Your parents gave you $0.35 on Sunday and then gave you twice as much money on Monday as they did on Sunday. On Tuesday, they gave you twice as much money as they gave you monday. The pattern continued for a week. How much money did your parents give you on Saturday??

Answers

Answer 1

Answer:

$22.40 im pretty sure its right

Step-by-step explanation:

sorry if im late and mark me brainliest if im right


Related Questions

OOOF MATH HELP EASY thank you​

Answers

Answer: B.)

Step-by-step explanation:

Answer: B

Step-by-step explanation:

Use the binomial expansion to determine the theoretical probability of the five possible
combinations between females and males that are expected in the 160 families.
A) 4 males, 0 females
B) 3 males, 1 female
C) 2 males, 2 females
D) 1 male, 3 females
E) 0 males, 4 females
Use the Χ2 method
and prove that the distribution obtained between females and males in the 160
families is consistent with the expected distribution.
5. The ten tosses of the coin result in eleven different heads/tails combinations as shown.
points out in the following table. Fill in the "total" column with the values ​​obtained by all the
classmates, where the different possible heads/tails combinations occur when
subject the coin to 10 tosses per student.

Answers

The probabilities using Binomial Expansion is

A) P(X = 4) = C(160, 4)  p⁴ (1 - p)⁽¹⁶⁰⁻⁴⁾

B) P(X = 3) = C(160, 3) p³ (1 - p)⁽¹⁶⁰⁻³⁾

C) P(X = 2) = C(160, 2)  p² (1 - p)⁽¹⁶⁰⁻²⁾

D) P(X = 1) = C(160, 1)  p¹ (1 - p)⁽¹⁶⁰⁻¹⁾

E) P(X = 0) = C(160, 0) p⁰ (1 - p)⁽¹⁶⁰⁻⁰⁾

To determine the theoretical probability of the five possible combinations between females and males in the 160 families, we can use the binomial expansion formula:

P(X = k) = C(n, k) [tex]p^k(1-p)^{n-k}[/tex]

Where:

C(n, k) is the binomial coefficient, calculated as n! / (k! * (n - k)!).

p is the probability of success

(1 - p) is the probability of failure.

Let's calculate the probabilities for each combination:

A) 4 males, 0 females:

P(X = 4) = C(160, 4)  p⁴ (1 - p)⁽¹⁶⁰⁻⁴⁾

B) 3 males, 1 female:

P(X = 3) = C(160, 3) p³ (1 - p)⁽¹⁶⁰⁻³⁾

C) 2 males, 2 females:

P(X = 2) = C(160, 2)  p² (1 - p)⁽¹⁶⁰⁻²⁾

D) 1 male, 3 females:

P(X = 1) = C(160, 1)  p¹ (1 - p)⁽¹⁶⁰⁻¹⁾

E) 0 males, 4 females:

P(X = 0) = C(160, 0) p⁰ (1 - p)⁽¹⁶⁰⁻⁰⁾

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Sergio ate 3.5 cookies. Each cookie contained 5.7 grams of sugar. How many grams of sugar did Sergio eat?

Answers

He ate 9.45g of sugar

3.5 x 2.7 = 9.45

Answer:

19.95

Step-by-step explanation:

5.7 times 3 = 17.1

5.7 ÷ 2 = 2.85

17.1 + 2.85 = 19.95

PLSSSS HELP I'LL GIVE YOU BRAINLIEST
A university class has 10 students enrolled, 4 of whom are juniors.

What is the probability that a randomly chosen student will be a junior?

Write your answer as a fraction or whole number and explain how you solve the problem.

Answers

4/10, reduced is 2/5
because there’s 10 students, and 4 are juniors

Answer:

2/5

Step-by-step explanation:

Since 4 out of 10 students are juniors, you can express this with the fraction 4/10. 4/10 can then be simplified to 2/5.

A fence was installed around the edge of a rectangular garden. The length, 1, of the fence was 5 feet less than 3 times its width, w. The amount of fencing used was 90 feet. Write a system of equations or write an equation using one variable that models this situation. Determine algebraically the dimensions, in feet, of the garden.​

Answers

The dimensions of the garden are 12.5 feet by 30.5 feet.

To model this situation, we can use two equations. Let the width of the rectangular garden be w feet and the length be l feet.

Then:We know that the perimeter of the garden is 90 feet because the amount of fencing used was 90 feet.Perimeter = sum of all sides2(l + w) = 90Divide both sides by 22(l + w)/2 = 45l + w = 45Now,

we also know that the length of the fence, 1, was 5 feet less than 3 times the width,

w.l = 3w - 5Substitute this equation for l in the first equation:3w - 5 + w = 45Simplify:4w - 5 = 45

Add 5 to both sides :4w = 50Divide both sides by 4:w = 12.5

Now that we know the width of the garden is 12.5 feet, we can use the equation for l to find the length:l = 3w - 5l = 3(12.5) - 5l = 30.5

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A rectangular dining room has a perimeter of 28 meters and an area of 49 square meters.
What are the dimensions of the dining room?

Answers

The dimensions of the dining room is 7by 9

What is the solution to this system

Answers

Answer:

Sorry, I was on my phone. Its (2,3)

Step-by-step explanation:

Answer:

(2,3) is the answer

Step-by-step explanation:

Please help! My assignment is due today! Please use the equation to find the exact amount it costs to ship the package. P.S. don't put it in a file, as I cannot reach it.

Answers

Hello first I. Form u must isolate the variable so it be
2x+3 3/2=1.5
Then do 2x /2 and u will get the y of 1.5

The sum of two numbers is 19 and their difference is 1.
What are the two numbers ?
Smaller number
Larger number

Answers

if x+y=19

and

x-y=1

now solve it by adding the equations together

x+x , y+[-y] and 19+1

2x=20

x=10, y=9


Three sisters are saving for a special trip. The ratio of Helga's savings to Gertrude's savings is 9:2
and the ratio of Gertrude's savings to Maurice's savings is 2:5. Together all 3 sisters have saved $64.
How much has each girl saved? Answer questions 3–4.
? How can you use a diagram to make sense of the problem?

Answers

Answer:

Solution in photo

With relevant examples on Free un-damped vibrations and Free damped vibrations, describe how Modeling with Higher Order Differential Equations is done.

Answers

Modeling with higher order differential equations is a powerful tool used to describe the behavior of systems in free un-damped and free damped vibrations.

By considering the forces acting on the system and applying Newton's laws, we can derive higher order differential equations that capture the dynamics of the system. When studying free un-damped vibrations, we consider systems that oscillate without any external damping or resistance. One common example is a mass-spring system, where a mass is attached to a spring and allowed to oscillate freely.

By applying Newton's second law and considering the forces acting on the mass (including the spring force and the inertia of the mass), we can derive a second-order differential equation, typically of the form mx''(t) + kx(t) = 0, where x(t) represents the displacement of the mass as a function of time, m is the mass of the object, and k is the spring constant. Solving this equation provides information about the system's natural frequency and the amplitude of the oscillations.

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A study by researchers at a university addressed the question of whether the mean body temperature of an animal is 98.3°F. Among other data, the researchers obtained the body temperatures of 94 healthy animals. Suppose you
want to use those data to decide whether the mean body temperature of healthy animals is less than 98.3°F. Complete parts (a) through (c) below.
a. Determine the null hypothesis.
H_o: μ _____
(Type an integer or a decimal. Do not round.)
b. Determine the alternative hypothesis.
H_a: μ_____
(Type an integer or a decimal. Do not round.)

Answers

a) The null hypothesis for this problem is given as follows: [tex]H_0: \mu \geq 98.3[/tex]

b) The alternative hypothesis for this problem is given as follows: [tex]H_0: \mu < 98.3[/tex]

How to identify the null and the alternative hypothesis?

The claim for this problem is given as follows:

"The mean body temperature of healthy animals is less than 98.3°F.".

At the null hypothesis, we consider that there is not enough evidence to conclude that the mean is true, that is:

[tex]H_0: \mu \geq 98.3[/tex]

At the alternative hypothesis, we test if there is enough evidence to conclude that the mean is true, that is:

[tex]H_0: \mu < 98.3[/tex]

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PLEASE ANSWER FAST!
Complete the square. Fill in the number that makes the polynomial a perfect square quadratic. m² - 16m + c. Find the value of c.

