Write a C program to prform simple C aritlimetic calculations. The user is to enter a simple expression(integer operaior integer) such as 15+30=45. The program is to exlract the 2 operands and the operator, perform the indicated calculation and display the result. For examole15 + 30 = 45. Operators should includc t, -, * , l, and %'.Operands are prcsitive integers, no sign. Use getchar to input the cxpression. Allow for variable spacing before the first operand and between operators and operands.
Answers
Answer:
Here is the C program:
#include <stdio.h> //to use input output functions
//functions prototype
unsigned int mod(unsigned int a, unsigned int b);
unsigned int mul(unsigned int a, unsigned int b);
unsigned int sub( unsigned int a,unsigned int b);
float divide(unsigned int a,unsigned int b);
unsigned int add( unsigned int a,unsigned int b);
int main() { //start of main method
unsigned int a, b; //declare variables to store the operands
char d; //declare variable to store the operator
printf("Enter an operator: "); //prompts user to enter an operator
scanf("%c",&d); //reads the operator from use
getchar(); //gets a character
while (d!='q') { //keeps iterating until user enters q to quit
printf("Enter 1st operand: "); //prompts user to enter first operand
scanf("%d",&a); //reads first operand from user
getchar(); //reads character
printf("Enter 2nd operand: "); //prompts user to enter second operand
scanf("%d",&b); //reads second operand from user
getchar();
if (d=='%') { //if the character of operator is a mod
printf("%d",a); //prints operand 1
putchar(d); //displays operator
printf("%d",b); //displays operand 2
printf(" = "); //displays =
mod(a,b); } //displays computed modulo of two input operands
if (d=='*') //if the input character is for multiplication operator
{printf("%d",a); //prints operand 1
putchar(d); //displays operator
printf("%d",b); //displays operand 2
printf(" = "); //displays =
mul(a,b); } //displays computed multiplication
if (d=='+') { //if the input character is for addition operator
printf("%d",a); //prints operand 1
putchar(d); //displays operator
printf("%d",b); //displays operand 2
printf(" = "); // displays =
add(a,b); } //displays computed addition
if (d=='/') { //if the input character is for division operator
printf("%d",a); // prints operand 1
putchar(d); //displays operator
printf("%d",b); //displays operand 2
printf(" = "); //displays =
divide(a,b); } //displays computed division
if (d=='-') { //if the input character is for subtraction operator
printf("%d",a); //prints operand 1
putchar(d); //displays operator
printf("%d",b); // displays operand 2
printf(" = "); //displays =
sub(a,b); } //displays computed subtraction
printf("Enter an operator: "); //asks again to enter an operator
scanf("%c",&d); //reads operator from user
getchar(); } } //gets character
unsigned int mod( unsigned int a, unsigned int b){ //function to compute modulo of two integers with no sign
int c = a%b; //computes mod
printf("%d",c); } //displays mod result
unsigned int add(unsigned int a, unsigned int b){ // function to compute addition of two integers
int c = a+b; //computes addition
printf("%d\n",c); } //displays result of addition
unsigned int mul(unsigned int a, unsigned int b){ //function to compute multiplication of two integers
int c = a*b; //multiplies two integers
printf("%d\n",c); } //displays result of multiplication
float divide(unsigned int a, unsigned int b){ //function to compute division of two integers
float c = a/b; //divides two integers and stores result in floating point variable c
printf("%f\n",c); } //displays result of division
unsigned int sub(unsigned int a, unsigned int b){ //function to compute subtraction of two integers
int c = a-b; //subtracts two integers
printf("%d\n",c); } //displays result of subtraction
Explanation:
The program is well explained in the comments mentioned with each line of the program. The program uses while loop that keeps asking user to select an operator and two operands to perform arithmetic calculations. The if conditions are used to check what arithmetic calculation is to be performed based on user choice of operand and calls the relevant function to perform calculation. There are five functions that perform addition, modulo, subtraction, division and multiplication and display the result of computation. The screenshot of output is attached.
