Answer: Relative to the bus, you are stationary. Relative to a point on the ground, you are walking forward with velocity equal to the velocity of the bus.
As a person walks toward the back of a bus, they are walking towards a stationary object according to their own perspective. However, from an outside perspective, the bus is moving forward with a constant velocity and so relative to that point in motion, you are actually walking backwards with respect to it. This difference in motion means you would not be able have the same experience as the person on the bus when getting off because when you get off you would stop while they continue going forward. The last sentence could be considered a footnote because it only applies if this was an actual situation rather than just an analogy question in a physics test.
Relative to the bus, you move at walking speed. The motion relative to the ground is in the direction same as the bus and equal to the difference between the speed of the bus and walking speed.
What is relative motion?When an object has a certain velocity, then this velocity is w.r.t. some frame that is called the reference frame. When we measure the velocity of an object, the ground or the earth is taken as the reference frame.
The motion of an object observed by the observer depends on the frame of the observer and this type of motion is known as relative motion.
For example, if you are traveling in a train and the train is moving at a speed of 80 km/hr, then your speed according to another passenger sitting on the same train is equal to zero.
Similarly, if you are walking toward the back of a bus, then your motion relative to the bus is walking speed. Relative to the ground, it is the difference between the speed of the bus and walking speed.
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What is an ellipse?
I want an accurate answer. No spam.
Answer:
It is defined as an astronomical phenomenon which occurs when one spatial object comes within the shadow of another spatial object.
A train travelling along a straight track starts from rest at point A and accelerates uniformly to 10 m si in 20 s. It travels at this speed for 60 s, then slows down uniformly to rest in 40 sat point C. It stays at rest at C for 30 s, then reverses direction, accelerating uniformly to 5 ms. in 10 s. It travels at this speed for 30 s, then slows down uniformly to rest in 10 s when it reaches point B.
1. Plot a graph of the motion of the train.
II. Use your graph to calculate:
III. the train's displacement from point A when it reaches point C
IV. the train's displacement from point A when it reaches point 13
V. the train's acceleration each time its speed changes.
Please find attached photographs for your answer.
Hope it helps.
Do comment if you have any query.
Which of the following is a defense technique to protect computers from incoming risks? *
Answer:
having a secure firewall
Explanation:
A firewall validates access by assessing this incoming traffic for any price malicious like hackers and malware that would infect your computer.
solve for the BMI weight 58kg Height 1.61
Answer:
Explanation:
BMI= weight/(height × height) ; weight in kilogram and height in metter
= 58kg / (1.61m × 1.61m )
= (58/ 2.5921) kg/[tex]m^{2}[/tex]
= 22.375 kg/[tex]m^{2}[/tex]
≈ 22.4 kg/[tex]m^{2}[/tex]
1 =
Q=240c
t=300s
Please explain Im so confused
Answer:
Answer:
0.8 A
Explanation:
Given: Q = 240 C
t = 300 s
Required: I
Equation: I = Q / t
Solution: I = 240 C / 300 s
Answer: I = 0.8 A
If professor X can move things with his mind.Then why cant he move his legs?
Answer: Varies
Explanation:
Because moving his legs require force.
Answer:
He is also a low-level telekinetic
Explanation:
He is a telepath and doesn’t have telekinesis btw.
this painting represents the milky way galaxy as it would appear edge-on from a distance. label the indicated features; be sure to pay attention to where the leader lines are pointing.
The galaxy is known to contain stars of different ages. The indicated features as it points from left to right are;
globular clusters bulge haloBottom row
Both are disksThe Milky Way Milky exist because our Sun (a star) and all the planets close to it are part of a galaxy called the Milky Way Galaxy.
A galaxy is known to be a large group of stars, gas, and dust bound together by the force of gravity.
Our galaxy is called by the name the Milky Way because it is usually seen or it appears as a milky band of light in the sky when you view it in a really dark area.
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A ball is falling toward the ground. Which of the following statements are false? (a) The force that the ball exerts on Earth is equal in magnitude to the force that Earth exerts on the ball. (b) The ball undergoes the same acceleration as Earth. (c) The magnitude of the force the Earth exerts on the ball is greater than the mag- nitude of the force the ball exerts on the Earth.
