You have $9.30 plus 6 percent of tax what is the total costs

Answer:

f(x-7) =  x -12

Step-by-step explanation:

horizontal translation 7 units right: f(x-7)

f(x) = x - 5

f(x-7) = x-7 -5 = x -12

Answer:

infinity

Step-by-step explanation:

lol

Answer:

Factoring the trinomial: [tex]x^2+13x+12[/tex] we get the factors [tex]\mathbf{(x+1)(x+12)}[/tex]

Step-by-step explanation:

We need to factor the trinomial: [tex]x^2+13x+12[/tex]

We can factor the trinomial by breaking the middle term i.e 13x

Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2

We can break 13x as: 12x and x

Adding them we get 13x and multiplying them we get 12x^2

So,

[tex]x^2+13x+12\\=x^2+12x+x+12\\=x(x+12)+1(x+12)\\=(x+1)(x+12)[/tex]

So, Factoring the trinomial: [tex]x^2+13x+12[/tex] we get the factors [tex]\mathbf{(x+1)(x+12)}[/tex]

[tex]{\underline{\underline{\bf{Given:}}}}[/tex]

[tex]{\underline{\underline{\bf{Need\:to\:find:}}}}[/tex]

[tex]{\underline{\underline{\bf{Formula\:to\:be\:used:}}}}[/tex]

Pythagorean Theorem:

[tex]\underline{\boxed{\sf{{Base}^{2}+{Perpendicular}^{2}={Hypotenuse}^{2}}}}[/tex]

[tex]{\underline{\underline{\bf{Solution:}}}}[/tex]

According to the given data, we know the measures of Perpendicular and Hypotenuse. Hence, the measure of the base (Side FE) can be found by substituting the given measures in Pythagorean Theorem.

[tex]\implies{\sf{{Base}^{2}+{Perpendicular}^{2}={Hypotenuse}^{2}}}[/tex]

[tex]\implies{\sf{{EF}^{2}+{DF}^{2}={DE}^{2}}}[/tex]

[tex]\implies{\sf{{EF}^{2}+{(13.6)}^{2}={(16.2)}^{2}}}[/tex]

[tex]\implies{\sf{ EF = \sqrt{ {(16.2)}^{2} - {(13.6)}^{2} } }}[/tex]

[tex]\implies{\sf{ EF = \sqrt{ 262.44 - 184.96 } }}[/tex]

[tex]\implies{\sf{ EF = \sqrt{77.48 } }}[/tex]

[tex]\implies{\sf{EF=\red{\underline{\underline{8.802\:m}}}}}[/tex]

[tex]{\underline{\underline{\bf{Required\:answer:}}}}[/tex]

Answer:

D

Step-by-step explanation:

Connect the point already at (0, –2) to a new point at (2, 0), connect

(2, 0) to (2, 4), and then connect (2, 4) to (–2, 4).

Im pretty sure

Answer:

D

Step-by-step explanation:

Answer:

taking cos

co62=b/h

cos 62=x/12

0.46947x12=x

so, x = 5.633

rounding off

x= 6

Answer:

x = 6.0

Step-by-step explanation:

Formula For Cos: cos (angle°) = adjacent/hypotenuse

Angle = 62

Adjacent = x

Hypotenuse = 12

cos (angle) = adjacent/hypotenuse

cos (62) = x/12

0.67350716232 = x/12

0.67 = x/12 (Rounded to make further calculations simpler)

12(x/12) = 12(0.67)

x = 8.04

x = 6.0 (Rounded to nearest tenth)

Therefore, x = 6.0

Hope this helped! <3

Answer:

8000

Step-by-step explanation:

Answer:

10x + 18

Step-by-step explanation:

First, we need to add like terms. Like terms are terms that are alike. For instance 8x and 2x are like terms. 15 and 3 are also like terms.

So, we have to add 8x plus 2x and 15 plus 3. That’s comes out to 10x plus 18.

Therefore, this expression is equivalent to 10x + 18.

Answer:

x²/4 + y²/16 = 1

Step-by-step explanation:

Foci on the y axis: major axis parallel to y axis

x²/b² + y²/a² = 1

x²/4 + y²/16 = 1

The required equation of an ellipse is given by x²/4 + y²/16 = 1

Given that,
Length of the major axis: 4 Length of the minor axis: 2 Foci are on the y-axis with center (0,0)​, the equation of the ellipse is to be determined.0

Ellipse is defined as the cross-section of the cone when cutting it with a plane parallel to its base.

Here,
Standard equation of the ellipse with origin as the center,
x²/a² + y²/b² = 1
where a and b are the minor and major axis of the ellipse.
From the given, we have a = 2 and b = 4
So the equation of the ellipse,
x²/4 + y²/16 = 1

Thus, the required equation of an ellipse is given by x²/4 + y²/16 = 1.

