You are enjoying a ride on a Ferris Wheel. The wheel has a circumference of 1,250m. The velocity of the wheel is 12m/s. How many minutes is one trip around the wheel?

Answers

Answer 1

Answer:

Time = 1.44 minutes

Explanation:

Given that the circumference of the wheel is 1250 m, which is the distance to be covered.

Thus,

speed =

distance = 1250 m, speed = 12 m/s.

So that;

12 =

time =

       = 104.16667

time = 104.17 s

But, 60 seconds = 1 minute

time = 1.4417

       = 1.44 minutes

The time required for one trip around the wheel is 1.44 minutes.


Related Questions

What are the energy transfers in a torch?

Answers

Explanation:

The battery is a store of internal energy (shown as chemical energy). The energy is transferred through the wires to the lamp, which then transfers the energy to the surroundings as light. These are the useful energy transfers - we use electric lamps to light up our rooms.


A thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center. A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s2, calculate the magnitude of F.

a. 35 N
a. 20 N
c. 25 N
d. 8 N

Answers

Given :

Thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center.

A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s².

To Find :

The magnitude of F.

Solution :

Torque on hoop is given by :

[tex]\tau =F\times R\\\\I\alpha = FR\\\\MR^2\alpha = FR\\\\F = MR\alpha[/tex]( Moment of Inertia of hoop is MR² )

Putting  value of M, R and α in above equation, we get :

[tex]F=5\times 2\times 2.5\ N\\\\F = 25 \ N[/tex]

Therefore, the magnitude of force F is 25 N.

Hence, this is the required solution.

A parallel circuit containing two bulbs and a bell has three paths for the current flow. If the first bulb in the circuit burns out, what effect will it have on the other loads in the circuit?

A. The other bulb will go out, but the bell will continue to work.

B. The other bulb will remain lit, but the bell will no longer work.

C. The other loads will not be affected.

D. All the other devices will stop working.

Answers

Answer:

C

Explanation:

Since the circuit is in parallel there will be no effect on the other loads.

Jacki evaluated the expression below. 2 cubed (3 minus 1) + 4 (8 minus 12) = 2 cubed (2) + 4 (4) = 8 (2) + 16 = 16 + 16 = 32. What was Jacki’s error? Jacki should have simplified the exponent first. Jacki should have multiplied 4 and 8 first. Jacki did not subtract 12 from 8 correctly. Jacki should not have multiplied 8 and 2.

Answers

Answer:

Her error was that she did not subtract 12 from 8 correctly

Explanation:

Jackie did 8-12 instead of 12-8

An 1850 kg car is moving to the right at a constant speed of 1.44 m/s.
a. What is the net force on the car?
b. What would be the net force on the car if it were moving to the left?

Answers

Answer:

Read explanation and see if that helps

Explanation:

Newton's second law of motion states that the force on an object is given by f = ma. since the car is moving to the right at a constant speed of 1.44 m/s the acceleration a = 0. this means that there is no net force driving the car.

direction doesnt matter as long as the car is moving in a straight line at a constant speed the force will always be zero

The acceleration of the car in both directions (right and left) is zero.

The given parameters;

mass of the car, m = 1850 kgspeed of the car, v = 1.44 m/s

The net force on the car is calculated by applying Newton's second law of motion as shown below;

F = ma

where;

a is the acceleration of the car

At constant speed, the acceleration of the car will be zero

F = m(a)

F m(0)

F = 0

When the car is moving left, the net force is also zero since the acceleration is zero.

Thus, the acceleration of the car in both directions (right and left) is zero.

Learn more here:https://brainly.com/question/19887955

A 100 kg cart on a roller coaster has 1800J of kinetic energy. How fast is it going?
KE= 1/2mv2

Answers

Answer:

the speed is equal to 6 m/s

Explanation:

value of i cap,j cap, k cap​

Answers

Answer:

i cap is the unit vector for x axis

eg 2 i cap

j cap is the unit vector for y axis

eg 3 j cap

hope it will help you

Explanation:

Which of the following statements is true of inertia?
(1 Point)
Inertia is a force
Inertia is a force which keeps stationary objects at rest and moving objects in motion at constant velocity.
Inertia is a force which brings all objects to a rest position.
A more massive object has more inertia than a less massive object.

Answers

All of them are right except for the third one

Options A, B & D are true.

We are dealing with the concept of inertia.

From Newton's first law of motion which is referred to as law of inertia, we are told that; An object will remain at rest or continue in constant motion unless it is acted upon by an external force.

This means that inertia is the force that keeps an object at rest or in constant motion.