Related Questions
On what date was jschlatt originally added to the dreamsmp server, and on which date was his second appearance on the server?
Answers
since this has already been answered, who is your favorite SMP character?
mines Wilbur/ Ghostbur
some people will disagree with me but jshlatt is one of my favorite characters on the dream smp . But my all time favorite characters is ALL of Wilbur's characters
According to Darwin’s theory of evolution, differences between species may be a result of which of the following?
a) The disuse of body structures
b) The transmission of acquired characteristics
c) Natural selection
d) Mutagenic agents
Answers
Answer:
The answer is C Natural selection
Explanation:
Natural selection is the differential survival and reproduction of individuals due to differences in phenotype. It is a key mechanism of evolution, the change in the heritable traits characteristic of a population over generations
According to Darwin’s theory of evolution, differences between species may be a result of Natural selection. Thus the correct option is C.
What is Darwin’s theory of evolution?According to Darwin, all species descended from a single ancestor, species can change through time, and new species can arise from existing ones which makes them interconnected with common traits.
Natural selection of traits in a species that would help the species in its survival is the process that drives diversification, the evolutionary process through which new biological species form.
Natural selection is the evolutionary mechanism stating that with many resources available in nature, creatures with genetically inherited features that promote survival and reproduction will typically produce more offspring than their conspecific competitors.
Therefore, option C is appropriate.
Learn more about Darwin’s theory of evolution, here:
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To use cout statements you must include the __________ file in your program.
Answers
Answer:
To use cout statements, you must include the iostream file in your program.
What does GDF is a measure of a nations?
Answers
Wireless technology is best described as a/an
stationary computing system.
office computing system.
mobile computing system.
inflexible computing system.
Answers
Answer:
mobile computing system
Explanation:
Answer:
mobile computing system... C
Challenge activity 1.3.6:output basics.for activities with output like below,your output's whitespace(newlines or spaces) must match exactly.see this note.write code that outputs the following.end with a newline.This weekend will be nice.
Answers
In python:
print("This weekend will be nice.")
I hope this helps!
Return to the Product Mix worksheet. Benicio wants to provide a visual way to compare the scenarios. Use the Scenario Manager as follows to create a PivotTable that compares the profit per unit in each scenario as follows:
a. Create a Scenario PivotTable report using the profit per unit sold (range B17:F17) as the result cells.
b. Remove the Filter field from the PivotTable.
c. Change the number format of the value fields to Currency with 2 decimal places and the $ symbol.
Answers
Answer:
To create a pivot table, select the columns to pivot and click on the insert option, click on the pivot table option and select the data columns for the pivot, verify the table range, select the location for the pivot and click ok. To format a column, select the columns and click the number option on the home tab, select the currency option and click on the number of decimal places
Explanation:
Microsoft Excel is a great tool for data analysis and visualization. It has several mathematical, engineering, statistical, and graphical tools for working with data.
A pivot-table is an essential tool for describing and comparing data of different types.
The steps to follow in order to produce a Pivot table would be as mentioned below:
Opting the columns for a pivot table. Now, make a click on the insert option. This click is followed by opting for the pivot table and the data columns that are available in it.After this, the verification of the range of the table is made and then, the location for the pivot table has opted. After this, the column is formatted and the number option is selected followed by the currency option, and the quantity of decimal places. A Pivot table allows one to establish a comparison between data of distinct categories(graphic, statistical, mathematical) and elaborate them.Learn more about 'Pivot Table' here:
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Kara's teacher asked her to create a chart with horizontal bars. Which chart or graph should she use?
Bar graph
Column chart
Line graph
Pie chart
Answers
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer to this question is the Bar graph.
Because we use this chart type to visually compare values across a few categories when the charts show duration or when the category text is long.