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Answer:

4000

Step-by-step explanation:

20 to the power of 3 is 8000 and 8000/2 is 4000

Given :

To Find :

Answer :

Adding eqⁿ (ii) and eqⁿ (i) we get :

→ x + y + x - y = 4 + 1

→ 2x = 5

→ x = 5/2

→ x = 2.5

Now, put the value of x = 5/2 in eqⁿ (i) we get :

→ x + y = 4

→ 5/2 + y = 4

→ y = 4 - 5/2

→ y = 1.5

Answer: the volume is 480 cm

Step-by-step explanation:

You find the volume of a shape by multiplying the base x width x height. In this case the height is 6 the width is 8 and the length is 10. 6x8x10= 480.

Answer:

lb×bh×hl

6×8×8×10×10×6

48×80×60

230400

Answer:

4:1

Step-by-step explanation:

hope this helps

Answer:

The ratio is 1 hour to 1.5 laptops

Step-by-step explanation:

If you divide the time by amount done, there you have the answer.

Answer:

Maximum amount of toppings is 14 inequality is t <=14

Step-by-step explanation:

let t be the amount of toppings on the pizza

0.75t + 2 <= 12.50

0.75t <= 10.50

t <= 14

Answer:

Step-by-step explanation:

Hi,

1) Find z if the standard normal curve area between -z and z is 0.4530.

Y1 = normalcdf(-x,x,0,1) - .4530 and x = .60226

a. ± 0.118

b. ± 0.398

c. ± 0.602 <==ANSWER

d. ± 0.752

2) If a random variable has the normal distribution with μ = 104.3 and σ = 5.7, find the probability that the value will be greater than 112.3

normalcdf(112.3, 500, 104.3, 5.7) = .08023

a. 0.08 <==ANSWER

b. 0.09

c. 0.10

d. 0.11

3) Determine a 90% confidence interval for μ if σ = 5, \bar{x} = 70, and n = 82. Answer interval rounded to two decimal places.

70 ± 1.645 (5/√82) or 69.09 to 70.91 <==ANSWER

I hope that helps!! :-)

Answer:

21

Step-by-step explanation:

set up proportion and solve

18/12=x/14 (cross multiply)

252=12x

21=x

;

Answer:

there is a graph first step to but I cannot draw it on here but you already have your answer without Step 2

Step-by-step explanation:

a simple path in a graph G that passes through every vertex exactly once is called a path . the graph G has no past because any past containing all vertices must contain one of the edges (e, c) (d, f ) and (B, G) move than once .

Answer: B. 77

Sub x =6 into the given expression

4x^2 - 12x + 5

= 4(6)^2 - 12(6) + 5

= 144 - 72 + 5

= 77

[tex]\\ \sf\longmapsto 4x^2-12x+5[/tex]

[tex]\\ \sf\longmapsto 4(6)^2-12(6)+5[/tex]

[tex]\\ \sf\longmapsto 4(36)-72+5[/tex]

[tex]\\ \sf\longmapsto 144-67[/tex]

[tex]\\ \sf\longmapsto 77[/tex]

Answer: then its blue, 1/3

Step-by-step explanation: in a box there are 8 red, 7 blue and 6 green balls. one ball is picked up randomly. what is the probability that it is neither red nor green?

---

I guess the ball was blue.

P(blue) = 7/21 = 1/3

Answer:

0.4

Step-by-step explanation:

Answer:

15 fifths

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

3/2 is equal to 1.5 and 3 1.5s can fit in 5 equaling 4.5

Answer:

160 pounds

Step-by-step explanation:

If she has 3 boxes and there's 40 more pounds than if she had one, that means each box is 20 pounds so multiply 20 by 8 and you get 160 pounds

The scale factor of PQRS to JKLM is 4/5 and the values of w, x and y are 20, 12.5 and 20 respectively.

A scale drawing is a drawing made by enlarging or reducing the size of the original object.

The factor by which the drawing is enlarged or reduced is called the scale factor.

Given two quadrilaterals PQRS and JKLM.

Since the shape is similar, the angles are equal and thus are similar figures.

The corresponding sides of two similar figures are proportional.

Scale factor of PQRS to JKLM = QR / KL = 12 / 15 = 4/5

Using the proportional rule for similar figures,

KL / QR = LM /RS  = MJ / SP = JK / PQ

15 / 12 = x / 10 = y / 16 = 25 / w

Scale factor = 15/12 = 5/4

Consider 15 / 12 = x / 10.

12x = 150

x = 12.5

Consider 15 / 12 = y / 16

12y = 15 × 16

y = 20

Consider 15 / 12 = 25 / w

15w = 12 × 25

w = 20

Hence the option d is the correct answer.

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Answer:

hope my answer is helpful to you

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As QR is parallel to ST Rs is parallel TU QS is congruent to SU the measure of their included angle is also same ∠QRS ≅ ∠STU.

We know two similar planer figures are congruent when we have sides or angles or both that are the same as the corresponding sides or angles or both.

Given, Line segment QR is parallel to line segment ST.

Line segment RS is parallel to line segment TU, And line segment QS is similar to line segment SU.

So, The included angle of two pairs of parallel lines will also be the same as

line segment QS is similar to line segment SU.

∴ ∠QRS is similar to ∠STU.

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