Which of the following is an equivalent expression of 14x² +18x + 5?
A 32x³ +5
B 14x²(18x + 5)
C 5(14x² + 18x)
D 18x + 14x² +5

Answer:

Step-by-step explanation:

Let total mass be x

(3/4)*x=15

on solving

x=20

now,

mass of 2/5 of piece of metal is-

=> (2/5)*20

=> 8

Ans- 8kg

Answer:

y = (-2/3)x + 6

Step-by-step explanation:

To find the equation of the line that passes through the points (-3, 8) and (6, 2), we can use the slope-intercept form of the equation of a line, which is:

y = mx + b

where m is the slope of the line and b is the y-intercept, which is the point where the line crosses the y-axis.
To find the slope of the line, we can use the following formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are two points on the line. Plugging in the coordinates of the two points given in the problem, we get:

m = (2 - 8) / (6 - (-3)) = -6/9 = -2/3

Next, we need to find the y-intercept of the line. This is the point where the line crosses the y-axis, which means that the x-coordinate of this point is 0. Since we know the slope of the line and one of the points that it passes through, we can use the point-slope form of the equation of a line to find the y-intercept:

y - y1 = m(x - x1)

Substituting the values we have calculated above and setting x = 0, we get:

y - 8 = (-2/3)(0 - (-3))

Solving for y, we find that the y-intercept is 8 - (2/3) * 3 = 8 - 2 = 6.

Therefore, the equation of the line that passes through the points (-3, 8) and (6, 2) is:

y = (-2/3)x + 6

The farthest drainage ditch​ is 39 feet away from the well.

The length of the line segment bridging two points on a plane is known as the distance between the points.

The formula to find the distance between the two points is usually given by d=√{(x₂-x₁)² + (y₂-y₁)²}

Given, an environmental engineer graphed the locations of a well and all the drainage ditches in the vicinity.

She positioned the well at (−6,7) and the farthest drainage ditch at (33,7).

To find the distance:

Let d be the distance.

d = √{(x₂-x₁)² + (y₂-y₁)²}

Here, x₂ = 33, x₁ = -6, y₂ = 7 and y₁ = 7

Substituting the value to the distance formula,

d = √{(33+6)² + (7-7)²}

d = √{(39)² + (0)²}

d = √{(39)²

d = 39

Therefore, the value of d is 39.

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Answer:

Below

Step-by-step explanation:

w = 7 - sqrt (g)    ?? ( syntax is unclear in your post)

sqrt(g) = 7-w

g = (7-w)^2

To expand the expression (x + 10)(3x² + 5x - 2), we can use the distributive property, which states that for any numbers a, b, and c, the product (a + b)(c) can be written as a * c + b * c. Applying this property to the given expression, we get (x + 10)(3x² + 5x - 2) = (x * 3x² + 10 * 3x²) + (x * 5x + 10 * 5x) + (x * -2 + 10 * -2) = 3x³ + 30x² + 5x² + 50x - 2x - 20. Combining like terms, we get 3x³ + 35x² + 51x - 20. Thus, the expanded form of the expression (x + 10)(3x² + 5x - 2) is 3x³ + 35x² + 51x - 20.

Answer:

No solution

Step-by-step explanation:

The numerical expression to represent the rate of temperature change in degrees Fahrenheit per foot is 0.14 degrees Celsius per foot.

What do you mean by numerical expression?

A group of numbers that have been written together using the arithmetic operations addition, subtraction, multiplication, and division is known as a numerical expression in mathematics. The number can be stated in a variety of ways, including verbally and numerically.

According to the given question,

To calculate the rate of temperature change in degrees Fahrenheit per foot,

We need to first convert degrees Fahrenheit to degrees Celsius.

To do this, we divide 100 by 5.9.

This yields a result of 0.14 degrees Celsius per foot.

Therefore, the numerical expression to represent the rate of temperature change in degrees Fahrenheit per foot is 0.14 degrees Celsius per foot.

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The answer, based on the information provided, fractional exponents will be 3.

A product in which the same integer is used repeatedly as a factor is represented by a number elevated to a power. The exponent provides the power, and the integer is referred to as the base. The exponent indicates the number of factors, while the base is the repeating factor (the multiplied number).

