Which linear inequality is represented by the graph?

Which Linear Inequality Is Represented By The Graph?

Answers

Answer 1

The linear inequality that is represented by the graph is y ≤ x/3 - 4. The correct option is the second option y ≤ x/3 - 4

Graph of Linear inequalities

From the question, we are to determine the linear inequality that is represented by the graph

First, we will determine two points on the line

The line in the graph passes through (0, -4) and (3, -3)

Using the equation,

(y - y₁)/(x - x₁) = (y₂ - y₁)/(x₂ - x₁)

(y - -4)/(x - 0) = (-3 - (-4))/(3 - 0)

(y + 4)/x = (-3 + 4)/3  

(y + 4)/x = 1/3

y + 4 = 1/3x

y = 1/3x - 4

y = x/3 - 4

This is the equation of the line

In the given graph, the line is a solid line and the solution of the inequality is below the line

Thus,

The inequality becomes y ≤ x/3 - 4

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Related Questions

Figure out how many offspring there would be for the fifth and sixth generations using the equation

Answers

Explanation

We are given the following:

The table above models the function:

[tex]\begin{gathered} f(x)=a(4)^x \\ where \\ a=initial\text{ }value\text{ }(when\text{ }the\text{ }generation)=0 \\ x=generation \end{gathered}[/tex]

We are required to determine how many offspring there would be for the fifth and sixth generations using the equation.

This is achieved thus:

[tex]\begin{gathered} \text{ Offspring:} \\ Fifth\text{ }generation\to a(4)^x \\ where \\ a=6 \\ x=5 \\ F\imaginaryI fth\text{ }generat\imaginaryI on\to6(4)^5=6144 \end{gathered}[/tex][tex]\begin{gathered} Sixth\text{ }generation\to a(4)^x \\ where \\ a=6 \\ x=6 \\ S\imaginaryI xth\text{ }generat\imaginaryI on\to6(4)^6=24576 \end{gathered}[/tex]

Hence, the answers are:

[tex]\begin{gathered} 5th\text{ }generation=6144 \\ 6th\text{ }generation=24576 \end{gathered}[/tex]

Can someone please explain to me where I did my math wrong and correct me. The answer is supposed to be $1065.00

The problem says: Lonnie Flanagan's weekly gross pay is $1250. Each week she has $64.37 in deductions, plus state tax of 2% of her gross pay, social security taxes of 6.2%, and Medicare taxes of 1.45%. What is her net pay?

I did 1250 - 64.37 = 1185.63

1185.63 (2%) = $23.71 State income Tax

1185.63 (6.2%) = $73.51 Social Security Tax

1185.63 (1.45%) = $17.19 Medicare tax

Then I added the 3 together.

$23.71 + $73.51 + $17.19 = $114.41

Then I subtracted $113.41 from $1250.
1250 - 113.41 = $135.59 net pay.
What did I do wrong?

Answers

The net pay for Lonnie Flanagan is $1065.

How to calculate the net pay?

From the information, Lonnie weekly gross pay is $1250 and each week she has $64.37 in deductions, plus state tax of 2% of her gross pay, social security taxes of 6.2%, and Medicare taxes of 1.45%.

Her net pay will be:

= Gross pay - Deduction - Tax - Social security - Medicare

= $1250 - $64.37 - (2% × $1250) - (6.2% × $1250) - (1.45% × $1250)

= $1250 - $64.37 - $25 - $$77.50 - $18.125

= $1065

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Garcia Co. owns equipment that cost $81,600, with accumulated depreciation of $43,200.

Record the sale of the equipment under the following three separate cases assuming Garcia sells the equipment for (1) $50,600 cash, (2) $38,400 cash, and (3) $33,300 cash.

Answers

(1) $50,600 cash implies that $50,600 - $38,400 = $12,200

Hence gets gain of $12,200.

(2) $38,400 cash implies that $38,400 - $38,400 = $0

Hence No profit no loss.

(3) $33,300 cash implies that $33,300 - $38,400 = - $5,100

Hence loss of $5,100.

Depreciation :-

Depreciation is the gross reduction in the book value of an asset due to regular use or wear and tear.

A capital gain occurs when Garcia Co. receives an amount in excess of the book value of the equipment.

If Garcia Co. receives an amount equal to the book value of the equipment, no profit or loss will result from the disposal.

If Garcia Co. receives an amount below the book value of the equipment, it will experience a capital loss.

In the given question cost of equipment is $81,600 with accumulated depreciation of $43,200 so that the book value will be

$81,600 - $43,200 = $38,400.

Now (1) $50,600 cash implies that $50,600 - $38,400 = $12,200

Hence gets gain of $12,200.

For (2) $38,400 cash implies that $38,400 - $38,400 = $0

Hence No profit no loss.

For(3) $33,300 cash implies that $33,300 - $38,400 = - $5,100

Hence loss of $5,100.

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Given the equation 5X-10=50 which properties will be used to solve for XA. Adition and subtractionB. Subtraction and divisionC. Adition and division D. Subtraction and Multiplication

Answers

Let's solve for x and see what properties are used

First, add 10 to both sides of the equation

[tex]\begin{gathered} 5x-10=50 \\ 5x-10+10=50+10 \\ 5x=60 \end{gathered}[/tex]

Now, divide by 5 on both sides of the equation

[tex]\begin{gathered} \frac{5x}{5}=\frac{60}{5} \\ x=12 \end{gathered}[/tex]

Therefore, the correct answer is C. Adition and division

Evaluate and simplify the expression
when a = 2 and b = 4.

4a - 2(a + b) + 1 = [?]

Answers

Answer:

-3

Step-by-step explanation:

4(a) - 2(a + b) + 1 = [?]

4(2) - 2(2+4) + 1

8 - 4 - 8 + 1

appilcation of bodmas

4 - 8 + 1

- 4 + 1

-

3

If XD = 2X – 6 and XV = 3x – 6 and WY and XV bisect at D, what is XV?

Answers

The diagonal WY bisects the diagonal XV at point D, which means that XV is divided into two equal line segments XD and XV.

[tex]XD=XV[/tex]

Replace the equation above with the given expressions for both line segments:

XD= 2x-6

XV= 3x-6

[tex]2x-6=3x-6[/tex]

[tex]undefined[/tex]

Hello! Please take a look at the picture to see the questions, thank you!

Answers

In the question, we are asked to find the degree and the leading coefficient of the polynomial below

[tex]f(x)=3x^4+2x^3+5x^2+7[/tex]

Explanation

The degree of the polynomial is the highest of all the degrees that make up the polynomial. Since each term in the polynomial has a degree we will pick the largest one.

Also, the leading coefficient is the coefficient of the term with the largest degree. Using these concepts, we can derive our answer as.

Answer:

[tex]4,3[/tex]

Option A

If the events have the same theoretical probability of happening, then they are called

Answers

Answer:7937

Step-by-step explanation:7596

16. The height, h, in feet of an object above the ground is given by h = -16t² +64t+190, t≥0, where t is the time in seconds. a) b) c) d) When will the object be 218 feet above the ground? When will it strike the ground? Will the object reach a height of 300 feet above the ground? Find the maximum height of the object and the time it will take.​

Answers

the maximum height is 254 feet.

Answer:

a)  0.5 seconds and 3.5 seconds.

b)  5.98 seconds (2 d.p.)

c)  No.

d)  254 feet at 2 seconds.

Step-by-step explanation:

Given equation:

[tex]h=-16t^2+64t+190, \quad t \geq 0[/tex]

where:

h is the height (in feet).t is the time (in seconds).

Part a

To calculate when the object will be 218 feet above the ground, substitute h = 218 into the equation and solve for t:

[tex]\begin{aligned}\implies -16t^2+64t+190 & = 218\\-16t^2+64t+190-218& = 0\\-16t^2+64t-28 & = 0\\-4(4t^2-16t+7) & = 0\\4t^2-16t+7 & = 0\\4t^2-14t-2t+7 &=0\\2t(2t-7)-1(2t-7)&=0\\(2t-1)(2t-7)&=0\\\implies 2t-1&=0\implies t=\dfrac{1}{2}\\\implies 2t-7&=0 \implies t=\dfrac{7}{2}\end{aligned}[/tex]

Therefore, the object will be 218 feet about the ground at 0.5 seconds and 3.5 seconds.

Part b

The object strikes the ground when h is zero. Therefore, substitute h = 0 into the equation and solve for t:

[tex]\begin{aligned}\implies -16t^2+64t+190 & = 0\\-2(8t^2-32t-95) & = 0\\8t^2-32t-95 & = 0\end{aligned}[/tex]

Use the quadratic formula to solve for t:

[tex]\implies t=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}[/tex]

[tex]\implies t=\dfrac{-(-32) \pm \sqrt{(-32)^2-4(8)(-95)} }{2(8)}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{1024+3040} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{4064} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{16 \cdot 254} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{16} \sqrt{254} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm 4 \sqrt{254} }{16}[/tex]

[tex]\implies t=\dfrac{8\pm \sqrt{254} }{4}[/tex]

As t ≥ 0,

[tex]\implies t=\dfrac{8+ \sqrt{254} }{4}\quad \sf only.[/tex]

[tex]\implies t=5.98 \sf \; s \; (2 d.p.)[/tex]

Therefore, the object strikes the ground at 5.98 seconds (2 d.p.).

Part c

To find if the object will reach a height of 300 feet above the ground, substitute h = 300 into the equation and solve for t:

[tex]\begin{aligned}\implies -16t^2+64t+190 & = 300\\-16t^2+64t+190-300 & =0\\-16t^2+64t-110 & =0\\-2(8t^2-32t+55) & =0\\8t^2-32t+55& =0\end{aligned}[/tex]

Use the quadratic formula to solve for t:

[tex]\implies t=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}[/tex]

[tex]\implies t=\dfrac{-(-32) \pm \sqrt{(-32)^2-4(8)(55)} }{2(8)}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{1024-1760} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{-736} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{16 \cdot -1 \cdot 46} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{16} \sqrt{-1} \sqrt{ 46}}{16}[/tex]

[tex]\implies t=\dfrac{32 \pm 4i\sqrt{ 46} }{16}[/tex]

[tex]\implies t=\dfrac{8\pm \sqrt{ 46} \;i}{4}[/tex]

Therefore, as t is a complex number, the object will not reach a height of 300 feet.

Part d

The maximum height the object can reach is the y-coordinate of the vertex.  

Find the x-coordinate of the vertex and substitute this into the equation to find the maximum height.

[tex]\textsf{$x$-coordinate of the vertex}: \quad x=-\dfrac{b}{2a}[/tex]

[tex]\implies \textsf{$x$-coordinate of the vertex}=-\dfrac{64}{2(-16)}=-\dfrac{64}{-32}=2[/tex]

Substitute t = 2 into the equation:

[tex]\begin{aligned}t=2 \implies h(2)&=-16(2)^2+64(2)+190\\&=-16(4)+128+190\\&=-64+128+190\\&=64+190\\&=254\end{aligned}[/tex]

Therefore, the maximum height of the object is 254 feet.

It takes 2 seconds for the object to reach its maximum height.

Find the value of x that will make A||B5x + 20A-В.3x + 60x= [?]Enter

Answers

ANSWER:

The value of x is 20

STEP-BY-STEP EXPLANATION:

By properties of the angles we know that these angles are equal, since they are alternative external angles. Thanks to that we can do the following equality to calculate the value of x:

[tex]5x+20=3x+60[/tex]

Solving for x:

[tex]\begin{gathered} 5x-3x=60-20 \\ 2x=40 \\ x=\frac{40}{2} \\ x=20 \end{gathered}[/tex]

The radius, R, of a sphere is 4.8 cm. Calculate the sphere's volume, V. Use the value 3.14 for it, and round your answer to the nearest tenth. (Do not round any intermediate computations.) --0- V = 3 em Х 5 ?

Answers

The formula to calculate the volume of a sphere is given to be:

[tex]V=\frac{4}{3}\pi r^3[/tex]

where r is the radius.

From the question, we have the following parameters:

[tex]\begin{gathered} \pi=3.14 \\ r=4.8 \end{gathered}[/tex]

Therefore, the volume is calculated to be:

[tex]\begin{gathered} V=\frac{4}{3}\times3.14\times4.8^3 \\ V=463.0 \end{gathered}[/tex]

The volume is 463.0 cm³.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.042 for the estimation of a population
proportion? Assume that past data are not available for developing a planning value for p*. Round up to the next whole number.

Answers

The  sample size should be taken as 545.6 to obtain a margin of error of 0.042 for the estimation of a population proportion.

What is sample size?

The process of deciding how many observations or replicates to include in a statistical sample is known as sample size determination. Any empirical study with the aim of drawing conclusions about a population from a sample must take into account the sample size as a crucial component. The sample size chosen for a study is typically influenced by the cost, convenience, or ease of data collection as well as the requirement that the sample size have adequate statistical power.

As given in the question,

Confidence level is 95% and the margin of error is 0.042

So,  

1 - α = 0.95,

α = 0.05,

E = 0.042

planning value (p) = 0.5

To calculate Sample size the formula is:

[tex]n = \frac{p(1-p)(Z_{a/2})^2}{E^2}[/tex]

From the table we can find that:

[tex]Z_{a/2} = 1.96[/tex]

Putting the values given in the question in formula:

[tex]n = \frac{0.5(0.5)(1.96)^2}{(0.042)^2}[/tex]

[tex]n = \frac{(0.25)(1.96)^2}{(0.042)^2}[/tex]

[tex]n = \frac{(0.25)(3.841)}{0.00176}[/tex]

n = 545.6

Hence the sample size is 545.6

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Artrigerator contains 5 cans of diet soda and 8 cans of regular soda. If three cans of soda are randomly selected without replacement, determine the probability that all can selected are diet soda. Use combinations to determine theprobabilityThe probability that all can selected are diet soda is(Type an integer or a simplified fraction)

Answers

The total number of cans in the refrigerator is 5 + 8 = 13

The number of diet soda cans is 5 while the number of regular soda cans is 8

If three cans are selected, the probability that the can is a diet soda can is

5/13

Since it was not replaced, the number of diet soda cans left would be 4 and the total number of cans left would be 12. The probability that the next selected can is a diet can is

4/12 = 1/3

Since it was not replaced, the number of diet soda cans left would be 3 and the total number of cans left would be 11. The probability that the next selected can is a diet can is

3/11

Thus, the probability that the three selected cans are diet soda cans is

5/13 * 1/3 * 3/11 = 5/143

= 0.035

the probability that the three selected cans are diet soda cans is 0.035

da can

r

I'll give brainliest!

Answers

Answer:

x equals to 11!!!

Answer:

11.

Step-by-step explanation:

1.02 x 10^11 = 102,000,000,000

Hope this helps!

Brainliest please, thanks!

O GRAPHS AND FUNCTIONSFinding values and intervals where the graph of a functioning is..

Answers

a.

From the graph we notice that when x=-1 the value of the function is zero; therefore:

[tex]f(-1)=0[/tex]

and it is not negative.

b.

The function is positive when its graph is above the x-axis. We notice that this happens in two regions of the graph:

From -4 to -3

From -1 to 4

Therefore, the function is positive in:

[tex]\lbrack-4,-3)\cup(-1,4)[/tex]

c.

The function is zero when the graph intersect the x-axis; from the graph we have that the function is zero for:

[tex]\begin{gathered} x=-3 \\ x=-1 \\ x=4 \end{gathered}[/tex]

A composite figure is created using asquare and a semicircle. What is the area ofthe figure?12 in200.52202.52204.52206.52

Answers

The area of the composite figure will be the sum of the area of the square and the area of the semicircle. The formula for determining the area of a square is expressed as

Area = length^2

From the diagram,

length = 12

Area of square = 12^2 = 144

The formula for determining the area of a semicircle is expressed as

Area = 1/2 * pi * radius^2

Radius = diameter/2

The diameter of the semicircle is 12. Thus,

radius = 12/2 = 6

pi = 3.14

Area of semicircle = 1/2 * 3.14 * 6^2 = 56.52

Area of composite figure = 144 + 56.52 = 200.52 in^2

The first option is the correct answer

There is a​ 5% chance that the mean reading speed of a random sample of 21

second grade students will exceed what​ value?

Answers

There is a 5% chance that second graders will be faster than 94.597 wpm.

Sample size = 21

standard deviation = 10 wpm

SE = 10/sqrt(21) = 2.18 as a consequence.

Let X be the average reading speed of 21 second-grade students. z = (X - 91)/2.18 Normal(91,2.18) (91,2.18).

If the 95th percentile of a standard normal variable z is 1.65 [5% probability], the outcome is 91 + 1.65 x 2.18 = 94.597.

So there's a 5% chance that the average reading speed of a random sample of 21 second-graders will be faster than 94.597 wpm.

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The factors of 6 are also the factors of which number? A 5 C 20 B 10 D 30

Answers

Solution:

Factors of a number are defined as numbers that divide another number evenly or exactly without giving any remainder.

Hence,

The factors of 6 are the numbers that can divide 6 without any remainder.

[tex]\text{Factors of 6 =1,2,3,6}[/tex][tex]\begin{gathered} \text{Factors of 5=1,5} \\ \text{Factors of 20=1,2,4,5,10,20} \\ \text{Factors of 10=1,2,5,10} \\ \text{Factors of 30=1,2,3,5,6,10,15,30} \end{gathered}[/tex]

From the above, we can deduce that the factors of 6 are also the factors of 30.

The corr

The equation for a line that has a y-intercept of -8 and passes through (-4,2) is y=-5/2x-8 True False

Answers

1) Let's verify whether that's true or not, plugging in that point into the equa

(-4,2)

[tex]\begin{gathered} 2=\frac{-5}{2}(-4)\text{ -8} \\ 2=10-8 \\ 2=2 \end{gathered}[/tex]

Since this is an identity, in other words, the left side is equal to the right side then we can say that's true.

So that's true y=-5/2x-8 is the equation of the line that has in one of its points the y-coordinate y=-8

rThe number of dogs per household in a neighborhood is given in the probabilitydistribution. Find the mean and the standard deviation. Round to 1 decimal.# of Dogs012.34P(x)0.640.250.060.03.02a) What is the mean rounded to 2 decimal place?b) What is the standard deviation rounded to 2 decimal place?

Answers

[tex]\mu=\frac{x1+x1\ldots xn}{N}[/tex]

N = Number of data

x1...xn = Samples

[tex]s=\sqrt[]{\frac{\sum ^n_{n\mathop=1}(y-\mu)^2}{n-1}}[/tex]

Let's calculate first:

[tex]\sum ^n_{n\mathop=1}yn=0.64+0.25+0.06+0.03+0.02=1[/tex]

Now:

[tex]\sum ^n_{n\mathop=1}yn^2=(0.64)^2+(0.25)^2+(0.06)^2+(0.03)^2+(0.02)^2=0.477[/tex]

So:

[tex]s=\sqrt[]{\frac{0.477-\frac{(1)^2}{5}}{5-1}}=0.2631539473\approx0.3[/tex]


Cuál es la probabilidad de obtener exactamente 5 caras en 10 lanzamientos de una moneda?

Answers

The probability of getting exactly 5 heads in 10 tosses of a coin 24.6%

What is Probability ?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

Ten times are spent flipping coins.

Total number of results = 2¹⁰ = 1024

C(10, 5) = 252 is the total number of favorable outcomes.

Probability is

252/1024,

which equals :

=0.24, or

=24.6%.

Therefore, the chance of getting exactly 5 "heads" out of a possible 10 is 0.246, or 24.6%.

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A football team was able to run the ball for 8 yards on their first play. On the second play they lost 12 yards. The third play they lost another 11 yards. What was their total yards they gained?

Answers

The total yards gained or lost is the algebraic sum so the resultant yards is -15 yards thus they lose 15 yards.

What is the arithmetic operator?

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Subtraction = Minus of any two or more numbers.

Summation = addition of two or more numbers or variable

Let's consider all gained yards by positive (+) and all lost yards by negative (-).

Given that,

In the first play = +8 yards (gain)

In second play = -12 yards (lost)

In the third play = 11 yards (Lost)

So total yards = +8 - 12 - 11 = -15 (Lost)

Therefore, the football team lost 15 yards.

Hence "The total yards gained or lost is the algebraic sum so the resultant yards is -15 yards thus they lose 15 yards".

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1. The data set represents the number of cars in a town given a speeding ticketeach day for 10 days.2 4 5 5 7 7 8 8 8 121. What is the median? Interpret this value in the situation.*

Answers

ANSWER:

7

STEP-BY-STEP EXPLANATION:

We have the following data:

[tex]2,4,5,5,7,7,8,8,8,12[/tex]

The median is the data value that separates the upper half of a data set from the lower half. Therefore:

In this case, being even, the two data are half, but since the value is the same, that is, 7, the median is equal to 7.

The interpretation of this value is in the middle of the 10 days (days 5 and 6), 7 would be the number of cars in a town given a a speeding ticket.

need help due tommorow​

Answers

Finding the ratio of

a)1:9

b)2 : 7

c) 2 : 5

What is Ratio?

A ratio indicates how often one number contains another number. For example, if a fruit bowl contains 8 oranges and 6 lemons, the ratio of oranges to lemons is 8 to 6. Similarly, the ratio of lemons to oranges is 6:8 and the ratio of oranges to whole fruit is 8:14.

Given,

Total no. of students =  42

a) Students who prefer punk to students who prefer hip-hop

  No. of students in punk = 2

  No. of students in hip-hop = 18

The Ratio will be,

punk : hip-hop = 2:18

                        = 1:9

b) Students who prefer rock to total no. of students that are surveyed

No. of students in rock = 12

Total no. of students =  42

The Ratio will be,

rock : total students = 12 : 42

                                 = 2 : 7

c) Students who prefer rock or classic rock to students who prefer all music

No. of students in rock = 12

Total no. of students who likes other music =  42 - 12

                                                                        = 30

The Ratio will be,

rock : total students with different music = 12 : 30

                                                                    = 2 : 5

Hence, The ratio comparison in three different way

a)1:9

b)2 : 7

c) 2 : 5

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Which equation is true when A.n = 1.2 B.
1.2n=10 n+1=1.2 C. 5+n=6.2 D. 10n=1.2​

Answers

The true equation is 5 + n = 6.2.

Here we have to find the equation for which n = 1.2.

So the first equation is

10n = 1.2

So for this, we get the value of n as:

n = 1.2/10

  = 0.12

which is not equal to 1.2.

So it is not correct

The second equation is:

n + 1 = 1.2

n = 0.2

which is not equal to 1.2

So it is also not correct.

The third equation is:

5 + n = 6.2

n = 6.2 - 5

  = 1.2

So it is correct.

The fourth equation is:

1.2n = 10

n = 10/1.2

  = 8.33

Here n is not equal to 1.2

So it is also correct.

Therefore the correct equation is 5 + n = 6.2.

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Edgar drew a scale drawing of the town library. The scale of the drawing was 5
centimeters: 2 meters. The parking lot is 34 meters wide in real life. How wide
is the parking lot in the drawing?

Answers

Answer:

85 cm

Step-by-step explanation:

The scale factor is:

5 cm ÷ 2 m

Find the width of the parking lot in the drawing:

5 cm ÷ 2 mx cm ÷ 34 m

Cross multiply and find the value of x:

x = 5*34/2x = 85 cm

A rectangular prism has dimensions of 2 cm by 2 cm by 5 cm. What is its surface area? Explain or show your reasoning

Answers

If a rectangular prism has dimensions of 2cm by 2 cm by 5 cm, then the surface area of the rectangular prism is 48 centimeter square

The length of the rectangular prism = 2 cm

The width of the rectangular prism = 2 cm

The height of the rectangular prism = 5 cm

The surface area of the rectangular prism = 2(lw+lh+hw)

Where l is the length

w is the width

h is the height

Substitute the values in the equation

The surface area of the rectangular prism = 2(2×2+2×5+2×5)

= 2(4+10+10)

= 2×24

= 48 centimeter square
Hence, if a rectangular prism has dimensions of 2cm by 2 cm by 5 cm, then the surface area of the rectangular prism is 48 centimeter square

Learn more about surface area here

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What is the answer to 2(7x-3)+9

Answers

Answer:

14x+3 is the answer I think

The solution to the given equation would be [tex]14x+3[/tex].

Hope this helps!

please help! I do not understand and it is due tonight!!!!!!!

Answers

Consider that there are, generally, the following types of angles pairs,

1. Adjacent Angles: Angles that share a common side and are formed on the same vertex.

2. Complementary Angles: Angles that are adjacent and together form a right angle.

3. Supplementary Angles: Angles that are adjacent and whose sum of degree measures is 180 degrees.

a.

The adjacent angles to angle 4 are angles 1 and 3.

There are no complementary angles associated with angle 4.

The supplementary angles to angle 4, are angles 1 and 3.

Thus, the angle pairs that include angle 4 are,

[tex](\angle4\text{ and }\angle1),\text{ }(\angle4\text{ and }\angle3)[/tex]

b.

The adjacent angles to angle 5 are angles 6 and 7.

There are no complementary angles associated with angle 5.

The supplementary angles to angle 5, are angles 6 and 7.

Thus, the angle pairs involving angle 5 are,

[tex](\angle5\text{ and }\angle6),\text{ }(\angle5\text{ and }\angle7)[/tex]

Given the definitions of f(x) and g(x) below, find the value of (gof)(9). f(x) = -x + 11 g(x) = 3x2 - x + 14

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

f(x) = -x + 11

g(x) = 3x² - x + 14​

(gof)(9) = ?

Step 02:

(gof)(x) = 3(-x+11)² - (-x+11) + 14​

= 3(x² + 2(-x)(11) + 121) + x - 11 + 14

= 3(x² - 22x + 121) + x - 11 + 14

= 3x² - 66x + 363 + x - 11 + 14

= 3x² - 65x + 366

(gof)(9) = 3(9)² - 65(9) + 366

= 3(81) - 585 + 366

= 243 - 585 + 366

= 24

The answer is:

(gof)(9) = 24

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