The mirror that you need is concave mirror and the radius of curvature of the concave mirror should be -5.44 cm to get a 3.4 times magnified virtual image.
(a) You will need a concave mirror to see a 3.4-times magnified virtual image of an object placed 4.1 cm away from the mirror's vertex.
(b) The radius of curvature (R) of the mirror can be calculated using the mirror formula for concave mirrors, which is given as:
1/f = 1/v + 1/u
where,
f is the focal length,
v is the image distance,
u is the object distance
The magnification (m) of the mirror is given as:-
m = v/u
Using the above equations, we can calculate the focal length (f) and magnification (m) of the concave mirror, and then use the formula,
R = 2f
u = -4.1 cm (since the object is placed in front of the mirror)
v = -13.94 cm (since the virtual image is formed behind the mirror)
m = -3.4 (since the image is 3.4 times larger than the object, it is magnified)
Using the mirror formula, we get:
1/f = 1/v + 1/u= 1/-13.94 + 1/-4.1= -0.123 + (-0.244)= -0.367
f = -2.72 cm
Using the magnification formula,
-m = v/u
v = -m/u
v = -57.14 cm
Using the formula for radius of curvature,
R = 2f
R = 2(-2.72)
R = -5.44 cm
The radius of curvature of the concave mirror should be -5.44 cm.
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If the wavelength of a light source in air is 536nm, what would it's wavelength (in nm) be in Cubic Zirconia (n=2.174)?
The wavelength of a light source in cubic zirconia (n=2.174) would be 246.5nm or rounded to 246.5nm
Cubic zirconia is a material with a refractive index (n) of 2.174. The refractive index determines how much light is bent as it passes through a medium. When light travels from one medium to another, such as from air to cubic zirconia, its wavelength changes.
To calculate the new wavelength in cubic zirconia, we can use the formula: λ1/λ2 = n2/n1, where λ1 is the wavelength in air (536nm), λ2 is the wavelength in cubic zirconia (unknown), n1 is the refractive index of air (1), and n2 is the refractive index of cubic zirconia (2.174).
Rearranging the formula to solve for λ2, we get: λ2 = (λ1 * n2) / n1 = (536nm * 2.174) / 1 = 1165.864nm.
Therefore, the wavelength of the light source in cubic zirconia would be approximately 1165.864nm or rounded to 246.5nm.
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QUESTION 5 An axon has a membrane capacitance of 3 x 10 F, membrane resistance of 1 ko. The time constant for this membrane circuit model is Answer ms.
The time constant for this membrane circuit model is 3 seconds. To calculate the time constant for a membrane circuit model, we use the formula:
Time Constant (τ) = Membrane Resistance (R) * Membrane Capacitance (C)
In this case, the membrane capacitance is given as 3 x 10 F and the membrane resistance is given as 1 kΩ.
Converting 1 kΩ to ohms, we have 1 kΩ = 1000 Ω.
Substituting the values into the formula, we get:
Time Constant (τ) = (1 kΩ) * (3 x 10 F)
= 1000 Ω * 3 x 10 F
= 3000 x 10-3 s
= 3 s
Therefore, the time constant for this membrane circuit model is 3 seconds.
The time constant in a membrane circuit model is a measure of how quickly the membrane potential changes in response to a stimulus. It is determined by the product of the membrane resistance and the membrane capacitance.
The membrane resistance represents the resistance to the flow of ions across the cell membrane. It is influenced by factors such as the number and distribution of ion channels in the membrane.
The membrane capacitance represents the ability of the cell membrane to store electrical charge. It is determined by the surface area and thickness of the membrane.
The time constant is a characteristic property of the membrane circuit and determines the rate at which the membrane potential reaches equilibrium after a change in stimulus. A larger time constant indicates a slower response, while a smaller time constant indicates a faster response.
In the given question, the membrane capacitance is given as 3 x 10 F (Farads) and the membrane resistance is given as 1 kΩ (kiloohms). By multiplying these values together, we obtain the time constant of 3 seconds. This means that it would take approximately 3 seconds for the membrane potential to reach 63.2% of its final value in response to a stimulus.
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A scuba diver and her gear displace a volume of 65.4 L and have a total mass of 67.8 kg. What is the buoyant force on the diver in sea water? F B
Part B Will the diver sink or float? sink float
The buoyant force acting on the scuba diver in sea water is 651.12 N. Based on this force, the diver will float in sea water.
The buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. In this case, the scuba diver and her gear displace a volume of 65.4 L of sea water. To calculate the buoyant force, we need to determine the weight of this volume of water.
The density of sea water is approximately 1030 kg/m³. To convert the displacement volume to cubic meters, we divide it by 1000: 65.4 L / 1000 = 0.0654 m³.
Next, we calculate the weight of this volume of water using the density and volume: weight = density × volume × gravity, where gravity is approximately 9.8 m/s². Thus, the weight of the displaced water is 1030 kg/m³ × 0.0654 m³ × 9.8 m/s² = 651.12 N.
Since the buoyant force is equal to the weight of the displaced water, the buoyant force on the diver is 651.12 N. Since the buoyant force is greater than the weight of the diver (67.8 kg × 9.8 m/s² = 663.24 N), the diver will experience an upward force greater than her weight. As a result, the diver will float in sea water.
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A source emits monochromatic light of wavelength 558 nm in air. When the light passes through a liquid, its wavelength reduces to 420 nm. (a) What is the liquid's index of refraction? (b) Find the speed of light in the liquid. m/s
Dividing the wavelength in air (558 nm) by the wavelength in the liquid (420 nm) will give the refractive index. The liquid's index of refraction is 1.33. The speed of light in liquid is [tex]2.26 x 10^8 m/s.[/tex]
(a) To calculate the refractive index of the liquid, we can use the formula: n = λ_air / λ_liquid
Substituting the given values of λ_air = 558 nm and λ_liquid = 420 nm into the formula, we have:
n = [tex]\frac{558}{420}[/tex]
Calculating the value:
n = 1.33
Therefore, the index of refraction of the liquid is approximately 1.33.
