Write the equation of the line.
y=-2/3x + 4
y =2/3x-4
Y=3/2x-4
y = -3/2x +4

Answer:

x = -4

Step-by-step explanation:

4(3x + 2) = 4(2x + 3) + 4x (distribute the 4's on both sides)

12x + 8 = 8x + 12 + 4x (collect like terms)

12x + 8 = 13x + 12 (subtract 12x on both sides)

8 = x + 12 (subtract 12 on both sides)

-4 = x

Hope this helps ya!

Answer:

the measure of angle M is 73 degrees

Step-by-step explanation:

the sum of complementary angles is 90 degrees. so set up the equation as:

x+16+x-40=90

combine like terms and you get:

2x-24=90

add 24 on both sides and you get:

2x=114

divide by 2 on both sides to isolate x and you get:

x=57

since the equation for angle M is x+16, you substitute 57 for x and you get:

M=57+16

M=73

Answer:

36

Step-by-step explanation:

(r∘q)(2)=

= ((3x)^2(2)

=(3*2)^2

=6^2

=36

9514 1404 393

Answer:

  d.  2

Step-by-step explanation:

The point-slope form of the equation for the line can make use of the given slope and point:

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

  y -3 = 1/4(x +2) . . . . line with slope 1/4 through point (-2, 3)

Filling in the unknown point values, we have ...

  4 -3 = 1/4(r +2)

  4 = r + 2

  2 = r

_____

Alternate solution

The way the question is worded, you seem to be expected to use the slope formula.

  m = (y2 -y1)/(x2 -x1)

For the given points and slope, you have ...

  1/4 = (3 -4)/(-2 -r)

  -2 -r = 4(-1) . . . cross multiply

  2 = r . . . . . . . . add r+4 to both sides

Answer:

[tex]f(x)=-\frac{1}{12}(x-3)^2(x+2)^2(x-4)[/tex]

Step-by-step explanation:

The standard form for a polynomial equation in its factored form is:

[tex]f(x)=a(x-p)(x-q)...[/tex]

Where p and q are the zeros and a is the leading coefficient.

We know that the degree of the polynomial is 5.

We are also given roots at x=3 and x=-2. Hence, our factors are (x-3) and (x+2).

These have a multiplicity of two, so we will square them.

We also know that there is a root at x=4. Hence, the factor is (x-4). This has a multiplicity of 1.

Therefore, our polynomial is now:

[tex]f(x)=a(x-3)^2(x+2)^2(x-4)[/tex]

We know that the y-intercept is 12. Therefore, if we substitute in 0 for x, we should get 12 for y. Here, we are solving for our a. Therefore:

[tex]12=a(0-3)^2(0+2)^2(0-4)[/tex]

Evaluate:

[tex]12=a(9)(4)(-4)[/tex]

Evaluate:

[tex]-144a=12[/tex]

Divide both sides by -144:

[tex]a=-1/12[/tex]

Hence, our entire polynomial is:

[tex]f(x)=-\frac{1}{12}(x-3)^2(x+2)^2(x-4)[/tex]

Answer:

[tex]c=4\\x=1, x=\frac{-25+\sqrt{721}}{12},x=\frac{-25-\sqrt{721}}{12}[/tex]

Step-by-step explanation:

See the picture attached

Answer:

Quadratic

Step-by-step explanation:

The type of quadratic function in the question is in vertex form.

Answer:

Step-by-step explanation:

Which number is greater 0.3 or -0.7?

0.3 is greater because it is a positive number. The other one is a negative.

Answer:

0.3 is greater than -0.7

Step-by-step explanation:

If you look at the number line, -0.7 is on the left side of 0, which means is less than 0.

so 0.3 > -0.7

for negative number the bigger is the number, the less is it’s value.

