You pull straight up on the string of a yo-yo with a force 0.19 N, and while your hand is moving up a distance 0.12 m, the yo-yo moves down a distance 0.30 m. The mass of the yo-yo is 0.058 kg, and it was initially moving downward with speed 3.4 m/s. (b) What is the new speed of the yo-yo

Answers

Answer 1

Answer:

2.54 m/s

Explanation:

By conservation of energy,

work done by force due to hand = mechanical energy gained by yo-yo

So Fd = mgh + 1/2m(v₂² - v₁²)

where F = force on string = 0.19 N, d = distance moved by hand = 0.12 m, m = mass of yo-yo = 0.058 kg, g = acceleration due to gravity = 9.8 m/s², h = distance moved by yo-yo = 0.30 m, v₁ = initial speed of yo-yo = 3.4 m/s and v₂ = final speed of yo-yo = unknown

So,  Fd = mgh + 1/2m(v₂² - v₁²)

Fd/m = gh + 1/2(v₂² - v₁²)

Fd/m - gh = 1/2(v₂² - v₁²)

2(Fd/m - gh) = (v₂² - v₁²)

(v₂² - v₁²) = 2(Fd/m - gh)

v₂²  = v₁² + 2(Fd/m - gh)

taking square-root of both sides, we have

v₂  = √[v₁² + 2(Fd/m - gh)]

Substituting the values of the variables into the equation, we have

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.0228 Nm/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.393 Nm/kg - 2.94 m²/s²)]

v₂  = √[(3.4 m/s)² + 2(-2.547 m²/s²)]

v₂  = √[11.56 m²/s² - 5.094 m²/s²)]

v₂  = √[6.466 m²/s²]

v₂ = 2.54 m/s


Related Questions

What is the name of the force that opposes, or the opposite of gravity ???!!

Answers

Answer:

Tension.

tension is the name of force that opposes or goes opposite of gravity

Hope this helps!

Answer: Friction

Explanation: Friction opposes gravity and any motion in two surfaces.

Hope This Helped, Have A Great Day!

Someone help me & extra pointsss!

Answers

Answer:

117.43 m

Explanation:

Eg=mgh=13x9.81xh=127.53h(N)

Ek=0.5mv^2=0.5(13)(48)^2=14,976 N

by conservation of potenial energy:

Ei=Ef

127.53h=14976

h=117.43m

A5.0 kg TNT explosive, initially at rest, explodes into two pieces. One of the pieces weighing 2.0 kg flies off to

the left at 36

What is the final speed of the remaining piece?

Answers

Answer:

v = 24 m/s, rightwards

Explanation:

Given that,

The mass of TBT explosive = 5 kg

It explodes into two pieces.

One of the pieces weighing 2.0 kg flies off to  the left at 36 m/s. Let left be negative and right be positive.

The law of conservation of momentum holds here. Let v be the final speed of the remaining piece. So,

[tex]5\times 0=2\times (-36)+3\times v\\\\-72=-3v\\\\v=24\ m/s[/tex]

So, the final speed of the remaining piece is 24 m/s and it is in the right direction.

Which of the following statements about Australian football is TRUE?
A.
The players tend to wear a large amount of padding.
B.
Goals are scored by kicking the ball through goalposts.
C.
Each team has a number of set plays for both offense and defense.
D.
The constant movement of the ball is similar to baseball.

Answers

Answer:

B.

Goals are scored by kicking the ball through goalposts.

Explanation:

8.
2
AI
6
HCI
AICI:
+
H



Answers

Answer:

I'm sorry I can't help you...

can someone help me with this please what are the two correct answers??​

Answers

Answer:

The answers should be B and D

Explanation:

I hope this helps!

The answers are B and D

i need help with this question really urgent

Answers

Answer:

Cost Per Hour:

132.0000

Cost Per Day:

39600.0000

Cost Per Month:

1204632.00

Cost Per Year:

14455584.00

kWh Per Day:

3600.00

An alien from the newly discovers planet nine weighs himself on his planet and finds his weight to be 3200 N. When he stoves on earth he once again weighs himself and find his aight to be 800 N. What is the acceleration due to gravity on planet 9?

