Which electrically neutral atom will have an electron configuration of 1822s22p4? Use a periodic table.​

Answer:

a) Upon adding silver nitrate, a white precipitate is observed

b) Upon adding ammonium hydroxide, the white precipitate dissolves to give a clear, colorless solution

Explanation:

Here, we want to state the observations when testing for chloride ions

From what we have:

a) When silver nitrate is added, a white precipitate is formed

This is as a result of the following chemical reaction:

The AgCl is the white precipitate formed

b) Upon the addition of the ammonium hydroxide solution, a colorless and clear solution is observed showing that the white precipitate has dissolved

Equilibrium constant is the only concept that is to be used here to calculate partial pressure of nitrogen. The partial pressure of Nitrogen comes out to be  1.17atm

Equilibrium constant is a rate constant at equilibrium shows the values of reaction with respect to the atmospheric pressure and concentration

[tex]K_{c}[/tex]  is equilibrium constant with respect to concentration.

[tex]K_{p}[/tex] is equilibrium constant with respect to atmospheric pressure.

Mathematically,

[tex]K_{p}=\frac{[N_{2}][Br_{2} ] }{[NBr_{3}] }[/tex]

Substituting values

(4.8×1.10atm)÷ 4.50atm=[tex]{[N_{2}][/tex]

1.17atm=[tex]{[N_{2}][/tex]

Thus the equilibrium partial pressure of N₂ is 1.17atm.

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No, Atoms of different element can not have same atomic number because only same type of atoms combine to form element.  Atoms belonging to different element can have different atomic number.

Element generally consist of atoms or we can  atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same. Two or more than two atoms with different physical or chemical properties can not combine together to form an element.

So we can say that atomic number of all atoms that is constituting an element is same. It can never be different.

Thus Atoms of different element can not have same atomic number.

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Answer: 0.132 moles of Na2SO4

Explanation:

Multiply the grams of Na2SO4 by the 1/molar mass of Na2SO4, which is the sum of all the elements 2(Na)+S+4(O)= 142.04.

We can care for the pH meter electrode by;

1) Making sure that the electrode remains moist

2) The electrode should be stored in a 4M solution of KCl

3) Electrodes should not come in contact with deionized water.

The term pH has to do with the negative logarithm of the hydrogen ion concentration. Now we know that the pH of a solution tells us the amount of the hydrogen ions or the hydroxyl ions that is present in the solution. The pH mete is the instrument that we could use to be able to measure the pH of the solution.

The pH scale runs between 0 - 14. The points on the scale that have been labeled from 0 - 6 tells us that the solution is an acidic solution and contains more hydrogen ions.  If the solution has a pH of 7, then it is neutral and contains equal concentration of hydrogen and hydroxyl ions. A solution of pH 8 - 14 is basic and contains more hydroxyl than hydrogen ions.

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Temperature is a measure of how hot a substance or radiation is expressed numerically.

There are three different types of temperature scales:

those that depend only on macroscopic properties and thermodynamic principles, like Kelvin's original definition;

those that depend on practical empirical properties of particles rather than theoretical principles;

and those that are defined by the average translational kinetic energy per freely moving microscopic particle, like an atom, molecule, or electron, in a body, like the SI scale.

How much heat is gained or lost by a sample can be calculated using the equation q = mcΔT, where m is the mass of the sample, c is the specific heat, and T is the temperature change (q).

Therefore,

q = m*c*ΔT

102.3 = 335 * 4.184 * ΔT

ΔT = 0.073 °c

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With a balanced reaction, we can determine the moles of products. The balanced equation will be:

FeCl3 + 3NH4OH → Fe(OH)3 + 3NH4Cl

They says that NH4OH is in excess, so, the limiting reactant will be FeCl3 and we will do all the calculations with this reactant.

We have to calculate the moles of FeCl3, we will use the molar mass:

Now, to calculate the moles of the products we must take into account the product/reactive ratios, for this we are guided by the coefficients that accompany the molecules.

Ratio Fe(OH)3 to FeCl3 = 1/1

Ratio NH4Cl to FeCl3 = 3/1

Moles of each product

Moles of Fe(OH)3

Moles of NH4Cl

The grams of each product we will find by multiplying the moles by the molar mass. So we have.

g of Fe(OH)3

g of NH4Cl

Answer:

0.834 mole = 13293.32 mg

2,600 mg = 0.16 mole

Explanation:

1 mole of K = 39.098 g

=> 0.34 mole has (0.34)(39.098) = 13.29332g

13.29332 g x 10^3 = 13293.32 mg

so 0.834 mole of K = 13293.32 mg

mole of 2,600mg = (0.834)(2,600)/(13293.32) = 0.16311952168 or 0.16 mole

33.6 g grams of O2 are needed to react with 24.0 g of NH3.

