You ask learners to select their course section number for your survey. For example, (1) 101, (2) 102, (3) 103. What type of variable is course section in this example?

Answer:

Four hundred thirty six million, seven hundred eighty-three thousand, two hundred ten

Step-by-step explanation:

four hundred and thirty six

seven hundred and eighty three

two hundred and ten

Step-by-step explanation:

Given:

Food = 30 pounds of food per hiker.

Food consumption = 12 pounds of food a day.

No. of hikers = 7

To find:

The equation for the given situation.

Solution:

Let x be the number of days and y be the amount of remaining food.

Total amount is the product of number of hikers and food per hiker.

[tex]\text{Total food}=7\times 30[/tex]

[tex]\text{Total food}=210[/tex]

Food consumption of one day = 12 pounds

Food consumption of x days = 12x pounds

Now,

Remaining food = Total food - Food consumption of x days

[tex]y=210-12x[/tex]

[tex]y=-12x+210[/tex]

Therefore, the required equation is [tex]y=-12x+210[/tex].

Note: Option C is correct if there is -12 instead of 12.

Answer:

5^6

Step-by-step explanation:

by the law of exponents,

5^2 * 5^(-8)

5^ [2+ (-8)]

5^(2-8) = 5^-6 = 1/5^6 = 5^6

Answer:

The dryer costs 425 dollars

Step-by-step explanation:

x - washer

y - dryer

x+y=774

x=y-76

(y-76)+y=774

2y=774+76, 2y=850

y=425

y-76=x

425-76=x

x=349

9514 1404 393

Answer:

  m∠WXY = 111°

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary.

  m∠WXY = 180° -m∠WZY

  m∠WXY = 180° -69°

  m∠WXY = 111°

Answer:

1. X- Intercepts(s) : (4,0)

X- Intercepts(s) : (4,0)

X- Intercepts(s) : (4,0) Y- Intercepts(s) : (0, -4)

X- Intercepts(s) : (4,0) Y- Intercepts(s) : (0, -4)2. . X- Intercepts(s) : (15/2, 0 in fraction form.)

X- Intercepts(s) : (4,0) Y- Intercepts(s) : (0, -4)2. . X- Intercepts(s) : (15/2, 0 in fraction form.) Y- Intercepts(s) :( 0, -5)

Step-by-step explanation:

To Find the X- Intercept Subsitute in 0 For Y solve for x. To find the y-intercept Substitute in 0 for x and solve for y.

Answer:

10

Step-by-step explanation:

Please use " * " or " · " to indicate multiplication; " x " is a variable, not an operator.

(5 + 3) x 2 - 6 => (5 + 3)·2 - 6

Order of operations rules require that we do first any work inside parentheses.  So we have:

(5 + 3)·2 - 6 => (8)·2 - 6

Those same rules dictate that we must multiply before subtracting.  So now we obtain:

16 - 6 = 10

Answer:

Constant of variation: $8.25

Equation: y=8.25x

Step-by-step explanation:

231/28=8.25

Answer:8.25

Step-by-step explanation:

231/28

Answer:

y = 26.2857143 or 184/7 or 26 2/7

x = -13.7142857 or -96/7 or -13 5/7

Step-by-step explanation:

-5x + 5y = 40

-x + y = 40

x = -40 + y

substitute x for -40 + y

4(-40 + y ) + 3y = 24

-160 + 4y + 3y = 24

7y = 184

y  = 26.2857143 (?)

x = -40 + 26.2857143

x = -13.7142857

Answer:

1.No

2.No

Step-by-step explanation:

5=x+5  x=10

5=10+5

5=15 is not solution

12x=196  x=7

12*7=196

84=196

Answer:

13

Step-by-step explanation:

3(2)(2) -4(2)+9

12 -8 +9= 13

Answer:

So Sorry Omg Wait I'll will come back

Answer:

The length of rectangular prism(l)=13inch

The breadth of rectangular prism(b)=9inch

the height of rectangular prism(h) =3inch

Volume of a rectangular cuboid =l×b×h

=13×9×3inch (write cube too)

=351 inch (write cube too)

Answer: The number of drinks she bought would be 6 and the number of pretzels she bought would be 10.

[tex]282.8cm pa brainlest po[/tex]

Answer: Each Swiss Guard will spend 1 hour 36 minutes on guard duty in one day.

Step-by-step explanation:

Given: The Vatican has to be guarded 24 hours a day.

Total Swiss Guards  = 15

If they split each day's guard duty equally, the time they will spend on guard duty in one day = (24)÷ 15

= [tex]\dfrac{24}{15}[/tex] hours

[tex]=\dfrac85[/tex] hours

[tex]=1\dfrac35[/tex] hours

= [tex]\text{1 hour }\dfrac35\times60\text{ minutes}[/tex]

= [tex]\text{ 1 hour }36\text{ minutes}[/tex]

Hence, each Swiss Guard will spend 1 hour 36 minutes on guard duty in one day.

