Which choice is it down below?

Answer:

6+2x >32

2x>32-6

2x>26

divide both sides by 2

therefore, x>13

Step-by-step explanation:

this is because x don't has a negative sign or is on the other side

In the proof given, BC║AD and CD║BA because: B. slopes of opposite sides are equal.

If two lines are parallel, they will have the same slope value,.

Slope = rise/run.

Slope of BC = rise/run = -2/5

Slope of AD = -2/5

Slope of BA = rise/run = -6/1 = -6

Slope of BA = rise/run = -6/1 = -6

Therefore, we can conclude that BC║AD and CD║BA because: B. slopes of opposite sides are equal.

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The correct option is option B :    -4 ≤ x ≤ 1

Increasing and decreasing functions are functions whose graphs go upwards and downwards respectively as we move towards the right-hand side of the x-axis. Increasing and decreasing functions are also called non-decreasing and non-increasing functions.

Here, from graph

as we can observe from x = -4 graph starts increases upto x = 1 and after that graph becomes constant.

Thus, between x belongs -4 to 1 the graph is increasing.

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Answer: [tex]R_{C, 180^{\circ}} \circ r_{m}[/tex]

Step-by-step explanation:

The sequence is a reflection over line m followed by a rotation 180 degrees about point C.

Among all the options give the last option that is,

⇒ r m0 Rc180° , is the right answer.

A transformation that occurs when a figure is moved from one location to another location without changing its size or shape is called translation.

Now, In the given figure ABCDE is transformed to figure A”B”C”D”E.

Hence, When a figure is reflected along a line  the reflected image is at the same distance to the line as the original figure was.

The figure ABCDE is first reflected through the line m to get the figure A'B'C'D'E'.

When a figure is rotated by 180 degrees the x and y coordinates change its place and y sign is reversed.

A'B'C'D'E' is  rotated by 180 degrees to come to figure A"B"C"D"E".

Hence, Among all the options give the last option that is,

⇒ r m0 Rc180° , is the right answer.

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The expression T = 7e + 13n represents the total income of Sherly where e is the number of earrings she sells and n is the number of necklace she sells.

It is defined as the combination of constants and variables with mathematical operators.

We have:

Sheryl makes $7 per a pair of earrings, e, and $13 per necklace, n, she sells.

Let's suppose the total income of Sherly is T:

Then,

T = 7e + 13n

Here e is the number of earrings she sells and n is the number of necklace she sells.

T is the total income and the expression T = 7e + 13n represents the total income of Sherly.

Thus, the expression T = 7e + 13n represents the total income of Sherly where e is the number of earrings she sells and n is the number of necklace she sells.

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Answer:

-17, -10, -6, -5, 3, 8 only change is between 3 and 8

Answer:

Step-by-step explanation:

We can set up two equations:  one for each sister:

Let C and D be the prices for a Candy bag and and Drink.  

Sister 1:  3C + 1D = 3.20  [The total spent by sister 1 is the sum of 3 candy bags(C) and 1 drink (D), which comes to $3.20.]

Sister 2:  2C + 4D = 6.30  [The total spent by sister 2 is the sum of 2 candy bags(C) and 4 drinks (D), which comes to $6.30.]

We have two unknowns, C and D, BUT we have 2 equations.  Therefore, we're likely going to be able to solve for C and D if we rearrange one of the equations to isolate one of the unknowns, and then use that expression in the other equation.  Seems unlikely, but it always works.

I'll pick Sister 1's equation and solve for D, the price of a drink:

3C + 1D = 3.20

1D = 3.20 - 3C  [This tells us the price of a drink is 3.20 - 3C]

Use this definition of 1D in Sister 2's equation:

2C + 4D = 6.30

2C + 4(3.20 - 3C) = 6.30

2C + 12.80 - 12C = 6.30

-10C = - 6.5

C = $0.65

One candy bag, C, is $0.65.

Use this value of C in any equation to find D, the cost of 1 drink.  I'll pick The expression we derived above:

1D = 3.20 - 3C

1D = 3.20 - 3(0.65)

1D = 3.20 - 1.95

1D = $1.25

One drink, D, is $1.25.