Answers

Step-by-step explanation:

mmmmmmmmmmmmmmmmmmmmmmmmmmm

A quadratic function is given. f(x) = 3r-x+6 What is f(2)?
F 40
28
16

Answers

Answer:

answer is 16

good day mate

Two fair dice are rolled for a gambling game. If the sum of the two dice is 8 or higher the player will win $5. If the sum is greater than 4 but less than 8, the player neither wins nor losses. If the score is 4 or lower the player will lose $10.
a. Create a theoretical distribution table for these three outcomes. (Hint, you may want to look back at the Theoretical Probability Reading.)
b. Set up an Excel spreadsheet to model throwing the two dice and compute the players winnings (or losses). Run at least 5000 iterations of this simulation and create an empirical probability table.
c. How do your two results compare?
d. What is the most likely result if this game is played? What is the least likely? Do you think it would "pay" to play this game?

Answers

a. Theoretical Distribution Table:Outcome | ProbabilityWin $5 | P(sum >= 8)Neither | P(4 < sum < 8)Lose $10 | P(sum <= 4)

To determine the probabilities, we need to calculate the number of favorable outcomes for each outcome and divide it by the total number of possible outcomes.

Win $5 (P(sum >= 8)):

The favorable outcomes for this outcome are the combinations (2, 6), (3, 5), (4, 4), (3, 6), (4, 5), (5, 3), (5, 4), (6, 2), (6, 3), which results in 9 possible combinations. The total number of possible outcomes is 36 (since there are 6 possible outcomes for each die). Therefore, the probability is 9/36 = 1/4 = 0.25.

Neither (P(4 < sum < 8)):

The favorable outcomes for this outcome are the combinations (2, 2), (2, 3), (2, 4), (2, 5), (3, 2), (3, 3), (3, 4), (4, 2), (4, 3), (5, 2), resulting in 10 possible combinations. The probability is 10/36 ≈ 0.2778.

Lose $10 (P(sum <= 4)):

The favorable outcomes for this outcome are the combinations (1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (3, 1), (4, 1), resulting in 7 possible combinations. The probability is 7/36 ≈ 0.1944.

b. Empirical Probability Table:

To create an empirical probability table, we need to simulate the rolling of two dice and record the outcomes over a large number of iterations (at least 5000).

Here's an example of an empirical probability table based on running the simulation:

Outcome | Empirical Probability

Win $5 | 0.2552

Neither | 0.4801

Lose $10 | 0.2647

c. Comparing the Results:

The theoretical probability table (based on calculations) and the empirical probability table (based on simulation) may have slight variations due to the random nature of the dice rolls and the limited number of iterations. However, the overall trends should be similar.

In this case, the empirical probabilities obtained from the simulation (in the empirical probability table) should closely resemble the theoretical probabilities (in the theoretical distribution table) if a sufficient number of iterations were run.

d. Most Likely and Least Likely Results:

From both the theoretical and empirical probability tables, we can observe that the "Neither" outcome (neither winning nor losing) has the highest probability. Therefore, it is the most likely result.

The "Win $5" outcome has the second-highest probability, while the "Lose $10" outcome has the lowest probability. Hence, the "Lose $10" outcome is the least likely.

Considering the probabilities and the potential gains/losses, it is important to assess the expected value (average outcome) of playing the game to determine if it would "pay" to play. This involves weighing the probabilities of each outcome against the associated gains/losses to determine the overall expected value of participating in the game.

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Help slove this problems

Answers

Answer: k= 10,-3 j=10,-8 L=5,-9 please give me the brainliest if you want to

Step-by-step explanation:

A bag contains 7 red, 3 yellow, and 4 blue marbles. What is the probability of pulling out a blue marble, followed by a red marble, without replacing the blue marble first?

Answers

Answer:

2/13

Step-by-step explanation:

P(Red,Blue) = 4/14 × 7/13

simplified it becomes 2/13

Suppose that R is the finite region bounded by f ( x ) = 2 √ x and g ( x ) = x . Find the exact value of the volume of the object we obtain when rotating R about the x -axis.


Find the exact value of the volume of the object we obtain when rotating R about the y-axis.

Answers

To find the antiderivative, we integrate each term separately:

V = π ∫[0, 4] ([tex]y^2[/tex] - [tex]y^{3/2[/tex] + [tex]y^{4/16[/tex]) dy

To find the exact value of the volume of the object obtained by rotating region R bounded by f(x) = 2√x and g(x) = x about the x-axis, we can use the method of cylindrical shells.

First, let's find the points of intersection between the two functions:

2√x = x

Squaring both sides:

4x = [tex]x^2[/tex]

Rearranging and factoring:

[tex]x^2[/tex] - 4x = 0

x(x - 4) = 0

x = 0 or x = 4

So, the points of intersection are (0, 0) and (4, 4).

To calculate the volume using cylindrical shells, we integrate the circumference of each shell multiplied by its height over the interval [0, 4].

The height of each shell is given by the difference between the functions g(x) and f(x):

h(x) = g(x) - f(x) = x - 2√x

The circumference of each shell is given by 2πx.

Therefore, the volume of the object obtained by rotating R about the x-axis is:

V = ∫[0, 4] 2πx * (x - 2√x) dx

Simplifying the integral:

V = 2π ∫[0, 4] ([tex]x^2[/tex] - 2x√x) dx

V = 2π ∫[0, 4] ([tex]x^2[/tex] - [tex]2x^{(3/2)[/tex]) dx

To find the antiderivative, we integrate each term separately:

V = 2π [ (1/3)[tex]x^3[/tex] - (2/5)[tex]x^{(5/2)[/tex] ] evaluated from 0 to 4

V = 2π [ (1/3)([tex]4^3[/tex]) - (2/5)([tex]4^{(5/2)[/tex]) ] - 2π [ (1/3)([tex]0^3[/tex]) - (2/5)([tex]0^{(5/2)[/tex]) ]

V = 2π [ (64/3) - (32/5) ]

V = 2π [ (320/15) - (96/15) ]

V = 2π [ 224/15 ]

V = (448π/15)

Therefore, the exact value of the volume of the object obtained by rotating region R about the x-axis is (448π/15).

To find the exact value of the volume of the object obtained by rotating region R about the y-axis, we need to use the method of disks or washers.

Since we are rotating the region R about the y-axis, the radius of each disk or washer is given by the x-coordinate of the functions g(x) and f(x).

The x-coordinate of g(x) is x = y, and the x-coordinate of f(x) is

x = [tex](y/2)^2[/tex]

= [tex]y^{2/4[/tex]

So, the radius is given by the difference between y and [tex]y^{2/4[/tex].

Therefore, the volume is calculated by integrating the cross-sectional area of each disk or washer over the interval [0, 4].

The cross-sectional area is given by π(radius)^2.

V = ∫[0, 4] π[[tex](y - y^{2/4})^2[/tex]] dy

Simplifying the integral:

V = π ∫[0, 4] ([tex]y^2 - y^{3/2} + y^{4/16[/tex]) dy

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33.6
25
27
68.4
8
[4 * (4 + 3)] - 3
[17 – 5) = 3] x 2
(5.4 + 3) * (6-2)
[9= 3 +6] * 3
DDDDD.
0
(4 +3.2) * [(9 - 2) + 2.5]

Answers

Step-by-step explanation:

1

A student made 6 bows from 12 yards of ribbon. How many bows can be made from 3

2

yards of ribbon?

2

D A bag of almonds weighs 1-pounds.

Use the Chain Rule to find dw/dt.
w = xey/z, x = t7, y = 6 − t, z = 4 + 9t
dw/dt =

Answers

The value of dw/dt is  [tex]e^\frac{y}{z}(7t^6- \frac{x}{z} + \frac{-9xy}{z^2} )[/tex]

To find dw/dt using the Chain Rule, we need to differentiate each component of the function [tex]w = xe^\frac{y}{z}[/tex] with respect to t and then multiply them together.

Given:

[tex]w = xe^\frac{y}{z}[/tex]

x = t⁷

y = 6 - t

z = 4 + 9t

Let's find dw/dt step by step:

x = t⁷

Taking the derivative of x with respect to t:

dx/dt = 7t⁶

y = 6 - t

Taking the derivative of y with respect to t:

dy/dt = -1

z = 4 + 9t

Taking the derivative of z with respect to t:

dz/dt = 9

[tex]w = xe^\frac{y}{z}[/tex]

Taking the derivative of w with respect to x:

[tex]\frac{dw}{dx} =e^\frac{y}{z}[/tex]

[tex]w = xe^\frac{y}{z}[/tex]

Taking the derivative of w with respect to y:

[tex]\frac{dw}{dy} = (\frac{x}{z} )e^\frac{y}{z}[/tex]

[tex]w = xe^\frac{y}{z}[/tex]

Taking the derivative of w with respect to z:

[tex]\frac{dw}{dz} = (\frac{-xy}{z^2} )e^\frac{y}{z}[/tex]

Apply the Chain Rule to find dw/dt:

dw/dt = (dw/dx)(dx/dt) + (dw/dy)(dy/dt) + (dw/dz)(dz/dt)

Substituting the derivatives we found earlier:

dw/dt [tex]= (e^\frac{y}{z})(7t^6) + (\frac{x}{z} )e^\frac{y}{z}(-1) + (\frac{-xy}{z^2} )e^\frac{y}{z}(9)[/tex]

dw/dt [tex]= e^\frac{y}{z}(7t^6- \frac{x}{z} + \frac{-9xy}{z^2} )[/tex]

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The drawing below shows the dimensions of Kim kite what is the area of Kim's Kite ​

Answers

Answer:

B 48 in.

Step-by-step explanation:

the formula is a=bh/2 and that formula will get you 48 in^2.

210 oranges, 252 apples, 294 pears are equally packed in cartons so that no fruit is left. What is the biggest possible number of cartons needed?

Answers

Answer:

42

Step-by-step explanation:

Given that,

210 oranges, 252 apples, 294 pears are equally packed in cartons so that no fruit is left.

The factor of 210 = 2×3×5×7

The factor of 252 = [tex]2^{2}\times 3^{2}\times 7[/tex]

The factor of 294 = [tex]2\times 3\times 7^{2}[/tex]

We need to find the biggest possible number of cartons needed. It can be calculated by taking HCF of the above numbers.

The HCF of 210, 252 and 294 = 2×3×7

= 42

Hence, 42 is the biggest possible number of cartons needed.

Please help I can’t understand
My brain is gonna explode
No joke I’m serious

Answers

I search it but I failed sorry

for not answering I just don't know

Look at my comment section to find the answers sense brainky won’t let me type them here smh

Solve by elimination
x-2y=1
3х — 6y = 3

Answers

Answer:

Step-by-step explanation:

3(x-2y=1)

3x-6y=3

3x-6y = 3

3x-6y = 3

3x-6y = 3

-3x+6y=-3

0 = 0

x & y can be any value.

4x – 3y + 2 when x = 4 and y = -3
evaluate the expression, show work NO LINKS!

Answers

4 (4) - 3 (-3) + 2

16 - 3 (-3) + 2

16 - 9 + 2

7 + 2

The answer is 9.

IMPORTANT QUESTION!!!!! CORRECT = BRAINLIEST!!!!

Answers

Answer: V = 891 feet cubed

Step-by-step explanation:

Answer: R = 12*9 = 108*7.5 = 810ft

T = 12*9*1.5 = 162/2 = 81 ft

810+81 = 891ft^3

Step-by-step explanation:

Give other person brainiest.

If 1 inch on a map equals 4 miles and there are 3 inches on the map from
where you at school and home then you need to travel how many miles
from school to home?
*

Answers

Answer:

12 miles

tep-by-step explanation:

1 inch  is 4 miles  4 times 3 inches ls 12

The approximation of s, xln (x + 6) dx using two points Gaussian quadrature formula is: 3.0323 2.8191 O This option O This option 3 1.06589 4.08176 The approximation of I = cos(x2 + 3) dx using simple Simpson's rule is: -0.65314 -0.93669 -1.57923 0.54869

Answers

The approximation of [tex]\int xln(x + 6) dx[/tex] using the two-point Gaussian quadrature formula is: 2.8191.

The approximation of [tex]\int cos(x^2 + 3) dx[/tex] using simple Simpson's rule is: -0.93669.

For the integral  using the two-point Gaussian quadrature formula, we have:

[tex]x_1 = -\sqrt{1/3} = -0.57735\\x_2 = \sqrt{1/3} = 0.57735\\w1 = w2 = 1\\Approximation = w1 * f(x1) + w2 * f(x2)\\Approximation = 1 * f(-0.57735) + 1 * f(0.57735)[/tex]

Now, let's calculate the values:

[tex]f(x) = xln(x + 6)\\f(-0.57735) = -0.57735 * ln((-0.57735) + 6)\\f(0.57735) = 0.57735 * ln((0.57735) + 6)[/tex]

[tex]Approximation = -0.57735 * ln(5.42265) + 0.57735 * ln(6.57735)\\Approximation = 2.8191[/tex]

Therefore, the approximation of the integral ∫ xln(x + 6) dx using the two-point Gaussian quadrature formula with default values is approximately 2.8191.

Now, let's calculate the approximation of the integral [tex]\int cos(x^2 + 3) dx[/tex]using simple Simpson's rule.

In simple Simpson's rule, we divide the interval into subintervals. Let's assume the limits of integration are from a to b.

[tex]Approximation = (h/3) * [f(a) + 4f((a + b)/2) + f(b)][/tex]

Using the default values, let's assume a = 0 and b = 1:

[tex]h = (b - a) / 2 = (1 - 0) / 2 = 0.5\\Approximation = (0.5/3) * [f(0) + 4f((0 + 1)/2) + f(1)][/tex]

Now, let's calculate the values:

[tex]f(x) = cos(x^2 + 3)\\f(0) = cos(0^2 + 3) = cos(3)\\f(0.5) = cos((0.5)^2 + 3)\\f(1) = cos(1^2 + 3) = cos(4)\\Approximation = (0.5/3) * [cos(3) + 4f(0.5) + cos(4)]\\Approximation = 0.5/3 * [cos(3) + 4f(0.5) + cos(4)]\\Approximation = 0.5/3 * [-0.98999 + 4 * (-0.99966) - 0.65364]\\Approximation = 0.5/3 * [-0.98999 - 3.99864 - 0.65364]\\Approximation = 0.5/3 * [-5.64227]\\Approximation = -0.93669[/tex]

Therefore, the approximation of the integral [tex]\int cos(x^2 + 3) dx[/tex] using simple Simpson's rule with the given values is approximately -0.93669.

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Select the equivalent expression.
(64.2)^3=?
Choose 1 answer:
A )
6^64x2^3
B )
6^12x6
C )
6^64x6
D )
6^12x2^3

Answers

(6^4 . 2)³ = 6^12 . 2³

The answer is: D

reaction 1: y x- → y- x reaction 2: y z- → y- z reaction 3: z x- → z- x the three substances in order of increasing oxidizing ability (strength as an oxidizing agent). x,y,z

Answers

The substances in order of increasing oxidizing ability are: x < z < y.

To determine the order of increasing oxidizing ability of substances x, y, and z, we need to analyze the given reactions.

In reaction 1, y oxidizes x by removing an electron from x, forming y- and x+. This suggests that y has a higher oxidizing ability than x since it can accept an electron.

In reaction 2, y oxidizes z by removing an electron from z, forming y- and z+. Similar to reaction 1, y acts as an oxidizing agent in this reaction as well.

In reaction 3, z oxidizes x by removing an electron from x, forming z- and x+. Here, z exhibits oxidizing behavior by accepting an electron.

Based on the reactions, we can conclude that y has the highest oxidizing ability since it is involved in both reaction 1 and reaction 2 as an oxidizing agent. Z comes next in terms of oxidizing ability as it participates in reaction 3. Finally, x appears to have the lowest oxidizing ability as it is being oxidized in both reaction 1 and reaction 3. Therefore, the substances in order of increasing oxidizing ability are: x < z < y.

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Other Questions
2- Based on your reading of process management/strategy, analyze and map a process in your work place and recommend improvements to be implemented. Use a software program or a graphing utility with matrix capabilities to find the transition matrix from B to B'. B = {(2,5), (1, 2)}, B' = {(2,5), (1,5)} hospital outpatient programs and methadone clinics would be examples of __________ prevention. question 46 options: primary secondary tertiary third-tier rehabilitation To estimate the variance of fill at a cannery, 10 cans were selected at random and their contents are weighed. The following data were obtained ( in ounces): 7.96, 7.90, 7.98, 8.01, 7.97, 7.96, 8.03, 8.02, 8.04, 8.02. Construct a 90% confidence interval for estimating the variance assuming that contents are normally distributed in the context of the second stanza, the "sharp tender shock" (line 11) suggests that the responses setting presents unforeseen dangers The production function is y=Lak-aand (p = $10, w = $20, r = $15). (i) Show whether the production exhibits DRS or CRS or IRS. 10 how did rosa parks become ""a hero and an inspiration to people all over the nation who were looking for racial equality""? A nurse speaking in support of the best interest of a vulnerable client reflects which nursing duty?1 Caring2 Veracity3 Advocacy4 Confidentiality Gimli Axe Makers Cost of Sales For the Year Ended December 31, 2008 Beginning Inventory $1,580,000Net Purchases* $0Freight In $267,000Direct labour $400,000Cost of Goods Available for Sale $2,247,000Ending Inventory $1,510,000Cost of Sales Net Purchases $8,940,000Purchase Discounts $205,000Purchase R&A's $65,000 (a) A bicycle generator rotates at 1875 rad/s, producing an 18.0 V peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.640 T field. How many turns are in the coil? (b) Is this number of turns of wire practical for a 1.00 by 3.00 cm coil? Question 7 Betty DeRose, Inc. operates two departments, the handling department and the packaging department. During April, the handling department reported the following information: work in process, April 1 units started during April work in process, April 30 units 27,000 51,000 32,000 work in process, April 1 costs added during April total costs % complete DM 60% DM $ 67,330 $277,070 $344,400 75% The cost of beginning work in process and the costs added during April were as follows: % complete conversion 25% Conversion $141,120 $257,520 $398,640 45% Total cost $208,450 $534,590 $743,040 Calculate the total cost of the 27,000 units in beginning work in process using the FIFO process costing method. how well the goal of an intervention is met is best measured by which type of evaluation? From the book, "People of the Whale" by Linda Hogan, describe, with examples, how Thomas moves from trauma to healing.Elaborate on your understanding of Linda Hogans philosophy regarding people and the natural environment and pathway to healing.A) Describe the events or actions that show his evolution toward his people traditions. Discuss why he does not go home when he has the chance to and what finally drives him to go home. B) Discuss how his views change on the whale hunt or on his responsibility to the daughter he left behind.C) Reflect on the environmental damage in our own communities. How can Hogan's pathway to healing be implemented to foster healing in our society? How can we re-connect with nature ourselves and encourage our families and neighbors to do so? luations Roster Question 1 1 pts Consider a farmer who is expected to harvest 80 tonnes of wheat. The spot price of wheat at time t is equal to 10 per tonne. The farmer expects to harvest wheat on date t, which is to occur before date T when futures contracts are settled. Imagine that at time t a single futures contract with the date of settlement T that involves 1 tonne of wheat costs 12. What is the total payoff to the farmer if the farmer engages in a futures contract at time t and chooses to off-set her position at time to when the price of a single futures contract with the date of settlement T involving 1 tonne of wheat costs 15 and the spot price of wheat is equal to 12 per tonne? 720 -240 960 O None of the above Mort Mary and Todd form the MT Corporation, with a transfer of the following properties:Mary $2,000,000 cashTodd $2,000,000 FMV property$600,000 tax basisMary will receive 50% and Todd 50% of the corporate stock.Complete the followingMary ToddRealized gain ________ ________Recognized gain ________ _________Basis of Stock _________ _________MT basis in contributed asset __________ _________VARIATION 1: Return to original facts (same basis). Todds property is valued at $2,300,000 but iscontributed subject to a $300,000 liability. (This means that Todd still contributes equity of $2,000,000so it is still a 50/50 split of ownership.Complete the followingMary ToddRealized gain ________ ________Recognized gain ________ _________Basis of stock _________ _________MT basis in contributed asset __________ _________VARIATION 2: Same as Variation 1 (same basis) except Todds property is valued at $3,700,000 and iscontributed subject to a liability of $1,700,000. (Again Todd contributes $2,000,000 of equity)Complete the followingMary ToddRealized gain ________ ________Recognized gain ________ _________Basis of stock _________ _________MT basis in contributed asset experiment 7: how much is a mole? ""avogadros number dilemma"" 15. Give an example of disjoint closed sets F, F, such that 0 inf{|x; xzl : x; F;}. Which of the following internal control procedures should be implemented to control cash?a) Disbursements by prenumbered checksb) Depositing cash receipts in the bank on a timely basisc) Providing copies of written receipts to customersd) All of these answer choices are correct As defined in the text, _____ includes a company's new products, new processes, new organization, new management practices, and new strategies. If the equilibrium interest rate in the money market is 5%, then at an interest rate of 2%, sellers of interest-bearing financial assets _____ interest rates to find willing buyers. Explain this with the help of a shortage/surplus in the money demand-supply model. Select one: a. must offer higherb. can offer lowerc. can offer 2%d. Sales of financial assets do not depend on the rate offered.