The molecular mass of NH3 = 14 + 3 = 17g

Given mass of NH3 = 24g

Firstly, we will calculate the number of moles.

Moles is defined as the ratio of given mass of substance to the molecular mass of substance.

Moles = given mass/ molecular mass

Number of moles of NH3 = 24/17

= 1.4 mole

4 NH3(g)+302(g) → 2N2(g)+6H₂O(1)

4 moles of NH3 require 3 moles of O₂ to react.

1 moles of NH3 require 3/4 moles of O₂ to react.

1.4 moles of NH3 require 1.05 moles of O₂ to react.

Now we calculate the grams of O₂.

1.05 × 32 = 33.6 g.

Thus, we concluded that the 33.6 g grams of O2 are needed to react with 24.0 g of NH3.

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A risk-benefit analysis compares the risks and benefits of a situation and determines whether the advantages outweigh the disadvantages. 

Strengths

Risk-benefit analysis calculates the amount of time will be worth it to the production of technology and whether the technology will have a healthy impact on the industry or not.

Weaknesses

Risk-benefit analysis cannon determine product implementation and the outcomes of real life experiences of individual customers. It has some drawbacks like benefits of customer is take under consideration but pollution in nature is not calculated.

Implication

Risk-benefit analysis is implied in almost all technical industry as it the decision maker of any developing team to work on a particular project or not. Some examples are automobile industry and smartphone industry.

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There are three possible values for the l and there are nine possible values for ml.

The term quantum numbers has to do with the description that shows the most probable position of the electron in an atom. We know that the orbital is a region in space, where there is a high probability of finding the electrons.

Given that the values of l must be in the range of 0 to n - l and the values of ml must be in the rang of -l to + l. we then can use this to know the  number of the possible combinations of  l and ml when n = 3.

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Here are all names of compounds in aqeous solution.

What is aqeous solution?

An aqeous solution is one in which the solvent is liquid water .

In this solution water act as a solvent.

Sol-

HBr- Hydrogen bromide

1-HBrO- hydrobromic acid

2-HCL-hydrochloric acid

3-H2O3- hydrogen peroxide

4- HC2H3O2- glacial acetic acid

5-H2SO4-sulfuric acid

6- H3ASO3- Arsenous acid

7- HNO2- Nitrous acid

8- HC104- Perchloric acid

9-H2C2O4- oxalic acid

10- H3pO4- phosporic acid

11-H2CrO4- chromic acid

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pH of the acid can be calculated from the first and second ionization constants of the acid. The pH of 0.294 M of Phthalic acid is 0.53.

pH of a solution is the measure of its H+ ion concentration.It measures the acidity or basicity of the solution. Mathematically it is the negative logarithm of hydrogen ion concentration.

pH = -log [H+]

Give that the first ionization constant of the acid is 1.12 × 10 ⁻³ and second ionization constant is 3.90 × 10⁻⁶. The diprotic acid can be represented as H2A and after its first ionization it produce HA- and H+ On the second ionization the base A- and H+ ion is produced.

The second ionization constant a₂  is written as follows:

a₂ =  [A-] [H+] / [HA - [A]] = 3.90 × 10⁻⁶

From this simply we can get [A] = 3.90 × 10⁻⁶

Thus [H+] = H₂A - [A]

The concentration of the diprotic acid H₂A is given 0.294 M.

Thus [H+] = 0.294 - 3.90 × 10⁻⁶  

                = 0.2933 M

Now, the pH is calculated as follows:

pH = -log (0.2933)

    = 0.53.

Therefore, the pH of 0.294 M of Phthalic acid is 0.53.

