Using WEKA software, answer the following questions based on the Phishing dataset provided.
a) Draw a simple confusion matrix (general one, not from WEKA) of the possible data scenarios for this
Phishing dataset. (0.5 Mark)
b) Draw a table that will outline the Accuracy, Precision, Recall, F-Measure, ROC Area of the following
Rules based algorithms; RIPPER (JRip), PART, and Decision Table (2 Marks)
c) Use Decision Trees algorithms (Random Forest, Random Tree) and Artificial Neural Network
(Multilayer Perceptrol) to compare with the results in part b) above. Do you have better prediction
accuracy with these in this dataset? (2 Marks)
d) What is your conclusion in these experiments pertaining to ML algorithms used? (0.5 Mark)
Answer:
This isn’t a difficult question, its a task
Explanation:
Write a recursive function called DigitCount() that takes a positive integer as a parameter and returns the number of digits in the integer. Hint: The number of digits increases by 1 whenever the input number is divided by 10. Ex: If the input is:
Recursive functions are functions that are called from within itself
The recursive function DigitCount() in Python where comments are used to explain each line is as follows:
#This defines the function
def countDigits(n):
#If the integer is less than 10
if n< 10:
#Then the integer has 1 digit
return 1
#Otherwise,
else:
#Count the number of integers
return 1 + countDigits(n / 10)
At the end of the function, the count of integers is returned to the main function
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6-Write a BNF description of the precedence and associativity rules defined for the expressions in Problem 9 - chapter 7 of the textbook . Assume the only operands are the names a,b,c,d, and e.
The BNF description, or BNF Grammar, of the precedence and associativity rules are
[tex]<identifier>\text{ }::=a|b|c|d|e[/tex]
[tex]<operand>\text{ }::=\text{ }NUMBER\text{ }|\text{ }<Identifier>[/tex]
[tex]<factor>\text{ }::=\text{ }<operand>|\text{ }-<operand>|\text{ }(<expression>)[/tex]
[tex]<power>\text{ }:=\text{ }<factor>\text{ }|\text{ }<factor>\text{**} <power>[/tex]
[tex]<term>\text{ }::=\text{ }<power>\text{ }\\|\text{ }<term>*<power>\text{ }\\|\text{ }<term>/<power>\\\\<expression>\text{ }::=\text{ }<term>\text{ }\\|\text{ }<expression>+<term>\text{ }\\|\text{ }<expression>-<term>[/tex]
BNF, or Backus-Naur Form, is a notation for expressing the syntax of languages. It is made up of a set of derivation rules. For each rule, the Left-Hand-Side specifies a nonterminal symbol, while the Right-Hand-side consists of a sequence of either terminal, or nonterminal symbols.
To define precedence in BNF, note that the rules have to be defined so that:
A negation or bracket matches first, as seen in the nonterminal rule for factorA power matches next, as seen in the rule defining a factorA multiplication, or division expression matches next, as seen in the rule defining a termFinally, addition, or subtraction match, as seen in the rule defining an expression.To make sure that the expression is properly grouped, or associativity is taken into account,
Since powers associate to the right (that is, [tex]x \text{**} y\text{**}z=x \text{**} (y\text{**}z)\text{ and not }(x \text{**} y)\text{**}z[/tex]), the rule defining power does this[tex]<power>\text{ }:=\text{ }<factor>\text{ }|\text{ }<factor>\text{**} <power>[/tex]
and not
[tex]<power>\text{ }:=\text{ }<factor>\text{ }|\text{ }<power>\text{**}<factor>[/tex]
Since multiplication/division are left associative (that is, [tex]x \text{*} y\text{*}z=(x \text{*} y)\text{*}z[/tex]), the rule defining a term takes this into account by specifying its recursion on the right of the operators like so;[tex]<term>\text{ }::=\text{ }<power>\text{ }\\|\text{ }<term>*<power>\text{ }\\|\text{ }<term>/<power>[/tex]
Also, addition and subtraction are left associative (that is, [tex]x \text{+} y\text{+}z=(x \text{+} y)\text{+}z[/tex]), the rule defining an expression takes this into account as seen below[tex]<expression>\text{ }::=\text{ }<term>\text{ }\\|\text{ }<expression>+<term>\text{ }\\|\text{ }<expression>-<term>[/tex]
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what are the main barriers to the adoption of an industry standard for internet system
Answer:
Industry experts say that although many companies find the potential of the Internet of Things very attractive, they either lack a clear value proposition for end-users or lack interoperability.
What is the best data type for traveling day?
In which wireless configuration type do nodes communicate directly with each other, rather than with an access point?
1)802.11b
2)Mesh network
3)Ad-hoc
4)2.4Ghz
Ad-hoc
Explanation:
In which wireless configuration type do nodes communicate directly with each other, rather than with an access point? In an AD-HOC network, all nodes communicate and transmit directly to each other.
What is ligma? please someone answers ill give the brainliest.
Answer:
Ligma is just a made-up disease, its not real. Tons of people use that word now for a inappropriate joke, don't fall for it!
Explanation:
The sugma and ligma are the rare diseases cause by the bofa family viruses.
What Sugma and Ligma are related?Sugma and Ligma are both diseases and are related to each other where LIGMA is also known as loose internal gene miaasintits and this is the second stage od BOFA which is biologically offset farkowonian asintits and this diseases interferes with the immune system and it increases the risk of having tuberculosis and if in LIGMA a person enter the BOFA stage.
