Answers
A. The ball's (vertical) velocity [tex]v[/tex] at time [tex]t[/tex] is
[tex]v(t) = 30\dfrac{\rm m}{\rm s} - gt[/tex]
so that after 4 seconds, the ball's speed is
[tex]|v(4\,\mathrm s)| = \left|30\dfrac{\rm m}{\rm s} - \left(10\dfrac{\rm m}{\mathrm s^2}\right) (4\,\mathrm s)\right| = \boxed{10\frac{\rm m}{\rm s}}[/tex]
(The velocity is -10 m/s, so the ball is falling back down at this point.)
B. At maximum height, the ball has zero velocity, so it takes
[tex]30\dfrac{\rm m}{\rm s} - gt = 0 \implies t = \dfrac{30\frac{\rm m}{\rm s}}g = \boxed{3\,\mathrm s}[/tex]
for the ball to reach this height.
C. The height of the ball [tex]y[/tex] at time [tex]t[/tex] is
[tex]y(t) = \left(30\dfrac{\rm m}{\rm s}\right) t - \dfrac g2 t^2[/tex]
The maximum height is attained by the ball at 3 seconds after it's thrown, so
[tex]y_{\rm max} = \left(30\dfrac{\rm m}{\rm s}\right) (3\,\mathrm s) - \dfrac{10\frac{\rm m}{\mathrm s^2}}2 (3\,\mathrm s)^2 = \boxed{45\,\mathrm m}[/tex]
D. The time it takes for the ball to reach its maximum height is half the time it spends in the air. So the total airtime is [tex]\boxed{6\,\mathrm s}[/tex].
Put another way: When the ball returns to the height from which it was thrown, its final velocity has the same magnitude as its initial velocity but points in the opposite direction. This is to say, after the total time the ball is in the air, it's final velocity will be -30 m/s. Then the total airtime is
[tex]30\dfrac{\rm m}{\rm s} - gt = -30\dfrac{\rm m}{\rm s} \implies t = \dfrac{60\frac{\rm m}{\rm s}}g = \boxed{6\,\mathrm s}[/tex]
Put yet another way: Solve [tex]y(t) = 0[/tex] for [tex]t[/tex]. I don't see a need to elaborate...
Related Questions
Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate .
An employee will display by adhering to professional standards of the workplace and encouraging co-workers to do the same.
Answers
Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.
Who is a leader?A person taking the charge of the organization and leading a team under him is known as a leader.
"The complete question is"Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate _______________. An employee will display _______________ by adhering to professional standards of the workplace and encouraging co-workers to do the same."
Options:
First Blank: work ethic
First Blank: self-representation
First Blank: diversity awareness
Second Blank: leadership skills
Second Blank: nonverbal skills
Self-representation may be shown through dressing appropriately for diverse settings, speaking politely, and keeping up with personal cleanliness.
By upholding the workplace's ethical norms and encouraging others to do the same, an employee will demonstrate leadership qualities.
Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.
An employee will display leadership skills by adhering to the professional standards of the workplace and encouraging co-workers to do the same.
Hence, self-representation and leadership skills are the correct answer.
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What keeps the Moon from falling directly to Earth?
OA. The Moon is balanced between the gravitational pulls from both
Earth and the Sun.
OB. The Moon's gravitational force balances the gravitational pull from
Earth.
OC. The Moon's rotation about its own axis creates centripetal force
that balances Earth's pull.
OD. The Moon has a large tangential velocity that causes it to "miss"
Earth as it falls toward it.
Answers
The reason why the moon does not fall back to the earth is that the Moon's rotation about its own axis creates centripetal force
that balances Earth's pull.
What is the gravitational force?The gravitational force is the force that keeps the solar system together. All the members of the celestial bodies are held in place by gravity.
Thus, the reason that keeps the moon from falling back to the earth is because the Moon's rotation about its own axis creates centripetal force that balances Earth's pull.
Hence, their tangential velocity is sufficient to ensure that the flight path misses the object being orbited. The centripetal force is enough to bend the otherwise straight path into an ellipse.
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Answer:
D. The Moon has a large tangential velocity that causes it to "miss" Earth as it falls toward it.
Explanation:
You want to know what keeps the Moon from falling directly to Earth.
OrbitThe Moon does not fall directly to Earth because the direction of motion is more or less perpendicular to the direction of Earth from the Moon. That is, the large tangential velocity causes it to "miss" Earth.
Additional comment
One object will orbit another if their mutual gravitational attraction provides enough acceleration (change in speed and/or direction) to bend the path into a circular or elliptical one. If the acceleration is too little, the path may be bent, but no orbit will be established. If the acceleration is too great, the path may be bent to a curve that ultimately causes the objects to collide.
