Explanation:
9.3x105
Simplifies to:
9.3x100000
=9.3x100000
Hope that helps
USATESTPREP
Examine the image here showing the different characteristics of the components of the electromagnetic spectrum. Ultraviolet light is often used to sterilize water in a water treatment facility. Which characteristics of ultraviolet light allow it to sterilize water? Select ALL that apply.
A) It is not visible, so pathogens cannot detect its presence.
B) It has low enough energy to be safe to humans but harmful to pathogens.
C) Its energy level is high enough to cause ionizing damage to DNA and molecules.
D) It has wavelengths too large to cause molecular changes to the molecules of water.
E) Its wavelengths are small enough to interact with bacteria and viruses, which can be pathogenic in the water.
Answer:
C, D, and E
Explanation:
Answer:it’s C, D, E
Explanation:
Brainliest if correct Question 6 of 10
According to the law of conservation of energy, which statement must be
true?
A. There is only one form of energy.
B. Energy that is transformed is neither destroyed nor created.
C. The total energy in a system can only increase over time.
D. Energy can change only from nuclear to chemical
Answer:
B. Energy that is transformed is neither destroyed nor created.
Explanation:
Hope this helped! :)
A horizontal force of 15N is needed to keep a box sliding on a horizontal floor at a constant speed of 0.5m/s. The speed of the box is increased to 1.5m/s by some means (which is not the concern of this question). What horizontal force would be needed to keep the same box sliding on the same horizontal floor at a constant speed of 1.5m/s?
The horizontal force needed to keep the same box sliding on the same horizontal floor at a given constant speed is 45 N.
Horizontal forceThe horizontal force needed to keep the same box sliding on the same horizontal floor at a given constant speed is calculated as follows;
[tex]F= \frac{mv}{t} \\\\mv = Ft\\\\m = \frac{Ft}{v} \\\\\frac{F_1}{v_1} = \frac{F_2}{v_2}[/tex]
where;
v1 is the initial velocityv2 is the final velocity[tex]F_2 = \frac{F_1v_2}{v_1} \\\\F_2 = \frac{15 \times 1.5}{0.5} \\\\F_2 = 45 \ N[/tex]
Thus, the horizontal force needed to keep the same box sliding on the same horizontal floor at a given constant speed is 45 N.
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Define the term Distance.
Maths :
The length between 2 points.
Physics =
Distance = speed × time
Distance is defined as the space between two points in space.
What is distance?Distance is defined as the space between two points in space.
The unit of distance is metres or kilometres.
Distance can be measured directly usind instruments such as metre rule and tape rule.
The formula for calculating distance is given below:
Distnce = velocity × time.
Therefore, distance is defined as the space between two points in space.
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what would the mass be of an object that was moving at a velocity of 35 m/s and has a kinetic energy of 500j be?
Answer:
0.816 kg
Explanation:
[tex]E_k=\frac{1}{2}mv^{2}\\[/tex]
so [tex]m=\frac{2E_k}{v^2}=\frac{2\times500}{35^2}=0.816 kg[/tex]
What is nature of light Definition
What is the sources of light
What is the behaviours of light
Reflection and refraction
Colours and light
Concave and convex mirrors
Please help fast
(25 points)
Answer:
1.Light is a transverse, electromagnetic wave that can be seen by the typical human.
2.The Sun is the major source of light for the earth.
3.An inclusive list of the basic categories of behavior for light would most likely include transmission, absorption, reflection, refraction, diffraction, scattering, polarization and interference.
4.Spherical mirrors contain curved surfaces which are painted on either one of the sides. When an inward surface of a spherical mirror is painted, then this type of mirror is considered a convex mirror. In the meantime, when the outward surface of the spherical mirror is painted, this mirror is called a concave mirror.
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l will help and if you get it correctly I will say you are welcome
list some of the electronic system?
Answer:
▪list some of the electronic system?
➢ An audio system, TV, or any Mp3 player is the example of an electronic system. The sound waves are converted to electrical signals and they are amplified to process the output of high strengthened audio signals, through speakers.
