Which missing item would complete this alpha decay reaction?

Among the elements Barium has the lowest Ionization Energy.

The process by which any neutral atom gets converted into electrically charged by gaining or losing electron is called Ionization Process.

K  is an alkali metal  it has to lose one electron to attain stable electronic configuration of an inert gas

For removing second electron , a stable configuration has to be broken and so will require high amount of energy.

Ca and Ba are alkaline earth metals.

They both have to lose 2 electrons to attain  stable electronic configuration of noble gas.

They have low Iow Ionization Energy as compared to K.

Ca has higher  Ionization Energy as compared to Ba because when we move down the periodic table , The ionization energy decreases.

Hence , Among the elements Barium has the lowest Ionization Energy.

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The pressure of the carbon dioxide will be 0.09079 atm.

The pressure exerted by the individual gas is known as partial pressure.

The partial pressure is given as

[tex]\rm P_{Total} = P_1 + P_2 + ...[/tex]

In a mixture of carbon dioxide and oxygen, 40.0% of the gas pressure is exerted by oxygen.

If the total pressure is 115 mmHg.

The total pressure in atm will be

P = 115 mmHg

P = 0.15132 atm

We have

[tex]\rm P_T \ \ \ = P_{O_2} + P_{CO_2}\\\\0.15132 \ \ = 0.4 \times 0.15132 +P_{CO_2}\\\\ P_{CO_2} = 0.09079\ atm[/tex]

Then the pressure of the carbon dioxide will be 0.09079 atm.

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Answer:

5.7400 × 10⁻⁵

Explanation:

Answer: 339.84 K

Explanation:

[tex]$$We are given: \\$\mathrm{n}=0.46$ moles \\$V=13.3 \mathrm{~L}$\\$\mathrm{P}=734 \mathrm{~mm} \mathrm{Hg}=0.965 \mathrm{~atm}$\\Putting these values in ideal gas equation we get:\\$0.965$ batm * $13.3 \mathrm{~L}=0.46 \mathrm{~mol} * 0.0821 \frac{\mathrm{atmL}}{\mathrm{molK}} * \mathrm{~T}$\\$\mathrm{T}=\frac{0.965 * 13.3}{0.46 * 0.0821} \mathrm{~K}$$$\mathrm{T}=339.84 \mathrm{~K}$$[/tex]

Explanation:

the law of conservation of mass

Answer:

Explanation:

the law of conservation of mass

The hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

Rate law depicts the rate of a chemical reaction depend on the concentration of the reactant.

The given reaction is second order reaction

Thus, the hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

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Answer:

An Arrhenius base is a substance that dissociates in water to form hydroxide (OH–) ions. In other words, a base increases the concentration of OH– ions in an aqueous solution.

The available energy decreases as one moves upward in an energy pyramid.

The energy pyramid represents a model of how energy is transferred from one trophic level to another in ecosystems.

Energy is transferred from producers to primary consumers, from primary to secondary consumers, from secondary to tertiary consumers, and so on.

Only about 10% of the available energy in one trophic level is transferred to the next with the remaining 90% being lost as heat to the environment.

Thus, as one moves up the energy pyramid, the available energy decreases. This is why organisms at the higher end of the energy pyramid have to devise an efficient way of extracting energy from their foods.

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Answer:

11–350°

Explanation:

If the mass number of an atom is 29, and it has 13 protons and 13 electrons, the identity of this atom is Aluminum.

An atom is the smallest indivisible particle of an element which still retains its chemical identity.

An atom consists of a nucleus surrounded by electrons. The nucleus is made up of protons and neutrons.

The identity of a chemical element is determined by its electron and proton number, which is the same for a neutral atom.

According to this question, the atom of an element has 13 protons and 13 electron. This suggests that the atom is that of Aluminum.

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Lithium reacts with one atom of fluorine, and the atomic mass of fluorine is 38 amu.

The atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit.

One lithium (Li) atom can combine with one fluorine (F) atom. Together, they make the formula LiF.

Fluorine has seven electrons of it's own. Lithium gives up its one electron to make both atoms happy.

Hence, lithium reacts with one atom of fluorine, and the atomic mass of fluorine is 38 amu.

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The total pressure in the container after the three gases are mixed is 6 atm and the partial pressure of He is 1 atm.

According to Dalton's Law of Partial Pressure , the pressure exerted by a mixture of gas is equal to the sum of the partial pressure of the gases in the mixture.

P(total) = p₁ +p₂+p₃+.....