However, we can present information similarly in the bar graph and in column charts, but if you want to create a chart with the horizontal bar then you must use the Bar graph. In an Excel sheet, you can easily draw a bar graph and can format the bar graph into a 2-d bar and 3-d bar chart.
A column chart is used to compare values across a few categories. You can present values in columns and into vertical bars.
A line graph chart is used to show trends over months, years, and decades, etc.
Pie Chart is used to show a proportion of a whole. You can use the Pie chart when the total of your numbers is 100%.
Answer:
Bar graph option A
Explanation:
I did the test
Who is a software engineer
Answers
Hope this helps !
3.What are the pros and cons of using a linked implementation of a sparse matrix, as opposed to an array-based implementation
Answers
Answer:
speed and storage
Explanation:
The pros and cons of both are mainly in regards to speed and storage. Due to linked lists elements being connected to one another it requires that each previous element be accessed in order to arrive at a specific element. This makes it much slower than an array-based implementation where any element can be quickly accessed easily due to it having a specific location. This brings us to the other aspect which is memory. Since Arrays are saved as a single block, where each element has a specific location this takes much more space in the RAM as opposed to a linked implementation which is stored randomly and as indexes of the array itself.
Array Implementation:
Pros: Much Faster and Easier to target a specific elementCons: Much More Space neededLinked Implementation
Pros: Less overall space neededCons: Much slower speed.How has the rise of mobile development and devices impacted the IT industry, IT professionals, and software development
Answers
Answer:
Throughout the interpretation section elsewhere here, the explanation of the problem is summarized.
Explanation:
The growth of smartphone production and smartphone apps and services, as well as the production of smartphones, has had a positive influence on the IT industry, IT practitioners, as well as the development of the technology. As normal, the primary focus is on smartphone apps instead of just desktop software. As we recognize, with innovative features, phone applications, and smartphones are all made, built, modernized every day, and always incorporated with either the latest technology.This has now resulted in far more jobs and employment for the IT sector, and therefore new clients for service-based businesses. It provided various-skilling the application production industry for IT experts including learning how to work on emerging technology. The demand for software production and software growth is evolving at a greater speed than it's ever been, so the increase of smartphone production and smartphones has had a very beneficial effect on perhaps the IT sector, IT practitioners, and business development.Data Structure in C++
Using namespace std;
In this assignment you will implement a variation of Mergesort known as a bitonic mergesort, recursively.
In a normal mergesort, the input to the merge step is a single array, which is divided into two sections, both sorted ascending. We assume that the first half (0 up to but not including size/2) is the first section and the second half (size/2 up to but not including size) is the second section.
In a bitonic mergesort, we use the same arrangement, except that the second sequence is sorted in descending order: the first half goes up, and then the second half goes down. This means that when we are doing a merge, sometimes we want to merge the results into ascending order, while other times we want to merge into descending order (depending on which "half" of the final array the result will end up in). So we add another parameter, to describe the direction the output should be sorted into:
void merge(int* input, int size, int* output, bool output_asc);
If output_asc == true then after the merge output should contain size elements, sorted in ascending order. If output_asc == false, output should contain the elements sorted in descending order.
The other thing we glossed over in class was the allocation of the temporary space needed by the algorithm. It’s quite wasteful to allocate it in each recursive call: it would be better to allocate all the necessary space up front, and then just pass a pointer to it. In order to do this, we’ll write the recursive mergesort function in a helper function which will preallocate the space needed for the results:
int* mergesort(int* input, int size) {
int* output = new int[size];
mergesort(input, size, output, true);
return output;
}
void mergesort(int *input, int size, int* output, bool output_asc) {
// Your implementation here
}
The parameter output_asc serves the same purpose here as for merge: it tells the function that we want the output to be sorted ascending.
Interface
You must implement the functions
void merge(int* input, int size, int* output, bool output_asc);
int* mergesort(int* input, int size);
void mergesort(int *input, int size, int* output, bool output_asc);
Download a template .cpp file containing these definitions. This file is also available on the server in /usr/local/class/src.
merge must run in O(n) time with n= size. mergesort (both versions) must run in O(nlogn) time, and must use O(n) space. If you allocate any space other than the output array, you should free it before your function returns.