In general, the multi-body dynamics present in the solar system mean that the orbits of various objects are chaotic. In the short term, they are fairly predictable, but short-term behavior may not be predictive of long-term behavior.
A 10.0-kg test rocket is fired vertically. When the engine stops firing, the rocket’s kinetic energy is 1960 J. After the fuel is burned, to what additional height will the rocket rise?
Answers
Answer:
20m
Explanation:
So the formula for PE(Potential Energy) = Mass x Acceleration x Height
So we are given the following
PE = 1960
Mass = 10Kg
Acceleration = 9.8m/s^2 (The reason we have an acceleration is due to gravity)
Height = ?
So to calculate height we will use the same formula
1960 = 10 x 9.8 x h
1960 = 98 x h
1960 = 98h
we divide 98 on both sides
H = 20m
Hope this helped.
Question 6 of 10
Which statements below are true?
Check all that apply.
A. Displacement measurements must include magnitude, unit, and
direction.
B. If motion starts and stops at the same location, then the
displacement is zero.
C. Distance can be fully described with a magnitude and a unit.
D. Distance is always less than or equal to the magnitude of the
displacement.
Answers
Answer:
A, AND B,
Explanation: just trust me bro
when the cross product of vector A and B are 2i+3j+4k and the sum of vector A and B are 3i+8j+7k then what will be the two vectors
Answers
Explanation:
the two vectors are 5i+11j+11k
When a force of 450N pushes on a 20kg box as
shown, the acceleration of the box up the incline is
0.70m/s2. Find the coefficient of sliding friction
between the box and the incline.
Answers
Answer:
ma+mgsinh0+f=F∴(25)(0.75)+(25)(10)sinh0+μkN=F∴18.75+(250)(0.6h)+μk(mgcosh0=F⟹18.75+150+μk((25)(10)(0.76))=500∴168.75+μk(190)=500⟹μk(190)=331.25⟹μk=1.74
Explanation:
An infinitely long line of charge has a linear charge density of 8.00*10^−12 C/m. A proton is at distance 19.0 cm from the line and is moving directly toward the line with speed 1200 m/s. How close does the proton get to the line of charge?
Answers
Hi there!
To solve, we need to find the distance traveled by the proton at which the proton's velocity reaches 0 m/s. This indicates the point at which the repulsive force caused by the line of charge and its consequential acceleration causes the proton to stop for an instant and be repelled back in the opposite direction.
For this, we can use the work-energy theorem to solve.
Recall the following equations:
[tex]W = \Delta KE[/tex]
[tex]W = \int F \cdot dx\\\\KE = \frac{1}{2}mv^2[/tex]
We will integrate along the path from the point 19.0 cm (0.19 m) from the line up to a point 'z' at which the proton has no kinetic energy (v = 0 m/s). This means that the wire will be doing NEGATIVE work on the proton as it is decreasing the proton's kinetic energy.
The equation for a force acting on a charged particle is given as:
[tex]F_E = qE[/tex]
For an infinite line of charge, the electric field is given as:
[tex]E = \frac{2k\lambda}{r}\\\\F_E = \frac{2k\lambda q}{r}[/tex]
**λ = Linear charge density (C/m)
To set up our integral:
[tex]W = \Delta KE = \int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2[/tex]
Integrate using the following natural log rule:
[tex]\int {\frac{1}{r}} \, dr = ln(r) + C[/tex]
[tex]\int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2\\\\2k\lambda q ln(r) \left \| {{z} \atop {0.19}} \right. = -\frac{1}{2}mv^2\\\\2k\lambda q (ln(z) - ln(0.19) = -\frac{1}{2}mv^2\\\\2k\lambda q ln(\frac{z}{0.19}) = -\frac{1}{2}mv^2[/tex]
Now, we can begin solving for 'a'.
Move coefficients to one side:
[tex]ln(\frac{z}{0.19}) = -\frac{mv^2}{4k\lambda q }[/tex]
Take the base 'e' of both sides:
[tex]e^{ln(\frac{z}{0.19})} = e^{-\frac{mv^2}{4k\lambda q }}\\\\\frac{z}{0.19} = e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{(1.67*10^{-27})(1200^2)}{4(8.99*10^9)(8.00*10^{-12}) (1.6*10^{-19}) }}\\\\\boxed{z = 0.1803 m= 18.03 cm}[/tex]
It will reach a distance 18.03 cm from the wire before it temporarily loses all of its kinetic energy (at rest) and begins to speed up in the opposite direction.
Classify each characteristic as either a metal or a nonmetal.
shiny surface
dull surface
good conductor of electricity
good conductor of heat
poor conductor of electricity
poor conductor of heat
malleable
brittle
Answers
Answer:
metal, non, metal, metal, non, non, metal, non
Explanation:
knowledge
(For example, if you used a lunch meat that claimed to be 97% fat-free, were just 3% of its calories provided by fat?) If the manufacturer made such claims, how do you explain the difference between the manufacturer's claims and your findings?