Hi there!
(A) The force that the ball exerts on Earth is equal in magnitude to the force that Earth exerts on the ball.
Gravitational force is an example of an action-reaction pair:
[tex]F_{1,2} = -F_{2,1}[/tex]
Gravitational force is given by the equation:
[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]
Plugging in the masses of the Earth and ball, gravitational constant, and radius will result in the SAME GRAVITATIONAL FORCE exerted by both objects on each other.
what is the magnitude of the torque that the axle must apply to prevent the disk from rotating?
The required torque at the axle, is given by the difference between the
moments of the applied forces.
The torque required is 19.62 N·m counterclockwise
Reasons:
The given parameters are;
Mass of the disk, m = 5.0 kg
Location of the axle = Half the radius of the disk
Diameter of the disk, D = 40 cm = 0.4 m
Applied mass, 0.1 m from the axle = 15 kg
Applied mass, 0.3 m from the axle = 10 kg
Required:
Magnitude of torque at the axle that prevent the disk from rotating
Solution:
Torque needed = Clockwise moment - Counterclockwise moment
Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m
Counterclockwise moment = 15 kg × 0.1 m × 9.81 m/s² = 14.715 N·m
τ + Counterclockwise moment = Clockwise moment
τ + 14.715 N·m = 34.335 N·m
Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m
Torque required, τ = 19.62 N·m counterclockwise
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The probable question drawing obtained from a similar question online is attached
A 45 kg object has a momentum of 255 kg m/s northward.What is the objects velocity
Answer:
5.66 m/s
Explanation:
p=mv
255 = 45v
v = 255/45
v = 5.66 m/s
If you want to verify your answer, just insert your value to the equation.
Explain how work and power are different. Give an example of doing the same amount of work, but producing different amounts of power.
Answer:Work is a measurement of energy.
Power is a measurement of energy per time.
So, power measures how fast work is done.
If we raise 1kg up to a height of 1 meter it takes a certain amount of work. It doesn't matter if it takes us 1 second or 1 hour to raise it. It takes more power, energy per second, to raise it in 1 second than to raise it in one hour.
An engines power rating is in horsepower. A higher horsepower car engine will get a certain car up a hill more quickly than if it had a lower horsepower engine. Even though both engines did the same amount of work in getting the car up the hill
Answer:
work is a measurement of energy, but power is how much energy it takes. Two people could do the same amount of work. Sally and James. James may finish his work in 2 days due to the amount of power he puts in, but it may take Sally a week.
you moved from the top bunk of a bunk bed to the bottom and noticed that the air is colder. the cold air stays at the bottom because of
Answer:
heat transfer? sorry if I'm wrong!
What can cause matter to change from one state to another?
a change in its temperature
a change in its pressure
both a and b
neither a nor b
explique ¿por que un objeto que tiene energía es capaz de realizar un trabajo?
newtons 2nd law of the law of…
Fuses of ________________________
a. same kind are used for different purposes
b. different kind are used for different purposes
c. both of the above are correct
d. none of these
Answer:
C
Explanation:
fuses of same kind can be used for different things, and of different kinds could be used for different things as well.
What is the equation for density?
O D= m
V
O D= V
-
m
O D= m
O D= { mu?
2
write the name of simple machine used to changed the direction of force?
Answer:
The variation of the wheel and axle is the pulley. In a pulley, a cord wraps around a wheel. It is a simple machine that is used to change the direction of the force. When the wheel rotates, the cord can move in either of the directions.
Explanation:
HELPPPPPPPPPPPPPPPPPPP
Answer:
directly proportional
Explanation:
What is the kinetic energy of a 100kg ship moving along the water at a rate of 10m/s?
Answer:
5000 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass in kg
v is the velocity of the object in m/s
From the question
m = 100 kg
v = 10 m/s
We have
[tex]k = \frac{1}{2} \times 100 \times {10}^{2} \\ = 50 \times 100 \\ = 5000 \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
5000 JHope this helps you
Select two of Earth's spheres and explain how they interact with each other.
atmosphere, biosphere, cryosphere, geosphere and hydrosphere
HELPPPPPPPP!!!!!
