Which statement about reversible reactions is correct?(1 point)

They are always at equilibrium.
They are always at equilibrium.

The forward and reverse reactions must happen at the same rate.
The forward and reverse reactions must happen at the same rate.

They can occur in either direction.
They can occur in either direction.

They always involve gases.
They always involve gases.

Answers

Answer 1

Answer:

I think the answer would be C

C = They can occur in either direction.

Explanation:

Answer 2

the answer is C. They can occur in either directions


Related Questions

Two point particles, with masses m and 2 m, are separated by some distance Lin an uniform gravitational field. The center of gravity of this two particle system is:________
А. located L/2 distance away from either mass and on the line joining the two particles.
B. located 1/3 distance away from 2 m and on the line joining the two particles.
C. located L/4 distance away from 2 m and on the line joining the two particles.
D. located L/3 distance away from mand on the line joining the two particles.
E. located L/4 distance away from m and on the line joining the two particles.
F. located where the mass 2 m is located.

Answers

The center of gravity of this two particle system is located 1/3 distance away from 2 m and on the line joining the two particles.

The given parameters:

Mass of the first particle, = mMass of the second particle, = 2mDistance between the two particles, = L

The center of gravity of the two particles when first particle is fixed is calculated as;

[tex]C_G = \frac{m(0 ) \ +2m(L) }{m+ 2m} \\\\C_G = \frac{2mL}{3m} \\\\C_G = \frac{2L}{3}[/tex]

The center of gravity of the two particles when second particle is fixed is calculated as;

[tex]C_G = \frac{m(L) \ + \ 2m(0)}{m + 2m} \\\\C_G = \frac{mL}{3m} \\\\C_G = \frac{L}{3}[/tex]

Thus, the center of gravity of this two particle system is located 1/3 distance away from 2 m and on the line joining the two particles.

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What are the customary units for real power? volt-amperes reactive (VAR) volt-amperes (VA) watts (W)

Answers

Answer:

watts is for real power

volt amperes reactive (VA) for reactive power

volt amperes (VA) for apparent power

Why did humans first develop culture?
A. It helped humans distinguish themselves from wild animals.
B. It helped humans become the dominant species on Earth.
C. It helped the members of a society survive in their environment.
D. It helped individuals survive without the support of a society.
SUBMIT

Answers

Answer: C.

Correct me if I'm wrong.

A pumpkin is launched in the air and travels at a horizontal velocity of 25 meters per second for 5 seconds. How far does it travel horizontally?

Answers

Answer:

30.3 meters, 172 degrees

Explanation:

To insure the most accurate solution, this problem is best solved using a calculator and trigonometric principles. The first step is to determine the sum of all the horizontal (east-west) displacements and the sum of all the vertical (north-south) displacements.

Horizontal: 2.0 meters, West + 31.0 meters, West + 3.0 meters, East = 30.0 meters, West

Vertical: 12.0 meters, North + 8.0 meters, South = 4.0 meters, North

The series of five displacements is equivalent to two displacements of 30 meters, West and 4 meters, North. The resultant of these two displacements can be found using the Pythagorean theorem (for the magnitude) and the tangent function (for the direction). A non-scaled sketch is useful for visualizing the situation.

Applying the Pythagorean theorem leads to the magnitude of the resultant (R).

R2 = (30.0 m)2 + (4.0 m)2 = 916 m2

R = Sqrt(916 m2)

R = 30.3 meters

The angle theta in the diagram above can be found using the tangent function.

tangent(theta) = opposite/adjacent = (4.0 m) / (30.0 m)

tangent(theta) = 0.1333

theta = invtan(0.1333)

theta = 7.59 degrees

This angle theta is the angle between west and the resultant. Directions of vectors are expressed as the counterclockwise angle of rotation relative to east. So the direction is 7.59 degrees short of 180 degrees. That is, the direction is ~172 degrees.

What are the two factors that affect the frictional force between objects

Answers

Answer: The factors that affect the friction between two surfaces are the weight of the object and the coefficient of friction of the surface.

A 27 kg chair initially at rest on a horizontal
floor requires a 173 N horizontal force to set
it in motion. Once the chair is in motion, a
148 N horizontal force keeps it moving at a
constant velocity.
The acceleration of gravity is 9.81 m/s.
a) What is the coefficient of static friction
between the chair and the floor?

Answers

Answer:

4653

4565445655687568677667876

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Answers

Good morning dear...

Have a beautiful and joyful day ahead.