Salmon
Answers
The difference between the manufacturer's claims and your findings is, the manufacturer is concerned about amount of fat in the meat while you are concerned about calories.
Difference between your findings and the manufacturers claimYour findings concluded that only fat can provide calories needed in the body, perhaps other classes of food or nutrients in the meat can provide calories as well.
In the manufacturer's claim there are about 3% fat in the lunch meat and doesn't necessary mean that all the calories needed is the 3% fat.
Thus, there are lots of difference between your findings and the manufacturer's claim. The manufacturer is concerned about amount of fat in the lunch meat while you are concerned about calories in the meat.
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which image shows an example of kinetic energy
Answers
Answer:
Hello there seems to be no Images in this question but Kinetic energy is a push or a pull force which has to do with motion if you just need to know what t is. Next time be sure to add the pictures for it.
Explanation:
Thank you!
Hello the other person (#Sonichj123), was indeed correct there appears to be no picture in your question. Although there is no picture in your question, If you have another question I will be gladly to help you!
Explanation:
Thank you so much! (≥ФωФ≤)
how much force is required to accelerate an 8.6kg wagon by 15 m/s ?
Answers
The amount of force required to accelerate the given mass of the wagon is 129 Newtons.
What is force?A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.
From Newton's Second Law, force is expressed as;
F = m × a
Where is mass of object and a is the acceleration.
Given the data in the question;
Mass of the rock m = 8.6kgAcceleration a = 15m/s²Force F = ?F = 8.6kg × 15m/s²
F = 129kgm/s²
F = 129N
Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.
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On a playground slide, a child has potential energy that decreases by 1000 J while her kinetic energy increases by 900 J. what other form of energy is involved, and how much?
Answers
Answer:
Friction 100 j
Explanation:
Friction causes the inequality between PE and KE
100 J
an object is thrown straight up. which of the following is true abought the sign of workdone by the force of gravity on the object, while the object moves up and then down
Answers
Answer:
Upward: Negative
Downward: Positve
Explanation:
Let upward be positive
We want to find the work done on the object upwards.
The equation of work done due to gravity is
[tex]f _{g}d \cos( \alpha ) [/tex]
It is read as force of gravity times displacement times cos of the angle between the force and displacement.
Since gravity is happening down of the center of mass and the displacement is upwards, the angle is 180° so
[tex]f_{g}d \cos(180) [/tex]
Cosine of 180 is -1
so
[tex] - f_{g}d [/tex]
If we go downwards, the sign will be positive because cos(0)=1
What is the velocity of a plane that travels 3,000 miles in 5.0 hours?
Answers
Answer:
600mph
Explanation:
hope this helps!
A rock is dropped from a bridge to the water below. It takes 2.40 s for the rock to hit the water (a) find the speed in m/s of the rock as it hits the water. (b) how high in metres is the bridge above the water
Answers
Answer: I think Its the Height is 11.76 Meters (38.582677 Feet) between the bridge and the ground
Explanation: Supposing that where not counting air resistance in the equation, the equation [tex]D = ut+\frac{1}{2} at^{2}[/tex] states that 1/2 multiplied by earths gravitational acceleration multiplied by the amount of time to reach the bottom: 2.4 seconds equals 11.76 meters of height between the bridge and the ground.
A sewing machine uses 1.6kWh of electricity in one day. If electricity costs 9p per unit, what is the total cost in pence of using the sewing machine that day? Give your answer to 3 significant figures.
Answers
Answer:
[tex]\huge\boxed{\sf 1.6\ units = 14.4p}[/tex]
Explanation:
Since,
1 kWh = 1 unitSo,
1.6 kWh = 1.6 units
If,
1 unit = 9p1.6 units = 9p × 1.6
1.6 units = 14.4p
[tex]\rule[225]{225}{2}[/tex]
You drive a car east on the highway at 26 m/s. Another car passes you moving east traveling at 32 m/s. How fast do you view the car passing you?
Answers
The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
Relative velocity of the carThe speed of the car passing you is determined by applying relative velocity principle as shown below;
Vr = Va - Vb
Vr = 26 m/s - 32 m/s
Vr = -6 m/s
Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
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Sunlight hits the black asphalt pavement on a sunny,
summer day. The pavement becomes excessively hot.
What wave behavior is demonstrated by this
phenomenon?
Answers
why do electrons flow threw a wire
Answers
Answer:
When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.
describe how standard of meter, second and kilogram are
agreed internationally?
Answers
The SI unit is agreed internationally through an agreement known as convention of the meter.
What is SI unit?
SI unit stands for International System Of Units (SI) - which is the metric system that is used universally as a standard for measurements.