Question:

Miriam is making a bulletin board that is shaped like a square. She has 72 inches of border material. If x represents the length of one side of the bulletin board, which inequality model and solution set best represents the possible side lengths of Miriam's bulletin board?​

Answer:

[tex]x \le 18[/tex]

Step-by-step explanation:

Given

[tex]Border\ Material = 72[/tex]

Required

Determine an inequality for x

Represent the side lengths of the border with y. So:

Since the border is on the 4 sides, then

[tex]4y = 72[/tex] -- i.e. the perimeter of the border material

Solve for y

[tex]y =\frac{72}{4}[/tex]

[tex]y =18[/tex]

Recall that x represents the board's side length.

Since x will be situated inside the boarder, then.

[tex]x \le y[/tex]

Substitute [tex]y =18[/tex]

[tex]x \le 18[/tex]

Answer:

the perimeter is 28

Step-by-step explanation:

2+2=4

12+12=24

24+4=28

Answer:

Perimeter = 28 feet

Step-by-step explanation:

The formula to find the area of a rectangle is Length * width and we already have one dimension here, so we simply plug it in and make an equation to the find the unknown measurement

12 * d = 24

d = 24/12

 d = 2

So the missing dimension is 2 feet

Now we simply find the perimeter of the rectangle  using the formula

   2 ( length + width)

 = 2 (12 + 2 )

           = 2 ( 14 )

           = 28 feet

Step-by-step explanation:

8²+x²=17²

74+ײ=289

x²=225

Sq root both sides

x=15

15×8=120 Sq ft

Given:

PQRS is a rectangle.

X is the midpoint of SR.

To find:

The measure of QX.

Solution:

It is given that X is the midpoint of SR. Draw a perpendicular on PQ from point X as shown in the below figure.

Now, the line XY divides the rectangle PQRS into two equal squares of sides 4 units.

The diagonal of a square is:

[tex]d=a\sqrt{2}[/tex]

Where, a is the side length of the square.

QX is the diagonal of the square whose side length is 4 units. So, the length of QX is:

[tex]d=4\sqrt{2}[/tex]

[tex]d=5.656854[/tex]

[tex]d\approx 5.7[/tex]

Therefore, the measure of segment QX is about 5.7 units.

Answer:

the height is 9.8 cm

Step-by-step explanation:

71.54 ÷ 7.3 = 9.8

Answer:

10/70

Step-by-step explanation:

Answer:

46°

Step-by-step explanation:

Given that :

Angle, A = 66°

Angle B = 68°

The sum of angles in a triangle is given by :

A + B + C = 180° (sum if angles una triangle)

66° + 68° + C = 180°

134° + C = 180°

C = 180° - 134°

C = 46°

Hence, angle C is 46°

Answer: 7.40 meters

Step-by-step explanation:

I went with 163 cm for the height because it says her eyeline is at 163 cm. I don't assume she would be looking from the top of her head so I went with that over 173 cm(h for hawk)

All you do is:

tan(30)=opposite/adjacent

tan(30)=h/10

10*tan(30)=h

h≈5.77 meters

163cm converted to meters is 1.63 meters, so add it to 5.77 and you will get 7.40 meters

This might help as well: https://www.ck12.org/book/ck-12-trigonometry-concepts/section/1.13/

0.3 so yea i guess....

Answer:

Step-by-step explanation: 380

The angels that are congruent to 8 are 6, 3, 1.

Answer:

third one

Step-by-step explanation:

pls try it yourself lololol

Answer:

279...................................

Answer:

[tex] \rm\displaystyle \: A _{ \text{ total}} = 212 [/tex]

Step-by-step explanation:

Prefer the attachment

so we have 3 rectangle

recall that,

[tex] \displaystyle \: A _{ \text{ rect}} = l \times w[/tex]

the width of the rectangle is 10m

and the length is 12+5=17m

so the area is

[tex] \displaystyle \: A _{ \text{ rect - 1}} = 17 \times 10[/tex]

[tex] \displaystyle \: A _{ \text{ rect - 1}} =170 \: {m}^{2} [/tex]

the length is 9 m

the width is 3 m

so the area is

[tex] \displaystyle \: A _{ \text{ rect - 2}} = 9 \times3[/tex]

[tex] \displaystyle \: A _{ \text{ rect - 2}} = 27 \: {m}^{2} [/tex]

the length is 5m

the width is 3m

so the area is

[tex] \displaystyle \: A _{ \text{ rect - 3}} = 5 \times 3[/tex]

[tex] \displaystyle \: A _{ \text{ rect - 3}} = 15 {m}^{2} [/tex]

[tex] \rm\displaystyle \: A _{ \text{ total}} =170 \: {m}^{2} + {27m}^{2} + {15m}^{2} [/tex]

[tex] \rm\displaystyle \: A _{ \text{ total}} = 212 {m}^{2} [/tex]