(b) To find the speed of light in the liquid, we can use the equation:
v = c / n
where v is the speed of light in the medium, c is the speed of light in a vacuum, and n is the index of refraction of the medium.
v = [tex]\frac{(3.0 x 10^8 m/s)}{1.33}[/tex]
Calculating the value:
v ≈ [tex]2.26 x 10^8 m/s[/tex]
Therefore, the speed of light in the liquid is approximately [tex]2.26 x 10^8 m/s.[/tex]
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Consider a point on a bicycle tire that is momentarily in contact with the ground as the bicycle rolls across the ground with constant speed. The direction for the acceleration for this point at that moment is: a. upward. b. down toward the ground. c. forward, with the direction of the bicycle's movement. d. at that moment the acceleration is zero. e. backward, against the direction of the bicycle's movement.
So the correct option is d. At that moment, the acceleration of the point on the bicycle tire is zero. Since the bicycle is rolling with constant speed and there is no change in its motion, the point in contact with the ground.
In physics, moment refers to a turning effect or rotational force produced by a force acting on an object. It is the product of the magnitude of the force and the perpendicular distance between the line of action of the force and the pivot point or axis of rotation. Moments are measured in units of newton-meters (Nm) or foot-pounds (ft-lb) and are essential in studying rotational motion, equilibrium, and the principles of torque and angular momentum.
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Question 2: Find the bound currents of a uniformly magnetized sphere along the z-axis with dipole moment M.
The bound currents of a uniformly magnetized sphere along the z-axis with dipole moment M are zero:
[tex]$K_{\phi} = 0$[/tex]
The equation you provided for the bound currents along the z-axis of a uniformly magnetized sphere is correct:
[tex]$K_{\phi}=\frac{1}{\mu_{0}} \nabla \times \mathbf{M}$[/tex]
Starting from [tex]$\mathbf{M} = M \hat{z}$[/tex], we can substitute this value into the equation for the bound currents:
[tex]$K_{\phi}=\frac{1}{\mu_{0}} \nabla \times (M \hat{z})$[/tex]
Next, we can evaluate the curl using the formula you provided for the curl in cylindrical coordinates:
[tex]$\nabla \times \mathbf{V}=\frac{1}{r} \frac{\partial}{\partial z}(r V_{\phi})$[/tex]
However, it seems there was a mistake in the previous equation you presented, so I will correct it.
Applying the formula for the curl, we find that the only non-zero component in this case is indeed in the [tex]$\hat{\phi}$[/tex] direction. Therefore, we have:
[tex]$\nabla \times \mathbf{M} = \frac{1}{r} \frac{\partial}{\partial z}(r M_{\phi})$[/tex]
However, since [tex]$\mathbf{M} = M \hat{z}$[/tex], the [tex]$\phi$[/tex] component of [tex]$\mathbf{M}$[/tex] is zero ([tex]$M_{\phi} = 0$[/tex]), and as a result, the curl simplifies to:
[tex]$\nabla \times \mathbf{M} = 0$[/tex]
This means that the bound currents along the z-axis of a uniformly magnetized sphere are zero, as there are no non-zero components in the curl of the magnetization vector.
Therefore, the conclusion is that the bound currents of a uniformly magnetized sphere along the z-axis with dipole moment M are zero: [tex]$K_{\phi} = 0$[/tex]
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A raft is made of 15 logs lashed together. Each is 41 cm in diameter and has a length of 6.4 m. specific gravity of wood is 0.60. Express your answer using two significant figures.
The weight of the raft is approximately 4750 kg.
To find the weight of the raft, we need to calculate the total volume of the logs and then multiply it by the specific gravity of wood.
The volume of each log can be calculated using the formula for the volume of a cylinder:
V = π[tex]r^{2h}[/tex]
where r is the radius (half of the diameter) and h is the length of the log.
Given that the diameter of each log is 41 cm, the radius is 20.5 cm or 0.205 m, and the length of the log is 6.4 m.
Substituting these values into the volume formula, we get:
V = π[tex](0.205)^{2}[/tex] × 6.4
Calculating this expression, we find:
V ≈ 0.528 [tex]m^{3}[/tex]
Since there are 15 logs in the raft, the total volume of the logs is:
Total Volume = 15 × 0.528 ≈ 7.92 [tex]m^{3}[/tex]
Now, we can calculate the weight of the raft using the specific gravity of wood. The specific gravity is defined as the ratio of the density of the wood to the density of water, which is 1. The specific gravity of wood is given as 0.60.
Weight of the raft = Total Volume × Specific Gravity × Density of Water
Weight of the raft ≈ 7.92 [tex]m^{3}[/tex] × 0.60 × 1000 kg/[tex]m^{3}[/tex] (density of water)
Calculating this expression, we find:
Weight of the raft ≈ 4750 kg
Therefore, the weight of the raft is approximately 4750 kg.
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A photon with wavelength 0.1120 nm collides with a free electron that is initially at rest. After the collision the wavelength is 0.1140 nm. (a) What is the kinetic energy of the electron after the collision? What is its speed? (b) If the electron is suddenly stopped (for example, in a solid target), all of its kinetic energy is used to create a photon. What is the wavelength of the photon?
By using the principle of conservation of energy and momentum, after the collision between a photon and a free electron. After calculating the change in wavelength (∆λ), and speed of the electron.
(a) To find the kinetic energy of the electron after the collision, we can use the energy conservation principle.
K.E. = (1/2) * m * v^2,
ΔE = hc / λ,
ΔE = (6.63 x 10^-34 J s * 3 x 10^8 m/s) / (0.1120 x 10^-9 m - 0.1140 x 10^-9 m) = 2.209 x 10^-17 J.
To find the speed of the electron,use the equation for the kinetic energy and rearrange it to solve for v:
v = √(2 * K.E. / m).
v = √(2 * 2.209 x 10^-17 J / (9.109 x 10^-31 kg)) = 3.58 x 10^6 m/s.
Therefore, the speed of the electron after the collision is 3.58 x 10^6 m/s.
(b) Using the equation ΔE = hc / λ, we can rearrange it to solve for the wavelength:
λ = hc / ΔE.
λ = (6.63 x 10^-34 J s * 3 x 10^8 m/s) / (2.209 x 10^-17 J) = 9.50 x 10^-8 m or 95 nm.
Therefore, the wavelength of the photon created when the electron is stopped is 95 nm.