Some examples of SI unit include;meter - unit of lengthsecond - unit of timekilogram - unit of massThe SI unit is agreed internationally through an agreement known as convention of the meter, which describes the measurement of fundamental quantities such as mass, time, and length.
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In-Class Problem #2
at
at
A 79.5 kg defensive end tackles a 60 kg
running back going north at 5 m/s. After the
hit both players move together at 2.5 m/s
south. How fast was the defensive end
running before the tackle?
on
ne ta
EAOLES
62
v = 8.16 m/s south
-0
362
Answers
Answer:
8.16m/s south
Explanation:
North is the negative direction.
60kg*(-5m/s)+79.5kg*v=(79.5kg+60kg)*(2.5m/s)
-300kgm/s+79.5kg*v=348.75kgm/s
79.5kg*v=648.75kgm/s
v=8.16m/s
As a wave travels through a medium, the particles of the medium vibrate in a direction perpendicular to the direction of the wave’s motion. What kind of wave is this? Longitudinal Wave, Pulse Wave, Transverse Wave, Pressure Wave, or Electromagnetic Wave?
Answers
A scientist is measuring various properties of a sound wave. She measures the value 340 m/s. Which of the following wave characteristics could this value correspond to?
A.
wavelength of the sound wave
B.
period of the sound wave
C.
wave speed of the sound wave
D.
frequency of the sound wave
Answers
Answer:
B. period of the sound wave
Is the ability to discriminate between two close objects.
Answers
Answer:
resolution
Explanation:
That is the definition of resolution
Discuss the role of oxygen in air supply.
Answers
T he role of oxygen in air supply is to keep all the ling beings live and healthy.
What is Oxygen?Oxygen is the most important gas required for the living of human beings, animals, birds and the whole ecosystem.
Oxygen is fundamental for breath on the grounds that the body utilizes it to 'consume' food atoms. Creatures take in oxygen while breathing in and radiate carbon dioxide while breathing out. Oxygen makes up practically 21% of the all out gases in air, with the majority of the excess gas being physiologically latent nitrogen.
Oxygen assumes a basic part in breath, the energy-delivering science that drives the digestion systems of most living things. We people, alongside numerous different animals, need oxygen in the air we inhale to remain alive. Oxygen is created during photosynthesis by plants and many sorts of organisms.
Thus, the air supply needs oxygen on the majority.
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A car of mass 500 kg is moving at a speed of 1.2 m/s. A man pushes the car, increasing the speed to 2 m/s. How much work did the man do?
A. 1360 J
B. 360 J
C. 640 J
D. 1000 J
Answers
Answer:
Option B - 360 J
Explanation:
One of the formulas used to find out how much work was done is :
E = 0.5×m×v² (where m is the mass and v is the velocity)
Now we substitute values from the question and simplify :
E = 0.5×500×1.2²
E = 250×1.2²
E = 250×1.44
E = 360 J
So our answer is Option B
Hope this helped and have a good day
If a 75 resistor is connected to a 18 V battery, how much current passes
through the resistor?
Answers
Answer:
0.24 A
Explanation:
Voltage is given by the equation :
V = I × R
Voltage = Current × Resistance
Rearrange to make Current/I the subject :
18 = I × 75
I = 18÷75
I = 0.24 A
Hope this helped and brainliest please
Ms. Paul is standing at the top of a cliff that is 100 m tall. She kicks a rock and it gets a horizontal velocity of 15.0 m/s. Determine the range of the
projectile.
Answers
vertical motion
h=1/2 gt²
100 = 1/2 x 10 x t²
t² = 100/5 = 20
t = 2√5 s
horizontal motion
x = v.t
x = 15 x 2√5
x = 30√5 m
How to determine the width/thickness of a coin using a screw gauge?
Answers
We can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.
How we can calculate the thickness using screw gauge?We can determine the width/thickness of a coin by using a screw gauge because screw gauge is an instrument that measures thickness of an object that are very thin. First we can placed the coin in between the teeth of the gauge and then move the gauge until the coin can be held tightly. After that note the reading on the scale.
So we can conclude that we can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.
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Two large parallel metal plates carry opposite charges. They are separated by 0.20 m and the p.d. between them is 500 V. What is the magnitude of electric field, if it is uniform, in the region between them.
Answers
Hi there!
We can use the following relationship between the Potential Difference and the Electric field:
[tex]V = E d[/tex]
V = Potential Difference (500V)
E = Electric Field (V/m)
d = separation between plates (0.2 m)
We can rearrange the equation to solve for the electric field:
[tex]E = \frac{V}{d}\\\\[/tex]
Plug in the given values.
[tex]E = \frac{500}{0.2} = \boxed{2500 \frac{V}{m}}[/tex]