You're flying from Joint Base Lewis-McChord (JBLM) to an undisclosed location 201 km south and 194 km east. Mt. Rainier is located approximately 56 km east and 40 km south of JBLM. If you are flying at a constant speed of 800 km/hr, how long after you depart JBLM will you be the closest to Mt. Rainier?

Answers

Answer 1

Answer:

The answer is "0.0846276476".

Step-by-step explanation:

Let all the origin(0,0) of JBLM be  

Let the y-axis be north along with the vector j unit.  

But along the + ve x-axis is east, and all along with the vector unit i.  

And at (194,-201) that undisclosed position is  

Mt. Ris (56,-40) at  

Let the moment it gets close to the Mt. rainier bet.  

Oh, then,  

If we know, the parallel to the direction from the point was its nearest one to a path to a point,

Calculating slope:

[tex]\to m=\frac{y_2-y_1}{x_2-x_1}\\[/tex]

points:  (0,0) and (194,-201)

[tex]\to m=\frac{-201 -0 }{194-0}\\\\\to m=\frac{-201}{194}\\\\\to m=-1.03[/tex]

equation of the line:

[tex]\to y= mx+c\\\\\to y= -1.03\ x+c[/tex]

when the slope is perpendicular= [tex]-\frac{1}{m}[/tex]

                                                     [tex]= - \frac{1}{ -1.03}\\\\= \frac{1}{ 1.03}\\\\= 0.97[/tex]

perpendicular equation:

[tex]\to y-(-40)=0.97 \times (x-56) \\\\\to y+40=0.97 \times (x-56) \\\\[/tex]

Going to solve both of the equations to have the intersection point,  

We get to the intersect level in order to be at

(47.16,-48.5748)

so the distance from origin:

[tex]= \sqrt{(47.16^2+48.5748^2)}\\\\= \sqrt{2224.0656 + 2359.5112}\\\\=\sqrt{4583.5768}\\\\=67.7021181[/tex]

[tex]\to time =\frac{distance }{speed}[/tex]

[tex]= \frac{67.7021181}{800}\\\\= 0.0846276476[/tex]


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What is the slope of a line that is parallel to the line joining (7,-5) and (-5,7)

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Answer:

Step-by-step explanation:

If two lines are parallel then they will have the same slope. So all you need to do is find the slope of the line that joins the two given points. You can use the slope formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]. You can also graph the two points and use rise over run. [tex]\frac{7-(-5)}{-5-7} =\frac{12}{-12}=-1[/tex]

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What is a Linear equation?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. Sometimes, the aforementioned is referred to as a "linear equation of two variables," with y and x serving as the variables.

Given, a line that is parallel to the line joining (7,-5) and (-5,7)

Since lines are parallel to each other thus their slope will be the same.

From the general formula of slope:

Slope = (y₂ - y₁)/(x₂ - x₁)

Slope = (7 + 5)/ -5 - 7)

Slope = -1

Therefore, the slope of a line that is parallel to the line joining (7,-5) and (-5,7) is -1.

Learn more about Linear equations here:

https://brainly.com/question/11897796

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Step-by-step explanation:

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Step-by-step explanation:i took the test

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

  see attached

Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

Let Lucas final grade be x

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Answers

Answer:

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Step-by-step explanation:

Given m∠GHF = 34°, m∠HJF = 124°, and m∠FKJ = 79°.

Answers

Angle GFJ = 56 degrees

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Step-by-step explanation:

The measure of the angles are:

[tex]\mathbf{GFJ = 56}[/tex]

[tex]\mathbf{GFJ = 56}[/tex]

[tex]\mathbf{\angle HFJ = 34}[/tex]

[tex]\mathbf{\angle HKJ =101}[/tex]

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So, we have:

[tex]\mathbf{GFJ = 180 - 124}[/tex]

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[tex]\mathbf{\angle HFJ = 34}[/tex]

(d) Angle ∠HKJ

This is calculated as:

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So, we have:

[tex]\mathbf{\angle HKJ =180 - 79}[/tex]

[tex]\mathbf{\angle HKJ =101}[/tex]

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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