Answers

Answer:

2.45 m/s²

Explanation:

From the question,

On the Earth

W = mg.................. Equation 1

Where W = weight of the alien on the earth, m = mass of the alien on the earth, g = acceleration due to gravity of the earth.

Make m the subject of equation 1

m = W/g................... Equation 2

Given: W = 3200 N

Constant: 9.8 m/s²

Substitute these value into equation 2

m = 3200/9.8

m = 326.5 kg.

Similarly,

On planet 9,

W' = mg'............... Equation 3

Where W' = weight of the alien on planet 9, g' = acceleration due to gravity on planet 9.

make g' the subject of the equation

g' = W'/m............ Equation 4

Given: W' = 800 N

Substitute into equation 4

g' = 800/326.5

g' = 2.45 m/s²

Which part of and organism is preserved in cast and mold fossils

Answers

Answer:

bones

Explanation:

Bones are is preserved in cast and mold fossils.

Normally the other 'parts of the body' like muscles, ligaments, blood and organs are soft.

Answer:

bones

Explanation:

I WILL GIVE U BRAINLIST layers: Earth:: ___: the Sun
A: Milky Way galaxy
B: Zero gravity
C: Solid surface
D:Gas

Answers

Answer:

There are layers on the Earth.  There is gas on the Sun.

This means that the answer is...

D: Gas

Which statement compares the attractive forces that hold particles together?

A. Covalent bonding and Van der Waals forces join separate
molecules together, while ionic and hydrogen bonding produce
compounds.
B. Covalent and hydrogen bonding produce compounds, while ionic
bonding and Van der Waals forces join separate molecules
together.
C. lonic and covalent bonding produce compounds, while hydrogen
bonding and Van der Waals forces join separate molecules
together.
D. Ionic and covalent bonding join separate molecules together, while
hydrogen bonding and Van der Waals forces produce compounds.

Answers

Answer:

Ionic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.

Ur welcome:)

Answer:

C) lonic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.

Explanation:

A submarine dives at an angle of 30.0o with the horizontal and follows a straight-line path for a total distance of 50.0 m. What distance is the submarine below the surface of the water?

Answers

Answer:

25 m

Explanation:

The submarine dives at angle of 30 degree with the horizontal . It has travelled 50 m at this angle . So , it will have both 25 horizontal as well as vertical displacement below the surface .

vertical displacement below the surface = vertical component of displacement of 50 m

= 50 sin30

= 25 m .

Depth of submarine below the surface = 25 m.

I need help with this question it's science

Answers

What is the question?
I CANT SEE THE QUESTION

what does point c represent

Answers

Explanation:

point c is minimum Amplitude in transversal wave

A plane travels 4.0 km at an angle of 25◦ to the ground, then changes direction and travels 10 km at an angle of 16◦ to the ground. What is the magnitude of the plane's total displacement? Answer in units of km.

Answers

Answer:

6.1 km

Explanation:

Given that a plane travels 4.0 km at an angle of 25◦ to the ground, then changes direction and travels 10 km at an angle of 16◦ to the ground. What is the magnitude of the plane's total displacement? Answer in units of km

The magnitude of the total displacement D can be calculated by using cosine formula

Ø = 25 - 16 = 9 degree

D^2 = 4^2 + 10^2 - 2 × 4 × 10 × cos 9

D^2 = 16 + 100 - 80cos9

D^2 = 116 - 79.02

D = sqrt( 36.98)

D = 6.1 m

Therefore, the magnitude of the plane's total displacement is 6.1 km

Someone help me extra points & brainlest

Answers

Answer:

75 m

Explanation:

the unit of force is the
backhaus
Einstein
newton
kilogram ​

Answers

Answer:

the answer is a C a newton

If a car accelerates from rest at a constant 4 m/s
, how long will it take for the car to reach a
velocity of 28 m/s?​

Answers

Answer:

Time, t = 7 seconds.

Explanation:

Given the following data;

Initial velocity = 0m/s (since it is starting from rest).

