Which of the following is the best way to make a conclusion?
A. The experiment must be manipulated until the results show what you want
B. Estimate results to where they should be
C. Choosing the results you like
D. Comparing data from the experiment to the prediction of the hypothesis

Answer:

D. The Church

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Answer:

Al2O3

Explanation:

Empirical formula is found by converting percent composition into a mole ratio.

First, assume you have a 100g sample of the substance. This allows you to make your percent composition into grams.

100% = 100g

53% = 53g Al

47% = 47g O

Next, divide each substance's mass by their molar mass. This converts your number to moles.

[tex]53g Al / 27g Al = 1.96 mol\\\\47g O/16g O = 2.93mol[/tex]

Next, divide both mol answers by the smallest number of moles.

[tex]1.96mol/1.96mol = 1\\2.93mol/1.96mol = 1.5[/tex]

Usually, these answers would be your subscripts for your empirical formula. However, we cannot have a decimal subscript, so we will multiply our answers by a factor of 2 to get to a whole number. This gives us 2 moles of Al and 3 moles of oxygen, or a formula of Al2O3.

Considering the definition of empirical formula, the correct answer is the second option: the empirical formula is Al₂O₃.

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 53 grams of Al and 47 grams of O.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

Al: [tex]\frac{53 grams}{27 \frac{grams}{mole} }[/tex]= 1.9629 moles

O: [tex]\frac{47 grams}{16 \frac{grams}{mole} }[/tex]= 2.9375 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Al: [tex]\frac{1.9629 moles}{1.9629 moles}[/tex]= 1

O: [tex]\frac{2.9375 moles}{1.9629 moles}[/tex]≅ 1.5

You cannot have a decimal subscript, so you will multiply our answers by a factor of 2 to get to a whole number:

Al: 1× 2= 2

O: 1.5× 2= 3

Therefore the Al:O mole ratio is 2: 3

Finally, the correct answer is the second option: the empirical formula is Al₂O₃.

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Answer:

C) Carbon dioxide is the answer.

Answer:

C. Carbon Dioxide

Carbon is absorbed by plants and chemically converted to oxygen via photosynthsis.

Hope this helps!

Answer:

S is [Ne] 3s²3p⁴

Cl is [Ne] 3s² 3p⁵

Explanation:

Answer: Model B. I have included a graph for this question. Model D is incorrect because that is a model for plasma as liquid doesn't contain ionized particles. Model C is incorrect as that represents a solid. Model A is incorrect because that is showing a gas; the particles are moving very freely

According to the forces of attraction, model B  communicates the kinetic energy and particle arrangement of a liquid.

Forces of attraction is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases  as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

The physical properties such as melting point, boiling point, density  are all dependent on forces of attraction which exists in the substances.

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Your question is incomplete  but most probably your full question was, The models show the phases of a substance at various temperatures. Which model BEST communicates the kinetic energy and particle arrangement of a liquid? A. Model D, because it has high kinetic energy so the particles in the model have ionized B. Model B, because it has some kinetic energy and the particles have a free flowing shape C. Model C, because it has high kinetic energy so the particles in the model have no definite shape D. Model A, because it has some kinetic energy and the particles move freely

Answer:

i think it wil be 567489

Explanation:

ik im right :)

Answer:

"100" is the molarity of solution.

Explanation:

The given values are:

Moles of solute,

= 5 mol

Liters of solution,

= 0.05 L

Now,

The molarity of a solution will be:

=  [tex]\frac{Moles \ of \ solute}{Liters \ of \ solution}[/tex]

On substituting the values, we get

=  [tex]\frac{5}{0.05}[/tex]

=  [tex]100[/tex]

Through satellites...

The molar mass of aspartic acid is 133.05g/mol.

The molar mass is the mass per unit amount of substance of a given chemical entity. It is denoted by a symbol M. The SI unit of molar mass is kg/mol.

Aspartic acid is one of the building-block of amino acids which is responsible for synthesizing proteins and regulating hormones in the human body.

The chemical formula of aspartic acid is C4H7NO4.

Atomic mass of C = 12.011u, H = 1.007u, N = 14.006u, O = 16u

Molar mass of C4H7NO4 = 4(12.011)+7(1)+14.006+4(16)

                 = 48.044+7+14.006+64

                 = 133.05g/mol

Hence, the molar mass of aspartic acid is 133.05g/mol.

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Explanation:

C3H8 + 502 ----> 3CO2 + 4H20

4NH3+7O2------> 4NO2+6H2O

2Al(NO3)3 + 3Na2S -------> Al2S3+6NaNO3

Answer:

68,400

Explanation:

Answer:

velocity

Explanation:

because he is going 30 miles west

The molarity is an important method to calculate the concentration of a solution. The molarity of calcium chloride of 16.4 g in 750.0 mL of solution is 0.196 mol L⁻¹.

The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. It is mainly employed in calculating the molarity of a binary solution. It is represented as 'M' and unit is mol L⁻¹.

The equation used to calculate the molarity is given as:

Molarity = Number of moles of the solute / Volume of the solution in litres

Molar mass of CaCl₂ = 110.98 g/mol

Given mass = 16.4 g

Number of moles = 16.4 / 110.98 = 0.147

750.0 mL = 0.75 L

Molarity = 0.147 / 0.75 = 0.196 mol L⁻¹

Thus the molarity is 0.196 mol L⁻¹.

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Answer: moles = 0.0799305403604264

Explanation:

Both animal X and animal Y begin life as a tadpole and change form as they develop

Answer:

it is c, for those who want an answer fast

Explanation:

Answer:

ethyl ethernal

Explanation:

no explanation

Answer:

A for growth and body repair

Explanation:

B, C, and D don't have anything to do with animals.

