Answer :
See below ~
Explanation :
Common difference (d) between terms is :31 - 27 = 4Then the recursive formula is :
aₙ = aₙ₋₁ + 4the pair of figures to the right are similar. what is the ratio of the perimeters and the ratio of the areas?
the ratio of perimeters is __
the ratio of the areas is __
Answer:
the ratio of perimeters is 3/5
the ratio of areas is 9/25
Step-by-step explanation:
first we divide the given sides of both figures
perimeter=side 1/side 2
=15/25
p=3/5
to find the ratios of the area
=(side 1/side 2)^2
=(3/5)^2
=9/25
Answer:
the ratio of perimeters is 3/5
the ratio of areas is 9/25
The number of siblings for a group of sixth grade students is shown below:
0, 1, 2, 1, 6, 0, 2, 0, 1, 10
Tim tried to use Cavalieri's principle to show that the two figures have the same volume.
"The base areas are the same. Therefore, corresponding cross-sections have the same area. So the volumes must be the same."
What is the first mistake Tim made?
Answer:
The base areas aren't same
Step-by-step explanation:
The base areas arent same
Answer:
He did not establish that heights are the same.
Three faces of a rectangular prism have areas 32 cm?, 40 cm?, and 20 cm? a) find the surface area of the prism. b) what are possible dimensions of the prism? how do you know? c) sketch and label the prism.
Answer:
Surface Area: 5440
Step-by-step explanation:
Volume: 25600
Surface Area: 5440
Work Volume
V = lwh
V = (32)(40)(20)
V = 25600
Work Surface Area
A = 2(wh + lw + lh)
A = 2( 40(20) + 32(40) + 32(20) )
A = 2(800 + 1280 + 640)
A = 2(2720)
A = 5440
The diagonal : 54.99
explain the steps
for solving the following.
3√3+4√3
Answer:
[tex]7 \sqrt{3} [/tex]
Step-by-step explanation:
Simply combine like radicals:
[tex]3 \sqrt{3} + 4 \sqrt{3} = 7 \sqrt{3} [/tex]
12.4 worksheet mathematics
Answer:
ok. Where is the Question
which number line shows -4 , 1,1 and 2 correctly plotted
Answer:
C
Step-by-step explanation:
The number line in option C contains the points -4, -1, 1 and 2 correctly plotted.
the answer is c :) lol it's the correct one I think
What is the equation for an arithmetic sequence with a first term of 7 and a second term of 3? (5 points)
an = 7 − 4(n − 1)
an = 7 + 4(n − 1)
an = 7 − 3(n − 1)
an = 7 + 3(n − 1)
Answer:
1st option
Step-by-step explanation:
the equation for an arithmetic sequence is
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = 7 and d = a₂ - a₁ = 3 - 7 = - 4 , then
[tex]a_{n}[/tex] = 7 - 4(n - 1)
Answer:
The answer is option A
Step-by-step explanation:
The solution is in the image
Two sets of data are each symmetrical and do not contain outliers. Which measures of center and
variability would be most effective to use when making comparisons between the two data sets?
A.
mean and MAD
B. mean and IQR
C. median and MAD
D. median and IQR
Solution:
As, two set of data are each symmetrical and do not contain outliers.
To find the center , the best way is to find Median of data set.Median of Data set is the mid value of Data that is center of Data.
As, you have to find variability , mean can't measure variability. Mean deviation would have been better option.
So, MAD=Median absolute Deviation , would be better tool to measure variability. Because it is Absolute difference between median and Each value of data set.
So, Option (C) median and MAD, would be best way to compare the two given data set.
NEED HELP ASAP 50 POINTS PLEASE ANSWER CORRECTLY!!!! I have 3 round stock tanks. I want to use the one with the largest volume in my cow- calf pasture. (That's where my cows that are having calves are held.) I want to use the one with the smallest volume in the corrals with the horses. It is easier to fill it when necessary. I don't mind running the hose on it everyday. I want to use the tank with the mid-sized volume in my bull pasture. I have 15 bulls for sale. I have people come by everyday so the number of animals in that pasture will go down. Please match the correct tank with the correct pasture. Mid-Sized tank. Bull Pasture 1. Tank 1: 3' tall, 10' diameter Smallest Tank. Horse/Corral Tank 2. Tank 2: 2' tall, 12' diameter + 3. Tank 3: 1.5' tall, 15' diameter Largest Tank. Cow-Calf Pasture Question 20 (10 points)
Answer:
Largest: 3
Smallest: 2
Mid-Sized: 1
Step-by-step explanation:
A region with a 10-mile radius has a population density of about 1500 people per square mile. Find the number of people who live in the region to the nearest ten thousand.
The number of people who live in the region is about
.
The number of people who live in the region to the nearest ten thousand will be 942000.
What is population density?
The number of the people live in the given volume is known as the population density.
(r)Region radius= 10 miles
Population density= 1500 per square mile
The area of the region is found as;
A=2πR²
A= 2π(10 x 10)
A=2(3.14) (100)
A= 628 square miles
Population density= Population/Area
1500= Population / 628 square miles
Population = 1500 x 628
Population = 942000
Hence,the number of people who live in the region to the nearest ten thousand will be 942000.
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PLEASE HELP!!!!
y = 1.4 (1.02)
a =
b=
r(as a percentage)
Answer:
a = 1.4 then b = (1+0.02) and r = 2%
Find the solutions to x² = 12.
O A. x = +2√3
OB. x=+5√2
X
C. x= +2√5
OD. x = 13√2
Answer:
[tex]x = \pm 2\sqrt3[/tex]
Step-by-step explanation:
Hello!
Let's use the square root property to solve this question
Solve:
[tex]x^2 = 12[/tex][tex]\sqrt{x^2} = \sqrt{12}[/tex][tex]x = \pm\sqrt{12}[/tex][tex]x = \pm \sqrt{4 * 3}[/tex][tex]x = \pm 2\sqrt3[/tex]The answer is option A: x = ±2√3
y=1/2x+1
how do i graph this?
Answer: Heyaa! ~
Graph the line using the slope and y-intercept, or two points.
Slope:
1/2
y-intercept: (0,1)
x ↓ y
0 ↓ 1
2 ↓ 2
Step-by-step explanation:
Hopefully this helps you! ~
Answer:
Use the Desmos graphing calculator. Look up "graphing calculator" and hit the Desmos option, then type in your equation. It works.
Please mark me Brainliest!!!
Which of the following represents the translation of R (-3, 4) along the vector
<7, -6> and then the vector < -1, 3 >?
Pls help lol
By applying concepts of linear algebra, the point P'(x, y) = (-3, 4) represents the translation of P(x, y) = (-3, 4) along the vectors <7, -6> and <-1, 3>.
How to determine the resulting point by applying translations
Translations are a kind of rigid transformation. A transformation is rigid if and only if Euclidean distances are conserved. By linear algebra, an image as a consequence of consecutive translations is described by the following formula:
[tex]P' (x,y) = P(x,y) + \left(\sum\limits_{i=1}^{n}x_{i}, \sum\limits_{i=1}^{n}y_{i}\right)[/tex] (1)
Where:
P(x, y) - Original pointP'(x, y) - Image[tex]\left(\sum\limits_{i=1}^{n}x_{i}, \sum\limits_{i=1}^{n}y_{i}\right)[/tex] - Net translation vectorNow we proceed to determine the image of the given point:
P'(x, y) = (-3, 4) + (7, -6) + (-1, 3)
P'(x, y) = (-3 + 7 - 1, 4 - 6 + 3)
P'(x, y) = (3, 1)
By applying concepts of linear algebra, the point P'(x, y) = (-3, 4) represents the translation of P(x, y) = (-3, 4) along the vectors <7, -6> and <-1, 3>.
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PLEASE HELP WILL GIVE BRAINLEST! What is the amplitude of the function graphed below?
Answer:
[tex]2\pi[/tex]
That's it
23/2 as a mixed number
Answer:
11 1/2.
Step-by-step explanation:
23 / 2 = 11 remainder 1.
So it is 11 1/2.
Two teams, a and b, are about to play a game. previous records show that a has an 80% chance of winning, while b has a 20% of winning. spectators can either choose to buy regular tickets or special tickets. a spectator with a special ticket will receive a refund of $2 if team a wins and a refund of $5 if team b wins. how much extra, minimally, should the special ticket cost to cover the expected value of the refunds offered?