Answer:

you just add 35 to her bill

What do you mean exactly

Answer:How was the question asked I bet I could figure it out if you told me that

Step-by-step explanation:

[tex] \LARGE{ \underline{\underline{ \tt{Required \: answer:}}}}[/tex]

The above quadrilateral is a square because of the marking shown for the equilaterality of sides.

We have,

We need to find:

Solution:

x is the side of the square and y is the diagonal. Hence,

[tex] \large{ \boxed{ \sf{x = 13}}}[/tex]

And for finding the diagonal which can use the Pythagoras theoram where the leg sides (p and b) are the sides of the triangle. Hence,

➝ y = √13² + 13²

➝ y = √338.

[tex] \large{ \boxed{ \sf{y = 13 \sqrt{2} }}}[/tex]

The correct option is Option (D)

☃️[tex] \large{ \purple{ \bf{FadedElla}}}[/tex]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

[tex]( {x - 5})^{2} + 2 \times ( x - 5 ) \times ( {y}^{3} ) + ({ {y}^{3} })^{2} = \\ [/tex]

[tex]( \: {(x - 5) + {y}^{3} } \: )^{2} [/tex]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

No Solution

Step-by-step explanation:

Answer:

pretty sure its

0.466666

Step-by-step explanation:

Answer:

3.901

Step-by-step explanation:

Add 0.001 to 3.9.

Answer:

3.901

Step-by-step explanation:

Answer:

(4) 29, 33, 37

(6) 53, 59, 65

(5) -16, -20, -24

Step-by-step explanation:

Answer:

569820/4=142455

569820/5=113964

569820/10=56982

569820/6=94970

569820/9=63313.33333333333333 (remainder)

569820/3=189940

569820/2=284910

Step-by-step explanation:

Answer:

24 look it up on Google and your welcome I hope I'm right good day

Answer:

no because if you insert 11 as h you get the inequality 2>11 wich isnt true

Step-by-step explanation:

1) x ≤ 30

2) 5x + 2x ≥ 14

3) xy ≤ 4

4) y - 5 < 20

Step-by-step explanation:

please mark me as brainlest

Answer:

Divide both sides by the numeric factor on the left side, then solve.

Exact Form:

x=−7/2

Decimal Form:

x=−3.5

Mixed Number Form:

x=−3 1/2

Step-by-step explanation:

Answer:

- 3.5

Step-by-step explanation:

hope this helps :)

Answer:

Option (2). 1

Step-by-step explanation:

Coordinates of point A, B, C and D are,

A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).

Quadrilateral ABCD when rotated 90° clockwise about the origin,

Rule for the rotation of the vertices,

(x, y) → (y, -x)

Following the rule of rotation coordinates of the image points,

A(-4, 4) → A'(4, 4)

B(-2, 4) → B'(4, 2)

C(-2, 1) → C'(1, 2)

D(-4, 3) → D'(3, 4)

Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.

Option (2) is the correct option.

Answer:

A

okay? Answer A

Answer:

600?

Step-by-step explanation:

you do 2400÷4 which would be 600 for each hour

Answer:5 h 48 min

Step-by-step explanation:

t/8+t/12=1

=> 3t+2t =24

5t=24

t=24/5

t=5 and 4/5 h

That equal to 5 h and 8/10 h or 5h and 8*6 min

So the answer is 5 h 48 min

Answer:

The answer is (B).

Step-by-step explanation:

A). y = f(x) = 6(x - 2) + 3 ⇔ y = 6x - 12 + 3 ⇔ 6x = y + 9 ⇔ x = [tex]\frac{y+9}{6}[/tex]

g(x) = [tex]\frac{x+9}{6}[/tex] is inverse function of f(x) and ≠ [tex]\frac{x+2}{6}[/tex] - 3

B). y = f(x) = [tex]\frac{5x}{4}[/tex] - 3 ⇔ 4y = 5x - 12 ⇔ x = [tex]\frac{4y+12}{5}[/tex]  

g(x) = [tex]\frac{4(x + 3)}{5}[/tex] is inverse of f(x)