===================

Check the values:

Candy Bags = $0.65 each    Drinks = $1.25 each

             Reported    

Sister         1      2      1       2  

Candy bags    3  2       $1.95   $1.30  

Drinks         1  4          $1.25   $5.00  

                $3.20   $6.30 Calculated

                 $3.20    $6.30 Reported

T

The function's behavior at vertical asymptote x = 2 is (b) [tex]\mathbf{ \lim_{x \to 2^-} f(x) = \infty\ and \ \lim_{x \to 2^+} f(x) = -\infty}[/tex]

The attached graph represents the missing information in the question.

From the attached graph, we have the following highlights:

This means that the limit of f(x) approaches negative infinity and positive infinity at this value of x

Hence, the function's behavior is (b) [tex]\mathbf{ \lim_{x \to 2^-} f(x) = \infty\ and \ \lim_{x \to 2^+} f(x) = -\infty}[/tex]

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3x - 5 = -26​

step 1:

subtract +5 on each side because you have to do the inverse operation

step 2:

3x= -21

step 3:

now divide 3 on each side

the answer is -7

Hope this helped!

TheOneAndOnlyLara~

Answer:

x=-7.

Step-by-step explanation:

Hi student! Let me help you out.

_________________

First, add 5 to both sides.

[tex]\sf 3x=-26+5[/tex]. Upon simplifying, we obtain this.

[tex]\sf 3x=-21[/tex].

                                           ↪

Now divide both sides, by 3.

[tex]\sf x=-7[/tex]

[tex]\therefore,\sf the \quad value \quad of \quad x \quad is \quad -7[/tex]. Which is our final answer.

⇨Hope that this helped! have a great day ahead! ⇦

Best Wishes!

[tex]\star\bigstar\underline{\overline{\overline{\textsf{Reach far. Aim high. Dream big.}}}}[/tex]

◆◆-Greetings!-◈◈

__________________________

[tex]\text{L.H.S}\\\\=(\tan q + \sec q)^2\\\\\\=\left(\dfrac{\sin q}{ \cos q} + \dfrac 1{ \cos q} \right)^2\\\\\\=\left( \dfrac{1+ \sin q}{\cos q}\right)^2\\\\\\=\dfrac{(1+ \sin q)^2}{\cos^2 q}\\\\\\=\dfrac{(1+ \sin q)^2}{1-\sin^2 q}\\\\\\=\dfrac{(1 + \sin q)(1 + \sin q)}{(1+ \sin q)(1 - \sin q)}\\\\\\=\dfrac{1+ \sin q}{1- \sin q}\\\\=\text{R.H.S}\\\\\text{Proved.}[/tex]

Answer:

11

Step-by-step explanation:

10/15=6/x-2

then solve for x

x=11

Answer:

square rooted numbers like the square root of 2 are irrational because when calculated they don't equal a whole number.

Step-by-step explanation:

3+5√3 = 11.66   // not whole - irrational

√2 =  1.4 // not whole - irrational

√25 = 5 // whole - rational

Answer:

the answer is 8200

Step-by-step explanation:

8200+8200=16400

The length of r if AB is tangent to circle C, forming a right triangle is 8 units.

An equation is an expression that shows the relationship between two or more variables or numbers.

From the diagram, using Pythagoras theorem:

BC² = AC² + AB²

17² = 15² + r²

r = 8 units

The length of r if AB is tangent to circle C, forming a right triangle is 8 units.

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The length of the support wire on the pole is 27 feet

The given parameters are:

The length (L) of the support wire is then calculated using the following cosine function

cos(x) = b/L

This gives

cos(68) = 10/L

Make L the subject

L = 10/cos(68)

Evaluate

L = 27

Hence, the length of the support wire is 27 feet

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[tex]~~~~~~\cos 45^{\circ} = \dfrac{\text{Base}}{\text{Hypotenuse}}\\ \\\implies \dfrac 1{\sqrt 2} = \dfrac{x}{22}\\\\\implies x = \dfrac{22}{\sqrt 2}\\\\\implies x = \dfrac{22\sqrt 2}{2}\\\\\implies x = 11\sqrt 2\\[/tex]

answer:

4nd rank

Step-by-step explanation:

I'm not sure btw.

Answer:

y = 9

Step-by-step explanation:

y = (2)^2 + 5

y = 4 + 5

y = 9

Answer:

<

Step-by-step explanation:

5.62x10^4=56200, 4.7x10^5=470000, so it is <.

These following translations happened to transform f(x) into g(x):

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the functions are as follows:

The changes were as follows:

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Answer:

C. 8/17

Step-by-step explanation:

Given:

Hypotenuse = 17

BC = 8

Cos (B) = leg adjacent to ∠B / hypotenuse

= BC/BA

Substitute

Cos (B) = 8/17

Hence option C is correct

Answer:

see below

Step-by-step explanation:

I would use the sine function for the info given

 in a right triangle    sine = opp leg / hypotenuse

        so  sin 57 =  10.8/x  

           then x =  10.8 / sin 57 = 12.87

Answer:

θ = 0°

θ = 30°

θ = 150°

θ = 180°

Step-by-step explanation:

2sin² θ = sin θ

Then

2sin² θ - sin θ = 0

Then

sin θ (2sin θ - 1) = 0

Then

sin θ = 0  or  2sin θ - 1 = 0

Then

sin θ = 0  or  sin θ = 1/2

…………………………………………

We have sin θ = 0 and - 270° ≤ θ ≤180°

Then

θ = 0 or θ = π = 180°

On the other hand,

sin θ = 1/2 and - 270° ≤ θ ≤180°

Then

θ = π÷6 or θ = 5π÷6

π÷6 = 30° and 5π÷6 = 150°

Answer:

15

Step-by-step explanation:

Just substitute the x for 5
In this case:

Original function: f(x) = [tex]x^{2}[/tex] - 2x

Substitute function: f(5) = [tex](5)^{2}[/tex] - 2(5)

Now solve for the substitute function

[tex](5)^{2}[/tex] - 2(5)

25 - 10

15

Therefore, f(5) is equal to 15

Answer: See the screenshot below.

Explanation:

We'll be using these trig functions

The inverse of those help us find the angle. Notation like arcsine is the same as inverse sine denoted as [tex]\sin^{-1}[/tex] on many calculators.

The decimal results are approximate.

Answer:

x = 10

Step-by-step explanation:

The sum of the angles of a quadrilateral is 360°

(4x + 23) + (7x - 3) + (6x - 5) + (16x + 15) = 360°

4x + 23 + 7x - 3 + 6x - 5 + 16x + 15 = 360°

Add like terms

33x + 30 = 360°

Subtract 30 from both sides

33x = 330°

x = 10

Answer:

10

Step-by-step explanation:

we should note that the sum of angles of a quadrilateral is equal 360°

therefore,

(4x+23)+(16x+15)+(6x-5)+(7x-3)=360

30 +33x= 360

33x= 360-30

33x= 330

dividing through by 33

x= 330/33

x= 10

Answer:

x - 2

Step-by-step explanation:

x^3 + 3x^2 - 4x - 12 simplifies to (x + 2)(x - 2)(x + 3)

x^2 + 5x + 6 simplifies to (x + 2)(x + 3)

(x + 2)(x - 2)(x + 3)

 (x + 2)(x + 3)

The (x + 2) and (x + 3) cancel

x - 2

Kayden Kohl

9th Grade Student

(Algebra 2)

For both problems, we can use the section formula.

1) [tex]Z=\left(\frac{(2)(7)+(1)(1)}{3}, \frac{((2)(5)+(1)(2)}{3} \right)=\boxed{(5, 4)}[/tex]

2) [tex]P=\left(\frac{(1)(1)+(5)(-9)}{6}, \frac{(1)(8)+(5)(3)}{6} \right)=\boxed{\left(-\frac{22}{3}, \frac{23}{6} \right)}[/tex]