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Three two-port eircuits, namely Circuit 1 , Circuit 2 , and Circuit 3 , are interconnected in cascade. The input port of Circuit 1 is driven by a 6 A de current source in parallel with an internal resistance of 30Ω. The output port of Circuit 3 drives an adjustable load impedance ZL The corresponding parameters for Circuit 1, Cireuit 2 , and Circuit 3 , are as follows. Circuit 1: G=[0.167S0.5−0.51.25Ω] Circuit 2: Y=[200×10−6−800×10−640×10−640×10−6]S Circuit 3: Z=[33534000−3100310000]Ω a) Find the a-parameters of the eascaded network. (20 marks) b) Find ZL such that maximum power is transferred from the cascaded network to ZL. (10 marks) c) Evaluate the maximum power that the cascaded two-port network can deliver to ZL.
a) The a-parameters of the cascaded network can be found by multiplying the a-parameters of the individual circuits in the cascade.
b) To maximize power transfer from the cascaded network to the load impedance ZL, we need to match the complex conjugate of the source impedance with the load impedance.
c) The maximum power that the cascaded two-port network can deliver to ZL can be calculated using the maximum power transfer theorem, which states that maximum power transfer occurs when the load impedance is equal to the complex conjugate of the source impedance.
a) To find the a-parameters of the cascaded network, we multiply the a-parameters of each individual circuit. The a-parameters represent the relationship between the voltage and current at the input and output ports of a two-port network. Multiplying the a-parameters of Circuit 1, Circuit 2, and Circuit 3 will give us the overall a-parameters of the cascaded network.
b) To maximize power transfer, we need to match the complex conjugate of the source impedance with the load impedance. In this case, we need to find the load impedance ZL that matches the complex conjugate of the source impedance of Circuit 1.
c) The maximum power that can be delivered to the load impedance ZL can be calculated using the maximum power transfer theorem. This theorem states that maximum power transfer occurs when the load impedance is equal to the complex conjugate of the source impedance. By substituting the values of the source impedance and load impedance into the appropriate formula, we can calculate the maximum power that the cascaded network can deliver to ZL.
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Use this circuit to answer the first set of questions: R1 R3 220 Ω 220 Ω 220 Ω R2 R4 220 Ω www +1 PSB 5 V • What is the total resistance in the circuit? (Remember that when measuring resistance, the components must not be connected to the PSB.) • What is the total voltage across the series of resistors? • What is the voltage across each of the resistors in the series? • What is the voltage when measuring at each of the location sets shown below (A, B, and C)? R3 R2 R1 220 R2 220 R3 220 R4 220 R1 2200 R2 2200 R4 220 R1 2200 R3 2200 R4 220 ܤܢܬ݁ܐܬ݁ܦܶ wwwwww + + PSB 5V PSB SV PSB SV Question 3 1 pts How much total current will flow through the circuit in Part 1? Total current is each resistor added together, so approximately 880 N. The current is 3.3V = 88012 (the total resistance), so approximately 3.8mA. The current is 5V + 2200 because all the resistors are equal, so approximately 22.7mA. The current is 5V +88012 (the total resistance), so approximately 5.7mA. Question 4 2 pts How much current will flow through each resistor in Part 1? Resistance limits current, so each resistor will have approximately 2201. The current through each component in a series must be the same, so the total current of about 5.7mA will flow through each resistor. Since the resistors have equal value, the current through each resistor will be the same, 5V = 22012, or approximately 227mA. The current will be divided equally among resistors of equal value, so 1/4 of the total current will flow through each resistor. Question 5 3 pts Match the voltage measurements from the resistor series in Part 1 with the approximate values below. You may use the same answer more than once. A: Voltage across R1. B: Voltage across R2 + R3 + R4. [Choose ] 2200 3.3V 2.5V 3.75V 825mV 660Ω 44022 1.25V 5V C: Voltage across R3 + R4. Question 6 2 pts Based on your observations in Part 1 (as well as previous labs), select both of the TRUE statements about voltage and resistors in series below. (2 answers) Resistors in series divide voltage proportionally depending on the relative value of each resistor, meaning the highest voltage will be across the highest value resistor and the lowest voltage will be across the lowest value resistor. Resistors in series divide voltage proportionally depending on their order (R1 has higher votage, R2 has less, and so on). Resistors in series reduce total resistance by adding distance to the path, so more charge can flow. | The voltage across each resistor in a series will be inversely proportionate to its resistance, meaning the highest voltage will be across the lowest value resistor and the lowest voltage will be across the highest value resistor. Resistors in series will divide voltage equally, with the total voltage determined by the total resistance. Resistors in series add to total resistance in a path.
Answers: (a) The total resistance = 880 Ω.
(b) The total voltage = 5V
(c) voltage across each of the resistors= 0.0057V
(d) Voltage across R1=1.25V
Voltage across R2 + R3 + R4= 3.75V
Voltage across R3 + R4= 2.5V
(e) Total current in Part 1 = 0.0057 A.
(f) The current that will flow through each resistor in Part 1 = 0.0014 A.
(a) The total resistance in the circuit is equal to the sum of resistance of each component present in it.
R1 + R2 + R3 + R4 = 220 + 220 + 220 + 220 = 880 Ω.
(b) The total voltage across the series of resistors is equal to the voltage of the power source that is connected across the circuit. So, the total voltage across the series of resistors is 5 V.
(c) As the resistance of all the resistors is the same, therefore the voltage across each of the resistors will be the same. Therefore, the voltage across each of the resistors in the series will be equal to the total voltage divided by the total resistance. Voltage across each of the resistors = Total voltage / Total resistance = 5 / 880 = 0.0057V
(d) The voltage at each of the location sets can be calculated as follows:
A: Voltage across R1 = Voltage across the series of resistors × (R1 / Total resistance)= 5 × (220 / 880) = 1.25 V
B: Voltage across R2 + R3 + R4 = Voltage across the series of resistors × (R2 + R3 + R4 / Total resistance)
= 5 × (220 + 220 + 220 / 880) = 3.75 V
C: Voltage across R3 + R4 = Voltage across the series of resistors × (R3 + R4 / Total resistance)
= 5 × (220 + 220 / 880) = 2.5 V.
(e) Total current is the current that flows through the circuit when the power source is connected across can be calculated as follows: Total current = Total voltage / Total resistance= 5 / 880 = 0.0057 A. Therefore, the total current that will flow through the circuit in Part 1 is 0.0057 A.
(f) Since all the resistors have the same value, therefore the current will be divided equally among them. So, the current that will flow through each resistor in Part 1 is equal to the total current divided by the total number of resistors. Therefore, the current that will flow through each resistor in Part 1 is 0.0057 / 4 = 0.0014 A.
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Electromagnetic waves (multiple Choice) Which of these are electromagnetic waves? a. visible light b. TV signals c. cosmic rays d. Radio signals e. Microwaves f. Infrared g. Ultraviolet h. X-Rays 1. gamma rays
The electromagnetic waves among the given options are: a. Visible light b. TV signals d. Radio signals e. Microwaves f. Infrared g. Ultraviolet h. X-Rays
Electromagnetic waves are waves that consist of oscillating electric and magnetic fields. They are produced by the acceleration of electric charges or by changes in the magnetic field. These waves do not require a medium for their propagation and can travel through vacuum. They are characterized by their wavelength and frequency, which determine their properties such as energy and interaction with matter.
Visible light is the portion of the electromagnetic spectrum that is visible to the human eye. It consists of different colors ranging from red to violet, each with a specific wavelength and frequency.
TV signals and radio signals are both forms of electromagnetic waves used for communication. TV signals carry audio and visual information, while radio signals are used for radio broadcasting and communication.
Microwaves are electromagnetic waves with shorter wavelengths than radio waves. They are used for various applications such as cooking, communication, and radar technology.
Infrared, ultraviolet, and X-rays are all part of the electromagnetic spectrum, with infrared having longer wavelengths than visible light, ultraviolet having shorter wavelengths, and X-rays having even shorter wavelengths. They are used in a wide range of applications, including heating, sterilization, imaging, and medical diagnostics.
Cosmic rays, on the other hand, are not electromagnetic waves. They are high-energy particles, such as protons and atomic nuclei, that originate from outer space and can interact with the Earth's atmosphere.
In summary, electromagnetic waves include visible light, TV signals, radio signals, microwaves, infrared, ultraviolet, and X-rays. Each of these types of waves has distinct properties and applications in various fields of science and technology.
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A spherical drop of water carrying a charge of 41pC has a potential of 570 V at its surface (with V=0 at infinity). (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, what is the potential at the surface of the new drop? (a) Number Units (b) Number Units
A spherical drop of water carrying a charge of 41pC has a potential of 570 V at its surface (with V=0 at infinity) (a) The radius of the drop is approximately 5.88 micrometers (μm).
(b) The potential at the surface of the new drop formed by combining two drops of the same charge and radius is approximately 1140 V.
(a) To find the radius of the drop, we can use the formula for the potential of a charged sphere, which is given by V = (k * Q) / r, where V is the potential, k is the electrostatic constant, Q is the charge, and r is the radius of the sphere. Rearranging the formula to solve for the radius, we have r = (k * Q) / V. Plugging in the given values of Q = 41 pC (pico coulombs) and V = 570 V, and using the value of k = 8.99 × 10^9 Nm^2/C^2, we can calculate the radius to be approximately 5.88 μm.
(b) When two drops combine to form a single spherical drop, the total charge remains the same. Therefore, the potential at the surface of the new drop can be calculated using the same formula as before, but with the combined charge. Since each drop has the same charge and radius, the combined charge will be 2 times the original charge. Plugging in Q = 82 pC (2 * 41 pC) and using the given value of V = 570 V, we can calculate the potential at the surface of the new drop to be approximately 1140 V.
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At a rock concert, a dB meter registered 124 dB when placed 2.5 m in front of a loudspeaker on stage. What is the sound level produced by the rock concert at 10 m, assuming uniform spherical spreading of the sound and neglecting absorption in the air? (l₀ = 1 ‘ 10⁻¹² W/m² is a reference intensity, usually taken to be at the threshold of hearing.) a. 109 Db
b. 112 dB c. 119 dB d. 129 dB e. 122 dB
The sound level produced by the rock concert at 10 m, the correct option is (b) 112 dB.
dB meter registered 124 dB when placed 2.5 m in front of a loudspeaker on stage.
We need to find the sound level produced by the rock concert at 10 m, assuming uniform spherical spreading of the sound and neglecting absorption in the air.
Sound is defined as the form of energy that travels in the form of waves through various mediums such as solids, liquids, and gases. It requires a medium to travel from one point to another.There are a few different ways to calculate sound intensity, but one common formula is:
I = P / A
where:
I = sound intensity in W/m²
P = sound power in W (measured in dB)
A = surface area
The formula for sound pressure level (SPL) in decibels (dB) is given by:
L = 10 log (I/I0)
where:
L = sound level (in dB)
I = sound intensity in W/m²
I0 = reference intensity of sound (usually 1 x 10-12 W/m²)
Thus, we can write as follows:
(I/I₀) = (r₀/r)²I₀ = 1x10^-12 W/m²
l₀ = 1 ‘ 10⁻¹² W/m²
The sound level produced by the rock concert at 10 m can be calculated as follows:
L₂ - L₁ = 10 log (I₂ / I₁)
L₁ = 124 dB
L₂ = 10 log (I₂ / I₀) - 10 log (I₁ / I₀)
L₂ = 10 log [(r₁/r₂)²]
L₂ = 10 log [(10m/2.5m)²]
L₂ = 10 log [16]
L₂ = 10(1.2041)
L₂ = 12.041 dB
L₂ = L₁ - (10 log [(r₁/r₂)²])
L₂ = 124 - 12.041
L₂ = 111.959 dB
Therefore, the sound level produced by the rock concert at 10 m is 112 dB (Approx).Hence, the correct option is (b) 112 dB.
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Select the correct answer.
How does the author introduce new points in this article?
O A.
O B.
OC.
D.
By describing studies that explain each point
By beginning each section with a statistic
By evaluating a point made by an expert
By using headings that set apart each point
Answer:
by using headings that set apart each point
The orbit of a planet is a very squished ellipse. Its eccentricity is closest to
a) unknown
b) 0
c) 1
The orbit of a planet is a very squished ellipse. Its eccentricity is closest to b) 0. An ellipse is a shape that is not a perfect circle. An ellipse has two foci instead of one, and a planet orbits one of the foci.
The distance between the center of the ellipse and either of its foci is called the eccentricity of the ellipse. It ranges between 0 and 1. If the eccentricity of the ellipse is close to 0, then the ellipse becomes almost circular, that is, it is squished. The more the eccentricity of the ellipse, the more squished or elongated the ellipse is. Therefore, option b) 0 is the answer.
The eccentricity of an ellipse can be defined as the ratio of the distance between the foci to the major axis' length. The ellipse's eccentricity is related to the shape of the ellipse, which is described by the eccentricity's numerical value. If the eccentricity is equal to 0, the ellipse will be a perfect circle, which is the case here.
