Which of the following will dissolve the fastest

Which Of The Following Will Dissolve The Fastest

Answers

Answer 1

Answer:

Saturated.

Explanation:

This explains the solute dissolving faster. It links with the definition of soaked with moisture; drenched.

Answer 2

Answer:

I believe the answer would be C. unsaturated. and for part 2 I believe would be A. hope that helps :)


Related Questions

Which of the following elements will form positive ions? Check all
that apply.
Na
z
Cu
Br

Answers

Answer:

cu and Na

Explanation:

When an atom losses electrons this results in a positive charge. A positively charged ion is called a cation.

Sodium and copper will form positive ions. Sodium is a monovalent cation while copper is a divalent cation.

What are positive ions?

The ions which contain a positive charge it is called positive ions. The atomic number of sodium is 11. It contains (2, 8, 1) electrons. When it loses it's one electron it will be a positive ion.

Copper has valence electrons. When it loses its two valence electrons it will be a copper ion. There are two types of ions such as positive ions and negative ions.

Small molecules that have acquired a positive charge are known as positive ions. Positive ions are the predominant type of air pollution, including hazardous substances, pollen, mold, pet dander, and other dangerous chemicals.

Therefore, Sodium and copper will form positive ions. Sodium is a monovalent cation while copper is a divalent cation.

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How many grams (g) are in 4.00 moles of Carbon (C) ?

Answers

Answer:

There are 36 grams in 4.00 moles of Carbon.

Explanation:

In order to convert from moles of a substance into grams of the same substance, we need to use the substance's molar mass.

That means that in this case we use the molar mass of Carbon:

4.00 mol * 12 g/mol = 36 g

Thus, there are 36 grams in 4.00 moles of Carbon.

Sulfuric acid (H₂SO₄), is formed when sulfur dioxide (SO₂) reacts with oxygen and water. Using the balanced chemical reaction above, how many moles of H₂SO₄ are produced from 8.5 moles of SO₂?

Answers

Answer:

8.5 mol H₂SO₄

Explanation:

It seems the balanced reaction the problem is referring to is absent, however the description matches the following balanced reaction:

2SO₂ + O₂ + 2H₂O → 2H₂SO₄

Now we can convert 8.5 moles of SO₂ into moles of H₂SO₄, using the stoichiometric coefficients of the balanced reaction:

8.5 mol SO₂ * [tex]\frac{2molH_2SO_4}{2molSO_2}[/tex] = 8.5 mol H₂SO₄

Water is amphoteric. If it reacts with a compound that is a stronger acid than itself, water acts as a

Answers

Answer:

Water acts as a base in the presence of a strong acid

Explanation:

Water,being an amphoteric compound, can act both as an acid and as a base.

In the presence of an acid , water acts as a base but in the presence of a base, water acts as an acid.

Imagine that you have an ideal gas in a 5.80 L container, and that 2950 molecules of this gas collide with a square-centimetre area of the container at any given instant.

If the volume is increased to 46.4 L at constant temperature, how many collisions will occur per square centimetre of this larger container?

Answers

Answer:

23,600 collisions.

Explanation:

Hello there!

In this case, according to the Avogadro's law, which help us to understand the molecules-volume relationship as directly proportional:

[tex]\frac{molecules_2}{V_2}=\frac{molecules_1}{V_1}[/tex]

It is possible for us to compute the collisions once the volume is increased as shown below:

[tex]molecules_2=\frac{molecules_1V_2}{V_1}\\\\molecules_2=\frac{2950*46.4L}{5.80L}\\\\molecules_2=23600[/tex]

Which means 23,600 collisions will occur per square centimeter.

Regards!

Which is the correct statement regarding the relative Rf values of the starting methyl benzoate vs the product, methyl m-nitrobenzoate on a silica gel TLC plate. The product has a higher Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. 1.5 points QUESTION 2 Methyl benzoate is more reactive than benzene in Electrophilic Aromatic Substition [EAS] reactions. True False 1 points QUESTION 3 Methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition [EAS] reactions. True False

Answers

Answer:

1. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate.

