this function.
Since Vertical asymptotes occur when the denominator of the function becomes zero and the numerator is not zero.
To determine the vertical asymptotes of the function, we need to solve the denominator for x²-1=0.
x²-1=0
x²=1
x=±√1
x=±1
Therefore, the vertical asymptotes of the given function are x = 1 and x = -1, since the denominator becomes zero at x=1 and x=-1.
To learn more about vertical asymptotes visit:
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Find the recursive rule, explicit rule, and f(20)
Answer:
Recursive:
[tex]f(1)=4, f(n)=f(n-1)-4[/tex]
Explicit:
[tex]f(n)=4-4(n-1)[/tex]
And the 20th term f(20) is -72.
Step-by-step explanation:
We have the sequence:
4, 0, -4, -8...
Let’s find the recursive and explicit rule for the sequence.
Recursive Rule:
Let’s determine the factor by which the sequence is decreasing by. We see that each subsequent term is 4 less than the previous term. In other words, our common difference is -4.
So, this is a arithmetic sequence.
The standard format for an recursive rule for an arithmetic sequence is:
[tex]f(1)=a , f(n)=f(n-1)+(d)[/tex]
Where a is the initial term and d is our common difference.
From our sequence, we know that our initial term a is 4.
We also determined that our common difference is -4.
Substitute. Hence, our recursive rule is:
[tex]f(1)=4, f(n)=f(n-1)-4[/tex]
Explicit Rule:
The standard format for an explicit rule for an arithmetic sequence is:
[tex]f(n)=a+d(n-1)[/tex]
Where a is the initial term and d is the common difference. So, again, let’s substitute 4 for a and -4 for d. Hence, our explicit formula is:
[tex]f(n)=4-4(n-1)[/tex]
To find f(20), we can use the explicit formula. It is possible to use the recursive formula, but it gets tedious. Therefore, we will substitute 20 for n for our explicit formula:
[tex]f(20)=4-4(20-1)[/tex]
Evaluate:
[tex]\begin{aligned} f(20)&=4-4(19) \\ f(20)&=4-76 \\ f(20)&=-72 \end{aligned}[/tex]
Hence, our 20th term is -72.
At part of an hour passes between 3:12pm an 4:30pm
Help
Answer:
1h 18min
Step-by-step explanation:
Not sure if that is what the problem is asking you.
Answer:
An 1 hour and 18 minutes
Step-by-step explanation:
Yes uhmmm hope this helps I guess
Jan jdjnznxwjzn help
Answer:
A.
Step-by-step explanation:
What is the estimated product?
86 × 32
Answer:
2,752
Step-by-step explanation:
86x32 = 2752
Product: It means to multiply.
Answer:
I believe the estimated product is 2749
for what value of X is ABCD a rectangle ? explain your answer
Answer:
10
Step-by-step explanation:
If ABCD is a rectangle, then AB=CD and AC=BD.
AC=BD, so x+6=2x-4Subtract, -x+6=-4Subtract, -x=-10Make positive, x=10Check work:
10+6=2(10)-410+6=20-416=16Simplify the expression.
-3a + (-5a) – 7 + 6a
A. 14a + 7
B. -2a + 7
C. 2a - 7
D. -2a - 7
SHOW YOIUR WORK PLZSSSSSS
Can you tell me whether this represents a function or not? (For both questions, just say ‘Yes or No’)
Answer:
No for both
Step-by-step explanation:
If 2 x values that are the same but different y values for them then its not a function
Please Help Quick ASAP Hurry This is Pre-Algebra 1 i need the answer now please ASAP
Which Word Best describes the numbers 10 and -10?
A.Opposites
B.Coordinate
C.Absolute Value
D.Expression
Answer:
Part A
Step-by-step explanation:
2.30+2.50+2.75+2.00
Answer:
9.55 hope this helps :)
Step-by-step explanation:
1
2.30
2.50
+ 2.75
2.00
-----------
9.55
is the point (-2,3) a solution to y<2x+1?
Answer:
No it is not
Step-by-step explanation:
Plug it in
3 < 2(-2) + 1
3 < -4 + 1
3 < -3
3 is not less than -3