That number will be the outcome! One of the simplest exponent laws is this one. You'll see that this rule doesn't merely apply to numerical data. We might, for example, elevate a statistic to the initial power.

[tex]=3^{\frac{1}{4} }\times3^{\frac{1}{4} }\times3^{\frac{1}{4} }\times3^{\frac{1}{4} }\\=3^{\frac{1}{4}+{\frac{1}{4}+{\frac{1}{4}+{\frac{1}{4}\\\\=3^{1} \\=3[/tex]

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Answer:30x^2 - 54x - 18

Step-by-step explanation: To find the product of f and g, we can simply multiply the expressions for f and g together. The product of f and g is:

(f * g)(x) = (6x + 2)(-5x - 9)

          = -30x^2 - 54x - 18

So, the product of f and g is -30x^2 - 54x - 18

The different combinations of groups for the group project is (b) 560

From the question, we have the following parameters that can be used in our computation:

Total number of people, n = 16

Numbers to selection, r = 3 people

The number of ways of selection could be drawn is calculated using the following combination formula

Total = ⁿCᵣ

Where

n = 16 and r = 3

Substitute the known values in the above equation

Total = ¹⁶C₃

Apply the combination formula

ⁿCᵣ = n!/(n - r)!r!

So, we have

Total = 16!/(13! * 3!)

Evaluate

Total = 560

Hence, the number of ways is 560

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Answer:

Step-by-step explanation:

There is a scale factor of 2 so since the trapezoid is 9 we can divide by 2 so AD is 4.5 and CB is 4.5

YZ is the same as ZW so 8

Using the scale factor we can divide 8 by 2 to get 4

Perimeters can be found from the sums so

ABCD would be 19 and WXYZ would be 38

[tex] \Large{\boxed{\sf \dfrac{1 + 2i}{3 - 4i} + \dfrac{2 - i}{5i } = - \dfrac{2}{5}}} [/tex]

[tex] \\ [/tex]

Given sum:

[tex] \sf \: \dfrac{1+2i}{3-4i} + \dfrac{2-i}{5i}[/tex]

[tex] \\ [/tex]

We can simplify the sum only if the denominators of the two fractions are the same. Since they are different, we have to multiply the numerator and the denominator of each fraction by the denominator of the other one.

[tex] \sf \: \dfrac{1+2i}{3-4i} + \dfrac{2-i}{5i} = \dfrac{5i(1 + 2i)}{5i(3 - 4i)} + \dfrac{(3 - 4i)(2 - i)}{(3 - 4i)5i} \\ \\ \\ \sf \: = \dfrac{5i + 10 {i}^{2} }{15i - 20 {i}^{2} } + \dfrac{6 - 3i - 8i + 4 {i}^{2} }{15i - 20 {i}^{2} } [/tex]

[tex] \\ [/tex]

Replace i² with -1:

[tex] \sf \dfrac{5i + 10 {i}^{2} }{15i - 20 {i}^{2} } + \dfrac{6 - 3i - 8i + 4 {i}^{2} }{15i - 20 {i}^{2} } \: \\ \\ \\ \\ \sf \: = \dfrac{5i + 10( - 1)}{15i - 20( - 1)} + \dfrac{ 6 - 11i + 4( - 1)}{15i - 20( - 1)} \\ \\ \\ \\ \sf = \dfrac{5i - 10}{20 + 15i} + \dfrac{2 - 11i}{20 + 15i} [/tex]

[tex] \\ [/tex]

Simplify the expression:

[tex] \sf = \dfrac{5i - 10}{20 + 15i} + \dfrac{2 - 11i}{20 + 15i} \\ \\ \\ \\ \sf \: = \dfrac{5i - 10 + 2 - 11i}{ 20 + 15i} = \sf \dfrac{ - 8 - 6i}{20 + 15i}[/tex]

[tex] \\ [/tex]

To write our solution in the x + iy form, also known as the algebraic form, we have to understand what the conjugate of a complex number is.