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The speed of light in a material is 1.70×10 8
m/s. What is the critical angle of a light ray at the interface between the material and a vacuum? Three significant digits please.
The critical angle can be calculated using Snell's law, which relates the angles of incidence and refraction at the interface between two media:
n₁ × sin(θ₁) = n₂ × sin(θ₂)
The critical angle of the light ray at the interface between the material and vacuum is approximately 33.9 degrees.
In this case, the first medium is the material with a speed of light of 1.70 × 10⁸ m/s, and the second medium is vacuum with a speed of light of approximately 3.00 × 10⁸ m/s.
The refractive index (n) of a medium is defined as the ratio of the speed of light in vacuum to the speed of light in that medium:
n = c/v
where c is the speed of light in vacuum and v is the speed of light in the medium.
Let's calculate the refractive indices for both media:
n₁ = c / v₁
= (3.00 × 10⁸ m/s) / (1.70 × 10⁸ m/s)
≈ 1.765
n₂ = c / v₂
= (3.00 × 10⁸ m/s) / (3.00 × 10⁸ m/s)
= 1.000
Now, we can determine the critical angle by setting θ2 to 90 degrees (since the light ray would be refracted along the interface):
n₁ × sin(θ₁_critical) = n₂ × sin(90°)
sin(θ₁(critical)) = n₂ / n₁
θ₁(critical) = sin⁻(n₂ / n₁)
θ₁(critical) = sin⁻(1.000 / 1.765)
θ₁(critical) ≈ 33.9 degrees
Therefore, the critical angle of the light ray at the interface between the material and vacuum is approximately 33.9 degrees (to three significant digits).
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1) athlete swings a 3.50-kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.870 m at an angular speed of 0.430 rev/s. (a)What is the tangential speed of the ball? (b)What is its centripetal acceleration? (c)If the maximum tension the rope can withstand before breaking is 104 N, what is the maximum tangential speed the ball can have? m/s 2) An electric motor rotating a workshop grinding wheel at a rate of 1.19 ✕ 102 rev/min is switched off. Assume the wheel has a constant negative angular acceleration of magnitude 2.10 rad/s2. (a) How long does it take for the grinding wheel to stop? s (b) Through how many radians has the wheel turned during the interval found in (a)? rad
Answer: (a) Maximum tangential speed the ball can have is 7.58 m/s.
(b) Time taken by the grinding wheel to stop is 9.43 s.
a) Mass of the ball, m = 3.50 kg
Radius of circle, r = 0.870 m
Angular speed, ω = 0.430 rev/s
Tangential speed of the ball is given by, v = rω
= 0.870 m × (0.430 rev/s) × 2π rad/rev
= 1.45 m/s.
Tangential speed of the ball is 1.45 m/s.
Centripetal acceleration is given by, a = rω²
= 0.870 m × (0.430 rev/s)² × 2π rad/rev
= 2.95 m/s² Centripetal acceleration is 2.95 m/s².
The maximum tangential speed the ball can have is given by,
F = ma =
a = F/mMax speed
= √(F × r/m)
= √(104 N × 0.870 m/3.50 kg)
= 7.58 m/s.
Maximum tangential speed the ball can have is 7.58 m/s.
b) Initial angular velocity, ω1 = 1.19 × 10² rev/min = 19.8 rev/s.
Final angular velocity, ω2 = 0
Angular acceleration, α = -2.10 rad/s²
Using angular kinematic equation,ω2 = ω1 + αt t = (ω2 - ω1) / α
= 19.8 rev/s / 2.10 rad/s²
= 9.43 s. Time taken by the grinding wheel to stop is 9.43 s.
Using rotational kinematic equation,θ = ω1t + (1/2) αt²θ = (19.8 rev/s) × 9.43 s + (1/2) × (-2.10 rad/s²) × (9.43 s)²θ
= 1487 rad. Through 1487 radians has the wheel turned during the interval found in part (a).
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A student standing on the top of a cliff shoots an arrow from a height of 30.0 m at 25.0 m/s and an initial angle of 32.0° above the horizontal. Show all your work in calculating the answers to the following 4 questions. What will be the horizontal and vertical components of the arrow's initial speed? How high above the landscape under the cliff will the arrow rise? Assume a level landscape. What will be the vertical and horizontal speeds of the arrow
Answer:
The vertical speed of the arrow at the highest point is zero, the horizontal speed remains constant at approximately 21.3 m/s, and the arrow reaches a maximum height of approximately 9.26 m above the landscape.
Given:
Initial speed (v) = 25.0 m/s
Launch angle (θ) = 32.0°
Height of the cliff (h) = 30.0 m
The horizontal component of the initial speed (v_horizontal) can be found using trigonometry:
v_horizontal = v * cos(θ)
Substituting the values:
v_horizontal = 25.0 * cos(32.0°)
Calculating:
v_horizontal ≈ 21.3 m/s
The vertical component of the initial speed (v_vertical) can also be found using trigonometry:
v_vertical = v * sin(θ)
Substituting the values:
v_vertical = 25.0 * sin(32.0°)
Calculating:
v_vertical ≈ 13.5 m/s
Therefore, the horizontal component of the arrow's initial speed is approximately 21.3 m/s, and the vertical component is approximately 13.5 m/s.
Question 2: Maximum Height Above the Landscape
To find the maximum height above the landscape that the arrow will reach, we can use the kinematic equation for vertical motion:
Δy = v_vertical^2 / (2 * g)
Where Δy is the change in height, v_vertical is the vertical component of the initial speed, and g is the acceleration due to gravity (approximately 9.8 m/s²).
Substituting the values:
Δy = (13.5^2) / (2 * 9.8)
Calculating:
Δy ≈ 9.26 m
Therefore, the arrow will rise approximately 9.26 m above the landscape.
Question 3: Vertical and Horizontal Speeds of the Arrow
The vertical speed of the arrow at any given time can be determined using the equation:
v_vertical = v_initial * sin(θ) - g * t
Where v_initial is the initial speed, θ is the launch angle, g is the acceleration due to gravity, and t is the time.
At the highest point of the trajectory, the vertical speed becomes zero. We can set v_vertical = 0 and solve for the time t:
0 = v_initial * sin(θ) - g * t
Solving for t:
t = v_initial * sin(θ) / g
Substituting the values:
t = (25.0 * sin(32.0°)) / 9.8
Calculating:
t ≈ 1.34 s
The horizontal speed of the arrow remains constant throughout the motion, assuming no horizontal forces act on it.
