Write an equation to represent the image.

Answer:

[tex]y2 - y1 \div x2 - x1[/tex]

Answer:

T, Q, and R

Step-by-step explanation:

These points are all on the same line, making them collinear.

I hope this helps!!

Answer:

√

4

x

5

√

(

x

−

1

)

2

−

3

2

+

3

y

−

3

Step-by-step explanation:

√

4

x

5

√

(

x

−

1

)

2

−

3

2

+

3

y

−

3

Answer:

it is Ahmed shoevked more your calculations are wrong

Answer:

[tex]i[/tex][tex]\sqrt{30}[/tex]

Step-by-step explanation:

[tex]\sqrt{-30}[/tex]

= [tex]\sqrt{30 * -1}[/tex]      

= [tex]\sqrt{30} * \sqrt{-1}[/tex]   Separate the two numbers into 2 radicals.

= [tex]i\sqrt{30}[/tex]             Simplify, knowing that [tex]i = \sqrt{-1}[/tex].

Answer:

1.   slope = 6,  y-intercept = 11

2.  slope = 1,  y-intercept = 6

Answer:

you are correct

Step-by-step explanation:

6 is the slope and 11 is the y-intercept

1 is the slope and 6 is the y-intercept

Answer:

The answer should be A......

Answer

To multiply integers, simply multiply the unsigned numbers and place the sign on the product by repeating the above rules.

To divide unsigned integers, we divide the unsigned numeric values and put a minus sign on the result.

Answer:

rise/run= -20/5= -4/1=-4 slope

or you sound use the slope formula (y2-y1)/(x2-x1)

(-9-11)/(1+4)

-20/5

-4

Hope this helps

Answer:

1, 2, 10 i think this is correct

Answer:

Step-by-step explanation:

You answer the question by understanding what the problem statement is telling you.

The double number line shows that 2 1/2 bananas make 1 loaf of bread.

The first blank is filled with 1.

__

You notice the number of bananas on the second line of the table is double the number on the first line: 5 = 2 × (2 1/2). That means the number of loaves that can be made is 2 × 1 = 2.

The second blank is filled with 2.

__

You notice the number of loaves on the third line of the table is double the number of loaves you just filled in on the second line. That means the number of bananas required is double the number listed on the second line.

  2 × 5 = 10

The third blank is filled with 10.

Answer:

They paid 247 dollar.

Step-by-step explanation:

They paid 247 dollar

Answer:

Step-by-step explanation:

1 student paid 6.50

25 students paid x

1/25 = 6.50 / x                     Cross multiply

x = 25 * 6.50

x = 162.50  

The total for all 25 came to 162.50 dollars.

Answer:

w^2z^4/y^2

Step-by-step explanation:

Answer:

5 is the answer

please mark as brainlist

thank you

========================================================

Explanation:

Let x and y be two positive whole numbers. They may or may not be equal.

The first bag has the ratio of red to blue as 3:5, which scales up to 3x:5x after multiplying both parts by x. We have 3x red and 5x blue.

The second bag has the ratio 3:2 which scales up to 3y:2y. This bag has 3y red and 2y blue.

We can make a handy table to keep track of all the expressions

[tex]\begin{array}{|c|c|c|}\cline{1-3}\text{ } & \text{Red} & \text{Blue}\\ \cline{1-3}\text{bag 1} & 3x & 5x\\ \cline{1-3}\text{bag 2} & 3y & 2y\\ \cline{1-3}\end{array}[/tex]

Based on that, we can then say:

Effectively, I added down along each column of that table.

Divide the two expressions for R and B to lead to the fraction 11/9, which is directly from the ratio 11:9

So,

(total red)/(total blue) = 11/9

R/B = 11/9

(3x+3y)/(5x+2y) = 11/9

---------------------

Let's cross multiply and then solve for y

(3x+3y)/(5x+2y) = 11/9

9(3x+3y) = 11(5x+2y)

27x+27y = 55x+22y

27y-22y = 55x-27x

5y = 28x

y = 28x/5

y = (28/5)x

y = 5.6x

We'll keep this in mind for later.

---------------------

Now let:

Recall that we had 3x red and 5x blue for the first bag. That means we have 3x+5x = 8x marbles in the first bag. Therefore, F = 8x.

Also, we had 3y red and 2y blue for the second bag.