Find the work done by the force field F in moving an object from A to B. F(x, y) = 6y3/2i + 9x y j A(1, 1), B(3, 4)

Answers

Answer:

138

Explanation:

(since there's a blank next to "9x y j", I'm assuming the y of F(x, y) is 9x[tex]\sqrt{y}[/tex] j)

1) find the partial derivative of each:

[tex](6y^{\frac{3}{2} })i + (9x\sqrt{y} )j[/tex]  

 [tex]f_{x} =(6y^{\frac{3}{2} })_{x} = \int\limits{6y^{\frac{3}{2} }} \, dx = 6xy^{\frac{3}{2} } +c \\\\f_{y} = (9x\sqrt{y} )_{y} = \int\limits{9xy^{\frac{1}{2} } } \, dy = 9x(\frac{2}{3} )y^{\frac{3}{2} } +c = 6xy^{\frac{3}{2} } +c[/tex]

2) use partial integrals to make gradient of f:

take whatever you got from partial integral and add them together (if they repeat, just use it once)

[tex]F =[/tex] Vf (V = gradient of)

[tex]F(x, y) = 6xy^{\frac{3}{2} }[/tex]

3) Evaluate the integrals with given points:

Integral of F dotted with dr = F(point B) - F(point A) = F(3, 4) - F(1, 1)

[tex]F(point B) = 6(3)(4)^{\frac{3}{2} }\\F(Point A) = 6(1)(1)^{\frac{3}{2}}\\F(point B) - F(pointA) = 6(3)(4)^{\frac{3}{2} }-(6(1)(1)^{\frac{3}{2}})[/tex]

= 144 - 6 = 138 units of work

Work done by the force field F in moving an object from A to B = 138 J

Given data :

Force field F(x,y) = [tex]6y^{\frac{3}{2} }i + (9x\sqrt{y} ) j[/tex]  

Step 1 : determine the partial derivatives of the vector quantity

Fx = ∫ [tex]6y^{\frac{3}{2} }i = 6xy^{\frac{3}{2} } + c[/tex]

Fy = ∫ [tex](9x \sqrt{y})_{y} = 9x(\frac{2}{3})y^{\frac{3}{2} } + c[/tex]

Equating the partial derivatives :  

[tex]9x(\frac{2}{3})y^{\frac{3}{2} } + c[/tex]  = [tex]6xy^{\frac{3}{2} } + c[/tex]

therefore the gradient of F  i.e. F = vF  = F( x,y ) = [tex]6xy^{\frac{3}{2} }[/tex]

Next step : Determine the work done

Work done ( F.dr ) = [ F(point b ) = F( 3,4 ) ]  - [ F(point A) = F( 1,1 ) ]

F(3,4 ) = 6(3)(4)[tex]^{\frac{3}{2} }[/tex]  = 144

F( 1,1 )  = 6(1)(1)[tex]^{\frac{3}{2} }[/tex]    = 6

Therefore the work done by the force field = 144 - 6 = 138 J

Hence we can conclude that the work done by the force field F is = 138 J

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How much force must be applied to push a 1.35 kg book across the desk at constant speed if the coefficient of sliding friction is 0.30?

Answers

The magnitude of the force that must be applied to push the book across the desk is 3.97 N.

The given parameters;

mass, m = 1.35 kgcoefficient of friction, μ = 0.3

The acceleration of the book across the desk is calculated as follows;

a = μg

where;

g is acceleration due to gravity

a = 0.3 x 9.8

a = 2.94 m/s²

The magnitude of the force that must be applied is calculated as follows;

F = ma

F = 1.35 x 2.94

F = 3.97 N

Thus, the magnitude of the force that must be applied to push the book across the desk is 3.97 N.

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The axis of the earth is
Tilted about 23.5 degrees
Vertical
Vertical

Answers

Answer:

The axis of rotation of the Earth is tilted at an angle of 23.5 degrees away from vertical, perpendicular to the plane of our planet's orbit around the sun. The tilt of the Earth's axis is important, in that it governs the warming strength of the sun's energy.

Explanation:

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10. On Earth, where is hydrogen not found?
A. Natural gas well
B. Water
C. Atmosphere
o D. Minę

Answers

Answer:

i think its D or B

Explanation:

i just think

On Earth,in atmosphere the hydrogen is found in the less quantity. Option C is correct.

What is hydrogen?

The chemical element hydrogen has the atomic number 1 and the symbol H. The smallest element is hydrogen.

Hydrogen is found in large numbers on Earth in combination with other elements, such as water and hydrocarbons, yet it is only 0.00005 percent present in Earth's atmosphere.

On Earth,in atmosphere the hydrogen is found in the less quantity.

Option C is correct.