Therefore, the horizontal speed (v_horizontal) of the arrow remains the same as the initial horizontal component of the velocity, which is approximately 21.3 m/s.
In summary, the vertical speed of the arrow at the highest point is zero, the horizontal speed remains constant at approximately 21.3 m/s, and the arrow reaches a maximum height of approximately 9.26 m above the landscape.
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A car with a mass of 405 kg is driving in circular path with a radius of 120 m at a constant speed of 5.5 m/s. What is the magnitude of the net force on the car? Round to the nearest whole number. 102 N 14182 N 6600 N 78000 N 558 N You throw a ball horizontally with an initial speed of 20 m/s from a height of 7.2 meters. How long does it take for the ball to land? Round to two decimal places. 0.55 seconds 0.39 seconds 6.53 seconds 0.15 seconds 1.20 seconds A car is initially traveling due South at 20 m/s. The driver hits the brake pedal and 1 second later, the car is traveling due South at 7 m/s. What is the magnitude of the average acceleration of the car during this 1 second interval? 13 m/s^2 27 m/s^2 7 m/s^2 60 m/s^2 25 m/s^2 Your friend (mass 60 kg) is wearing frictionless roller skates on a horizontal surface and is initially at rest. If you push your friend with a constant force of 1200 N, over what distance must you exert the force so they reach a final speed of 10 m/s? 0.25 meters 0.5 meters 1.25 meters: 2.5 meters 5 meters
1. the magnitude of the net force on the car is 558 N. Hence, the correct option is (e) 558 N.
2. it will take 1.20 seconds for the ball to land. Hence, the correct option is (e) 1.20 seconds.
3. the magnitude of the average acceleration of the car is 13 m/s². Hence, the correct option is (a) 13 m/s².
4. the distance over which the force must be exerted is 0.5 meters. Hence, the correct option is (b) 0.5 meters.
1. Calculation of the magnitude of the net force on the car:
We know that,
Formula used for the calculation of net force is:
F = m * v²/r
F = (405 kg) * (5.5 m/s)²/120 m
F = 558 N
2. Calculation of time taken by the ball to land:
Given,
V₀ = 20 m/s, h = 7.2 m, and g = 9.81 m/s². Formula used for the calculation of time taken by the ball to land is:
t = (sqrt(2h/g))
t = sqrt(2 * 7.2/9.81)
t = 1.20 s (rounded to two decimal places)
3. Calculation of the magnitude of the average acceleration of the car:
Given,
Vᵢ = 20 m/s, Vf = 7 m/s, and t = 1 s. Formula used for the calculation of the magnitude of the average acceleration of the car is:
a = (Vf - Vᵢ)/t
a = (7 - 20)/1
a = -13 m/s²
4. Calculation of the distance over which the force must be exerted:
Given,m = 60 kg, F = 1200 N, Vf = 10 m/s, and V₀ = 0 m/s. Formula used for the calculation of the distance over which the force must be exerted is:
Vf² = V₀² + 2*a*d10² = 0 + 2*(F/m)*d10² = (2400/60)*dd = 0.5 m
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When this astronaut goes
back to Earth, what will
happen?
A. His weight will increase.
B. His mass will increase.
C. Both his mass and weight will decrease.
Answer: A
Explanation: The mass of a thing never changes but weight is the act of gravity on mass. This rules out B and C since mass can’t change. Leaving A as the only possible answer.
Body is moving with speed of 40km/ m one sec later its is moving at 58 km/h find its acceleration
The 2nd harmonics of 0.30 m length guitar is 440 Hz under 200 N tension. Which of the following is/are correct about the system? A. The fundamental frequency is 880 Hz. B. The speed of the wave on the string is 130 m/s. The wavelength of the second overtone is 0.20 m. C.
The second harmonic of a 0.30 m long guitar is 440 Hz under a 200 N tension. The following options are correct about the system:
B. The speed of the wave on the string is 130 m/s.
C. The wavelength of the second overtone is 0.20 m.
The fundamental frequency of a string is given by:f = (1/2L) * (√(T/μ))
where f is the frequency, L is the length of the string, T is the tension in the string, and μ is the linear density of the string. Given:
Length of the string L = 0.30 m
Tension T = 200 N
The frequency of the second overtone = 440 Hz
Hence, the frequency of the fundamental is given by:
f1 = (1/2L) * (√(T/μ)) ... (1)
For the second harmonic:f2 = 2f1
For a string fixed at both ends, the wavelength of the second overtone can be given by
λ2 = 2L/2 = L = 0.30 m
Speed of the wave is given by
v = f2 λ2 ... (2)
From equations (1) and (2), we can find μ
μ = (T/((4L^2)(f1^2)))
From equation (1):
f1 = (1/2L) * (√(T/μ))√(T/μ) = 2f1L
Therefore,√(T/μ) = 2f1L
Substituting in the above expression for μ:
μ = (T/((4L^2)(f1^2)))
Thus, using the given values, we can determine the required properties of the system.
The speed of the wave on the string is given by:
v = f2λ2
v = (2f1)λ2
v = 2(√(T/μ))(2L) = 2(2f1L)(2L)
Therefore,v = 2f1L = 2(440/2) * 0.3 = 130 m/s
The wavelength of the second overtone is given by:
λ2 = L = 0.30 m
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Two measurements for the ratio of neutral to charged current events for neutrinos interacting on nuclei are 0.27 0.02 CITF (Fermilab) 0.295 ± 0.01 CDHS (CERN). What would you quote for a combined result? [20 points]
The combined result for the ratio of neutral to charged current events for neutrinos interacting on nuclei is 0.2885 ± 0.0894.
The combined result for the ratio of neutral to charged current events for neutrinos interacting on nuclei can be obtained by considering the weighted average of the individual measurements.
The given measurements are 0.27 ± 0.02 CITF (Fermilab) and 0.295 ± 0.01 CDHS (CERN).
To combine these results, we need to take into account both the central values and the uncertainties associated with each measurement.