So we have S = 3y+2y = 5y

Then we can apply further substitution to say

S = 5y

S = 5(5.6x) .... plug in y = 5.6x

S = 28x

---------------------

In short,

for some positive whole number x. We don't have enough info to pin down what x is exactly; however, it doesn't really matter. This is because the x variable will cancel when dividing F over S

F/S = (8x)/(28x) = 8/28 = 2/7

The fraction 2/7 leads directly to the final answer of the ratio 2:7

In other words, the ratio 8x:28x simplifies fully to 2:7 after dividing both parts by 4x.

The ratio between the total marbles of the first bag and the second bag is 2:7.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Example:

2x + 4 = 9 is an equation.

We have,

x marbles in the first bag.

red marbles = 3x

blue marbles = 5x

y marbles in the second bag.

red marbles = 3y

blue marbles = 2y

Now,

Total red marbles in both bags.

3x + 3y = 11 _____(1)

3x = 11 - 3y

x = (11 - 3y) / 3

Total blue marbles in both bags.

5x + 2y = 9 ______(2)

From (1) and (2) we get,

Multiply 2 in (1).

6x + 6y = 22

6y = 22 - 6x _____(3)

Multiply 3 in (2)

15x + 6y = 27 ______(4)

Putting (3) in (4)

15x + 22 - 6x = 27

9x = 27 - 22

9x = 5

x = 5/9

Now,

x = 5/9 in (3)

6y = 22 - 6(5/9)

6y = 22 - 10/3

6y = (66 - 10)/3

y = 56/18

y = 28/9

Now,

First bag.

Red marbles = 3x = 3 x 5/9 = 5/3

Blue marbles = 5x = 5 x 5/9 = 25/9

Total marbles = 5/3 + 25/9 = (15 + 25)/9 = 40/9

Second bag.

Red marbles = 3y = 3 x 28/9 = 28/3

Blue marbles = 2y = 2 x 28/9 = 56/9

Total marbles = 28/3 + 56/9 = (84 + 56)/9 = 140/9

Now,

The ratio between the total marbles of the first bag and the second bag.

= 40 :140

= 4:14

= 2:7

Thus,

The ratio is 2:7.

Learn more about equations here:

https://brainly.com/question/17194269

#SPJ2

Answer:

-8 or 8

Step-by-step explanation:

We are given the absolute equation:

[tex]\displaystyle \large{4|x|=32}[/tex]

First, divide both sides by 4 which leaves [tex]\displaystyle \large{|x|=8}[/tex]

Absolute Value Definition

[tex]\displaystyle \large{|x|=\begin{cases} x \ \ \ (x\geq 0)\\ -x \ \ \ (x<0) \end{cases}}[/tex]

So from |x| = 8, break into two intervals/conditions.

(1) when x ≥ 0

x = 8

(2) when x < 0

-x = 8

x = -8

From (1) and (2), the solution to 4|x| = 32 is 8 or -8

Answer:

wowo

Step-by-step explanation:

I may be wrong, but im pretty sure its C

Answer:

I might be wrong but I think it is B. or A.

Step-by-step explanation:

Answer:

868,412 visitors

Explanation:

434,206 x 2 (double)

From the information given, it can be inferred that the expansion of the equation will be 5a - 9b + 16 - ab.

= 2(- a + 5) – 3 (a + 5b-2)+b (6-a)

We've to expand the functions and this will be:

= -2a + 10 - 3a - 15b + 6 + 6b - ab

Collect like terms

= - 2a - 3a - 15b + 6b + 10 + 6 - ab

= -5a - 9b + 16 - ab

Therefore, the expression is equivalent to 5a - 9b + 16 - ab.

