Within which of Linnaeus's groupings are organisms most closely related to one another?
A) species
B) genus
C) phylum
D) kingdom

Answer:

The 3rd Law

Explanation:

The rockets burns fuel, pushing down onto the ground which then creates equal force pushing it up.

Answer:

the answer is newtons 3rd law of motion (number 3)

Explanation:

.

Answer:

1.86% Na₂CO₃

Explanation:

The additional volume that is required to reach endpoint with methyl orange indicator is due the presence of carbonate (Calculated as sodium carbonate). The reaction is:

Na₂CO₃ + 2HCl → H₂O + CO₂ + 2NaCl

Thus, we need to obtain moles of HCl and, using the reaction, solve for moles of sodium carbonate, its mass and percentage using molar mass of Na₂CO₃: 106g/mol.

Moles HCl:

0.700mL = 0.700x10⁻³L * (0.100mol / L) = 7.00x10⁻⁵moles HCl

Moles Na₂CO₃:

7.00x10⁻⁵moles HCl * (1mol Na₂CO₃ / 2 mol HCl) = 3.5x10⁻⁵ moles Na₂CO₃

Mass:

3.5x10⁻⁵ moles Na₂CO₃ * (106g / mol) = 0.00371g Na₂CO₃

Percentage:

0.00371g Na₂CO₃ / 0.200g * 100 =

Answer:

subatomic particles are actually small than atoms

Yes, particles such as protons, neutrons, and electrons that make up the atom are smaller than atoms.

Answer:

It would be B

Explanation:

Explanation:

using Boyles law: which shows the relationship between pressure and volume, when temperature Is kept constant

P1V1 = P2V2

2 x 7.2 = 0.5 x V2

14.4 = 0.5 x V2

V2 = 14.4/0.5 = 28.8 L

Hence the new size of the balloon in litres is 28.8

Missing options

a. There are no sets of orbitals of equal energy

b. Two electrons will occupy the same orbital rather than separate orbitals

c. Two electrons will occupy different orbitals and have opposing spins.

d. Two electrons will occupy different orbitals and have like spins

Answer:

d. Two electrons will occupy different orbitals and have like spins

Explanation:

When the orbitals are degenerate ( equal energy)  pairing does not start until each orbital in a particular subshell gets one electron each. After that pairing start. This is the basis of Hund's rule of maximum multiplicity.

When the electrons have occupied different orbitals in the same subshell their spin remains same, because opposite spin electrons exist in the same orbitals. and this pattern continues in the second, so the electron in the second orbital will resemble to that of the first orbital electron

Answer:

0.65mole of CO₂

Explanation:

Given parameters:

Volume of CO₂ = 14.6L

Unknown:

Number of moles of CO₂ = ?

Solution:

To solve this problem, we must understand that a mole of a gas occupies a volume of 22.4L at STP;

           1 mole of gas occupies  22.4L of volume at STP;

           y mole of CO₂ will occupy 14.6L of volume at STP

                    22.4y  = 14.6

                          y = [tex]\frac{14.6}{22.4}[/tex]  = 0.65mole of CO₂

Hydrogen atoms are in a molecule of table sugar (C₁₂H₂₂O₁₁) is 22

An atom is a particle of matter that uniquely defines a chemical element and in the table sugar molecule the formula is C₁₂H₂₂O₁₁ then the hydrogen atoms are present in the molecule is 22 and it is used for the adding sweetness to your coffee and baking and used as the food manufacture in various food and drink products due to its unique properties that add to the appearance

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Answer:

Increases

Explanation:

As ice melts into liquid water, the kinetic energy of the particles increases.

This is because to melt ices, heat energy is supplied.

According to the placement of elements in the periodic table and the atomic structure, protons from atom on right will attract electrons from atom on left.

Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.

It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.

Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.

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Answer: atomic mass of cl = 35.5 amu.

molar mass of ccl4 = (12) +4 (35.5)

= 12 + 142

= 154 amu.

mass of ccl4 = 385 g

no. of moles present = 385 / 154 = 2.5 mole

so, 2.5 mole of ccl4 is present in 385 grams .

Explanation:

In chemistry, the formula weight is a quantity computed by multiplying the atomic weight (in atomic mass units) of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

Using the chemical formula of the compound and the periodic table of elements, we can add up the atomic weights and calculate molecular weight of the substance.