The test runner will test each function separately, and then in combination. It checks the result of sorting to make sure that it’s actually sorted, and then nothing is missing or added from the original (unsorted) sequence.
Answers
The code .cpp is available bellow
#include<iostream>
using namespace std;
//declaring variables
void merge(int* ip, int sz, int* opt, bool opt_asc); //merging
int* mergesort(int* ip, int sz);
void mergesort(int *ip, int sz, int* opt, bool opt_asc);
void merge(int* ip, int sz, int* opt, bool opt_asc)
{
int s1 = 0;
int mid_sz = sz / 2;
int s2 = mid_sz;
int e2 = sz;
int s3 = 0;
int end3 = sz;
int i, j;
if (opt_asc==true)
{
i = s1;
j = e2 - 1;
while (i < mid_sz && j >= s2)
{
if (*(ip + i) > *(ip + j))
{
*(opt + s3) = *(ip + j);
s3++;
j--;
}
else if (*(ip + i) <= *(ip + j))
{
*(opt + s3) = *(ip + i);
s3++;
i++;
}
}
if (i != mid_sz)
{
while (i < mid_sz)
{
*(opt + s3) = *(ip + i);
s3++;
i++;
}
}
if (j >= s2)
{
while (j >= s2)
{
*(opt + s3) = *(ip + j);
s3++;
j--;
}
}
}
else
{
i = mid_sz - 1;
j = s2;
while (i >= s1 && j <e2)
{
if (*(ip + i) > *(ip + j))
{
*(opt + s3) = *(ip + i);
s3++;
i--;
}
else if (*(ip + i) <= *(ip + j))
{
*(opt + s3) = *(ip + j);
s3++;
j++;
}
}
if (i >= s1)
{
while (i >= s1)
{
*(opt + s3) = *(ip + i);
s3++;
i--;
}
}
if (j != e2)
{
while (j < e2)
{
*(opt + s3) = *(ip + j);
s3++;
j++;
}
}
}
for (i = 0; i < sz; i++)
*(ip + i) = *(opt + i);
}
int* mergesort(int* ip, int sz)
{
int* opt = new int[sz];
mergesort(ip, sz, opt, true);
return opt;
}
void mergesort(int *ip, int sz, int* opt, bool opt_asc)
{
if (sz > 1)
{
int q = sz / 2;
mergesort(ip, sz / 2, opt, true);
mergesort(ip + sz / 2, sz - sz / 2, opt + sz / 2, false);
merge(ip, sz, opt, opt_asc);
}
}
int main()
{
int arr1[12] = { 5, 6, 9, 8,25,36, 3, 2, 5, 16, 87, 12 };
int arr2[14] = { 2, 3, 4, 5, 1, 20,15,30, 2, 3, 4, 6, 9,12 };
int arr3[10] = { 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 };
int *opt;
cout << "Arays after sorting:\n";
cout << "Array 1 : ";
opt = mergesort(arr1, 12);
for (int i = 0; i < 12; i++)
cout << opt[i] << " ";
cout << endl;
cout << "Array 2 : ";
opt = mergesort(arr2, 14);
for (int i = 0; i < 14; i++)
cout << opt[i] << " ";
cout << endl;
cout << "Array 3 : ";
opt = mergesort(arr3, 10);
for (int i = 0; i < 10; i++)
cout << opt[i] << " ";
cout << endl;
return 0;
}
Please help me. Anyone who gives ridiculous answers for points will be reported.
Answers
Answer:
Well, First of all, use Linear
Explanation:
My sis always tries to explain it to me even though I know already, I can get her to give you so much explanations XD
I have the Longest explanation possible but it won't let me say it after 20 min of writing
7. While an adjacency matrix is typically easier to code than an adjacency list, it is not always a better solution. Explain when an adjacency list is a clear winner in the efficiency of your algorithm
Answers
Answer:
The answer is below
Explanation:
Adjacency list is a technique in a computer science that is used for representing graph. It deals with a gathering of unorganized lists utilized to illustrate a limited graph. In this method, each list depicts the group of data of a peak in the graph
Adjacency List are most preferred to Adjacency Matrix in some cases which are:
1. When the graph to is required to be sparsely.
2. For iterability, Adjacent List is more preferable
What is the process to add images to your library panel in Adobe Animate CC?
Answer choices
Choose file>import>import library
Choose file>open>insert image
Choose file>export>export file
Choose file> New> file
Answers
Answer:
Choose file>import>import library
Explanation:
because it is the process to add images to your library
How can you create an illusion of spatial depth in a two-dimensional design?
Answers
Answer:
Using three or more vanishing points within a work to create the illusion of space on a two-dimensional surface.
Explanation:
Jason works as a financial investment advisor. He collects financial data from clients, processes the data online to calculate the risks associated with future investment decisions, and offers his clients real-time information immediately. Which type of data processing is Jason following in the transaction processing system?
A.
online decision support system
B.
online transaction processing
C.
online office support processing
D.
online batch processing
E.
online executive processing
Answers
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer to this question is online decision support system. Because the decision support systems process the data, evaluate and predict the decision, and helps the decision-makers, and offer real time information immediately in making the decision in an organization. So the correct answer to this question is the decision supports system.
Why other options are not correct
Because the transaction processing system can only process the transaction and have not the capability to make the decision for the future. Office support processing system support office work, while the batch processing system process the task into the batch without user involvement. however, online executive processing does not make decisions and offer timely information to decision-makers in an organization.
A CPU with a quad-core microprocessor runs _____ times as fast as a computer with a single-core processor.
two
three
four
eight
Answers
Answer:
four
Explanation:
quad means four so it runs four times faster
In Python
Write the special method __str__() for CarRecord.
Sample output with input: 2009 'ABC321'
Year: 2009, VIN: ABC321
Answers
Answer:
def __str__(self):
return ('Year: %d, VIN: %s' %(self.year_made, self.car_vin))
Explanation:
Here you go! This should do it.
The program gives an implementation of the car record class which displays the model year and registration number of a car. The program written in python 3 goes thus :
class CarRecord :
#initialize a class named carRecord
def __init__(self):
#define the init method of the class
self.year_made = 0
#year car was made is initialized to 0 (integer)
self.car_vin = ' '
#vehicle registration is an empty string
def __str__(self):
#define an str method
return f"Year:{self.year_made}, VIN:{self.car_vin}"
#returns formatted display of the year and VIN number
my_car = CarRecord()
#creates an instance of the carRecord class
my_car.year_made = int(input())
#prompts user for the model year of the car
my_car.car_vin = input()
#prompts user for the model Vin number
print(my_car)
# display the details
A sample run of the program is given
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A have a string, called "joshs_diary", that is huge (there was a lot of drama in middle school). But I don't want every one to know that this string is my diary. However, I also don't want to make copies of it (because my computer doesn't have enough memory). Which of the following lines will let me access this string via a new name, but without making any copies?
a. std::string book = joshs_diary;
b. std::string & book = joshs_diary; const
c. std::string * book = &joshs_diary;
d. std::string book(joshs_diary);
e. const std::string & book = joshs_diary;
f. const std::string * const book = &joshs_diary;
g. std::string * book = &joshs_diary;
Answers
Answer:
C and G
Explanation:
In C language, the asterisks, ' * ', and the ampersand, ' & ', are used to create pointers and references to pointers respectively. The asterisks are used with unique identifiers to declare a pointer to a variable location in memory, while the ampersand is always placed before a variable name as an r_value to the pointer declared.
Secondary sources
information gathered from primary sources.
Answers
Answer:
The answer is interpret Proof is down below
Explanation:
Here is the proooooooffffffff i made a 90 but this one was right
Secondary sources interpret information gathered from primary sources.
What are Secondary sources of information?A secondary source is known to be made up of discussion that is often based on a primary information source.
Hence, the feature of secondary sources are known to give some kind of interpretation to all the information that has been gathered from other primary sources.
Learn more about Secondary sources from
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If you want Nud3s add me on sc Kermit4lyfe1
Answers
Answer:
que pinga this is a hw website not snap
Explanation:
Need help with coding.
I'm trying to input a list that uses int(input("Element: ")) and it's causing an error. Anything to help with this?
Answers
You could try something likes this.
lst = []
n = int(input("Number of elements: ))
for i in range(0, n):
element = int(input("Element: "))
lst.append(element)
Which type of chart or graph uses vertical bars to compare data?
Column chart
Line graph
Pie chart
Scatter chart
Answers
Answer:
Colunm Chart
Explanation:
Trust me
The Gas-N-Clean Service Station sells gasoline and has a car wash. Fees for the car wash are $1.25 with a gasoline purchase of $10.00 or more and $3.00 otherwise. Three kinds of gasoline are available: regular at $2.89, plus at $3.09, and super at $3.39 per gallon. User Request:
Write a program that prints a statement for a customer. Analysis:
Input consists of number of gallons purchased (R, P, S, or N for no purchase), and car wash desired (Y or N). Gasoline price should be program defined constant. Sample output for these data is
Enter number of gallons and press 9.7
Enter gas type (R, P, S, or N) and press R
Enter Y or N for car wash and press Y
**************************************
* *
* *
* Gas-N-Clean Service Station *
* *
* March 2, 2004 *
* * ************************************** Amount Gasoline purchases 9.7 Gallons Price pre gallons $ 2.89 Total gasoline cost $ 28.03 Car wash cost $ 1.25 Total due $ 29.28 Thank you for stopping Pleas come again Remember to buckle up and drive safely
Answers
Answer:
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
//print the header
System.out.println("**************************************");
System.out.println("* *");
System.out.println("* *");
System.out.println("* Gas-N-Clean Service Station *");
System.out.println("* *");
System.out.println("* March 2, 2004 *");
System.out.println("* *");
System.out.println("**************************************");
//set the constant values for gasoline
final double REGULAR_GASOLINE = 2.89;
final double PLUS_GASOLINE = 3.09;
final double SUPER_GASOLINE = 3.39;
// initialize the variables as 0
double gasolinePrice = 0, gasolineCost = 0, carWashCost = 0, totalCost = 0;
Scanner input = new Scanner(System.in);
//ask the user to enter the gallons, gas type and car wash choice
System.out.print("Enter number of gallons ");
double gasolinePurchase = input.nextDouble();
System.out.print("Enter gas type (R, P, S, or N) ");
char gasType = input.next().charAt(0);
System.out.print("Enter Y or N for car wash ");
char carWashChoice = input.next().charAt(0);
//check the gas type. Depending on the choice set the gasolinePrice from the corresponding constant value
if(gasType == 'R')
gasolinePrice = REGULAR_GASOLINE;
else if(gasType == 'P')
gasolinePrice = PLUS_GASOLINE;
else if(gasType == 'S')
gasolinePrice = SUPER_GASOLINE;
//calculate the gasolineCost
gasolineCost = gasolinePurchase * gasolinePrice;
//check the carWashChoice. If it is yes and gasolineCost is greater than 10, set the carWashCost as 1.25. Otherwise, set the carWashCost as 3.00
if(carWashChoice == 'Y'){
if(gasolineCost >= 10)
carWashCost = 1.25;
else
carWashCost = 3.00;
}
//calculate the total cost, add gasolineCost and carWashCost
totalCost = gasolineCost + carWashCost;
//print the values in required format
System.out.println("Amount Gasoline purchases " + gasolinePurchase);
System.out.println("Gallons Price per gallons $ " + gasolinePrice);
System.out.printf("Total gasoline cost $ %.2f\n", gasolineCost);
System.out.println("Car wash cost $ " + carWashCost);
System.out.printf("Total due $ %.2f\n", totalCost);
System.out.println("Thank you for stopping\nPlease come again \nRemember to buckle up and drive safely");
}
}
Explanation:
*The code is in Java.
Please see the comments in the code for explanation
Plz answer me will mark as brainliest
Answers
IT professionals have a responsibility to educate employees about the risks of hot spots. Which of the following are risks associated with hot spots? Check all of the boxes that apply.
third-party viewing
unsecured public network
potential for computer hackers
unauthorized use
Answers
Answer:
All of them
Explanation:
got it right on edge 2020
Answer:
All of the above
Explanation:
just do it
def build_dictionary(string):
d = dict()
for x in string:
if not d.get(x):
d[x] = 1
else:
d[x] += 1
return d
Part 2:
Create a function named build_word_counter that has the same signature as build_dictionary. This function also returns a dictionary, however, it normalizes each word such that the case of the word is ignored (i.e. case insensitive). So the words LIKE, Like, like should be considered the same word (much like a regular dictionary would). You must use the same function add_item again (so don't make any modifications to it) Normalize words by using the lower case version of the word.
Part 3:
Create a function named build_letter_distribution that has the same signature as build_dictionary. This function returns a dictionary; however, each key will be a letter and the value will be the count that represents how many times that letter was found. Essentially you will have a letter distribution over a sentence (which is a list of words). The letters should be case insensitive.
Answers
Answer:
Follows are the code to this question:
def build_word_counter(string):#defining a method build_word_counter that accepts string as a parameter
d = dict()#defining d variable as a dictionary
for x in string:#defining for loop that use string
x = x.lower()#Use lower method
if not d.get(x):#defining if block that holds value in d variable
d[x] = 1#use dictionary to hold value in 1
else:#defining else block
d[x] += 1#use dictionary to increment value by 1
return d#return dictionary
print(build_word_counter(["Like","like","LIKE"]))#use print method to call method
def build_letter_distribution(string):#defining a method build_letter_distribution that accepts string variable
d = dict()#defining d variable as a dictionary
for i in string:#defining for loop to count string value
for j in i:#defining for loop to hold string as number
if not d.get(j):#defining if block that doesn't get value in dictionary
d[j] = 1#hold value in dictionary
else:#defining else block
d[j] += 1#use dictionary to increment the dictionary value
return d#return dictionary
print(build_letter_distribution(["Like","test","abcdEFG"]))#use print method to return its value
Output:
please find the attached file.
Explanation:
In the first program a method, "build_word_counter" is defined that accepts a string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the for loop to hold string value and convert all value into lower case.
In the next step, a conditional statement is used that holds value in the dictionary and count its word value.
In the second program a method, "build_letter_distribution" is defined that holds string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the two for loop and in if the block, it holds value in the dictionary and returns its value, and use print method to print its return its value.
Your job is to write a basic blurring algorithm for a video driver. The algorithm will do the following: it will go through all pixels on the screen and for each pixel, compute the average intensity value (in red, green and blue separately) of the pixel and its 8 neighbors. (At the edges of the screen, there are fewer neighbors for each pixel.) Let's say the number of pixels on the screen is n. Then what is the order of the number of arithmetic operations (additions and divisions) required?
a. The number is order of n 4 .
b. The number is order of n2.
c. The number is order of n
d. The number is order of n3.
Answers
What are two examples of items in Outlook?
a task and a calendar entry
an e-mail message and an e-mail address
an e-mail address and a button
a button and a tool bar
Answers
Answer:
a task and a calendar entry
Explanation:
ITS RIGHT
Answer:
its A) a task and a calendar entry
Explanation:
correct on e2020