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Scientists are looking for ways to help increase the amount of calcium carbonate in oceans so that coral reefs can be healthy ecosystems again mount of calcium carbonate in the ocean decreasing because increased amounts of carbon dioxide cause reactions to happen in the water that decrease the pH and the amount of calcium carbonate

Calcium carbonate is a compound CaCO₃ found in nature as calcite and aragonite and in plant ashes, bones and shells and used especially in making lime and portland cement and as a gastric antacid and as ocean acidification increases available carbonate ion bond with excess hydrogen resulting in fewer carbonate ion available for calcifying organisms to build and maintain their shells, skeletons, and other calcium carbonate structures

Ocean acidification describe the lowering of sweater pH and carbonate saturation that result from increasing atmospheric CO₂ concentration and that's why increased amounts of carbon dioxide cause reactions to happen in the water that decrease the pH and the amount of calcium carbonate.

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Answer: Its C I did my research and that's what makes sense to me. because increased amount of carbon dioxide decreases the PH and the amount of calcium carbonate.

Answer: nbhhvyyvub

Explanation:

1) The calculate rate constant is  9.22 * 10^-5 s-1

2) In the period of  is 15033 s 75% is used up

3) From the calculation, there is an initial 9.22 * 10^-5 M.

In chemistry, the rate of reaction would give the idea that the reaction is proceeding quickly or slowly. If a reaction has a large rate of reaction then it tends to move on to completion.

From the question, it  is clear that there is 25% in t =52 min.

Initial concentration [A]o =  [A]o

Final concentration =  [A]o - 0.25  [A]o = 0.75 [A]o

Time taken = 52 min or 3120 s

From the formula that can be applied to a first order reaction;

ln[A] = -kt + ln[A]0

k = -(ln[A] -  ln[A]0)/t

k = - (ln0.75 [A]o/A]0)/3120

k = 9.22 * 10^-5 s-1

b)

Then we have  to find  the time after the initial concentration decrease with 75%

[A] =  [A]o - 0.75  [A]o = 0.25 [A]o

ln[A] = -kt + ln[A]0

t = -(ln[A] -  ln[A]0)/k

t = - (ln0.25 [A]o/A]0)/9.22 * 10^-5

t = 15033 s

c)  Given that in this case, the initial concentration of the reactant is 2.5 mol/L·s

k = - (ln0.25 (2.5)/ln(2.5))/15033

k = 9.22 * 10^-5 M

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The molar mass of unknown gas is 211.59 g/mol.

Since both the gases are present in identical experimental condition, using Grahams law of effusion:

      [tex]\frac{time req for unknown gas}{time of oxygen}[/tex] = [tex]\sqrt{\frac{Molar mass of unknown gas}{molar mass of Oxygen} }[/tex]

  Given:

Time of unknown gas = 72 sec

Time of Oxygen = 28 sec

we know the molar mass of oxygen = 32 g/mol

Now substituting:

    [tex]\frac{72 sec}{28 sec} = \sqrt{\frac{M.M of unknown}{32g/mol} }[/tex]

M.M of unknown = (72 / 28)² × 32 g/mol

                            = 211.59 g/mol

So the molar mass of unknown gas is 211.59 g/mol

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Answer: .509

Explanation: Im pretty sure

The temperature of land far from water is hotter than land near water.

The lower heat capacity of land often allows them to cool the nearby water temperature so it takes less energy to change the temperature of land compared to water bodies. This means that land heats and cools more quickly as compared to water. This difference affects the climate of different areas on Earth. Large bodies of water like oceans, seas and large lakes can affect the climate of the nearby regions such as coastal regions. Water heats and cools more slowly than land regions. The coastal regions will stay cooler in summer season and warmer in winter season, which creates moderate climate on the coastal regions.

So we can conclude that the temperature of land far from water is different from land near water because of cooling effect of water bodies.

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To calculate the total change in binding energy we must apply the following equation:

This equation tells us that the energy change will be equal to the sum of the potential energy of the product bonds minus the sum of the potential energy of the reagent bonds.

Now, let's calculate each term separately.

So, the change in bond energy will be:

We have a negative value in the result, when this happens it means that the reaction is exothermic, that is to say, that it releases heat and the energy of the products is greater than that of the reagents.

When we have a positive value the reaction will be endothermic, this means that it needs energy.

The molar change in enthalpy of reaction is 99.6 kJ/mol.

the formula for the specific heat capacity expressed as :

Q = mcΔT

where,

m , mass = 104.153 g

c, specific heat = 4.184 J/g °C

dt, change in temperature = 22.9  °C

Q = 104.153 × 4.184 × 22.9

Q = 9969.7 J = 9.96 kJ

now, the molar change in enthalpy is give by:

Q = ΔH / n

n is no. of moles

morality of HCl = 2.2 M

v = 50 mL = 0.05 L

n = 0.05 × 2.2

   =  0.11 moles

no. of moles of NaOH = mass / molar mass

                                    = 4.039 / 40

                                    = 0.100

NaOH is limiting reactant.

using the formula we get:

Q = ΔH / n

ΔH = Q / n

ΔH  =  9.96 kJ/ 0.10

ΔH, change in enthalpy  = 99.6 kJ/mol

Thus, combine 50.0 mL H₂O, 50.0 mL of 2.2 M HCl(aq), and 4.039 g NaOH(s) (molar mass of NaOH = 40.00 g/mol) in a Styrofoam calorimeter, recording a maximum solution temperature change of 22.9 °C and a final solution mass of 104.153 g (c solution = 4.184 J/g°C).  the molar change in enthalpy of reaction is 99.6 kJ/mol.

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In order to answer this question we will need to use the molar mass of Calcium bromide (CaBr2), which is 199.89 g/mol, now we can find how much of this mass is only Bromide, so what is the percentage of Bromide that makes up this whole compound, to do so we will also use the molar mass of Bromide (Br2) which is 159.8 g/mol

199.89 g/mol = 100% of the compound

159.8 g/mol = x %

x = roughly 80% (is like 79.9%)

So, regardless of the mass of CaBr2, bromide needs to be 80% of its mass, now solving our question

395 g = 100%

x grams = 80%

x = 316 grams is the mass of Bromide in the compound

The molarity of NaOH solution that required 20.15mL is 0.0004032M.

Molarity is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.

Molarity of a solution can be calculated by dividing the number of moles in the solution by the volume as follows:

Molarity = no of moles ÷ volume

According to this question, 0.325g of KHP required 20.15ml of NaOH for neutralization. The number of moles in this mass can be calculated as follows:

no of moles = 0.325g ÷ 40g/mol

no of moles = 0.008125mol

Molarity = 0.008125mol ÷ 20.15mL

Molarity = 0.0004032M

Therefore, 0.0004032M is the molarity of the solution.

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Taking into account definition of percent yield, the percent yield of carbon dioxide is 30.90%

In first place, the balanced reaction is:

2 CH₃CH₃ + 7 O₂ → 4 CO₂ + 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 224 grams of O₂ reacts with 60 grams of CH₃CH₃, 16.7 grams of O₂ reacts with how much mass of CH₃CH₃?

mass of CH₃CH₃= (16.7 grams of O₂× 60 grams of CH₃CH₃)÷ 224 grams of O₂

mass of CH₃CH₃= 4.47 grams

But 4.47 grams of CH₃CH₃ are not available, 2.71 grams are available. Since you have less mass than you need to react with 16.7 grams of O₂, CH₃CH₃ will be the limiting reagent.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield= (actual yield÷ theoretical yield)×100%

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 60 grams of CH₃CH₃ form 176 grams of CO₂, 2.71 grams of CH₃CH₃ form how much mass of CO₂?

mass of CO₂= (2.71 grams of CH₃CH₃× 176 grams of CO₂)÷ 60 grams of CH₃CH₃

mass of CO₂= 7.96 grams

Then, the theoretical yield of CO₂ is 7.96 grams.

In this case, you know:

Replacing in the definition of percent yields:

percent yield= (2.46 grams÷ 7.96 grams)×100%

Solving:

percent yield= 30.90%

Finally, the percent yield for the reaction is 30.90%.

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Let's see that the formula to find the volume using density and mass is:

In this case, the problem is asking about the volume in mL but remember that mL is the same that cm^3, so using the formula we're going to obtain:

The volume of 5.52 g of acetone is 7.02 mL.

Answer:

It would generate a electro lithium nucleous

Answer:

flammability, toxicity etc..

Explanation:

are chemical changes

The volume of NaOH required is 80ml.

Sulfuric acid is a dibasic acid and NaOH is monoacidic base.

M1V1 = M2V2

where, M1 = initial concentration,

V1 = initial volume,

M2 = concentration after mixing

V2 = total final volume.

This formula is used for calculating the final volume or molarity after mixing two solutions.

Given the question,

M1 = 0.505M

V1 =?

M2 = 0.505M

V2 = 40 ml

M1V1 = 2×M2V2

0.505 × V2 = 2 × 0.505 × 40

V2 = 2×0.505×40

            0.505

V2 = 80ml

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