The special ticket cost to cover the expected value of the refunds would be $2.60
How to solve for the minimal extra cost.Probability of A winning = 80%
Probability of B winning = 20%
We have to solve for the rebate of the bet.
80% = 0.8, 20% = 0.2
0.8 x 2 = 1.6
0.2 x 5 = 1
The extra minimal cost of the special ticket would be calculated as: 1 + 1.6
= $2.6
Therefore the answer to the question is $2.6
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What is the volume of a sphere with a diameter of 9.1 m, rounded to the nearest tenth of a cubic meter?
!!100!! POINTS PLEASE HELP!!
Answer:
x = 5
Step-by-step explanation:
The triangles are similar by AA similarity.
They share a common angle (∠A) and have an angle of 90°.
Since they are similar, we can takes the sides in proportion.
[tex]\frac{BC}{DE} = \frac{AB}{BD}[/tex]8/16 = x/10x/10 = 1/2x = 10/2x = 5Answer:
x = 10.
Step-by-step explanation:
Triangles ABC and ADE are similar so their corresponding sides are in the same ratio.
So we have:
8/16 = x / (x + 10)
16x = 8(x + 10)
16x - 8x = 80
8x = 80
x = 10
I need an answer to this:
Answer:
It will decrease cause there will be more deer. Deer eat blackberry bushes
Step-by-step explanation:
Answer:
It will decrease because there will be more deer
Step-by-step explanation:
Because of the lack of wolves, the deer population would increase. Since it would increase the amount of deer there would be less of the deer's food sources.
Walter wants to make 200 candles in the shape of a cone for his new candle business. The mold shown below will be used to make the candles. Each mold will have a height of 6 inches and a diameter of 2 inches. To the nearest cubic inch, what will be the total volume of 200 candles
Answer:
1256 cubic inches
Step-by-step explanation:
Volume of all 200 candles = volume of one mold × 200
Finding the volume of one mold:
We are given that the molds are in the shapes of cones and have a height of 6 inches as well as a diameter of 2 inches.
The volume of a cone can be calculated using the formula
V = πr²(h/3) where r = radius and h = height
Converting the diameter to radius
The volume of a cone formula requires the radius however we are only given the diameter. However we know that the radius is equal to half of the diameter or radius = diameter / 2
So if diameter = 2 then radius = 2 / 2 = 1 so r = 1
Plugging in the given values into the formula
V = πr²(h/3)
==> plug in r = 1 and h = 6 and π = 3.14 approximately
V = (3.14)1²(6/3)
==> simplify exponent
V = 3.14(1)(6/3)
==> divide 6 by 3
V = 3.14(2)
==> multiply 3.14 by 2
V = 6.28
Finding the volume of the 200 candles.
So we have calculated that the volume of one candle is about 6.28in³ and we want to find the volume of 200 of those candles.
To do so we simply multiply the volume of one of those candles by 200
So volume of 200 candles = 200 × 6.28 = 1256 cubic inches
What is the answer please?
Answer:
The figures are not similar. If the purple rectangle were to get a transformation, then it would grow. For it to be
Step-by-step explanation:
If the purple rectangle were to get a transformation, then it would grow. For it to be similar it would be stretched one way to be as long as the green rectangle, but that's not how this works. Therefore, they are not similar.
Hope this helps <3
julie buys a bike for $2700 and sells it a year later, making a 15% profit
How much profit did Julie make?
Answer:
$405.
Step-by-step explanation:
That would be 15% of $2700
= 2700 * 0.15
= $405
Dan had $34 to spend at the fair if the admission to the fair is $10 and the rides cost $1.50 each, what is the greatest number of rides dan can go on. write an inequality that represents dan's situation
Answer:
Equation: 1.50x + 10 [tex]\leq[/tex] 34
Amount of rides Dan can go on: 16 rides
Step-by-step explanation:
We can represent this situation using this equation:
1.50x + 10 [tex]\leq[/tex] 34
The $10 Dan has to pay as admission is the fixed number because it doesn't vary and always remains the same, so no x goes next to 10.
Each ride costs $1.50 so this is the variable number as it changes with how many rides Dan goes on, therefore an x will go next to 1.50 to represent the amount of rides Dan goes on.
Lastly, Dan has $34 to spare, so the amount spent has to be less than or equal 34.