[tex] \textsf{Let z be our complex number, and} \: \overline{\sf z} \: \textsf{its conjugate.} [/tex]

[tex] \\ [/tex]

The conjugate of z, [tex] \overline{ \sf z}, [/tex] is the complex number formed of the same real part as z but of the opposite imaginary part.

Since x is the real part of z, and y is its imaginary part, this can be expressed as:

[tex] \sf If \: z = x + iy \:, then \: \overline{ \sf z} = x - iy [/tex]

[tex] \\ [/tex]

Now, we have to multiple both the denominator and the numerator of our fraction by the conjugate of its denominator:

[tex]\sf \dfrac{ - 8 - 6i}{20 + 15i} = \dfrac{( - 8 - 6i)( \overbrace{20 - 15i}^{ \overline{z}}) }{ (20 + 15i)( \underbrace{20 - 15i}_{ \overline{z}}) } \\ \\ \\ \sf = \dfrac{ - 160 + 120i - 120i + 90 {i}^{2} }{400 - 300i + 300i - 225 {i}^{2} } \\ \\ \\ \sf = \dfrac{ - 160 + 90 {i}^{2} }{400 - 225 {i}^{2} }[/tex]

[tex] \\ [/tex]

One more time, substitute -1 for i²:

[tex] \sf \: \dfrac{ - 160+ 90 {i}^{2} }{400 - 225 {i}^{2} } \: = \dfrac{ - 160 + 90( - 1)}{400 - 225( - 1)} \\ \\ \\ \sf = \boxed{\sf - \dfrac{ 250}{625}} [/tex]

[tex] \\ [/tex]

Finally, let's simplify our result:

[tex] \sf - \dfrac{250}{625} = - \dfrac{2 \times 125}{5 \times 125} = \boxed{ \boxed{ \sf - \dfrac{2}{5}}}[/tex]

[tex] \\ \\ [/tex]

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Answer:

Translation: 4 to the right and 8 up.

Scale factor: 3

Step-by-step explanation:

If you move CDE 4 spaces to the right and 8 spaces up C and C' will match up. If you dilate (make bigger) CDE 3 times it will perfectly be C'D'E'.

Answer:

a)1/216

b)1/36

Step-by-step explanation:

p(2r)and p(3b) and p(4g)

1/6×1/6×1/6=1/216

p(4r) and p(even b) and p(no less than 3)

1/6×3/6×2/6=1/36

Answer:

Step-by-step explanation:

Let, the Speed of the water be 'x'

and the Radius be 'r'

Now, the speed of Water Varies inversely with the Radius

So, x ∝ 1/r

      x = k/r   -----------(i)

Here, k is the proportionality constant

Now,

Given that, x = 2.5 ft per sec

then, 30 ft,

So, from eq. (i)

               2.5 = k/30

          So, k = 75

Again From eq. (i)

                    x = 75/r

          Now, if r = 3ft

           then, x = 75/3

                     x = 25

Hence, Speed of the water (x) = 25 ft per sec.

Answer:

72kg

Step-by-step explanation:

Stephen = 72

Saravanan = x

Shamsul = (x • 1.5) since Shamsul's mass is 1.5 times Saravanan's mass

1. make an equation:

( 72 + x + (x • 1.5) ) ÷ 3 = 64

2. solve it:

( 72 + x + (x • 1.5) ) ÷ 3 = 64

( 72 + x + (x • 1.5) ) = 64 • 3

( 72 + x + (x • 1.5) ) = 192

x + 1.5x = 192 - 72

2.5x = 120

x = 120 ÷ 2.5

x = 48

Thus shamsul's mass is:

48 • 1.5 = 72kg

Answer:

  £46

Step-by-step explanation:

You want to know the cost of luggage in the hold when 2 in the hand and 1 in the hold is £86, and 1 in the hand and 1 in the hold is £66.

Let 'a' and 'b' represent the costs of a piece of hand luggage and one in the hold, respectively. Then the given relations are ...

  2a +b = 86

  a +b = 66

Subtracting the first equation from twice the second gives ...

  2(a +b) -(2a +b) = 2(66) -(86)

  b = 46 . . . . . . . simplify

It costs £46 to put an item of luggage in the hold.