Acceleration, a = 4 m/s²

Final velocity, v = 28 m/s

To find the time, we would use the first equation of motion given by the formula;

V = u + at

Substituting into the formula, we have;

28 = 0 + 4*t

28 = 4t

Time, t = 28/4

Time, t = 7 seconds.

which diagram represents the greatest magnitude of displacement for an object

Answers

Answer: if every arrow=1m do 1 times 1 times 1 times 1

Explanation:

(p.s. it equals 1 meter in area 4 meters in perimeter)

(True/False) The normal force is always opposite in direction to weight.

Answers

Answer:

True

Explanation:

CAN SOMEONE HELP ME WITH THIS

Answers

Answer:

D

Explanation:

Answer is D, you are welcome


Explain how air exerts a pressure​

Answers

air exert a pressure take a glass and put the water on it and small piece a paper and glass take downword and observe it so tha air exert pressure

A student is sitting in a chair and not moving, however, there are forces acting on her. What must be trust about the forces acting on the student?

Answers

Answer: It is trusted that the sum of all forces acting on the student, adds up to zero the student is not moving.

Explanation: the plane they give you that the plane is moving at a constant velocity of 250 m/s this means that the acceleration is zero, we substituted in the formula F=ma which will give us the Force. And knowing that its constant speed, forward force is then equal to the Air resistance. Hence we find the Air resistance force

Calcular la densidad absoluta de un fluido cuya masa es de 12.8 kg y que ocupa un volumen de 16.3 cm

Answers

Answer:

[tex]d=785.27\ g/cm^3[/tex]

Explanation:

The question says that, "Calculate the absolute density of a fluid whose mass is 12.8 kg and which occupies a volume of 16.3 cm³".

Mass, m = 12.8 kg = 12800 g

Volume, V = 16.3 cm³

The density of an object is defined as the mass per unit volume i.e.

[tex]d=\dfrac{m}{V}\\\\d=\dfrac{12800}{16.3}\\\\d=785.27\ g/cm^3[/tex]

So, the absolute density of the fluid is equal to [tex]785.27\ g/cm^3[/tex].

Marcus tries to move a refrigerator but can't. Has he done work?

A) Yes, because he used energy.
B) Yes, because he exerted a force.
C) No, because he did not move the object.
D) No, because he did not use energy.

Answers

Answer:

A

Explanation:

Even if the refrigerator did not move he still used energy to try to push it it's just his energy wasnt stronger than the refrigerator's energy

number of atoms of each element potassium chlorate?​

Answers

5 atoms is the answer

Please help me and get 15 points and Brainlessly!!!!!!!
Bauxite is the chief ore from which aluminum is extracted. Which of these statements is correct about bauxite? (15 points)
Group of answer choices

It has a definite crystal structure.

It does not have a definite chemical composition.

Its atoms do not arrange themselves in a definite order.

Its molecules are made up of a different number of atoms.

Answers

Answer:

A

Explanation:

Bauxite is the primary mineral from which aluminum is produced. The ore must first be cleaned before the metal can be electrolytically reduced out of it. Thus, option A is correct.

What Bauxite is the chief ore from which aluminum?

Bauxite normally has a Mohs hardness of 1 to 3 and is a soft substance. Its color ranges from white to gray to reddish-brown and has a pisolitic structure. It also has an earthy gloss and a specific gravity of 2.0 to 2.5. These characteristics help distinguish bauxite, although they have no bearing on its worth or potential uses.

Typically, aluminum is manufactured in regions with relatively low electricity costs. An abrasive substance is bauxite.

Therefore,  Bauxite is crushed to a fine powder and then fused at a very high temperature to form spherical beads, creating sintered bauxite, which is frequently used as a sand-blasting abrasive.

Learn more about Bauxite here:

https://brainly.com/question/4372634

#SPJ2

What might you be doing if you measure your heart rate and find that it beats 100 times in a minute?

Answers

Answer:

Rigorous exercise

Explanation:

For your heart rate is been around 100 bpm you should be doing a rigorous exercise . but if ain't doing any rigorous exercise and your heart rate is constantly above 100 bpm you should consult your doctor.

An average heart is between 60 bpm to 100 bpm.

What are some ways scientists can study the seafloor?

Answers

Answer: A device records the time it takes sound waves to travel from the surface to the ocean floor and back again. Sound waves travel through water at a known speed. Once scientists know the travel time of the wave, they can calculate the distance to the ocean floor.