Furthermore, it means that the bigger the object, the more the inertia because a bigger object will require more force to make it move from rest.

Looking at the options, the only option that doesn't correspond with definition of Inertia is Option C. Options A, B and D are true based on our explanation above.

Read more at; brainly.com/question/13656225

Sienna made a chart listing the steps that describe how a four-stroke heat engine operates.
COM
Step
1
Name
intake
2
ignition
Description
piston moves down and fuel-air mixture
enters cylinder
spark plug fires and causes combustion,
leading to gas expansion
piston moves up and temperature of gas
increases
piston moves up, pushing burned gas
through exhaust valve
3
compression
4
exhaust
Which best describes Sienna's error?
o The descriptions for intake and ignition should be switched with one another.
O During compression, temperature does not increase, it decreases.
O Compression happens before ignition, so it should be step 2.
O The piston moves down, not up, during the exhaust step.

Answers

Answer:

C

Explanation:

Answer:

c

Explanation:

e2020

1. What does a negative value mean? Can distance be negative? Explain.

Answers

Answer: A negative value is values and frequency for the data you are analyzing had enough negative values. Sometimes distance can be negative. For example, when you are in the pool, underwater, or standing left from the middle of origin.

Explanation:

Plss help



The above person is in an elevator as it accelerates
upward. What do they feel?
a. Heavier than normal. c. The same weight as
normal.
b. Lighter than normal. d. Scared to be in an elevator
with no door.

Answers

Answer:

b

Explanation:

imagine urself on an elevator dont you feel lighter

Isaac Newton's first law of motion states?

Answers

Answer:

His first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. In other words its  inertia.

Explanation:

Newtons first law of motion states that"A body will continue to its state of rest or motion unless external force acted upon it.

A firefighter of mass 75 kg slides down a pole. The force of friction is 400N. What is the firefighter's acceleration as they slide down the pole?

Answers

Answer:

a = 5.33 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of the forces acting on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

F = force = 400 [N]

m = mass = 75 [kg]

a = F/m

a = 400/75

a = 5.33 [m/s²]

who first calculated the value of G?​

Answers

Answer:

Lord Henry Cavendish

Explanation:

The constant of proportionality in this equation is G - the universal gravitation constant. The value of G was not experimentally determined until nearly a century later (1798) by Lord Henry Cavendish using a torsion balance.

Answer: Lord Henry Cavendish.

A baseball is thrown towards home plate. It takes 3.4 seconds for the ball to reach the catcher's glove from the pitcher's glove and reaches a maximum velocity of 90m/s. What is the ball's acceleration?​

Answers

Answer:

57

Explanation:

Which of the following describes one of Galileo Galilei's contributions to the development of the concept of gravity?
a.He conducted experiments with balls and inclined planes.
b.He theorized that Earth was at the center of the universe.
c.He theorized that planets move around the Sun in an elliptical pattern.
d.He calculated a value that is currently known as the gravitational constant.​

Answers

Answer:

The correct option is;

c. He conducted experiments with balls and inclined planes

Explanation:

The inclined plane experiment conducted by Galileo Galilei was one of his most important experiments.

The experiment consisted of a grooved board with which a small metal ball is rolled down in, so as to analyze the held Aristotelian ideas about motion.

In the experiment, the focus was on acceleration, a concept that the previously held ideas about motion

How is fishpond raising affected by global climate change?

Answers

Answer:

It creates bad air so that’s like air pollution I guess

Explanation:

Climate change is modifying fish distribution and the productivity of marine and freshwater species. ... The effect of sea level rise means that coastal fishing communities are significantly impacted by climate change, while changing rainfall patterns and water use impact on inland freshwater fisheries and aquaculture.

Mechanical weathering does not change a rock's

Answers

Answer:

composition

Explanation:

With mechanical weathering, the composition of the rocks does not change. ... This process can cause the rock to again break down into smaller pieces.

Answer:

composition

Explanation:

A parachute provides an upward force of 400 N. If the person has a mass of 150.0 kg, what does the force due to gravity have to be in order for there to be a constant velocity in the down direction?

A) 1500.0 m/s/s
B) 400 N
C) 10 m/s/s

Answers

Answer:

1,500 N

Explanation:

Given:

Mass = 150 kg

Gravitational acceleration = 10m/s²

Find:

Force

Computation:

Force = mg

Force = 150 x 10

Force = 1,500 N

A man has a weight of 85 kg what is his weight

A. 833 N
B. 85 N
C. 724 N
D. 145 N

Answers

Answer:

A)833N

Explanation:

weight=9.8x85=833N

I hope it helps

A hockey puck with a mass of 0.18 kg is at rest on the horizontal frictionless surface of the rink. A
player applies a horizontal force of 0.5 N to the puck. Find the speed and the traveled distance 5s
later.