Answer:

19.4 mL Ba(OH)2

Explanation:

H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)

At STP, 1 mol gas = 22.4 L gas. Use this conversion factor to convert the 100. mL of Cl2 to moles.

0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2

Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.

0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl

HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.

0.00892 mol OH- • (1 mol Ba(OH)2 / 2 mol OH-) • (1 L Ba(OH)2 / 0.230 M Ba(OH)2) = 0.0194 L = 19.4 mL Ba(OH)2

The first step in answering this reaction is to write down the required reaction equations and then answer the questions from stoichiometry(mass-mole relationship).

The first equation is;

[tex]H2(g) + Cl2(g) ------->2HCl(g)[/tex]

The second equation is

[tex]2HCl(g) + Ba(OH)2(aq) -------> BaCl2(aq) + 2H2O(l)[/tex]

From stoichiometry;

1ml = 1cm3

Since hydrogen is in excess, chlorine is the limiting reactant

1 mole of Cl2 occupies 22400cm3

x moles of Cl2 occupies 100cm3

x = 1 * 100/22400

x = 0.00446 moles of Cl2

According to the reaction equation;

1 mole of Cl2 yields 2 moles of HCl

0.00446 moles of Cl2 yields 0.00446 * 2/1

= 0.00892 moles of HCl

From the reaction equation;

2 moles of HCl reacts with 1 mole of Ba(OH)2

0.00892 moles of HCl reacts with 0.00892 * 1/2 = 0.00446 moles of Ba(OH)2

Since 0.00446 moles of Ba(OH)2 reacted

number of moles = concentration * volume

number of moles =  0.00446 moles

concentration = 0.230M

Let the volume in ml be V

0.00446 =  0.230 * V/1000

V = 0.00446 * 1000/ 0.230

V = 19.39 ml

Volume in ml = 19.39 ml of Ba(OH)2

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Explanation:

(formula)

Answer:

[tex]58.48^{\circ}\text{C}[/tex]

Explanation:

[tex]P_1[/tex] = Initial pressure = 2.77 atm

[tex]V_1[/tex] = Initial volume = 263 mL

[tex]T_1[/tex] = Initial temperature = [tex]47^{\circ}\text{C}=(47+273.15)\ \text{K}[/tex]

[tex]P_2[/tex] = Final pressure = 3.87 atm

[tex]V_2[/tex] = Final volume = 197 mL

[tex]T_2[/tex] = Final temperature

We have the relation

[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow T_2=\dfrac{P_2V_2}{P_1V_1}\times T_1\\\Rightarrow T_2=\dfrac{3.87\times 195}{2.77\times 263}\times (47+273.15)\\\Rightarrow T_2=331.63\ \text{K}=331.63-273.15\\\Rightarrow T_2=58.48^{\circ}\text{C}[/tex]

The final temperature will be [tex]58.48^{\circ}\text{C}[/tex].

Answer:

84.3 g of nitrogen triiodide is the theoretical yield.

Explanation:

Hello there!

In this case, according to the chemical reaction:

[tex]N_2 + 3I_2 \rightarrow 2NI_3[/tex]

It is possible to compute the theoretical yield of nitrogen triiodide by each reactant via stoichiometry as shown below:

[tex]m_{NI_3}^{by\ N_2}=4.49gN_2*\frac{1molN_2}{28.01gN_2} *\frac{2molNI_3}{1molN_2}*\frac{394.72gNI_3}{1molNI_3} =126.55gNI_3\\\\m_{NI_3}^{by\ I_2}=81.3gI_2*\frac{1molI_2}{253.81gI_2} *\frac{2molNI_3}{3molI_2}*\frac{394.72gNI_3}{1molNI_3} =84.29gNI_3[/tex]

Therefore, we infer that the smallest amount is the correct theoretical yield as it comes from the limiting reactant, in this case, diatomic iodine as it yields 84.3 g (three significant figures) of nitrogen triiodide as the theoretical yield; incidentally, nitrogen acts as the excess reactant.

Best regards!

Answer:

0.42 J/gºC

Explanation:

We'll begin by calculating the heat energy used to heat up the water. This can be obtained as follow:

Mass (M) of water = 560 g

Initial temperature (T₁) = 22.7 °C

Final temperature (T₂) = 80.3 °C.

Specific heat capacity (C) of water = 4.18 J/gºC

Heat (Q) absorbed =?

Q = MC(T₂ – T₁)

Q = 560 × 4.18 (80.3 – 22.7)

Q = 2340.8 × 57.6

Q = 134830.08 J

Finally, we shall determine the specific heat capacity of the burner. This can be obtained as follow:

Mass (M) of burner = 699 g

Initial temperature (T₁) = 482.0°C

Final temperature (T₂) = 22.7 °C

Heat (Q) evolved = – 134830.08 J

Specific heat capacity (C) of the burner =?

Q = MC(T₂ – T₁)

–134830.08 = 699 × C (22.7 – 482.0)

–134830.08 = 699 × C × –459.3

–134830.08 = –321050.7 × C

Divide both side by –321050.7

C = –134830.08 / –321050.7

C = 0.42 J/gºC

Therefore, the specific heat capacity of the burner is 0.42 J/gºC

Answer:

Im gonna go with.... B. False

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Yes it is true. That physical chemistry is a bridge between physics and chemistry. Because here we study the physical behaviours of the chemical reactions.

Answer:

spring tides is the correct answer of your question

Answer: 1. A, 2.B, 3. D, 4. B, 5. C

Explanation:

i have P.E. too lol have a great day!