As the volume of the containers are same and the

n = 1*5/RT for Helium

n = 2*5 /RT for Neon

n= 3*5/RT for Argon

Mole fraction = moles of the element/Total moles

Moles fraction of Helium is

[tex]\rm \dfrac{1*5}{1*5+2*5+3*5}[/tex]

= 1/6

Total Pressure in the container = 1 + 2 +3 = 6 atm

The partial pressure of Helium will be

=Mole fraction * Total pressure

=(1/6)*6 atm

= 1 atm , as the volume is same the temperature is same , the pressure will also be same.

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Answer:

True

Explanation:

Answer:

Explanation:

Remark

It's true.

That's how the  periodic table is designed. Hydrogen is #1 and #116 is the latest entry. It is known as  flerovium and livermorium. I'm not sure if that and shouldn't be an or, but that is your answer.

Answer: 78.919 amu

Explanation:

If the natural abundance of Br-81 is 49.310%, then the natural abundance of Br-79 must be 100%-49.310%=50.690%

Substituting into the atomic mass formula,

[tex]79.904=(0.49310)(80.9163)+(0.50690)(x)\\79.904=39.89982753+(0.50690)(x)\\40.00417247=(0.50690)(x)\\x=\frac{40.00417247}{0.50690}=\boxed{78.919 \text{ amu}}[/tex]

Answer:Not the same class but it will give u 100%

Explanation:

1. This experiment was to find how mass and speed effect KE. This is important because if you were in a situation where you needed something to go higher, you would know to add more or less of mass/speed.  

To test mass, we filled the bean bag with a certain amount of water, then dropped it. After, you recorded how high it made the bean bag go. The same with speed, but same amount in the bottle, just dropped from different heights.  

My hypothesis is when you have more mass, the KE will be greater. This is also the same with speed, if it is dropped from a higher place, the bean bag will launch farther than the last time.  

2. Data I collected from the lab was like my hypothesis explained. When the height of the bottle increased, it made the bean bag go higher than the last. And I tested 4 different masses, 0.125 kg, 0.250kg, 0.375kg and 0.500kg. Each time the bean bag went higher on a larger mass.  

A lot of times on the speed test, the bean bag would go higher than the bottle drop point, but not every time. Also, when it was dropped from the same height each time, some results varied quite a bit, like when it was dropped from 1.28 the results were 1.14 then 1.30 1.30. Mass on the other hand was all in the same number range, only once the numbers were a bit off from each other.  

3.  Some formulas I used were KE= ½ mv^2 and Ht v^2/2g. The first was to calculate the kinetic energy of an object, m=mass v=speed. Second was for finding out what height I needed to drop something to reach a certain speed, Ht=Height and g= Gravitational Acceleration of 9.8 m/s^2.  

I used these to figure out tables that showed relationships between different things like mass and KE or speed and height. The whole time I was doing the lab, my data was going up, when there was more mass/speed there were higher values in the table.  

This means that my hypothesis at the beginning was correct, more of m/s means KE will increase proportionally because they are all linear. I found it surprising when the bean bag height went over the water bottle drop mark.  

4.     To conclude, my hypothesis matched my data. The data values went up when more mass or speed was added. This means if I were in a situation where I needed more kinetic energy for something, I would know to increase mass or the speed of the object giving it energy.  

The reason that this hypothesis is correct is when you have more mass, you have more energy. So, when you drop let's say a baseball, it isn’t that heavy so it would only launch the bean bag so far. But a bowling ball is very heavy and has lots of energy when falling because of that, it would make the bean bag go very high.  

To make this experiment better, I would use a smoother material for the lever so energy wouldn’t be lost by friction from wood rubbing together. Also, maybe a scanner or video camera to more accurately record how far the bean bag went. All of these would help the lab get more precise results, maybe they could be used in a future lab.

The temperature of the gas would be 81.2 K

The ideal gas equation is given by:

PV = nRT, where P, V, n, R, and T equals pressure, volume, number of moles, constant, and temperature respectively.

In this case, V = 8L, n = 3 moles, R = 8.317, and P = 2.5 atm or 253.3125 kpa

T = PV/nR = 253.3125 x 8/3 x 8.317 = 2026.5/24.951 = 81.2 K

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From the calculation, the age of the sample of carbon - 14 is 9156 years.

The term radioactivity refers to the fact that a substance could disintegrate spontaneously when left alone.

Now, given that;

0.693/t1/2 = 2.303/t log (No/N)

t1/2 = half life

t = age of the sample

No = amount of sample originally present

N = amount of sample present at time t

Hence;

0.693/5730 =  2.303/t  log (9216/3072)

1.2 * 10^-4 =  2.303/t * 0.4771

1.2 * 10^-4 = 1.09876/t

t =  1.09876/1.2 * 10^-4

t = 9156 years

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If the temperature of the sample of gas increases to the given value, the volume also increases to 600mL.

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

V₁/T₁ = V₂/T₂

V₂ = V₁T₂ / T₁

V₂ = ( 300mL × 200K ) / 100K

V₂ = 60000mLK / 100K

V₂ = 600mL

Therefore, if the temperature of the sample of gas increases to the given value, the volume also increases to 600mL.

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The reaction that occur at the anode of an electrochemical cell is Zn(s) Zn²+ (aq) + 2e. The correct option is B.

An electrochemical cell has two eletcrodes present in an solution. The one electrode is anode where oxidation occurs and second is cathode hwere reduction occurs.

The reaction Zn(s) = Zn²+ (aq) + 2e due to oxidation chrage is added here.

Thus, the correct option is B. Zn(s) = Zn²+ (aq) + 2e.

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An advantage of describing a system with a mathematical model is that it enables people to calculate how a change in one variable will affect other variables.

A mathematical model usually describes a system by a set of variables and equations that formed relationships between the variables. Variables examples such as real or integer numbers.

So we can conclude that An advantage of describing a system with a mathematical model is that it enables people to calculate how a change in one variable will affect other variables.

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Answer:

0.24%

Explanation:

A toothpaste contains 0.24% by mass sodium fluoride (NaF) used to prevent dental caries and 0.30% by mass triclosan, C12H7Cl3O2, a preservative and antigingivitis agent. One tube contains 119 g of toothpaste. (6.4, 6.5) Components in toothpaste include triclosan and NaF.a. How many moles of NaF are in the tube of toothpaste?b. How many fluoride ions (F?) are in the tube of toothpaste?c. How many grams of sodium ion (Na+) are in 1.50 g of toothpaste?d. How many molecules of triclosan are in the tube of toothpaste?Solution 124CQStep 1 of 4:Given:Mass of toothpaste = 119 g. Mass percent of sodium fluoride (NaF) = 0.24%Mass percent of triclosan (C12H7Cl3O2) = 0.30%a. Here, we are asked to find the number of moles of NaF in the tube of toothpaste.Mass percent of sodium fluoride (NaF) = 0.24%First, let’s find the mass of NaF in the tube: = 119 g = 0.2856 grams Molar mass of NaF = 41.98 g/mol This means, 1 mol NaF = 41.98 g. So, the mole-mass factor is: and Therefore, number of moles of NaF will be: = 0.2856 g NaF = 0.00680 mol NaFHence, the number of moles of NaF in 119g toothpaste is 0.00680 moles. ________________

According to mole concept, there are 41.988 grams   in 1 mole NaF that is sodium fluoride.

Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.

It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.

It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Molar mass has units of gram per mole . In case of molecules, where molar mass  in grams present in one mole  of atoms is its atomic mass.

Number of moles is given by the formula, mass/molar mass and hence mass= 1×41.988= 41.988 g.

Thus, there are 41.988 g in 1 mole NaF.

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Answer:

to attain stability atoms form covalent bonds

Answer:

Gas tests include:

hydrogen - lighted splint goes out with a squeaky pop.

Explanation:

Answer:

0.254 M

Explanation:

If the formula mass of sugar is 342.3 g/mol, and there are 65.3 g, then there are 65.3/342.3=0.190768 mol.

Also, 750 mL = 0.750 L.

molarity = (moles of solute)/(liters of solution)

molarity = 0.190768/0.750 = 0.254 M

There is no reaction when you add catalase to sucrose.

Sucrose is a disaccharide that consist of glucose and fructose. Both glucose and fructose are hexoses.

Owing to the fact that catalase is specific to sucrose, there is no reaction when you add catalase to sucrose.

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Answer:

I think the Molar mass of H₂CO₂ should be 62..

Explanation:

I'm not too sure tho... Hope this helps!

3.

Explanation:

all Chemical mixtures have the same amount of numbers making them all balanced.

(that's the simple way of putting it, but hoped it helped ✌)

Answer:

four

Explanation:

There is four

CH 4    methane

O2      oxygen

CO2    carbon dioxide

H20    water