Answer:

Step-by-step explanation:

To find the linearization of the function f(x) = sqrt(x) at x = a, we can use the linearization formula:

f(x) ≈ f(a) + f'(a) (x - a)

To use this formula, we first need to find the value of f(a) and f'(a). At x = a = 4, the value of f(x) is f(4) = sqrt(4) = 2. The derivative of f(x) is f'(x) = 1/(2 * sqrt(x)), so the value of f'(a) is f'(4) = 1/(2 * sqrt(4)) = 1/4.

Substituting these values into the linearization formula, we get:

f(x) ≈ 2 + 1/4 (x - 4)

This is the linearization of f(x) = sqrt(x) at x = 4. It is an approximation of the function f(x) that is valid for values of x that are close to 4.

The first, second, third, and fourth consecutive even integers must be greater than 10, 12, 14, and 16 respectively.

A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.

Let the four consecutive even integers be n, (n + 2), (n + 4) and (n + 6).

Such that twice the sum of the second and third exceeds 3 times the first by 32.

2{(n + 2) + (n + 4)} > 3(n) + 32.

2n + 4 + 2n + 8 > 3n + 32.

4n - 3n > 32 - 12.

n > 10.

So, the consecutive even numbers must all be greater than 10.

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Answer: 24

Step-by-step explanation:

Answer:

h = 24

Step-by-step explanation:

The number 'n' is equal to 14

In the question, we have been given that the number n is equal to 7 more than half of the number 'n'.

So in these linear equation-solving types of problems, first of all, we convert the written sentence into an equation.

So the equation for the following problem statement is -

n = 7 + n/2  

{since we have been given the number equals 7 more than half of the number }

Solving the equation we have,

n = 14.

We can easily see that 14 is the number which is 7 more than half of itself.

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Answer:

see explanation

Step-by-step explanation:

(a)

given y is inversely proportional to x² then the equation relating them is

y = [tex]\frac{k}{x^2}[/tex]

to find k use any ordered pair from the table

using (1, 4 ) and substituting into equation

4 = [tex]\frac{k}{1^2}[/tex] = [tex]\frac{k}{1}[/tex] , thus

k = 4

y = [tex]\frac{4}{x^2}[/tex] ← equation of proportion

(b)

when y = 25 , then

25 = [tex]\frac{4}{x^2}[/tex] ( multiply both sides by x² )

25x² = 4 ( divide both sides by 25 )

x² = [tex]\frac{4}{25}[/tex] ( take square root of both sides )

x = ± [tex]\sqrt{\frac{4}{25} }[/tex] = ± [tex]\frac{2}{5}[/tex]

then

positive value of x when y = 25 is x = [tex]\frac{2}{5}[/tex]

Answer: -10,-8.7, -9.1, 8, 8.7, 8.06, 9

Step-by-step explanation:

77 squared rooted equals 8.7

-83 square rooted equals -9.1

-76 square rooted equals -8.7 ( remember negative numbers are greater than positive numbers)

65 square rooted equals 8.06

Using mathematical operations on the word problem, the amount he will receive as his change is $1.43

A word problem is a few words are presented in a form of problem and  needs to be solved by way of a mathematical calculation.

This problem can be solved using mathematical operation such as addition and subtraction.

The total amount he has with him = $15

The current bill = $8.33

The fruit salad = $2.99

Tip = $2.25

Total amount spent = 8.33 + 2.99 + 2.25

The total amount spent = 13.57

The amount of change = total amount he has with him - total amount spent

The amount of change = 15 - 13.57

The amount of change = 1.43

The change he is going to receive is $1.43

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Answer:

Step-by-step explanation: for the first part, 525/7 = 75.

for the second part, 55y = x, which means 55 words per day for a total of (55*7) or 385

for the third part, 1200-525-385=290, not totally sure, but I think this is the answer, the text was a bit blurry and I couldn't understand everything, try not to following this blindly and just see if it makes sense. Hope I could help

Answer:

2

Step-by-step explanation:

-2(-3)+18=24

6+18 = 24

24 = 24

6(-3) +9=-13

-18+9 = -13

-9 ≠ - 13

4(-3)-9=-21

-12 -9 =-21

-21 = -21

The measure of the angle ∠MAR will be equal to 26°. The correct option is A.