Solve the equation for x to find the greatest amount of rides Dan can go on:
1.50x + 10 [tex]\leq[/tex] 34 Subtract 10 from 34
1.50x [tex]\leq[/tex] 24 Divide 24 by 1.50
x [tex]\leq[/tex] 16
So, Dan has enough money to go on 16 rides or less.
Let's check this answer:
1.50(16) + 10 [tex]\leq[/tex] 34 Multiply 1.50 by 16
24 + 10 [tex]\leq[/tex] 34 Add 24 and 10
34 [tex]\leq[/tex] 34
Hope this helps! Good luck and if you have any questions let me know in the comments!
Evaluate 2(5a – 2) a=3
Please solve
Answer:
26
Step-by-step explanation:
a=3
2(5x3-2)
5x3=15
15-2=13
2x13=26
area of a circle radius 12
Answer: 3.14 x 12^2 = 452.16
When 1,250 superscript three-fourths is written in its simplest radical form, which value remains under the radical?
The number that still remains under the radical when the expression is in its simplest form is 8.
What is a radical?
A radical refers to a root form. In this case, we can write this number as; 1,250^3/4.
If we try to simplify this in line with the laws of indicies, we have; 4√(1250)^3. If we simpify further, we obtain; (125)4√8.
Thus, the number that still remains under the radical when the expression is in its simplest form is 8.
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A radio státlon réports news and weather
every 20 minutes for 4 minutes, if the
radlo is turned on at a random time, what
is the probabllty that the news
and weather report is NOT on?
E 0.2
H 0.6
G 0.4
J 0.8
[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]
[tex] \large\underline{ \boxed{ \sf{✰\:Note }}}[/tex]
➣ Timing of ràdiò station reporting news and weather is every in 20 minutes for 4 minutes➣ Probability :- An event that is likely to occur also A number, between 0 and 1, expressing the precise likelihood of an event happening.➣Denoted by :- P(A)[tex] \rule{70mm}{2.9pt}[/tex]
★ To find ★ ➣ we have to find Probability when news and weather report is not on ➣ we know that Probability[tex]{ \boxed{✠ \: \underline{ \boxed{ \sf{\: P(A) = \frac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: favourable \: outcomes} }}} \: ✠}}[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
✛ Here ✛
➣ Number of favourable outcomes = 4 min➣ Total number of favourable outcomes = 20 min➣ and P(A) = x ★ Now let's solve according to formula ★[tex] \qquad \sf \:➛ \: x = \frac {4 }{20} \\ \qquad \sf \:➛ \: x = \frac { \cancel4 }{ \cancel{20}} \\ \qquad \sf \:➛ \: x = 0.2min[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
★ Hence probabllty that the news and weather report is NOT on P(A)
[tex] \qquad \qquad{ \boxed{✟\: \underline{ \boxed{ \sf{\:0.2min\green ✓ }}} \:✟ }}[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
Hope it helps !
Leon has a piece of cheese shaped like a triangular prism that he needs to wrap in plastic wrap. a triangular prism. the triangular base has a base of 4 inches and height of 3 inches. the height of the prism is 7 inches. what is the minimum amount of plastic wrap that he needs to cover the entire piece of cheese? 42 inches squared 84 inches squared 96 inches squared 108 inches squared
The minimum amount of plastic wrap needed to cover the entire piece of cheese is : 84 squared inches.
What is a triangular prism?A triangular prism is a solid geometrical shape made of three rectangles and two triangles.
Analysis:
base of triangle = 4 inches, height of triangle = 3 inches, length of rectangles = 7 inches
Total surface area of the triangular prism = area of two triangles + plus area of two slant rectangles + area of 1 straight face rectangle.
for the slant rectangle, the width of the rectangle, half the base of the triangle and the height of triangle form right- angled triangle using Pythagoras to solve for the width of the rectangle we have
[tex]l^{2}[/tex] = [tex]2^{2}[/tex] + [tex]3^{2}[/tex]
l = [tex]\sqrt{13}[/tex] = 3.6
Total surface area = 2(1/2bh) + 2(l x b) + L x B
= 2 ( 1/2 x 2 x 3) + 2( 7 x 3.6) + 7 x 4 = 84.4 = 84 squared inches.
in conclusion, the amount of plastic needed is 84 inches squared.
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