You can model an arch at your school using the equation $y=-0.5\left(x+4\right)\left(x-4\right)$ , where $x$ and $y$ are measured in feet. The x-axis represents the ground. Find the width of the arch at ground level.

Answers

Answer 1

Answer:

8feet

Step-by-step explanation:

Given the equation that models the arch of a school expressed as;

[tex]$y=-0.5\left(x+4\right)\left(x-4\right)$[/tex]

If the x axis represents the ground;

At the ground level, x = 0

Substitute x = 0 into the equation to get y;

y = -0.5(0+4)(0-4)

y = -0.5(4)(-4)

y = -0.5 * -16

y = 8ft

Hence the y axis at the ground level is 8feet


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(5, 1050), (9, 900), (12, y)
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

I think 4?????

Step-by-step explanation:

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Answer:

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Answer:

62 grados x

Step-by-step explanation:

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because the first side equal for the second side this means that this triangle is isosceles

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Answer:

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Step-by-step explanation:

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Answer:

So, basically AB goes through (bisects) CAD, which CAD is the kite-like shape you see. So line AB goes through line CAD. Now what they what you to do is prove if lines AB and lines AC are equal.

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Step-by-step explanation:

4x²-64

(2x)²-(8)²

a²-b²=(a+b)(a-b)

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yes the factors are indeed 4 and -4 boom your welcome

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Answer:

1/3

Step-by-step explanation:

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so first we should make the denominators the same so find a multiple that 5 and 8 share: they share a multiple of 40, so whatever you do to the denominator you do to the numerator. So the equation should now look like 16/40+15/40 and the answer is 31/40!!

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Answer:

167.55

Step-by-step explanation:

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B. 120

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Answer:

120

Step-by-step explanation:

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Answers

Answer:

w=-50

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Step-by-step explanation:

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Amir jumped exactly 2,000 mm further than Alex.

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Answers

Answer:

Step-by-step explanation:

The distances they jumped were

x,y,z

y=x+2

z=x+2+2=x+4

x+y+z=12.69

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Step-by-step explanation:

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42

Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

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m∠2=9

Step-by-step explanation:

Hello There!

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6

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