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In an oscillating LC circuit, when 86.6% of the total energy is stored in the inductor's magnetic field, (a) what multiple of the maximum charge is on the capacitor and (b) what multiple of the maximum current is in the inductor

Answers

We have that for the Question "(a) what multiple of the maximum charge is on the capacitor and (b) what multiple of the maximum current is in the inductor"  

Answer:

a) maximum charge =  [tex]0.366Q_{max[/tex]b) maximum current = [tex]0.931I_{max}[/tex]

From the question we are told

In an oscillating LC circuit, when 86.6% of the total energy is stored in the inductor's magnetic field

A) When 86.6\% energy is stored in inductor

[tex]\%[/tex]of energy stored in electric field = [tex]1 - 0.866 = 13.4\%[/tex]

[tex]\frac{V_E}{V} = \frac{\frac{q^2}{2c}}{\frac{Q^2}{2c}} = 0.134\\\\\frac{q}{Q} = \sqrt0.134\\\\\frac{q}{Q} = 0.366\\\\q = 0.366Q_{max[/tex]

B)

[tex]\frac{V_B}{V} = \frac{\frac{Li^2}{2}}{\frac{LI^2}{2}} = 0.866\\\\\frac{i}{I} = \sqrt0.866\\\\\frac{i}{I} = 0.931\\\\i = 0.931I_{max[/tex]

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Eric drops a 2.20 kg water balloon that falls a distance of 45.08 m off the top of a
building. What is the kinetic energy at the bottom?

Answers

Answer:

972 J

Explanation:

At the bottom, all the gravitational potential energy was converted into kinetic energy. If you calculate the GPE, its value will be the same that the KE at the bottom. The GPE can be calculated this way:

GPE = mass×gravity×heigth

GPE = 2.2×9.8×45.08 ≈ 972

Which of the following best describes an achievement test that is given at the end of a learning segment to evaluate mastery of objectives?

Answers

Answer

An Achievement test is an assessment of developed knowledge or skill. ... Achievement tests are developed to measure skills and knowledge learned in a given grade level, usually through planned instruction, such as training or classroom instruction. Achievement tests are often contrasted with aptitude tests.

Explanation:

The current in the long wire is decreasing. What is the direction of the current induced in the conducting loop below the wire

Answers

Answer:

anlatamadım herkeze ben sorulara bakamiyorum cumku analmaiyirum yardim edin

bu sorunu nasil cozebilirim

lutfsn...

Some amount of ideal gas with internal energy U was heated from 100^0C to 200^0C. We can predict that internal energy after heating in terms of U is:

Answers

The internal energy after heating in terms of U is 100U.

The given parameters;

initial temperature of the gas, T₁ = 100 ⁰Cfinal temperature of the gas, T₂ = 200 ⁰C

Assuming a constant pressure, the internal energy of the ideal gas is equal to the change in the enthalpy of the ideal gas.

[tex]\Delta H = U \times \Delta T\\\\\Delta H = U (200 - 100)\\\\\Delta H = 100 U[/tex]

Thus, we can conclude that the internal energy after heating in terms of U is 100U.

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Define critical angle

Answers

Answer:

Critical angle is a angle of incidence, for which refraction is 90 degree, this is a least angle of incidence at which total reflection takes place, please mark me Brainliest

What’s Newton’s second law? Explain and mention some examples in daily life

Answers

Newton’s second law of motion is force equals mass times acceleration.

F = m•a

An example of this would be hitting a ball. If you hit the ball, it will move however fast you hit the ball. The harder you hit the ball, the faster it will move.

hope this helps and brainliest please

Answer:

Newton's second law states that .

The rate of change of linear momentum is directly proportional to the force applied.

Formulically

F=ma

F=Force

m=mass

a=acceleration

The best example is hitting a tennis ball.

Suppose that you release a small ball from rest at a depth of 0.590 m below the surface in a pool of water. If the density of the ball is 0.370 that of water and if the drag force on the ball from the water is negligible, how high above the water surface will the ball shoot as it emerges from the water? (Neglect any transfer of energy to the splashing and waves produced by the emerging ball)

Answers

Answer:

Explanation:

The work of the buoyancy force will convert to gravity potential energy

Fresh Water has a density of 1000 kg/m³

The ball has a density of 370 kg/m³

assume the ball is 1 m³

weight of the ball is 370g

The buoyancy force is 1000g

Assume the buoyancy force drops suddenly to zero when the center of the ball clears the water level.

The Work done on the ball is

W = Fd = 1000g(0.590)

the change in potential energy is

PE = mgh = 370g(0.590 + y)

where y is the height above the water level.

1000g(0.590) = 370g(0.590 + y)

1000(0.590) = 370(0.590 + y)

y = (0.590)(1000 - 370) / 370

y = 1.004594... ≈ 1.00 m

Although genes contribute to whatever IQ scores measure, IQ can change radically due to changes in the __________.

Answers

Answer: Even though the genetic susceptibility plays a crucial role on the IQ of the individual, various modifiable environmental factors like education, premature birth, nutrition, pollution, drug and alcohol abuse, mental illnesses, and diseases can have an influence on an individual's IQ.

Two parallel plates, separated by 0.20 m, are connected to a 12-V battery. An electron released from rest at a location 0.10 m from the negative plate. When the electron arrives at a distance 0.050 m from the positive plate, what is the potential difference between the initial and final points

Answers

The potential difference between the initial and final point is 3.0 V.

The given parameters:

distance between the plates, d = 0.2 mvoltage across the plates, V = 12 Vposition of the electron from negative plate, x₁ = 0.1 mposition of the electron from the positive plate, x₂ = 0.0 5m

The potential difference between the initial and final point is calculated as follows;

[tex]E = \frac{V}{d} \\\\\frac{V_1}{d_1} = \frac{V_2}{d_2}[/tex]

where:

[tex]d_2[/tex] is the distance of the electron between the positive and negative plate

[tex]0.1 + d_2 + 0.05 = 0.2\\\\d_2 + 0.15 = 0.2\\\\d_2 = 0.2 - 0.15\\\\d_2 = 0.05 \ m[/tex]

[tex]V_2 = \frac{V_1d_2}{d_1} \\\\V_2 = \frac{12 \times 0.05}{0.2} \\\\V_2 = 3.0 \ V[/tex]

Thus, the potential difference between the initial and final point is 3.0 V.

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50 points please help ASAP! !

What is the average velocity of an object that moves from 6 meter to 2 meter relative to origin in 2 second?

Answers

Total Displacement=6-2=4mTime=2s

[tex]\\ \rm\rightarrowtail Avg\: velocity=\dfrac{Total\: Displacement }{Total\: time}[/tex]

[tex]\\ \rm\rightarrowtail Avg\: velocity=\dfrac{4}{2}=2m/s[/tex]

A fat wire, radius a, carries a constant current I, uniformly distributed over its cross section. A narrow gap in the wire, of width w << a, forms a parallel-plate capacitor. Find the magnetic field in the gap, at a distance s < a from the axis.

Answers

The magnetic field in the gap is [tex]\mathbf{B = \dfrac{\mu_oI s}{2 \pi a^2}}[/tex]

In a circuit, a magnetic flux is circulated or followed via a confined environment or passage called a magnetic field gap. The narrow air gap is a non-magnetic component of a magnetic circuit that is normally connected to the remainder of the circuit magnetically in series. This enables a significant amount of magnetic flux to pass via the gap.

The magnetic field in the gap at a distance s < a can be computed by using the formula:

[tex]\mathbf{ \oint Bdl = \mu_oI_{enclosed}}[/tex]

where;

Magnetic flux density = Bdistance = d

[tex]\mathbf{B( 2 \pi d) = \mu _o \oint _s J_d da }[/tex]

where;

[tex]\mathbf{J_d}[/tex] = drift current density

[tex]\mathbf{B( 2 \pi d) = \mu _o J_d \oint _sda }[/tex]

[tex]\mathbf{B( 2 \pi d) = \mu _o J_d (\pi d^2) }[/tex]

Making the magnetic flux density the subject, we have:

[tex]\mathbf{B =\dfrac{ \mu _o J_d (\pi d^2) }{( 2 \pi d)}}[/tex]

[tex]\mathbf{B =\dfrac{ \mu _o J_dd}{ 2 }}[/tex]

Recall that, the drift current density [tex]\mathbf{J_d = \dfrac{I}{\pi a^2}}[/tex]

[tex]\mathbf{B = \dfrac{\mu_o d}{2}(\dfrac{I}{\pi a^2})}[/tex]

Recall that distance in question is said to be (s);

[tex]\mathbf{B = \dfrac{\mu_oI s}{2 \pi a^2}}[/tex]

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Using Electrostatic Concept Explain The Classification of substances in Terms of Their ability to Conduct Electric Charges.

Answers

Answer:

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Explanation:

The behavior of an object that has been charged is dependent upon whether the object is made of a conductive or a nonconductive material. Conductors are materials that permit electrons to flow freely from particle to particle. An object made of a conducting material will permit charge to be transferred across the entire surface of the object. If charge is transferred to the object at a given location, that charge is quickly distributed across the entire surface of the object. The distribution of charge is the result of electron movement. Since conductors allow for electrons to be transported from particle to particle, a charged object will always distribute its charge until the overall repulsive forces between excess electrons is minimized. If a charged conductor is touched to another object, the conductor can even transfer its charge to that object. The transfer of charge between objects occurs more readily if the second object is made of a conducting material. Conductors allow for charge transfer through the free movement of electrons

HELP ASAPPPPPPPPPPPPPP

Answers

Answer:

F=15N

Explanation:

F=m.a

m=1500g ÷1,000 = 1.5kg

a= 10m/s/s

F =1.5 × 10

F = 15 Newton

The force of earth’s gravity is 10N downward. What us the acceleration of a 15kg backpack if lifted with a a 15N force?

Answers

Answer:

F-F(gr) = ma

a= {F-F(gr)}/m =

=(15-10)/15=0.33 m/s² (upward)

At what speed must the electron revolve round the nucleus of
the hydrogen in its ground state in order that it may not be pulled into the
nucleus by electrostatic attraction

Answers

Explanation:

I think this is it, give it a try

How much heat must be removed from 1.61 kg of water at 0 ∘C to make ice cubes at 0 ∘C?

Answers

Answer:

Explanation:

All

An applied force accelerates a 4.00 kg block to an initial velocity of 11 m/s across a rough horizontal surface, in the positive x direction. As the block reaches 11 m/s, the applied force is removed. The block then slows to 1.5 m/s at a distance of 4.00 m beyond where the applied force was removed. Determine the magnitude and the direction of the non-conservative force acting on the box as it slides.

Answers

The only force opposing the block's sliding as it slows down is friction with magnitude f . By Newton's second law, the net force in this direction is

F = -f = ma = (4.00 kg) a

Assuming constant acceleration a , the acceleration applied by friction is such that

(1.5 m/s)² - (11 m/s)² = 2a (4.00 m)

Solve for the acceleration :

a = ((1.5 m/s)² - (11 m/s)²) / (8.00 m) ≈ -14.8 m/s²

Then the frictional force exerted a magnitude of

-f = (4.00 kg) (-14.8 m/s²)

f59.4 N

and was directed opposite the block's motion.

Please solve this This is my exam question please be fast

Answers

Answer:

OK sure why not!!!!!!!!!!!!

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Sort the following elements in order from least reactive to most reactive.A - SbB - SC - FD - As Choose the appropriate gerund to fill in the sentence.Ests ________ en clase.dormindotedurmindotedurmindose What is the meaning of term Amino acid Find the measure of each angle indicated. Jessica is a 28 year-old married female. She has a very demanding, high stress job as a second year medical resident in a large hospital. Jessica has always been a high achiever. She graduated with top honors in both college and medical school. She has very high standards for herself and can be very self-critical when she fails to meet them. Lately, she has struggled with significant feelings of worthlessness and shame due to her inability to perform as well as she always has in the past. For the past few weeks, Jessica has felt unusually fatigued and found it increasingly difficult to concentrate at work. Her coworkers have noticed that she is often irritable and withdrawn, which is quite different from her typically upbeat and friendly disposition. She has called in sick on several occasions, which is completely unlike her. On those days, she stays in bed all day, watching TV or sleeping. At home, Jessicas husband has noticed changes as well. She has shown little interest in sex and has had difficulties falling asleep at night. Her insomnia has been keeping him awake as she tosses and turns for an hour or two after they go to bed. He has overheard her having frequent tearful phone conversations with her closest friend, which have him worried. When he tries to get her to open up about what is bothering her, she pushes him away with an abrupt everythings fine. Although she has not ever considered sui-slide, Jessica has found herself increasingly dissatisfied with her life. She has been having frequent thoughts of wishing she were dead. 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When the valve between the right atrium and right ventricle has an abnormal narrowing, this is known as(Answer is NOT pulmonary valve or pulmonary stenosis) Which savings account will earn the most interest?A $5,000 at 4 percent interest compounded for four yearsB. $10,000 at 2 percent interesi compounded for four yearsC. $10,000 at 2 percent simple interest for four yearsD. $5,000 at 4 percent simple interest for four years PLZ TRY YOUR HARDEST I WONT GET CHRISTMAS IF THIS IS WRONG 100 POINTS AND WILL GET MY a word BEAT.AssignmentClose Reading: Borderbus. quesion 1 .The poet writes first in Spanish and follows it with an English translation. This allows non-Spanish speakers to understand the lines in Spanish. What is another reason the poet uses both Spanish and English?. question 2.Cite textual evidence that supports the inference that the women crossed the border illegally. question 3.Read the lines from the poem Borderbus. 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