2. False

3. True

Explanation:

In chromatography, there is a stationary phase and a mobile phase. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).

Since silica gel is a polar solvent, it will retain the more polar product methyl m-nitrobenzoate compared to the methyl benzoate starting material.

In comparing the electrophillic aromatic substitution of m-nitrobenzoate  and methyl benzoate, we must remember that the presence of electron withdrawing groups (such as -NO2 and -CHO) on the aromatic compound deactivates the compound towards electrophillic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substition

The final result has a higher Rf value because the TLC plate has more polarity than the other compound.

The answer to the following question is as follows:-

False True

In chromatography, it is a process that is used to separate the different components on the basis of their votality. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).

In comparing the electrophilic aromatic substitution of m-nitrobenzoate and methyl benzoate, we must remember that the presence of electron-withdrawing groups on the aromatic compound deactivates.

The compound towards electrophilic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substitution and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substitution.  

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How many moles of aspirin (C9H8O4) are contained in 3.13 g of aspirin?

Answers

Answer:

The correct answer is - 0.0173888 moles.

Explanation:

Aspirin,  C 9 H 8 O 4 , the atomic mass rounded to the nearest whole number, so: c- 12 h- 1 o - 16

now multiply these number by how many of each there are in the formula:

c - 12 x 9 = 108

h - 1 x 8 = 8

0 - 16 x 4 = 64

add these numbers up 108 + 8 + 64 = 180

aspirin has a molar mass of  

180.g mol ^− 1 . This means that one mole of aspirin will have a mass of 180 g .

You're dealing with 3.13 g  of aspirin, which will be equivalent to

3.13 g  /180g

=  0.0173888 moles aspirin

You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accu­rately (to four significant figures). You use a simple metric ruler to measure its dimensions and obtain the results for Method A. Your partner uses a precision micrometer and obtains the results for Method B.
Method A (g/cm3) 2.7 Method B (g/cm3) 2.703 2.701 2.705 5.811
The accepted density of aluminum is 2.702 g/cm 3 .
(a) Calculate the average density for each method.
Should all the experimental results be included in your calculations? If not, justify any omissions.
(b) Calculate the percent error for each method’s average value.
(c) Calculate the standard deviation for each set of data.
(d) Which method’s average value is more precise? Which method is more accurate?

Answers

Complete Question

You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accu­rately (to four significant figures). You use a simple metric ruler to measure its dimensions and obtain the results for Method A. Your partner uses a precision micrometer and obtains the results for Method B.

Method A (g/cm3) 2.2,2.3,2.7,2.4 Method B (g/cm3) 2.703 2.701 2.705 5.811

The accepted density of aluminum is 2.702 g/cm 3 .

(a) Calculate the average density for each method.

Should all the experimental results be included in your calculations? If not, justify any omissions.

(b) Calculate the percent error for each method’s average value.

(c) Calculate the standard deviation for each set of data.

(d) Which method’s average value is more precise? Which method is more accurate?

Answer:

a)[tex]Ma_{avg}= 2.4g/cm^3[/tex]

   [tex]Mb_{avg}=2701g/cm^3[/tex]

b)[tex]PE_a=7.5\%[/tex]

  [tex]P.E_b=28.8 \%[/tex]

c) [tex]\sigma_A=0.35[/tex]

   [tex]\sigma_B=0.0545[/tex]

d)Method A

Explanation:

From the question we are told that:

Method A Density values

2.7

Method B Density values

2.703,2.701,2.705,5.811

Density of aluminium [tex]p_d=2.702 g/cm^3[/tex].

a)  

Generally the average density for each method is mathematically given by

Method A

[tex]Ma_{avg}= \frac{2.2+2.3+2.7+2.4}{4}[/tex]

[tex]Ma_{avg}= 2.4g/cm^3[/tex]

Method B

[tex]Mb_{avg}=\frac{2.703+2.701+2.705}{3}[/tex]

[tex]Mb_{avg}=2701g/cm^3[/tex]

b)

Generally the equation for percentage error [tex]PE[/tex] is is mathematically given by

percent error = (measured- real)/real *100

Given real = 2.702 g/ cm​​​3

Method A =

[tex]PE_a=(2.5- 2.702)* \frac{100}{2.702}[/tex]

[tex]PE_a=7.5\%[/tex]

Method B =

[tex]PE_b=( 3.481- 2.702)*\frac{100}{2.702}[/tex]

[tex]P.E_b=28.8 \%[/tex]

c)

Generally the standard deviation [tex]\sigma[/tex] for each method is mathematically given by

Method A

[tex]\sigma=\sqrt{\frac{\sum(x-a)^2}{N} }[/tex]

[tex]\sigma=\sqrt{\frac{0.25+0.16+0+0.09}{4} }[/tex]

[tex]\sigma_A=0.35[/tex]

Method B

[tex]\sigma=\sqrt{\frac{\sum(x-a)^2}{N} }[/tex]

[tex]\sigma=\sqrt{\frac{0.000001+0.00000+0.000009+0.011881}{4} }[/tex]

[tex]\sigma_B=0.0545[/tex]

d)

Therefore with lower percentage error the method who's average value is more precise is

Method A

Which of the following correctly shows a synthesis reaction involving potassium?

A. Br2 + 2KI → I2 + 2KBr
B. 4K + O2 → 2K2O
C. 2KClO3 → 2KCl + 3O22KClO3 → 2KCl + 3O2
D. 2K2O → 4K + O22K2O → 4K + O2

Answers

Answer:

B. 4 K + O₂ → 2 K₂O

Explanation:

Which of the following correctly shows a synthesis reaction involving potassium?

A. Br₂ + 2 KI → I₂ + 2 KBr

No, this is a single displacement reaction, in which Br displaces I from its salt.

B. 4 K + O₂ → 2 K₂O

Yes, this is a synthesis reaction, in which 2 elements combine to form a compound.

C. 2 KClO₃ → 2 KCl + 3 O₂

No, this is a decomposition reaction, in which a big substance decomposes into smaller ones.

D. 2 K₂O → 4K + O₂

No, this is a decomposition reaction, in which a big substance decomposes into smaller ones.

True or False?
A hydrogen bond is an attraction between molecules containing hydrogen that is not considered a true chemical bond.

Answers

Answer:TRUE

Explanation:

A hydrogen bond is the electromagnetic attraction created between a partially positively charged hydrogen atom attached to a highly electronegative atom and another nearby electronegative atom. A hydrogen bond is a type of dipole-dipole interaction; it is not a true chemical bond.

C12H26+Oxygen=12CO2+water
calculate the mass of one mole of the liquid alkane C12H26.​

Answers

Answer:

170.38g is the mass of 1 mole of C₁₂H₂₆

Explanation:

To solve this question we must find the molar mass of the alkane C₁₂H₂₆. The molar mass is defined as the mass of one mole of a substance.

In 1 mole of C₁₂H₂₆ we have 12  moles of Carbon and 26 moles of Hydrogen. With the periodic table of elements we can know the molar mass of 1 mole of Carbon and 1 mole of hydrogen, and, thus, the molar mass of the alkane (Molar mass C = 12.01g/mol, H = 1.01g/mol)

Molar mass C₁₂H₂₆:

12C = 12*12.01g/mol = 144.12g/mol

26H = 26*1.01g/mol = 26.26g/mol

144.12g/mol + 26.26g/mol =

170.38g is the mass of 1 mole of C₁₂H₂₆

pls help What are the benefits and limitations of scientific experiments and investigations?

Answers

The benefits and limitations of scientific experiments and investigations is the knowledge allows us to develop new technologies

Predict the products for the reaction shown in the picture.
Fe(s) + CuCrO4(aq) —>

Answers

Answer:

After checking many websites as well

I haven't seen any answer for this reaction

While I found answers or other reactions

Therefore I think this reaction cannot occur

Please mark my answer as brainliest if you feel I helped you in any way :)

Redox reactions refer to a pair of reactions in which a particular oxidation is coupled to a corresponding reduction.

a. True
b. False

Answers

Answer:

A. True

Explanation:

Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and 71.1% O. Oxalic acid can interfere with respiration and cause kidney or bladder stones. If a large quantity of rhubarb leaves is ingested, the oxalic acid can be toxic. The lethal dose (LD50) in rats for oxalic acid is 375 mg/kg. Rhubarb leaves contain about 0.5% by mass of oxalic acid. (Show your work, using the insert equation tool :) What is the empirical formula of oxalic acid

Answers

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g;     Hydrogen H = 2.24 g     Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

[tex]=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon[/tex]

For Hydrogen:

[tex]=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen[/tex]

For Oxygen:

[tex]=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen[/tex]

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon[/tex]

For Hydrogen:

[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen[/tex]

For Oxygen:

[tex]\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen[/tex]

Thus, the empirical formula is HCO₂

If the pH of a solution is 1.5 , calculate [H^ + ] .
Help plz?? ​

Answers

Answer: Thus hydrogen ion concentration is 0.031622777

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

[tex]pH=-\log [H^+][/tex]

Putting in the values:

[tex]1.5=-\log[H^+][/tex]

[tex][H^+]=10^{-1.5}=0.031622777[/tex]

Thus hydrogen ion concentration is 0.031622777

The following containers have the same number of molecules and temperature. Which container has the most collisions?

Answers

Answer:

Container 1 I think.

The containers have the same number of molecules and temperature. The container 1.

What is collision?

Collision is the encounter between two particles or object. There are three type of collision: perfectly elastic collision, inelastic collision, perfectly inelastic collision.

Container 1 is smallest, so there will be less distance between the molecules, so they will collide most.

Thus, the containers have the same number of molecules and temperature. The container 1.

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A rock is made of the same substance while a mineral is made up of different type of
rocks

True

False

Answers

Answer:

False i think

The colder parts of the surface of Pluto have a temperature of –382°F. What is this temperature in Celsius?

Answers

-113.2 °F

Step-by-step explanation:

Well assign the coldest place on earth on the day as having x temperature
Therefore based on the statement;

2x – 53.6 = -280

2x = -280 + 53.6

2x = - 226.4

X = -113.2

How many moles are there in 87.2 g of zinc fluoride?

Answers

Answer:

what I got was 0.8435160945347224 moles

Eaterfication experiment

Answers

Answer:

Do you mean Esterification experiment?

Explanation:

Plzzzzz help me to solve this question.​

Answers

Answer:

Explanation:

A1. Chemical indicator, any substance that gives a visible sign, usually by a colour change, of the presence or absence of a threshold concentration of a chemical species, such as an acid or an alkali in a solution. An example is the substance called methyl yellow, which imparts a yellow colour to an alkaline solution.

A2. The reaction of an acid with a base is called a neutralization reaction. The products of this reaction are a salt and water. ... For example, the reaction of hydrochloric acid, HCl, with sodium hydroxide, NaOH, solutions produces a solution of sodium chloride, NaCl, and some additional water molecules

A3. Methyl orange has the property to color alkaline and neutral water yellow. If the water becomes acidic, it turns red immediately.

What is the pH of a neutral solution at 25ºC?
a. 14
b. 0
c. 1
d. 7

Answers

Answer:

d.7 is the correct answer

Which among the following is not required in the synthesis of fatty acids.
A). Acetyl-CoA
B). Biotin
C). Carbon iv oxide
D). NADH

Answers

Answer:

D). NADH

Explanation:

Calculate the pH of a solution containing 25 g of barium hydroxide (171.34 mel) dissolved in 250 mL of
solution.

Answers

Answer:

14

Explanation:

Step 1: Calculate the moles corresponding to 25 g of Ba(OH)₂

The molar mass of Ba(OH)₂ is 171.34 g/mol.

25 g × 1 mol/171.34 g = 0.15 mol

Step 2: Calculate the molar concentration of Ba(OH)₂

Molarity is equal to the moles of solute divided by the liters of solution.

[Ba(OH)₂] = 0.15 mol/0.250 L = 0.60 M

Step 3: Calculate the molar concentration of OH⁻

Ba(OH)₂ is a strong base according to the following equation.

Ba(OH)₂ ⇒ Ba²⁺ + 2 OH⁻

The molar ratio of Ba(OH)₂ to OH⁻ is 1:2. The molar concentration of OH⁻ is 2/1 × 0.60 M = 1.2 M.

Step 4: Calculate the concentration of H⁺

We will use the ionic product of water expression.

Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴/[OH⁻] = 1.0 × 10⁻¹⁴/1.2 = 8.3 × 10⁻¹⁵ M

Step 5: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺] = -log 8.3 × 10⁻¹⁵ = 14

Answer please correctly

Answers

Answer:

the correct answere to that is q

Answer:

D.

Explanation:

Select the correct structure that
corresponds to the name.
3-bromo-6-methyl-4-octene
CHE
A
Br
B.
CH3CH2CHBrCH = CHCH(CH3)CH2CH3
C. both

Someone please help

Answers

Answer:

b

Explanation:

one clue is the double bond at 4 carbon c=c

The correct structure that corresponds to the name.

3-bromo-6-methyl-4-octene is   [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex] .

What is 3-bromo-6-methyl-4-octene?

The molecule in which bromine is attached with C-3 carbon and double present at C-4 carbon containing total number of 8 carbon atom can be considered as 3-bromo-6-methyl-4-octene.

What is structure?

A chemist specifies the molecular geometry and, where possible and required, the electronic structure of such given molecule as well as other solid during a chemical structure determination.

It can be seen that in molecule [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex] bromine is attached with C-3 carbona and double bond exist at C-4 carbon. the total number of carbon atom is 8.

therefore, the structure of the compound will be [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex].

To know more about  structure of the  3-bromo-6-methyl-4-octene click here.

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Plz help me I am timed!!

Answers

answer: i think it is C

7th grade science lol help​

Answers

Answer:

The process you are referrring to is erosion.

Explanation:

Weathering would be the breaking down of rock/other land debris. Its more active counterpart would be erosion, wherein the process transports the bits of rock and minerals away. Hope it helps!

3. You will need to make ~0.1 M solutions of one (or more) of the following salts. For each compound, determine (or look up) its molecular weight, and determine the mass necessary to make 100.0 mL of 0.100 M solution. Pay attention to significant figures! Sodium acetate anhydrous Sodium acetate trihydrate Iron(III) chloride hexahydrate g

Answers

Answer: The mass of sodium acetate anhydrous required is 0.820 g

The mass of sodium acetate trihydrate required is 1.36 g

The mass of Iron (III) chloride required is 2.70 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

= volume of solution in ml

1. moles of =

Now put all the given values in the formula of molarity, we get

[tex]0.100=\frac{x\times 1000}{82.03\times 100.0}[/tex]

[tex]x=0.820g[/tex]

Therefore, the mass of sodium acetate anhydrous required is 0.820 g

2.   moles of [tex]CH_3COONa.3H_2O[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{136.08g/mol}[/tex]

Now put all the given values in the formula of molarity, we get

[tex]0.100=\frac{x\times 1000}{136.08\times 100.0}[/tex]

[tex]x=1.36[/tex]

Therefore, the mass of sodium acetate trihydrate required is 1.36 g

3. moles of [tex]FeCl_3.6H_2O[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{g/mol}[/tex]

Now put all the given values in the formula of molarity, we get

[tex]0.100=\frac{x\times 1000}{270.33\times 100.0}[/tex]

[tex]x=2.70g[/tex]

Therefore, the mass of Iron (III) chloride required is 2.70 g

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