If the formula used in calculating molar mass is the molecular formula, the formula weight computed is the molecular weight. The percentage by weight of any atom or group of atoms in a compound can be computed by dividing the total weight of the atom (or group of atoms) in the formula by the formula weight and multiplying by 100.

The atomic weights used on this site come from NIST, the National Institute of Standards and Technology. We use the most common isotopes. This is how to calculate molar mass (average molecular weight), which is based on isotropically weighted averages. This is not the same as molecular mass, which is the mass of a single molecule of well-defined isotopes. For bulk stoichiometric calculations, we are usually determining molar mass, which may also be called standard atomic weight or average atomic mass.

A common request on this site is to convert grams to moles. To complete this calculation, you have to know what substance you are trying to convert. The reason is that the molar mass of the substance affects the conversion. This site explains how to find molar mass.

Formula weights are especially useful in determining the relative weights of reagents and products in a chemical reaction. These relative weights computed from the chemical equation are sometimes called equation weights.

Finding molar mass starts with units of grams per mole (g/mol). When calculating molecular weight of a chemical compound, it tells us how many grams are in one mole of that substance. The formula weight is simply the weight in atomic mass

Answer:

2.33g of NaHCO3

Explanation:

The balanced equation of the reaction is;

2NaHCO3  + 2HA --> 2CO2  +  2H2O + 2NaA

From the reaction above;

2 mol of NaHCO3 produces 2 mol of CO2

using mass = number of moles * molar mass

Mass = 2 * 84  = 164g of NaHCO3

Mass of CO2 = 2 * 44 = 88g of CO2

This means 164g of NaHCO3 produced 88g of CO2

How many grams of NaHCO3 would then produce 1.25g of CO2?

164 = 88

x = 1.25

upon solving for x;

x = 2.33g

The reaction of sodium bicarbonate with  acid produces equivalent moles of carbon dioxide. The mass of sodium bicarbonate in the given reaction is 2.352 grams.

The stoichiometric law is used for the determination of the moles of each product or reactant, from the stoichiometric coefficient of the balanced chemical equation.

The balanced chemical equation for the reaction of sodium bicarbonate with HA acid is :

[tex]\rm 2\;NaHCO_2\;+\;2\;HA\;\rightarrow\;2\;CO_2\;+\;2\;H_2O\;+\;2\;NaA[/tex]

From the stoichiometric law, 2 moles of carbon dioxide is produced from 2 moles of sodium bicarbonate.

The moles of carbon dioxide in 1.25 grams is:

[tex]\rm Moles=\dfrac{mass}{molar\;mass}\\\\ Moles\;CO_2=\dfrac{1.25\;g}{44\;g/mol} \\\\Moles\;CO_2=0.028\;mol[/tex]

From the stoichiometric law, the moles of sodium bicarbonate required is:

[tex]\rm 2\;mol\;CO_2=2\;mol\;NaHCO_3\\\\0.028\;mol\;CO_2=\dfrac{2\;mol}{2\;mol}\;\times\;0.028\;mol\;NaHCO_3\\\\ 0.028\;mol\;CO_2=0.028\;mol\;NaHCO_3[/tex]

The mass of sodium bicarbonate required is given as:

[tex]\rm Mass=Moles\;\times\;Molar\;mass\\Mass\;NaHCO_3=0.028\;mol\;\times\;84\;g/mol\\Mass\;NaHCO_3=2.352\;g[/tex]

The mass of sodium bicarbonate in the reaction is 2.352 grams.

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Answer:

use socratic it helps me get A+

Answer:

Yes

Explanation:

Answer:

0.00500M of Na₂C₂O₄

Explanation:

When are dissolved in 150 mL of 1.0 M H2SO4.

We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:

0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄

In 0.150L:

7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =

The concentration of the solution is 0.005 M.

From the information available in the question;

We know that;

Mass of  Na2C2O4 = 0.1005 g

Volume of solution = 150 ml

To obtain the number of moles of Na2C2O4;

Number of moles = mass/molar mass

Molar mass of Na2C2O4  = 134 g/mol

Number of moles =  0.1005 g /134 g/mol = 0.00075 moles

Concentration = number of moles/volume

Volume of solution = 150ml or 0.15 L

Concentration =  0.00075 moles/0.15 L

= 0.005 M

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Missing parts

An acidic solution of sodium oxalate (Na2C2O4) was prepared by dissolving ~0.100 g of Na2C2O4 in 150 mL of 1.0 M H2SO4 in a 250 mL Erlenmeyer flask. Calculate the concentration of the resulting sodium oxalate solution if 0.1005 g of Na2C2O4 was used.

Answer:

c

Explanation:

because it is c ok ????????????

Answer:

C.

Explanation:

The same amount of force reacts to you

Answer:

[tex]\Delta U=-94.0J[/tex]

Explanation:

Hello!

In this case, since the first law of thermodynamics allows us to understand how the energy behaves when heat and work are involved during a process, we can mathematically define it as:

[tex]Q-W=\Delta U[/tex]

Whereas Q is the heat added to the system, W the work done by the system and ΔU the change in the internal energy, we can notice that since 97.0 J of work are done on the system it would be negative and the given off heat is also heat due to the used convention; therefore the change in its internal energy turns out:

[tex]-191.0J-(-97.0J)=\Delta U\\\\\Delta U=-94.0J[/tex]

Best regards!

Answer:

[tex]m_{CaCO_3}=0.465g[/tex]

Explanation:

Hello!

In this case, since the reaction between two aqueous solutions may turn out in the production of a solid precipitate, for potassium carbonate and calcium chloride, calcium carbonate is precipitated out as shown below:

[tex]CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)[/tex]

Now, since the two reactants are in a 1:1 mole ratio, we infer they react in the same proportion, thus we compute the reacting moles, considering the used volumes of those molar solutions:

[tex]n_{K_2CO_3}=0.0152L*0.306mol/L=0.00465mol\\\\n_{CaCl_2}=0.0170*0.295mol/L=0.00502mol[/tex]

Thus, since just 0.00465 mol out of 0.00502 moles of calcium chloride are consumed, the potassium carbonate is the limiting reactant, therefore the mass of yielded calcium carbonate (molar mass = 100.09 g/mol) is:

[tex]m_{CaCO_3}=0.00465molK_2CO_3*\frac{1molCaCO_3}{1molK_2CO_3} *\frac{100.09gCaCO_3}{1molCaCO_3}\\\\m_{CaCO_3}=0.465g[/tex]

Best regards!

Answer:

a. [Ar]4s13d10.

Explanation:

Hello!

In this case, since the electron configuration allows us to arrange the electrons moving around the atom of an element and equal the atomic number, we can write the electron configuration of copper as shown below:

[tex]Cu^{29}=1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^9[/tex]

However, in terms of the argon's electron configuration, which is:

[tex]Ar^{18}=1s^2,2s^2,2p^6,3s^2,3p^6[/tex]

We infer that the electron configuration of copper in terms of that of argon's is:

[tex]Cu^{29}=[Ar]4s^2,3d^9[/tex]

Therefore, the answer is a. [Ar]4s13d10 because the 4s² can be written as 4s¹ and therefore the 3d⁹ is changed to 3d¹⁰.

Best regards!

Answer: 6.6855 × 1024 Molecules.

Explanation:

Answer:

b

Explanation:

Answer:

Water.

Explanation:

Water is the most important agent of chemical weathering. Two other important agents of chemical weathering are carbon dioxide and oxygen.

Answer:t pans

Explanation:it’s the cool thing

Answer:

This dilution problem uses the equation

M

a

V

a

=

M

b

V

b

M

a

= 6.77M - the initial molarity (concentration)

V

a

= 15.00 mL - the initial volume

M

b

= 1.50 M - the desired molarity (concentration)

V

b

= (15.00 + x mL) - the volume of the desired solution

(6.77 M) (15.00 mL) = (1.50 M)(15.00 mL + x )

101.55 M mL= 22.5 M mL + 1.50x M

101.55 M mL - 22.5 M mL = 1.50x M

79.05 M mL = 1.50 M

79.05 M mL / 1.50 M = x

52.7 mL = x

59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M.

Explanation:

Answer:

3. d. Mg 4. a. Photoelectric effect 10. c. 2 11. b. 3s^2 3p^5

Explanation:

Answer:

B

Explanation:

Answer: B the biosphere it is a animal and a living thing

Explanation:

Answer:

I believe the answer is false. Acceleration increases when force is increased.

Explanation: