Write an equation for the graph below which represents a logarithmic function f with base 2 or 3 translated and/or reflected. X=3 (7,1) (5,0) (4,-1)

Answer:

The answer is "[tex]\log(x-3)- \log(2)[/tex]"

Step-by-step explanation:

The asymptote is that when the group is 0 within. Let's all assume that log base 2 is: Log(ax-b); a position mostly online also they know. Let's use this (5,0)  and log(5a-b)=0; they get out of it 5a-b=1; now that the results for a and b must be known. So we can say unless the asymptote is x=3, 3a-b=0; then we have the equations system, and with a and b we can solve

[tex]\to b=5a-1 \\\\ \therefore\\\\\to 3a-(5a-1)=0\\\\\to 3a-5a+1=0\\\\\to -2a+1=0\\\\\to -2a=-1\\\\\to a=\frac{1}{2} \ and\ b= \frac{3}{2}[/tex]

[tex]\to \log(\frac{x}{2}-\frac{3}{2})\\\\\to \log(\frac{(x-3)}{2})\\\\\to \log(x-3)- \log(2)[/tex]

Rewrite in simplest terms: -3(-8d – 1) + 2d

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