First, let's calculate the weighted average of the central values. We assign weights based on the inverse squares of the uncertainties:
w1 = 1/[tex](0.02)^2[/tex] = 25
w2 = 1/[tex](0.01)^2[/tex] = 100
Using the weighted average formula, the combined central value is given by:
[tex]\bar{x}[/tex] = (w1 * x1 + w2 * x2) / (w1 + w2)
where x1 and x2 are the central values of the measurements. Substituting the values, we have:
[tex]\bar{x}[/tex] = (25 * 0.27 + 100 * 0.295) / (25 + 100) = 0.2885
Next, let's calculate the combined uncertainty.
The combined uncertainty can be determined using the formula:
Δx = √(1 / (w1 + w2))
Substituting the values, we have:
Δx = √(1 / (25 + 100)) = √(1 / 125) = 0.0894
Therefore, the combined result for the ratio of neutral to charged current events is 0.2885 ± 0.0894.
In summary, the combined result for the ratio of neutral to charged current events is 0.2885 ± 0.0894.
This combined result takes into account both the central values and the uncertainties associated with the individual measurements, providing a more accurate representation of the true value.
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A 25 kg block is being pushed forward on a flat surface with a force of magnitude 66 N. The coefficient of static friction on the block is 0.23 and the coefficient of kinetic friction on the block is 0.16 (only one of these needs to be used). You are encouraged to draw a free body diagram of the block before trying the following questions. a) What is the net force acting on the block? b) What is the acceleration of the block?
The block has a coefficient of static friction of 0.23 and a coefficient of kinetic friction of 0.16. We must determine the net force acting on the block and its acceleration.
To solve this problem, we first draw a free-body diagram of the block. The forces acting on the block are the applied force pushing it forward, the gravitational force pulling it downward (mg), and the frictional force opposing its motion. The net force acting on the block is the vector sum of all the forces. In this case, the net force can be calculated as the applied force minus the force of friction. The force of friction can be determined by multiplying the coefficient of friction (either static or kinetic) by the normal force, which is equal to the weight of the block (mg). Therefore, the net force is given by
[tex]F_net = F_applied - μ * mg,[/tex]
where μ is the coefficient of friction.The acceleration of the block can be determined using Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration [tex](F_net = ma)[/tex]
. Rearranging the equation,
we get [tex]a = F_net / m[/tex]
.By plugging in the given values into the equations, we can calculate the net force and the acceleration of the block.
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Two identical waves each have an amplitude of 6 cm and interfere with one another. You observe that the resultant wave has an amplitude of 12 cm. Of the phase differences listed (in units of radian), which one(s) could possibly represent the phase difference between these two waves? I. 0 II. TU III. IV. V. REIN 2 2π 3πT 4
Two identical waves each have an amplitude of 6 cm and interfere with one another. Therefore, only phase difference 0 could possibly represent the phase difference between these two waves. Therefore, the correct option is I.
In a wave, the amplitude determines the wave's maximum height (above or below its rest position), whereas the phase determines the wave's location in its cycle at a particular moment in time.
Since the waves have an amplitude of 6 cm, the resulting wave has an amplitude of 12 cm. It means that the waves are constructive and in phase.
Constructive interference happens when waves with the same frequency and amplitude align.
The combined amplitude of the two waves is equal to the sum of their individual amplitudes when this happens.
The formula for the resultant wave's amplitude is 2A cos(ϕ/2), where A is the amplitude of the two waves, and ϕ is the phase difference.ϕ = 0 corresponds to in-phase waves.
ϕ = 2π corresponds to waves that are shifted by one complete wavelength.
ϕ = π corresponds to waves that are shifted by half a wavelength.ϕ = 3π corresponds to waves that are shifted by 1.5 wavelengths.
ϕ = 4 corresponds to waves that are shifted by two complete wavelengths.
ϕ = T corresponds to waves that are shifted by the time period of the wave.
Therefore, only phase difference 0 could possibly represent the phase difference between these two waves. Therefore, the correct option is I.
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A vertical spring (ignore its mass), whose spring stiffness constant is 3n/m is attached to a table and is compressed down 3.2 m. (a) What maximum upward speed can it give to a 0.30−kg ball when released? ( Note you need to find the equilibrium point)(b) How high above its original position (spring compressed) will the ball fly?
The maximum upward speed the spring can give to the ball when released is 6.48 m/s, and the ball will fly approximately 0.331 m above its original position.
(a) To find the maximum upward speed of the ball, we need to consider the conservation of mechanical energy. At the maximum height, the ball will have zero kinetic energy. Initially, the ball is compressed against the spring with potential energy given by the equation U = (1/2)kx², where U is the potential energy, k is the spring constant (3 N/m), and x is the compression distance (3.2 m).
Setting the potential energy equal to the initial kinetic energy of the ball, (1/2)mv², where m is the mass of the ball (0.30 kg) and v is the maximum upward speed we want to find. Therefore, we have (1/2)kx² = (1/2)mv². Rearranging the equation and solving for v, we get v = √((kx²)/m). Substituting the given values, we find v = √((3(3.2)²)/0.30) ≈ 6.48 m/s.
(b) To determine the height the ball will reach above its original position, we can use the conservation of mechanical energy again. At the highest point of the ball's trajectory, its potential energy will be maximum, and its kinetic energy will be zero.
The potential energy at this point is given by mgh, where m is the mass of the ball, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the maximum height above the original position. Equating the initial potential energy (U = (1/2)kx²) with the potential energy at the highest point (mgh), we can solve for h.
Therefore, (1/2)kx² = mgh. Rearranging the equation and substituting the values, we have h = (kx²)/(2mg) = (3(3.2)²)/(2(0.30)(9.8)) ≈ 0.331 m.
Thus, the ball will reach approximately 0.331 m above its original position.
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A time period of a simple pendulum of length L on earth is 2.0 s and suppose it is taken to moon to measure the time period there and its period is found to be 4.90 s on moon. From these information find the value of g on the moon. Take the value of g on earth = 9.80 m/s2
When on Earth, the time period of a simple pendulum is 2.0 seconds, and the acceleration due to gravity(g) is 9.80 m/[tex]s^2[/tex] then the value of g on the Moon is approximately 0.408 m/[tex]s^2[/tex].
The time period of a simple pendulum is given by the formula:
T = 2π√(L/g)
where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity.
On Earth, the time period is given as 2.0 seconds, and the acceleration due to gravity is 9.80 m/[tex]s^2[/tex].
Plugging these values into the formula, we have:
2.0 = 2π√(L/9.80)
Simplifying the equation:
1 = π√(L/9.80)
Squaring both sides of the equation:
1 = π^2(L/9.80)
L/9.80 = 1/π^2
L = (9.80/π^2)
Now, on the Moon, the time period is given as 4.90 seconds.
Let's denote the acceleration due to gravity on the Moon as g_moon.
Plugging the values into the formula for the Moon, we have:
4.90 = 2π√(L/g_moon)
Substituting the value of L, we get:
4.90 = 2π√((9.80/π^2)/g_moon)
Simplifying the equation:
4.90 = 2√(9.80/g_moon)
Squaring both sides of the equation:
24.01 = 9.80/g_moon
g_moon = 9.80/24.01
Therefore, the value of g on the Moon is approximately 0.408 m/[tex]s^2[/tex].
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Derive the Boolean expression for the output Y directly from the circuit shown below. Do not simplify the final expression. A B Y Y = (A + D + BC)(BC) Y = (A + D + BC)(BC) OY = (A + D + BC) (BC) O Y = (A + D + BC) (BC) O None of the options. Y = (A + D + BC) (BC) Question 3 What is the truth table for the circuit below? A B ABC Y 000 Y 4 pts 4 pts
The truth table for the given circuit is as follows: A B C Y0 0 0 00 0 1 00 1 0 00 1 1 01 0 0 01 0 1 01 1 0 01 1 1 0
The Boolean expression for the output Y directly from the given circuit is Y = (A + D + BC)(BC).The Given circuit is shown below: From the above circuit diagram, it can be observed that the output Y is obtained by taking the AND operation between the outputs of two OR gates. The output of the first OR gate is given by (A + D + BC) and the output of the second OR gate is given by BC. Therefore, the Boolean expression for the output Y can be derived as follows: Y = (A + D + BC)BC. This is the final Boolean expression for the output Y that is derived directly from the given circuit. The truth table for the given circuit is as follows:
A B C Y0 0 0 00 0 1 00 1 0 00 1 1 01 0 0 01 0 1 01 1 0 01 1 1 0
The above truth table is obtained by substituting all possible values of A, B and C in the Boolean expression of the output Y and noting down the corresponding output values.
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A uniform solid cylinder rolls without slipping along a horizontal surface. Calculate the ratio E/E rot,
where E rot
is the rotational kinetic energy and E is the total kinetic energy. a. 10 b. 4 C. 5 d. 2 e. 3
The ratio [tex]E/E_rot[/tex] is equal to 1, which means that both the translational and rotational kinetic energies of the rolling cylinder are similar.
The problem involves calculating the ratio
[tex]E/E_rot[/tex], where [tex]E_rot[/tex]
represents the rotational kinetic energy, and E is the total kinetic energy of a uniform solid cylinder rolling without slipping on a horizontal surface.
When a solid cylinder rolls without slipping, it possesses translational and rotational kinetic energy. The total kinetic energy, E, is the sum of these two energies. The rotational kinetic energy,[tex]E_rot[/tex], can be calculated using the formula
[tex]E_rot = (1/2) * I * ω²[/tex]
, where I is the moment of inertia of the cylinder and ω is the angular velocity.For a solid cylinder, the moment of inertia about its central axis is given by
[tex]I = (1/2) * m * r²[/tex]
, where m is the mass of the cylinder and r is its radius.The translational kinetic energy is given by
[tex]E_trans = (1/2) * m * v²[/tex], where v is the linear velocity.Since the cylinder is rolling without slipping, the linear velocity v is related to the angular velocity ω by the equation
[tex]v = r * ω[/tex].
Substituting this into the formula for[tex]E_trans[/tex] gives [tex]E_trans = (1/2) * m * (r * ω)² = (1/2) * m * r² * ω² = (1/2) * I * ω²[/tex], which is the same as [tex]E_rot[/tex]
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"Charging" the magnetic field of an inductor 60.000 m of wire is wound on a cylinder, tight packed and without any overlap, to a diameter of 2.00 cm (relenoid 0.0100 m ). The wire has a radius of rune −0.00100 m and a total resistance of 0.325Ω. This inductor initially has no current flowing in it. It is suddenly connected to a DC voltage source at time t−0.000sec. V s
=2.00Volts. After 2 time constants, the current across the inductor will be.... Hint: first find the inductor currents I t=[infinity]
I F=[infinity]
After 2 time constants, the current across the inductor will be approximately 5.320 Amperes. The current across the inductor after 2 time constants, we need to calculate the time constant and then use it to find the current at that time. The time constant (τ) of an RL circuit (resistor-inductor circuit) is given by the formula:
τ = L / R,
where L is the inductance and R is the resistance.
First, let's calculate the inductance of the coil. The inductance of a tightly packed solenoid can be approximated using the formula:
L = (μ₀ * N² * A) / l,
where μ₀ is the permeability of free space (4π x [tex]10^-7[/tex]T·m/A), N is the number of turns, A is the cross-sectional area of the solenoid, and l is the length of the solenoid.
Number of turns, N = 60,000
Cross-sectional area, A = π * ([tex]0.0200 m)^2[/tex]
Length of the solenoid, l = 0.0100 m
Using these values, we can calculate the inductance:
L = (4π x [tex]10^-7[/tex]T·m/A) * ([tex]60,000 turns)^2[/tex] * (π * [tex](0.0200 m)^2[/tex]) / 0.0100 m
≈ 0.301 T·m²/A
Next, we can calculate the time constant:
τ = L / R = 0.301 T·m²/A / 0.325 Ω
≈ 0.926 s
Now, we can determine the current after 2 time constants:
I(t) = I(∞) * (1 - e^(-t/τ)),
where I(t) is the current at time t, I(∞) is the final current (as t approaches infinity), and e is the base of the natural logarithm.
Since t = 2τ, we can substitute this value into the equation:
I(2τ) = I(∞) * (1 - e^(-2))
≈ I(∞) * (1 - 0.1353)
≈ I(∞) * 0.8647
We are given that the voltage source is 2.00 Volts. Using Ohm's law (V = I(∞) * R), we can solve for I(∞):
2.00 V = I(∞) * 0.325 Ω
I(∞) = 2.00 V / 0.325 Ω
≈ 6.153 A
Finally, we can calculate the current after 2 time constants:
I(2τ) ≈ I(∞) * 0.8647
≈ 6.153 A * 0.8647
≈ 5.320 A
Therefore, after 2 time constants, the current across the inductor will be approximately 5.320 Amperes.
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