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When you push on a stationary object on a horizontal surface and it doesn't move, what kind of force is most likely opposing your efforts
Re arrange the formula to make v the subject
Answer:
[tex]v = \sqrt{ \frac{2 e}{m} } [/tex]
Explanation:
[tex]e = \frac{1}{2} m {v}^{2} [/tex]
[tex]e = \frac{m {v}^{2} }{2} [/tex]
[tex]2e = m {v}^{2} [/tex]
[tex] \frac{2e}{m} = {v}^{2} [/tex]
[tex] \sqrt{ {v}^{2} } = \sqrt{} \frac{2e}{m} [/tex]
[tex]v = \sqrt{ \frac{2e}{m} } [/tex]
Brainliest if correct Question 5 of 10
Which two types of energy does a book have as it falls to the floor?
A. Kinetic energy
B. Potential energy
c. Nuclear energy
D. Magnetic energy
E. Light energy
SUBMIT
Answer:
A and B
Explanation:
Kinetic energy is when an object is in motion, and potential energy is kind of when an object stops being in motion, or there is a pause in motion for an extent of time.
When you are holding the book before dropping it, that book is at potential energy. When you drop the book, the book gains kinetic energy as it falls from your hands and hits the floor. Once it hits the floor and rests, it regains potential energy.
I hope that this helps.
When the reflection of an object is seen in a concave mirror the image will: Select one: a.will always be enlarged. O b.may be either real or virtual. c.always be real. d.always be virtual.
A car weighing 14,700 N is speeding down a highway with a velocity of 99 km/h. What is the
momentum of this car?
Answer: 148348.6239 kg•m/s
Explanation: Firstly, we need to convert the 14700 N into kilograms, and to do so, use the formula net force is equal to mass times acceleration and rearrange the formula to find mass like shown below...
F = ma
F/a = m
14700/9.81 = 1498.470948 kg, this is your mass
Now that we convert it into kilograms, plug all the numbers into the variable of the momentum formula.
Momentum formula is P = mass x velocity
Like this:
P = 1498.470948 x 99
p = 148348.6239 kg•m/s.
I believe that is your answer, hope that helps you even a bit out.
Thanks.
The speed of a rocket just after being launched is 12 m / s.
The mass of the rocket is 0.05 kg.
Calculate the kinetic energy of the rocket just after being launched. Use the equation: Kinetic energy = 0.5 x mass x velocity squared
As the rocket moves upwards, it gains gravitational potential energy.
State the maximum gravitational potential energy gained by the rocket. Ignore the effect of air resistance.
Maximum gravitational potential energy =
Calculate the maximum height the rocket will reach.
Ignore the effect of air resistance.
Gravitational field strength = 10 N/kg.
This question involves the concepts of the equations of motion, kinetic energy, and potential energy.
a. The kinetic energy of the rocket at launch is "3.6 J".
b. maximum gravitational potential energy of the rocket is "3.6 J".
a. KINETIC ENERGY AT LAUNCHThe kinetic energy of the rocket at launch is given by the following formula:
[tex]K.E=\frac{1}{2} m v_i^2[/tex]
where,
K.E = initial kinetic energy = ?m = mass of rocket = 0.05 kg[tex]v_i[/tex] = initial speed = 12 m/sTherefore,
[tex]K.E=\frac{1}{2}(0.05\ kg)(12\ m/s)^2[/tex]
K.E = 3.6 J
b. MAXIMUM GRAVITATIONAL POTENTIAL ENERGY
First, we will use the third equation of motion to find the maximum height reached by rocket:
[tex]2gh=v_f^2-v_i^2[/tex]
where,
g = -9.81 m/s²h = maximum height = ?vf = final speed = 0 m/sTherefore,
2(-9.81 m/s²)h = (0 m/s)² - (12 m/s)²
h = 7.34 m
Hence, the maximum gravitational potential energy will be:
P.E = mgh
P.E = (0.05 kg)(9.81 m/s²)(7.34 m)
P.E = 3.6 J
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This is how high or low a sound is. It is related to the frequency of the soundwave.
a
volume
b
pitch
c
amplitude
d
echo
Answer:
a
Explanation:
a
the speed, (u) of a car after a time (H is given by
v=utat
Where u is the initial speed and a is the acceleration
S,
Re-arrange the equation to make
a the subject of formala.
-
Answer:
[tex]a = \frac{v - u}{t} [/tex]
Explanation:
[tex]v = u + at[/tex]
[tex]v - u = at[/tex]
[tex] \frac{v - u}{t} = \frac{at}{t} [/tex]
[tex]a = \frac{v - u}{t} [/tex]
1. Explain what happens during a solar eclipse
Answer:
when the moon moves in front of the Sun as seen from a location on Earth.
Explanation:
A solar eclipse happens when the moon moves in front of the Sun as seen from a location on Earth. During a solar eclipse, it gets dimer and dimmer outside as more and more of the Sun is covered by the Moon. During a total eclipse, the entire Sun is covered for a few minutes and it becomes very dark outside.
A fighter jet is being tested before it is delivered. The jet took off and had its initial velocity of 280 m/s. As the pilot ask permission from the flight control to test its capacity the jet reached its final velocity of 1250 m/s in just 20 seconds. What is the acceleration of the fighter jet?
Answer:
48.5 m/s².
Explanation:
We can use the following kinematic equation:
[tex]\displaystyle v_f = v_i + at[/tex]
Substitute in the appropriate values and solve for acceleration a:
[tex]\displaystyle \begin{aligned} (1250\text{ m/s}) & = (280\text{ m/s}) + a(20\text{ s}) \\ \\ a & = 48.5\text{ m/s$^2$} \end{aligned}[/tex]
Therefore, the acceleration of the fighter jet was 48.5 m/s².
Which of the following shows the correct order of a life cycle for an animal?
Egg → Adolescent → Infant → Adult → Embryo
Egg → Embryo → Infant → Adolescent → Adult
Embryo → Egg → Infant → Adult → Adolescent
Infant → Adolescent → Adult → Embryo → Egg
Answer:
Egg, Embryo, infant, adolescent and adult
Answer:
egg,embryo,infant,adolesent,adlt /B
Explanation:
A 0.001 kg nail is placed 0.2m away from 0.1 kg hammer. Calculate the gravitational force on the nail from the hammer.
Answer:
F= 1.67 x [tex]10^{-13}[/tex]N
Explanation:
I used this equation:
F = GMm/R²
Where M is mass 1
where m is mass 2
where R is distance
where F is gravitational force
How far will 60J of work push a hockey puck if the applied force is 5N? Question 15 options: 0.1 meters 300 meters 12 meters 65 meters
The distance travelled by the hockey puck, given that 60 J of work was done by an applied force of 5 N is 12 meters
How do I determine the distance travelled by the hockey puck?We know already that work is the product of force and distance moved in the direction of the force:
Work done (Wd) = force (F) × distance (d)
Using the above formula, we can determine the distance travelled by the hockey puck. Details below:
Workdone (Wd) = 60 JForce applied (F) = 5 NDistance travelled (d) =?Work done (Wd) = force (F) × distance (d)
60 = 5 × distance travelled
Divide both sides by 5
Distance travelled = 60 / 5
Distance travelled = 12 meters
Thus, from the above calculation, we can conclude that the distance travelled is 12 meters
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What is the minimum diameter necessary for a radio telescope working at f=1×10^10 Hz to be able to separate two objects 1 deg apart?
[a] 0.03 m
[b] 0.037 m
[c] 0.47 m
[d] 2.1 m
[e] 6.3 m
Luminous intensity depends on what values?
It is dependent on the sensitivity of the eye to the entire spectrum of visible wavelengths emitted by the source, and the radiant flux (or radiant power) produced at each wavelength. We weight the radiant flux at each wavelength using the luminosity function V-lambda.
An object is orbiting uniformly around a center, has a radius of 1 km, and undergoes an angular displacement of 1 every 0.1 s. What is the position vector (x and y component) of that object at = 1 s if the object starts its motion at x = 1000m, y = 0 m?
The position vector of the object after 1 second is (11,000 m, 10,000 m).
Angular speed of the objectThe angular speed of the object is calculated as follows;
[tex]\omega = \frac{1 \ }{0.1 \ s} = 10 \ rad/s[/tex]
Linear speed of the objectv = ωr
v = 10 x 1 km
v = 10 x 1000 m
v = 10,000 m/s
Position of the object after 1 second[tex]v_x = 1000\ m \ + \ 10,000\ m/s \times 1\ s = 11,000 \ m\\\\v_y = 0 m \ + \ 10,000 \ m/s \times 1 \ s = 10,000 \ m[/tex]
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What is the net force on this object A: 0 newtons b: 200 newtons c:400 newtons D:600 newtons
Answer:
100kg
Explanation:
Total force =400N+600N=1000N
As we have,
F=m×g
1000N=m×10m/s²
1000N÷10m/s²=m
m=100kg
who discovered the law of gravity and motion?
Answer:
Physically, Sir Isaac Newton was not a large man. However, he had a large intellect, as shown by his discoveries on gravity, light, motion, mathematics, and more. Legend has it that Isaac Newton came up with gravitational theory in 1665, or 1666, after watching an apple fall.
Explanation:
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Why is it incorrect to say that astronauts are weightlesS in space while orbiting Earth in a space shuttle?
This is because Gravity exists everywhere in the universe.
What is Gravity?This is the force of attraction which acts on all matters in the universe. Astronauts appear weightless while in orbiting the Earth because the space shuttle and the astronauts are in free fall around it.
They fall at the same rate as the space shuttle which is why the astronauts appear weightless.
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Astronauts and their spaceship are affected by Earth's gravity in space. Even though Earth's gravitational influence is weaker in orbit than on Earth's surface, they have weight. They don't feel their weight since nothing's pushing back.
What is weightlessness in space?Weightlessness means no weight. It's also called zero-G. Weight is the force on a stationary object in a strong gravitational field.
The sensation of weightlessness that astronauts on board the International Space Station enjoy is due to the fact that they are free falling toward the planet Earth. Because the space station and the astronauts are moving at the same rate, there is no external normal force acting upon the body in free fall to balance out the effects of the body's own weight (equal to g).
Therefore, the astronauts and their spaceship continue to have mass and are still affected by the gravitational pull of the Earth.
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A man pulls a box with an applied force of 500N. He pulls the box 100.0 m. About how much work does he do? Question options: 0.5 J 50,000 J 5,000 J 2 J
Workdone:-
[tex]\\ \tt\longrightarrow Force\times Displacement [/tex]
[tex]\\ \tt\longrightarrow 500(100)[/tex]
[tex]\\ \tt\longrightarrow 50000J[/tex]
Two charges (Q1 = 0.00368 ; Q2 = 0.00059 ) are separated by a distance of 0.4 meters. What is the Force between them?
Coulomb force
[tex]\tt F=k\dfrac{q_1.q_2}{r^2}[/tex]
F = coulomb force (N)
Q1,Q2 = the charge (C)
r = distance between two charges (m)
k = constant = 9.10⁹ Nm² / C²
Input the value:
[tex]\tt F=9.10^9\dfrac{0.00368\times 0.00059}{0.4^2}=122130~N[/tex]
When you apply a horizontal force of 51 N to a block, the block moves across the floor at a constant speed. (a) When you apply a force of 40 N to the block initially at rest, what is the magnitude of the horizontal component of the force that the floor exerts on the block? (b) When you apply a force of 59 N, what is the magnitude of the horizontal component of the force that the floor exerts on the block?
(a) When you apply a force of 40 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.
(b) When you apply a force of 59 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.
Net force on the blockThe horizontal component of the force that the floor exerts on the block is determined by applying Newton's second law of motion;
[tex]F = ma[/tex]
When the block moves at a constant speed[tex]\Sigma F = 0\\\\F - F_f = 0\\\\F = F_f[/tex]
[tex]F_f = F\\\\F_f = 51 \ N[/tex]
where;
[tex]F_f[/tex] is the frictional force exerted on the block by the floorSince the surface (floor) is constant, the frictional force (horizontal component of the force that the floor exerts on the block ) will be the same on the cases.
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Based on the definition of limiting frictional force;
the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 40 N when a force of 40 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 51 N, the limiting frictional force, when a force of 59 N is applied to the block.What is force?Force is any push or pull effect which tends to cause a change in the motion or shape of an object.
Based on Newton's third law, every force produces an equal and opposite reaction.
Therefore, the force that the floor exerts on the block is oppositely direction to the force exerted by the horizontal force acting on the block.
Since a horizontal force of 51 N applied to the block is required to keep the block moving across the floor at a constant speed, this is the limiting frictional force.
a) when a force of 40 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 40 N
b) when a force of 59 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 51 N, the limiting frictional force.
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