Answer and Explanation: The geosphere interacts with the cryosphere when glaciers and sheets of ice from the cryosphere erode the rocks located on the geosphere. This happens as ice passes over the land and carries eroded rocks to new locations. The cryosphere can also cause soil to become icy and take hold of greenhouse gases from the atmosphere. The geosphere is the part of the Earth that has rocks, minerals, sand, and lava. The cryosphere has frozen water, ice, and glaciers. The cryosphere also interacts frequently with the hydrosphere because it draws water from the hydrosphere and freezes it during cold temperatures. Warmer temperatures cause the cryosphere to melt and release water back to the hydrosphere.
A student pushes on an object with a force of 6 newtons and the object does not move. what force does the object exert on the student’s hands?
Answer:
6 newtons
Explanation:
If it's an equal force exerted on the student's hands, the object will not move.
If a student pushes on an object with a force of 6 newtons and the object does not move then the force exerted by the object on the student’s hands would be 6 Newtons because the applied force is equal to the static frictional force until the object does not move.
What is friction?Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact
As given in the problem If a student pushes on an object with a force of 6 newtons and the object does not move then we have to find out the force exerted by the object on the student’s hands,
Force applied by the student of the object = 6 Newtons
The force exerted by the object on the student's hand = 6 Newtons
Thus, the force exerted by the object on the student’s hands would be 6 Newtons
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what types of electromagnetic radiation does the sun emit?
Answer:
https://gml.noaa.gov/education/info_activities/pdfs/LA_radiation.pdf
Explanation:
In the very distant future, given our best model of the accelerating universe, what will the universe look like?
The models of the universe allow finding the result for how serious the universe in the distant future is:
In the distant future the galaxies are far apart and the interaction between them would be negligible.
The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.
Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.
Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.
In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:
In the distant future the galaxies are far apart and the interaction between them would be negligible.
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PLS ANSWER FAST CORRECT ANSWER WILL BE BRAINLIEST
Answer:
Current
Explanation:
If the momentum of the NASA space shuttle as it leaves the atmosphere is 3.75 x 10^8 kg ·m/s and its mass is 75000 kg, what is its speed?
Hi there!
We know that:
Momentum (p) = mass (kg) × velocity (m/s)
Or:
P = mv
We can rearrange the equation to solve for speed:
P/m = v
Plug in the given values:
(3.75 × 10⁸)/75000 = 5000 m/s
In an experiment to determine the density of a substance the following results were
obtained. Use the results to plot a graph of mass against volume.
Mass (g) 10 20 30 40 50 60 70 80 90
Volume (cm 3 ) 0.5 1.0 1.4 2.0 2.2 2.6 3.0 3.6 4.5
a) Find the gradient of the graph.
b) What does the gradient represent?
c) What is the mass when the volume is 1.5cm 3 ?
d) What is the volume when the mass is 65g?
Answer:
a) Gradient = rise/run = mass/volume
since the graph is mass against volume we know mass is on the y-axis and volume is on the x-axis
in physics it’s best to use a larger part of the graph to find the gradient, so imma use the biggest values.
90/4.5 = 20
(additional note: sometimes you may get a different gradient. For example, when using 30 and 1.4 you get ≈21 this is an anomalous result since ita gradient differs; a mass against volume graph is supposed to be linear)
b) gradient represents density (p) since gradient is = mass/volume. And density also = mass/volume
For c and d just plot the points and you’ll be able to read from the graph to get the values.
I got this graph (the image)
but you’ll be able to interpret better when ‘you’ draw it (so try plotting it)
A tellurium-sapphire laser can produce light at wavelength of 800 nm in ultrashort pulses that last only 4.00x10-15s (4.00 femtoseconds, or 4.00 fs). The energy in a single pulse produced by one such laser is 2.00 μJ = 2.00x10-6 J, and the pulses propagate in the positive x-direction. Find a) the frequency of the light; b) the energy and minimum energy uncertainty of a single photon in the pulse
The speed of light and the propagation of errors allows to find the results on the questions of the radiation emitted by the laser are:
a) The frequency is: f = 3.7 10¹⁴ Hz
b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J
a) The speed of a wave is related to its wavelength and frequency.
c = λ f
[tex]f = \frac{c}{\lambda}[/tex]
Where c is the speed of light, λ the wavelength and f the frequency.
They indicate that the wavelength is λ = 800 nm = 800 10⁻⁹ m, the speed of light is a constant c = 2.99 10⁸ m/s.
f = [tex]\frac{2.99 \ 10^8}{800 \ 10^{-9}}[/tex]
F = 3.7 10¹⁴ Hz
b) Planck's equation states that the energy is proportional to the frequency of the radiation.
E = h f
Where E is the energy, h the Planck constant and f the frequency.
E = 6.63 10⁻³⁴ 3.7 10¹⁴
E = 2.46467 10⁻¹⁹ J
The uncertainty or error is the fluctuation that a magnitude may have due to the precision in the measurements, when the magnitude is calculated by some formula, the propagation of these uncertainties must be carried out.
Δm = ∑ [tex]\sum \frac{dm}{dx_i} | \Delta x_I|[/tex]
the expression for energy is:
E = [tex]\frac{hc}{\lambda }[/tex]
[tex]\Delta E = \frac{dE}{d \lambda} |D\lambda |[/tex]
[tex]\Delta E = \frac{h c }{\lambda^2 } |\Delta \lambda |[/tex]
When the error in the measured magnitude is not explicitly indicated, we assume that the error is in the last digit written, therefore
Δλ = ± 1 nm = ± 1 10⁻⁹ m
We calculate.
[tex]\Delta E = \frac{6.63 \ 10^{-34} \ 2.99 \ 10^8 }{(800 \ 10^{-9})^2} 1 \ 10^{-9}[/tex]
ΔE = 3.1 10⁻²² J
the error is given with a significant figure.
ΔE = 3 10⁻²² J = 0.004 10⁻¹⁹ J
The result of the energy is:
E = (2.465 ± 0.004) 10⁻¹⁹ J
In conclusion, using the speed of light and the propagation of errors, we can find the results on the questions of the radiation emitted by the laser are:
a) The frequency is; f = 3.7 1014 Hz
b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J
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Imagine a monkey is sitting inside a barrel turned on its side. A cruel elephant pushes the barrel down a hill and the monkey starts to roll inside the barrel. This particular monkey gets motion sickness, and an outside observer has noticed that if the monkey spins more than once per second, the monkey will likely vomit. The barrel rolls perfectly down the slope (without slipping) and the outside observer calculates the angular acceleration of the barrel to be 1.2rad/s2. The barrel has a diameter of 1.5 m.
(a) How long will it take for the monkey to spin fast enough to vomit? (b) How far will the monkey have rolled before vomiting?
(c) How many times will the monkey have made a complete circle before vom- iting?
Hi there!
We can begin by converting "spinning once per second" to angular velocity:
[tex]\frac{1rev}{1s} * \frac{2\pi rad}{1rev} = 2\pi rad/sec[/tex]
(a)
As we are given the angular acceleration, we can calculate the time using the following equation:
ωf = ωi + αt
There is an initial angular velocity of 0 rad/sec, so:
ωf = αt
2π/1.2 = t
t = 5.236 sec
(b)
We can use the following rotational kinematic equation to first solve for the angular displacement:
θ = ωit + 1/2αt²
The initial velocity is 0 rad/sec, so plug in values:
θ = 1/2(1.2)(5.236²)
θ = 16.449 rad
Convert to linear distance using the following:
d = θr
d = 1.5m, so r = 1.5/2 = 0.75m
d = 16.449(0.75) = 12.337m
(c)
Find the amount of revolutions by converting radians to revolutions:
[tex]16.449 rad * \frac{1rev}{2\pi rad} = \large\boxed{2.618 rev}[/tex]
OR, 2.618 times.
Which statement about a HORIZONTAL projectile is false?
The horizontal velocity is constant.
The horizontal acceleration is constant.
The vertical velocity is constant.
The vertical acceleration is constant.
Answer:
the vertical velocity is constant.
Explanation:
The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; thus, the vertical velocity of a projectile changes. and the horizontal motion of a projectile is independent of its vertical motion.