Learn more about equations on:

https://brainly.com/question/13763238

Answer:16

Step-by-step explanation:

144^0.5 = 12

400^0.5 = 20

a^2=b^2+c^2

20^2 = 12^2 +x^2

x^2 = 400-144= 256

x =16

Answer:

16

Step-by-step explanation:

Answer:

768x4%= 30.72

His commission was $30.72

Step-by-step explanation:

Answer:

70

Step-by-step explanation:

Given -

the least common denominator of 10 and 14 is - *70*

Prime factor of 14 are 2 and 7

14 = 2 * 7

Prime factor of 10 are 2 * 5

10 = 2 * 5

Now Multiplying the highest exponent prime factor to calculate the LCM of 14 and 10

LCM (10,14) = 2 * 5 * 7

LCM (10,14) = 70

Answer:

B.) the number of tents the army orders

Step-by-step explanation:

The word problem does not speak of any prices or tent sizes so it cant be A or C

Answer:

its B

Step-by-step explanation:

Answer:

sin α = [tex]\frac{y}{r}[/tex] = [tex]\frac{1}{\sqrt{10} }[/tex]

cos α = [tex]\frac{x}{r}[/tex] = [tex]\frac{3}{\sqrt{10} }[/tex]

tan α = [tex]\frac{y}{x}[/tex] = [tex]\frac{1}{3}[/tex]

cot α = [tex]\frac{x}{y}[/tex] = [tex]\frac{3}{1}[/tex]

sec α = [tex]\frac{r}{x}[/tex] = [tex]\frac{\sqrt{10} }{3}[/tex]

csc α = [tex]\frac{r}{y}[/tex] = [tex]\frac{\sqrt{10} }{1}[/tex]

Step-by-step explanation:

If the point is given on the terminal side of an angle, then:

Calculate the distance between the point given and the origin:

r = [tex]\sqrt{x^2+y^2}[/tex]

Here it is: [tex]\sqrt{3^2+1^2}[/tex] = [tex]\sqrt{9+1}[/tex] = [tex]\sqrt{10}[/tex]

So we have:

x = 3

y = 1

r = [tex]\sqrt{10}[/tex]

Now we can calculate all 6 trig, functions:

sin α = [tex]\frac{y}{r}[/tex] = [tex]\frac{1}{\sqrt{10} }[/tex]

cos α = [tex]\frac{x}{r}[/tex] = [tex]\frac{3}{\sqrt{10} }[/tex]

tan α = [tex]\frac{y}{x}[/tex] = [tex]\frac{1}{3}[/tex]

cot α = [tex]\frac{x}{y}[/tex] = [tex]\frac{3}{1}[/tex]

sec α = [tex]\frac{r}{x}[/tex] = [tex]\frac{\sqrt{10} }{3}[/tex]

csc α = [tex]\frac{r}{y}[/tex] = [tex]\frac{\sqrt{10} }{1}[/tex]

Answer:

but what if it is a virus?

Step-by-step explanation:

Answer:

isnt oit iron pick

Step-by-step explanation:

Answer: I hope this helps! :)

x = -3

Answer: x=-3

Answer:

Step-by-step explanation:

Conclusion:

Therefore, x = -3

Hoped this helped.

[tex]GeniusUser[/tex]

Saved:-

[tex]\\ \sf\Rrightarrow 2\dfrac{1}{4}-\dfrac{3}{8}[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{9}{4}-\dfrac{3}{8}[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{18-3}{8}[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{15}{8}[/tex]

[tex]\\ \sf\Rrightarrow 1\dfrac{7}{8}[/tex]

Answer:

[tex]\textsf{D)} \quad 1 \dfrac{7}{8}[/tex]

Step-by-step explanation:

Subtract the used volume of punch from the starting volume of punch.

Convert the mixed number to an improper fraction:

[tex]\begin{aligned} \implies 2\frac{1}{4}-\frac{3}{8} & = \dfrac{2 \times 4+1}{4}-\dfrac{3}{8}\\\\ & = \dfrac{9}{4}-\dfrac{3}{8}\end{aligned}[/tex]

Make the denominators of both fractions the same by multiplying the numerator and the denominator of 9/4 by 2:

[tex]\implies \dfrac{9 \times 2}{4 \times 2}-\dfrac{3}{8} = \dfrac{18}{8}-\dfrac{3}{8}[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}-\dfrac{b}{c}=\dfrac{a-b}{c}:[/tex]

[tex]\begin{aligned} \implies \dfrac{18}{8}-\dfrac{3}{8} & = \dfrac{18-3}{8}\\\\ & = \dfrac{15}{8}\end{aligned}[/tex]

Convert back into a mixed number:

[tex]\begin{aligned}\implies \dfrac{15}{8} & = \dfrac{8+7}{8}\\\\ & = \dfrac{8}{8}+\dfrac{7}{8}\\\\ & = 1\dfrac{7}{8}\end{aligned}[/tex]