In geometry, an angle bisector is a line that divides an angle into two equal angles. A bisector is something that divides a shape or object into two equal parts. An angle bisector is a ray that divides an angle into two equal parts of the same measurement.

Given that Ray AT bisects ∠MAR. If m∠MAT = (8x − 3)° and m∠RAT = (2x + 9)°,

The two angles ∠MAT and ∠RAT will be equal. Then calculate the value of x.

8x - 3 = 2x + 9

8x - 2x = 9 + 3

6x = 12

x = 2

The angle ∠MAR is calculated as,

∠MAR = 2 x ∠RAT

∠MAR = 2 x ( 2x + 9)

∠MAR = 2 x ( 2 x 2 + 9 )

∠MAR = 2 x ( 13 )

∠MAR  = 26°

Option A is correct for the angle ∠MAR.

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Answer:

A all the way

Step-by-step explanation:

We have proved that the ray FE is parallel to the ray GC.

What is meant by parallel lines?

In geometry, parallel lines are coplanar straight lines that do not intersect at any point. Parallel planes are planes in the same three-dimensional space that never meet. Parallel curves are curves that do not touch each other or intersect and keep a fixed minimum distance.

Angle DEF intersects at B

which results in angle DEF corresponding to the angle  ACG.

As DEF = 45 so angle ACG = 45

So by the above discussion, we can say that the ray FE is parallel to the ray GC.

Hence, we have proved that the ray FE is parallel to the ray GC.

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Step-by-step explanation:

since it is geometric sequence we will use the formula

[tex]tn = {ar}^{n - 1} [/tex]

a = 6

r = 4

The first term

T1(a) = 6

The second term

[tex]t2 = {a \times r}^{2 - 1} [/tex]

[tex]t2 = {6 \times 4}^{1 } = 24[/tex]

The Third Term

[tex]t3 = {a \times r}^{3 - 1} = {a \times r}^{2} [/tex]

[tex]t3 = {6 \times 4}^{2} = 6 \times 16 = 96[/tex]

The fourth term

[tex]t4 = {a \times r}^{4 - 1} = {a \times r}^{3} [/tex]

[tex]t4 = {6 \times 4}^{3} = 6 \times 64 = 384[/tex]

The fifth term

[tex]t5 = {a \times r}^{5 - 1} = {a \times r}^{4} [/tex]

[tex]t5 = {6 \times 4}^{4} = 6 \times 256 = 1,536[/tex]

i hope these helped

Answer:

6, 24, 96, 384, 1536, ...

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{5.5 cm}\underline{Geometric sequence}\\\\$a_n=ar^{n-1}$\\\\where:\\\phantom{ww}$\bullet$ $a$ is the first term. \\\phantom{ww}$\bullet$ $r$ is the common ratio.\\\phantom{ww}$\bullet$ $a_n$ is the $n$th term.\\\phantom{ww}$\bullet$ $n$ is the position of the term.\\\end{minipage}}[/tex]

Given:

Substitute the given values of a and r into the formula to create an equation for the nth term:

[tex]a_n=6(4)^{n-1}[/tex]

To find the first 5 terms of the geometric sequence, substitute n = 1 through 5 into the equation.

[tex]\begin{aligned}\implies a_1&=6(4)^{1-1}\\&=6(4)^{0}\\&=6(1)\\&=6\end{aligned}[/tex]

[tex]\begin{aligned}\implies a_2&=6(4)^{2-1}\\&=6(4)^{1}\\&=6(4)\\&=24\end{aligned}[/tex]

[tex]\begin{aligned}\implies a_3&=6(4)^{3-1}\\&=6(4)^{2}\\&=6(16)\\&=96\end{aligned}[/tex]

[tex]\begin{aligned}\implies a_4&=6(4)^{4-1}\\&=6(4)^{3}\\&=6(64)\\&=384\end{aligned}[/tex]

[tex]\begin{aligned}\implies a_5&=6(4)^{5-1}\\&=6(4)^{4}\\&=6(256)\\&=1536\end{aligned}[/tex]

Therefore, the first 5 terms of the given geometric sequence are: