Which is in the Moneran kingdom? A. plants B. bacteria C. animals D. mushrooms

Answers

Answer 1

Answer: b

Explanation:


Related Questions

Chemical messengers that stimulate a specific cellular response.
Glucose
Hormones
Mitochondria
Nerves

Answers

Answer:

Explanation:

hormones. please mark me brainliest

Hormones is the correct answer

A weightlifter curls a 32 kg bar, raising it each time a distance of 0.50 m. How many times must he repeat this exercise to burn off the energy in one slice of pizza? Assume 25% efficiency.

Answers

Answer:

Explanation:

Average energy contained by  a slice of pizza is 860 J  .

energy used in lifting 32 kg bar by .50 m = mgh

= 32 x 9.8 x .5 = 156.8 J

efficiency is 25 % , so energy used up = .75 x 156.8 = 117.6 J

So number of times exercise to be repeated to burn off energy of a slice of pizza

= 860 / 117.6

= 7.3 or 7 times .

Which image shows the difference between the speed of molecules in hot and cold water? Explain your answer choice.
HELP ME,EVERYONE!!!!!!!! :(

Answers

There is no image btw

Answer:

the answer is B

Explanation:

I think its B because on the top it shows the molecule speed and A looks like the water is cold, C shows that the hot

water is cooler, and D shows that both are cold

Which is the best explanation for why Toms technique works ?

Answers

I believe the correct answer is B

An 88 kg person steps into a car of mass 2002 kg, causing it to sink 5.36 cm on itssprings. Assuming no damping, with what fre-quency will the car and passenger vibrate onthe springs? Answer in units of Hz. The acceleration of gravity is 9.81 m/s^2.

Answers

Answer:

The required frequency = 0.442 Hz

Explanation:

Frequency [tex]f = ( \dfrac{1}{2 \pi}) \omega[/tex]

where;

[tex]\omega = \sqrt{\dfrac{k}{m} }[/tex]

Then;

[tex]f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{k}{m} } \Bigg )[/tex]

However;

[tex]k = \dfrac{F}{x}[/tex] and;

mass [tex]m = m_{car } + m_{person}[/tex]

[tex]f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{\dfrac{F}{x}}{m_{car}+m_{person}} } \Bigg )[/tex]

[tex]f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{{F}}{x(m_{car}+m_{person})} } \Bigg )[/tex]

where;

[tex]F = m_{person}g[/tex]

Then;

[tex]f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{ {m_{person}g }}{x(m_{car}+m_{person})} } \Bigg )[/tex]

replacing the values;

[tex]f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{ {(88 \ kg)* (9.81 \ m/s^2) }}{(5.36 \times 10^{-2} \ m) (2002 \ kg +88 \ kg)} } \Bigg )[/tex]

[tex]\mathbf{f = 0.442 \ Hz}[/tex]

Water will expand more than ___

A. door
B. juice
C. air

Answers

I think the answer is B because juice has a higher density than water

Answer:

Its A. door because liquids expand better than solids

Learning task 2: Using the information you gathered from Learning Task 1, make a concept web of the contributions of the following scientist in the DEVELOPMENT OF MAGNETIC THEORY
A. Andre- Marie Ampere
B. Michael Faraday
C. Heinrich Herts
D. James Clerk Maxwell
E. Hans Christian Oersted

Answers

Answer:

The contributions of the following scientist in the DEVELOPMENT OF MAGNETIC THEORY

James Clerk Maxwell Hans Christian Oersted

Explanation:

George Green was the first personality to formulate a mathematical principle of magnetism and electricity and his system created the framework for the work of different scientists such as William Thomson, James Clerk Maxwell, and others. Magnetism is the power exercised by magnets when they drag or deflect each other. Magnetism is produced by the movement of electric charges.

The contributions of James Clerk Maxwell  and Hans Christian Oersted, et al in the DEVELOPMENT OF MAGNETIC THEORY are as follows:

They discovered that the speed at which electromagnetic waves traveled was similar to that of lightThey proved that there was a proportional connection between electricity and magnetism

According to the given question, we are asked to show the contributions which the aforementioned scientists had in the development of the magnetic theory.

As a result of this, we can see that James Maxwell first developed this theory in the nineteenth century and the theory was modified by other scientists who made the framework for the electrical system and magnetism.

Read more here:

https://brainly.com/question/17913237

Heather drives her Super-Beetle around a turn on a circular track which has a radius of 200 m. The Super-Beetle has a mass of 1500 kg and the coefficient of static friction between the road and tires is 0.6.

a. What is the force of static friction the road can apply batore the car starts to selon (use Ft= uFn).
b. What is the maximum speed the car can travel before it would start to slide?

Answers

Answer:

a) The force of static friction the road can apply before the car starts to move is 8826.3 newtons.

b) The maximum speed that a car can travel before it would start to slide is approximately 34.305 meters per second.

Explanation:

a) Let suppose that the car is on a horizontal ground and travels at constant speed. The vehicle experiments a centripetal acceleration due to friction, which can be seen in the Free Body Diagram (please see image attached for further details). By Newton's Laws, we construct the following equations of equilibrium:

[tex]\Sigma F_{x} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R}[/tex] (1)

[tex]\Sigma F_{y} = N -m\cdot g = 0[/tex] (2)

Where:

[tex]\mu_{s}[/tex] - Static coefficient of friction, dimensionless.

[tex]N[/tex] - Normal force from ground to the car, measured in newtons.

[tex]v[/tex] - Maximum speed of the car, measured in meters per second.

[tex]R[/tex] - Radius of the circular track, measured in meters.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

By applying (2) in (1):

[tex]\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}[/tex] (3)

The force of static friction the road can apply in the car ([tex]f[/tex]), measured in newtons, is: ([tex]\mu_{s} = 0.6[/tex], [tex]m = 1500\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex])

[tex]f = \mu_{s}\cdot m \cdot g[/tex]

[tex]f = (0.6)\cdot (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]f = 8826.3\,N[/tex]

The force of static friction the road can apply before the car starts to move is 8826.3 newtons.

b) Then, we calculate the maximum speed of the car by (3):

[tex]\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}[/tex]

[tex]\mu_{s}\cdot g = \frac{v^{2}}{R}[/tex]

[tex]v = \sqrt{\mu_{s}\cdot g\cdot R}[/tex]

If we know that [tex]\mu_{s} = 0.6[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]R = 200\,m[/tex], then the maximum speed of the car can travel before it would start to slide is:

[tex]v =\sqrt{(0.6)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (200\,m)}[/tex]

[tex]v \approx 34.305\,\frac{m}{s}[/tex]

The maximum speed that a car can travel before it would start to slide is approximately 34.305 meters per second.

If California experienced heavy rainfall, which system would be responsible for it and WHY?

Answers

Answer:

California has one of the most variable climates of any U.S state, and often experiences very wet years followed by extremely dry ones . The state's reservoirs have insufficient capacity to balance the water supply between wet and dry years.

PLEASE MARK ME AS BRAINLIEST

3. A car is traveling up a 3% grade, with the speed of 85mph, on a road that has good, wet pavement. A deer jumps out onto the road and the driver applies the brakes 290-ft from it. The driver hits the deer at a speed of 20mph.If the driver did not have antilock brakes, and the wheels were locked the entire distance, would a deer-impact speed of 20mph be possible

Answers

Answer:

Explanation:

From the given information;

Let assume that:

the wheel radius = 15 inches

the driveline slippage = 3%;  &

the gear reduction ratio (overall) = 2.5 to 1

So; using the equation:

[tex]v_1= \dfrac{2 \pi r n_o (1 -i)}{\varepsilon_o}[/tex]

[tex]v_1= \dfrac{2 \times 3.14 \times \dfrac{15}{12} \times \dfrac{85}{100} (1 -0.03)}{2.5}[/tex]

[tex]v_1= \dfrac{2 \times 3.14 \times \dfrac{15}{12} \times \dfrac{85}{100} (0.97)}{2.5}[/tex]

[tex]v_1 = 126.92 \ fp^3[/tex]

[tex]frl = 0.01 ( 1+ \dfrac{v}{147}) \ if \ v \ is \ ft/sec[/tex]

[tex]frl = 0.01 \Bigg( 1+ \dfrac{\dfrac{126.92 +(20)1.47 }{2} }{147}\Bigg)[/tex]

[tex]S = \dfrac{v_b ( v_1^r-v_2^r)}{2g(n_b \mu + frl \pm sin \ y}[/tex]

where;

[tex]\mu = 0.6[/tex]

[tex]291 = \dfrac{1.64( 126.92^2-29.9^2)}{64.4(n_b \times 0.6 +0.01532 +0.03}[/tex]

[tex]n_b = 1.33 \to which \ is \ not \ possible[/tex]

However;

[tex]n_b \mu = 1.33(0.6) = 0.80[/tex]

[tex]\mu = 0.9 \to[/tex] if the car's anti-clock breaking system did not fail

Thus;

[tex]n_b (0.9) = 0.80[/tex]

[tex]n_b =\dfrac{ 0.80}{(0.9) }[/tex]

[tex]n_b = 0.89[/tex]

Hence, the distance is possible if the anti-clock breaking system did not fail.

A 12-kg object is moving rightward with a constant velocity of 4 m/s. How much net force is required to keep the object moving with
the same speed and in the same direction?

Answers

c an s and yes ihavetotypemore

True or False. Facts are based on observations. *

True
False

Answers

Answer:

TRUE

Explanation:

IM SMART

Answer:

Stay  Safe! ,God bless you . The answer is false ,

Explanation:

What is the correct organization of living things, from smallest to largest?
Cells - Tissues - Organs - Organ Systems - Organism
Organs - Tissues - Cells - Organ Systems - Organism
Cells - Organs - Tissues - Organism - Organ Systems
Cells - Organism - Tissues - Organ Systems - Organs

Answers

The first one A should be your correct answer

a student lift a 25kg mass at vertical distance of 1.6m in a time of 2.0 seconds. a. Find the force needed to lift the mass (in N ). b. Find the work done by the student (in J). c. Find the power exerted by the student (in W)

Answers

Answer:

a. F = 245 Newton.

b. Workdone = 392 Joules.

c. Power = 196 Watts

Explanation:

Given the following data;

Mass = 25kg

Distance = 1.6m

Time = 2secs

a. To find the force needed to lift the mass (in N );

Force = mass * acceleration

We know that acceleration due to gravity is equal to 9.8

F = 25*9.8

F = 245N

b. To find the work done by the student (in J);

Workdone = force * distance

Workdone = 245 * 1.6

Workdone = 392 Joules.

c. To find the power exerted by the student (in W);

Power = workdone/time

Power = 392/2

Power = 196 Watts.

PLEASEEEEEEEEE HELPPPPPPPPPP

Describe what determines magnetism.

Answers

Answer:

Magnetism is caused by the motion of electric charges. Every substance is made up of tiny units called atoms. Each atom has electrons, particles that carry electric charges. ... Their movement generates an electric current and causes each electron to act like a microscopic magnet.

Explanation:

A pingpong ball has 2 kg/s of momentum when
thrown 8 m/s. Find the mass of the ball.

Answers

Answer:

0.25 kg

Explanation:

p = mv

2 = m(8)

2/8 = m(8)/8 *cancels

m = 1/4 OR 0.25 kg

In the figure, given ∆x=30cm, k=200N/cm, g=10m/s². Find the mass of the object​

Answers

Answer:

600 Kg

Explanation:

From the question given above, the following data were obtained:

Extention (∆x) = 30 cm

Spring constant (K) = 200 N/cm Acceleration due to gravity (g) = 10 m/s²

Mass (m) of object =?

Next, we shall determine force exerted. This can be obtained as follow:

Extention (∆x) = 30 cm

Spring constant (K) = 200 N/cm

Force (F) =?

F = K∆x

F = 200 × 30

F = 6000 N

Finally, we shall determine the mass of the object. This can be obtained as follow:

Acceleration due to gravity (g) = 10 m/s²

Force (F) = 6000 N

Mass (m) of object =?

F = mg

6000 = m × 10

Divide both side by 10

m = 6000 / 10

m = 600 Kg

Thus, the mass of the object is 600 Kg

If the force of gravity suddenly stopped acting on planets, they would

A.) spiral slowly towards the sun

B.) continue to orbit the sun

C.) move in straight lines tangent to thier orbits

D.) spiral slowly away from the sun

E.) fly straight away from the sun

Answers

i believe it is C i am not sure

A 2.6 kg ball is accelerated at 4.5 m/s2.
Calculate the force needed to achieve this feat.
Show all work including formula and units!

Answers

Answer:

[tex]12\:\mathrm{N}[/tex]

Explanation:

Force is given by the equation [tex]F=ma[/tex].

Plugging in given values, we have:

[tex]F=ma=2.6\cdot 4.5=11.7=\fbox{$12\:\mathrm{N}$}[/tex] (two significant figures).

The graph shows projected changes in the populations of the world.
World Population Growth
20,000
10,000
World
5,000
Asia
2,000
Africa
1,000
Europe
500
200
United States,
Canada, and Greenland
100 Mexico
Central America, Caribbean Islands,
50
and South America
Oceania (Australia and
20
nearby islands in the Pacific)
10
2040
2050
Based on the information in the graph, which region is expected to have the
greatest increase in its population over the period shown?
1950
1960
1970
1980
1990
2000
2010
2020
2030

Answers

Answer: C. Africa

Explanation:

The data given on the graph shows that:

Asia will grow from around 1,300 million to 5,000 million in 2050 which is an increase of:

= 5,000 /1,300 = 3.84 times

Europe will decrease over that period.

Africa will go from around 300 million to 2,000 million which is an increase of:

= 2,000 / 300

= 6.67 times

Mexico

, Central America, Caribbean Islands:

= 900 / 120

= 7.5 times

United States,  Canada, and Greenland:

= 400/120

= 3.33

Oceania:

= 50 / 13

= 3.85

From the options give, Africa will see the greatest increase at 6.67 times its population in 1950.

A car is traveling at a constant speed of 20 m/s for 3 seconds. Then the driver puts on the brakes. The total distance the car travels is 100 m. What is the total time the car was moving?

Answers

Answer:

15 seconds

Explanation:

If car was moving at 20m/s for 3 sec.

if car traveled 100m = 15 sec total

PLZ HELP WILL MARK BRAINLIEST!!


Amy has a mass of 50 kg, and she is riding a skateboard traveling 10 meters per second. What is her momentum?

5 kg·m/s

10 kg·m/s

50 kg·m/s

500 kg·m/s

Answers

Answer:

[tex]500 \: \mathrm{kg} \cdot \mathrm{m/s}[/tex]

Explanation:

The momentum of an object is given as [tex]p=mv[/tex]. Since Amy has a mass of 50 kg and is travelling 10 m/s, her momentum is [tex]p=mv=50\cdot 10 =\fbox{$500\: \mathrm{kg\cdot m/s}$}[/tex].

Answer:

500

Explanation:

How do sound waves travel?

Answers

Sound waves travel in a wave pattern such as viberation by viberating it taking sound with it

A ball bearing is projected vertically upwards from the ground with a velocity of 15ms. Calculate the time taken by the ball to return to the ground (g=10ms^2)​

Answers

Answer:

t = 3 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}-g*t[/tex]

where:

Vf = final velocity [m/s]

Vo = initial velocity = 15 [m/s]

g = gravity acceleration = 10 [m/s²]

t = time [s]

Now replacing we have:

[tex]0 = 15 -10*t\\10*t=15\\t= 1.5[s][/tex]

Note: In the equation above the gravity acceleration is negative, because the movement of the ball bearing is pointing againts the gravity acceleration.

The time calculated is only when the ball bearing reaches the highest elevation, and it will take the same time for descending, therefore the total time is:

t = 1.5 + 1.5 = 3 [s]

What is nature/nurture debate and why is it important in psychology

Answers

Answer: The nature versus nurture debate is one of the oldest issues in psychology. The debate centers on the relative contributions of genetic inheritance and environmental factors to human development.

This illustration shows two opposing forces pulling on a wagon. Which description best describes how the wagon will move?
10N
30N
The wagon will slow down
The wagon will move to the left.
The wagon will not move because the forces are opposite
The wagon will move to the right.
4 5 6 7 8
9 10 11 12 13
Next
Type here to search

Answers

Answer:

The wagon will move to the right.

Explanation:

From the question given above, the following data were obtained:

Force applied to the left (Fₗ) = 10 N

Force applied to the right (Fᵣ) = 30 N

Direction of the wagon =.?

To determine the direction in which the wagon will move, we shall determine the net force acting on the wagon. This can be obtained as follow:

Force applied to the left (Fₗ) = 10 N

Force applied to the right (Fᵣ) = 30 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 30 – 10

Fₙ = 20 N to the right

From the calculations made above, the net force acting on the wagon is 20 N to the right. Hence the wagon will move to the right.

If 478 watts of power are used in 14 seconds,how much work was done

Answers

Answer:

6692J

Explanation:

Power is defined as the rate at which work is being done.

So,

    Power  = [tex]\frac{workdone}{time }[/tex]  

  Work done  = Power x time

Given parameters:

Power  = 478watts

Time  = 14s

So;

 Work done  = 478 x 14  = 6692J

at what speed does the kg ball move ?

Answers

Answer:  Choice A) 2 meters per second

=======================================================

Explanation:

The smaller ball has momentum of

p = m*v

p = (1 kg)*(4 m/s)

p = 4 kg*m/s

All of this momentum transfers into the larger ball because the smaller ball comes to a complete stop.

For the larger ball, we have p = 4 and m = 2. Let's find v.

p = m*v

4 = 2*v

4/2 = v

2 = v

v = 2 m/s which is why the answer is choice A

The larger ball moves at a speed of 2 meters per second. The speed is cut in half compared to the smaller ball because the larger ball has more inertia (aka more mass), and therefore it takes more energy to move it. If you apply the same energy to each, then the smaller object moves faster.

A hot-air balloon has a volume of 2500 m3 . The balloon fabric (the envelope) weighs 860 N . The basket with gear and full propane tanks weighs 1200 N .
a) If the balloon can barely lift an additional 3400 N of passengers, breakfast, and champagne when the outside air density is 1.23kg/m3, what is the average density of the heated gases in the envelope?

Answers

Answer:

1.007 kg/m³

Explanation:

Given that:

volume = 2500 m³

density of air [tex]\rho = 1.23 \ kg/m^3[/tex]

weight of air displaced = [tex]V \times \rho \times g[/tex]

= 2500 × 1.23 × 9.81

= 30165.75 N

weight of the ballon fabric = 860 N; &

The propane weight = 1200 N

The passenger additional weight = 3400 N

weight of the heated gas will be = V × d × g

= 2500 × d  9.81

= 24525 d

For floating

The weight of air displaced is less than 30165.75

∴ 860 + 1200 + 3400 + 24525 d = 30165.75

5460 + 24525 d = 30165.75

24525 d = 24705.75

d = 24705.75  / 24525

d = 1.007 kg/m³

Hence, the average density of the heated gas = 1.007 kg/m³

A device for acclimating military pilots to the high accelerations they must experience consists of a horizontal beam that rotates horizontally about one end while the pilot is seated at the other end. In order to achieve a radial acceleration of 32.7 m/s2 with a beam of length 5.29 m , what rotation frequency is required

Answers

Answer:

The rotation frequency required is 23.78 RPM

Explanation:

Given;

radial acceleration, a = 32.7 m/s²

length of the beam, r = 5.29 m

The linear velocity is calculated as;

[tex]a = \frac{v^2}{r} \\\\v^2 = ar\\\\v = \sqrt{ar}[/tex]

where;

v is linear velocity

The angular velocity is calculated as;

[tex]\omega = \frac{v}{r} \\\\Recall, v = \sqrt{ar} \\\\Then, \omega = \frac{\sqrt{ar}}{r}} \\\\ \omega = \frac{\sqrt{32.7 \times5.29}}{5.29}\\\\\omega = 2.49 \ rad/s\\\\Angular \ frequency \ is \ calculated \ as;\\\\\omega = 2\pi f\\\\f = \frac{\omega}{2\pi} \\\\f = \frac{2.49}{2\pi} \\\\f = 0.396 \ rev/s\\\\f = 23.78 \ rev/min[/tex]

Therefore, the rotation frequency required is 23.78 RPM

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