Explanation:

A 90° elbow in a horizontal pipe is used to direct water flow upward at a rate of 40 kg/s. The diameter of the entire elbow is 10 cm. The elbow discharges water into the atmosphere, and thus the pressure at the exit is the local atmospheric pressure. The elevation difference between the centers of the exit and the inlet of the elbow is 50 cm. The weight of the elbow and the water in it is considered to be negligible. Determine (a) the gage pressure at the center of the inlet of the elbow and (b) the anchoring force needed to hold the elbow in place. Take the momentum-flux correction factor to be 1.03 at both the inlet and the outlet.

Answers

Answer:

(a) The gauge pressure is 4,885.3 Pa

(b) The anchoring force needed to hold the elbow in place is approximately 296.5 N

The direction of the anchoring force is approximately ≈ 134.8

Explanation:

The given parameters in the fluid dynamics question are;

Pipe elbow angle, θ = 90°

The mass flowrate of the water, [tex]\dot m[/tex] = 40 kg/s

The diameter of the elbow, D = 10 cm

The pressure at the point of discharge of the fluid = Atmospheric pressure

The elevation between the inlet and exit of the elbow, z = 50 cm

The weight of the elbow and the water = Negligible

(a) The velocity of the fluid, v₁ = v₂ = v is given as follows;

ρ·v·A = [tex]\dot m[/tex]

v = [tex]\dot m[/tex]/(ρ·A)

Where;

ρ = The density of the fluid (water) = 997 kg/m³

A = The cross-sectional area of the of the elbow = π·D²/4 = π×0.1²/4 ≈ 0.00785398163

A = 0.00785398163 m²

v = 40 kg/s/(0.00785398163 m² × 997 kg/m³) ≈ 5.1083 m/s

Bernoulli's equation for the flow of fluid is presented as follows;

[tex]\dfrac{P_1}{\rho \cdot g} +\dfrac{v_1}{2 \cdot g} + z_1 = \dfrac{P_2}{\rho \cdot g} +\dfrac{v_2}{2 \cdot g} + z_2[/tex]

v₁ = v₂ for the elbow of uniform cross section

P₁ - P₂ = ρ·g·(z₂ - z₁)

P₁ - P₂ = The gauge pressure = [tex]P_{gauge}[/tex]

z₂ - z₁ = z = 50 cm = 0.5 m

∴ [tex]P_{gauge}[/tex] = 997 kg/m³ × 9.8 m/s² × 0.5 m = 4,885.3 Pa

The gauge pressure, [tex]P_{gauge}[/tex] = 4,885.3 Pa

(b) The forces acting on the elbow are;

[tex]F_{Rx}[/tex] + [tex]P_{gauge}[/tex]·A = -β·[tex]\dot m[/tex]·v

[tex]F_{Ry}[/tex]  = β·[tex]\dot m[/tex]·v

∴ [tex]F_{Rx}[/tex]  = -β·[tex]\dot m[/tex]·v -  [tex]P_{gauge}[/tex]·A

[tex]F_{Rx}[/tex]  = -1.03 × 40 kg/s × 5.1083 m/s -  4,885.3 Pa × 0.00785398163 m² ≈ -208.83 N

[tex]F_{Ry}[/tex]  = 1.03 × 40 kg/s × 5.1083 m/s = 210.46196 N

The resultant force, [tex]F_R[/tex], is given as follows;

[tex]F_R[/tex] = √([tex]F_{Rx}[/tex]² + [tex]F_{Rz}[/tex]²)

∴ [tex]F_R[/tex] = √((-208.83)² + (210.46196)²) ≈ 296.486433934

Therefore;

The anchoring force needed to hold the elbow in place, [tex]F_R[/tex] ≈ 296.5 N

The direction of the anchoring force, θ

[tex]\theta = tan^{-1}\left( \dfrac{F_{Ry}}{F_{Rx}} \right)[/tex]

∴ θ = arctan(210.46196/(-208.83)) = -45..2230044°

θ = 180° + -45.2230044° = 134.7769956°

∴ The direction of the anchoring force is approximately, θ ≈ 134.8°

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