It is considered as last treatable stage and due to highly weakened immune system the people are most likely to die at this stage but still there is one treatment suggested n this case called as LIGMA balls where as SUGMA is the rarest antibiotic strain resistant of LIGMA virus.
The sugma is non lethal but is contagious and can spread very fast and its great prevention is by awareness of BOFA family viruses s sugma strain can be transferred via both verbal and virtual communication and as it is a rare disease.
Therefore, The sugma and ligma are the rare diseases cause by the bofa family viruses.
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#SPJ2
Write a program that lists all ways people can line up for a photo (all permutations of a list of strings). The program will read a list of one word names (until -1), and use a recursive method to create and output all possible orderings of those names separated by a comma, one ordering per line.
The solution is the recursive Python 3 function below:
########################################################
def allNamePermutations(listOfNames):
# return all possible permutations of listOfNames
if len(listOfNames) == 0 or len(listOfNames) == 1:
# base case
return [listOfNames]
else:
# recursive step
result_list = [ ]
remaining_items = [ ]
for firstName in listOfNames:
remaining_items = [otherName for otherName in listOfNames if
(otherName != firstName)]
result_list += concat(firstName,
allNamePermutations(remaining_items))
return result_list
#######################################################
How does the above function work?
As with all recursive functions, this one also has a base case, and a recursive step. The base case tests to make sure the function terminates. Then, it directly returns a fixed value. It does not make a recursive call.
In the case of this function, the base case checked listOfNames to see if it was empty or only had one name. If any of the conditions were satisfied, a new list containing listOfNames is returned.
The recursive step is where the function allNamePermutations() calls itself recursively. The recursive step handles the case where listOfNames has more than one item. This step first iterates over each name in listOfNames, and then does the following;
Gets a name in listOfNameGets a list of other names in listOfNamesCalls allNamePermutations() on the list of other names to get a list of permutation of the other names.(By first getting the list of other names before passing it into
allNamePermutations(), we make sure the recursive step eventually
terminates. This is because we are passing a smaller list each time
we make the recursive call.)
Inserts the current name in front of each permutationAdds the results to the result list to be returned laterAfter the iteration, it returns the result list which will now contain all permutations of the names in the list.
The concat function is defined below
##################################################
def concat(name, listOfNameLists):
# insert name in front of every list in listOfNameLists
result_list = [ ]
for nameList in listOfNameLists:
nameList.insert(0, name)
result_list.append(nameList)
return result_list
#####################################################
If we run the sample test case below
####################################
name_list = ['Adam', 'Barbara', 'Celine']
allNamePermutations(name_list)
####################################
the following output is produced
[['Adam', 'Barbara', 'Celine'],
['Adam', 'Celine', 'Barbara'],
['Barbara', 'Adam', 'Celine'],
['Barbara', 'Celine', 'Adam'],
['Celine', 'Adam', 'Barbara'],
['Celine', 'Barbara', 'Adam']]
For another example of how to use recursion in Python, see the following example in the link below
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A large company pays its salespeople on a commission basis. The salespeople receive $900 per week, plus 8.75 percent of their gross sales for that week. For example, a salesperson who sells $10000 worth of merchandise in a week receives $900 plus 8.75 percent of $10000, or a total of $1775. You have been supplied with a list of the products sold by each salesperson. The values of these products are as follows:
Item Value
1 100
2 200
3 300
4 400
Develop a script that inputs one salesperson’s items sold for last week, calculates the salesperson’s earnings and outputs HTML5 text that displays the salesperson’s earnings.
Answer:
Explanation:
Which device can perform both input and output functions?
Answer:
For instance, a keyboard or computer mouse is an input device for a computer, while monitors and printers are output devices. Devices for communication between computers, such as modems and network cards, typically perform both input and output operations.
Answer:
Modems and network cards, typically perform both input and output operations
A programmer will typically write a(n) _____ and pass it to the interpreter. Group of answer choices object method variable script
Answer:
Script
Explanation:
A set of code blocks which is written to solve a particular problem in a certain programming language and passed to the interpreter to run is called a script.
The script is program's body which is made up of codes written in accordance to the syntax of a certain programming language. In other to execute the program written, it has to be passed to the interpreter, which run the script and produces an output.Hence, the set of code written by a programmer is called the script.
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Why does a computer need an operating system?
Answer:
An operating system helps it to manage and run its designed duties.
If it lacks an operating system, it wouldn't be able to work
Write the function void sort2(double* p, double* p) that receives two pointers and sorts the values to which they point. To test the function, write the main function that prompts the user to enter two values and then print out the sorted values. If you call sort2(&x, &y) then x <= y after the call.
The function illustrates the use of pointers.
Pointers are used to store address in programming languages such as C and C++.
The program in C language where comments are used to explain each line is as follows:
#include <stdio.h>
//This defines the function
void sort2(double* p1, double* p2){
//This declares a temporary variable t
double t;
//If p2 is less than p1,
if (*p2 < *p1) {
//The next 3 lines swap their values
t = *p2;
*p2 = *p1;
*p1 = t;
}
//This prints p1
printf("%f ", *(p1));
//This prints p2
printf("%f ", *(p2));
}
//The main method to test the function begins here
int main(){
double x = 23.0;
double y = 14.1;
sort2(&x, &y);
return 0;
}
//The program ends here
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