Answers

Given :

A hockey puck with a mass of 0.18 kg is at rest on the horizontal frictionless surface of the rink.

A  player applies a horizontal force of 0.5 N to the puck.

To Find :

The speed and the traveled distance 5s  later.

Solution :

Acceleration is :

a = F/m

a = 0.5/0.18 = 2.78 m/s² .

Now, velocity after 5 seconds is given by :

v = 0 + 2.78×5 m/s

v = 13.9 m/s

Also, distance travelled :

[tex]d = \dfrac{v^2-u^2}{2a}\\\\d = \dfrac{13.9^2-0^2}{2\times 2.78}\\\\d = 34.75 \ m[/tex]

Therefore, speed and the traveled distance 5 s later is 13.9 m/s and 34.75 m.

PLEASE HELP , THOSE ARE ALL THE ANSWERS!

Answers

Answer:

I don't understand

Explanation:

Erin runs at a constant speed for some time.

Nikhat’s speed is constantly increasing over time.

Nikhat finishes the race before Erin.

A sled slides down a snow-covered hill at constant speed. If the hillside is 10° above the horizontal, what is the coefficient of kinetic friction between the runners of the sled and the snow?​

Answers

Answer:

The kinetic coefficient of friction between the runners of the sled and the snow is approximately 0.176.

Explanation:

At first we present a free body diagram of the sled as an image attached below. From 1st and 2nd Newton's Laws we know that an object is at equilibrium when it is either at rest or moving at constant velocity. The equations of equilibrium associated with the sled is:

[tex]\Sigma F_{x'} = f-W\cdot \sin \theta = 0[/tex] (1)

[tex]\Sigma F_{y'} = N-W\cdot \cos \theta = 0[/tex] (2)

Where:

[tex]\theta[/tex] - Inclination of the hillside, measured in sexagesimal degrees.

[tex]N[/tex] - Normal force from ground to sled, measured in newtons.

[tex]W[/tex] - Weight of the sled, measured in newtons.

[tex]f[/tex] - Kinetic friction between sled and ground, measured in newtons.

The definitions of kinetic friction and weight are, respectively:

[tex]f=\mu_{k}\cdot N[/tex] (3)

[tex]W = m\cdot g[/tex] (4)

Where:

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.

[tex]m[/tex] - Mass of the sled, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

By applying (3) and (4) in (1) and (2), we have the following system of equations:

[tex]\mu_{k}\cdot N-m\cdot g\cdot \sin \theta = 0[/tex] (1b)

[tex]N -m\cdot g \cdot \cos \theta = 0[/tex] (2b)

And by applying (1b) in (2b), we have the following expression for the kinetic coefficient of friction:

[tex]\mu_{k}\cdot m\cdot g \cdot \cos \theta -m\cdot g \cdot \sin \theta = 0[/tex]

[tex]\mu_{k} = \tan \theta[/tex] (5)

If we know that [tex]\theta = 10^{\circ}[/tex], then the kinetic coefficient of friction between the runners of the sled and the snow is:

[tex]\mu_{k} = \tan 10^{\circ}[/tex]

[tex]\mu_{k}\approx 0.176[/tex]

The kinetic coefficient of friction between the runners of the sled and the snow is approximately 0.176.

Describe an experiment to show that the force pulling an object increase
with the increase in the mass of the object.

Answers

Answer:

"Acceleration due to gravity" whereby Force and Mass are directly proportional

Explanation:

F=ma

Answer:

just use the magnet experience

Explanation:

it shows how force pulling an object increase

with the increase in the mass of the object.

Oysters are filter feeders. They get their food by moving large amounts of water through their bodies and filtering out whatever is in it. They eat plankton, algae, and similar things that they find in the water. They also remove dirt and chemicals that they find in the water.

How do oysters help other things that live in the water with them?
A.
by removing harmful substances from the water
B.
by removing food from the water
C.
by adding air to the water
D.
all of these

Answers

A. Oysters, clams, and other shellfish are efficient filter feeders that help remove excess nitrogen from waters by incorporating it into their shells and tissue as they grow. ... Adult oysters reportedly can filter up to 50 gallons a day, while large quahogs (hard clams) can clean about 24 gallons of water a day

Una esfera de radio 0.4m tiene una masa de 300kg, se desea sumergir en agua para saber si flota o no. En este ejercicio use la densidad del agua en kg/m^3.

Answers

Answer:

La esfera no flotará pero se hundirá cuando se coloque en el agua porque su densidad es mayor que la del agua.

Explanation:

De la pregunta anterior, se obtuvieron los siguientes datos:

Radio (r) de la esfera = 0,4 m

Masa de esfera = 300 Kg

Densidad del agua = 1000 Kg / m³

A continuación, determinaremos el volumen de la esfera. Esto se puede obtener de la siguiente manera:

Radio (r) de la esfera = 0,4 m

Pi (π) = 3,14

Volumen (V) de la esfera =?

V = 4/3 πr³

V = 4/3 × 3,14 × 0,4³

V = 12,56 / 3 × 0,064

V = 0,27 m³

A continuación, determinaremos la densidad de la esfera. Esto se puede obtener como se ilustra a continuación:

Masa de esfera = 300 Kg

Volumen de esfera = 0,27 m³

Densidad de esfera =?

Densidad = masa / volumen

Densidad de la esfera = 300 / 0,27

Densidad de la esfera = 1111,11 Kg / m³

Comparando la densidad del agua y la de la esfera.

Sustancia >>>>>>> Densidad

Agua >>>>>>>>>>> 1000 Kg / m³

Esfera >>>>>>>>>> 1111,11 Kg / m³

De la ilustración anterior, podemos ver que la densidad de la esfera es mayor que la del agua.

Por lo tanto, la esfera no flotará sino que se hundirá cuando se coloque en el agua porque su densidad es mayor que la del agua.

Why do we wear rubber soled sneakers when we run? (PHYSICS)

Answers

Answer:

Rubber soled sneakers make it harder to slip while running

Explanation:

Using your Texting and Driving Spreadsheet: Velocity of the Car: 10 m/s Time of distraction: 8.0 sec Time of reaction: 0.5 sec Velocity after braking: 0.0 m/s Deceleration due to braking: -8.0 m/s/s Warm Up If roads were icy: 1. What would you change in the inputs above and why? ____________ Now, what is: 2. Distance while distracted:_______ m 3. Distance while reacting: _______ m 4. Time while braking: _______ sec 5. Distance while braking: _______ m 6. Total distance: _______ m

Answers

Answer:

1. I would like to change the time of distraction. Because 8 s is a long time to be distracted while driving on the road. Its not safe for the driver and the other people on road if the driver is distracted even for a second.

2. s₁ = 80 m

3. s₂ = 5 m

4. t = 1.25 s

5. s₃ = 7.5 m

6. s = 92.5 m    

Explanation:

1.

I would like to change the time of distraction. Because 8 s is a long time to be distracted while driving on the road. Its not safe for the driver and the other people on road if the driver is distracted even for a second.

2.

Distance Covered While Distracted = s₁ = (speed of car)(distraction time)

s₁ = (10 m/s)(8 s)

s₁ = 80 m

3.

Distance Covered While Reacting = s₂ = (speed of car)(reaction time)

s₂ = (10 m/s)(0.5 s)

s₂ = 5 m

4.

Using 1st equation of motion braking motion:

Vf = Vi + at

where,

Vf = Final Speed = 0 m/s

Vi = Initial Speed = 10 m/s

a = acceleration = - 8m/s²

t = ?

Therefore,

0 m/s = 10 m/s + (-8m/s²)t

t = (10 m/s)/(8 m/s²)

t = 1.25 s

5.

Now, using second equation of motion:

Distance Covered While Braking = s₃ = Vi t + (1/2)at²

s₃ = (10 m/s)(1.25 s) + (1/2)(-8m/s²)(1.25 s)²

s₃ = 12.5 m - 5 m

s₃ = 7.5 m

6.

Total Distance = s = s₁ + s₂ + s₃

s = 80 m + 5m + 7.5 m

s = 92.5 m

You launch a model rocket that has a mass of 1.5 kg. At a height of 300 m, it is traveling at 125 m/s. What is it's kinetic energy at this point

Answers

Answer:

KE = 11,719 J

Explanation:

KE = ½ mv²

KE = ½ (1.5 kg) (125 m/s)²

KE = 11,719 J

Answer: 11,719 J

Explanation:

just did it on a.p.e.x

What type of modulation is typically used by broadcasting stations to transmit pictures on television screens?

Answers

analog

Television transmitters use one of two different technologies: analog, in which the picture and sound are transmitted by analog signals modulated onto the radio carrier wave, and digital in which the picture and sound are transmitted by digital signals.
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