Which box has a volume of 125 cubic feet?
4 feet
9 feet
5 feet
4 feet
3 feet
4 feet
5 feet
12 feet
2 feet
5 feet
5 feet
5 feet

Which Box Has A Volume Of 125 Cubic Feet?4 Feet9 Feet5 Feet4 Feet3 Feet4 Feet5 Feet12 Feet2 Feet5 Feet5

Answers

Answer 1

Answer: Bottom left

5x5x5=125

Answer 2

The volume having 125 cubic, is a box which has dimensions,  5 feet, 5 feet, 5 feet. So Option D is correct

What is Volume?

In mathematics, Space occupied by three dimensional objects is called Volume. Basically it is a space within a closed region of every three dimensional object.

Given that,

4 boxes having different different dimensions

1. 4 feet, 9 feet, 5 feet

2. 4 feet, 3 feet, 4 feet

3. 5 feet, 12 feet, 2 feet

4. 5 feet, 5 feet, 5 feet

lets calculate the volume for all the four boxes

V = 4 feet  × 9 feet  × 5 feet  = 180  feet³

V = 4 feet × 3 feet × 4 feet  = 48 feet³

V =  5 feet × 12 feet × 2 feet  = 120 feet³

V =  5 feet × 5 feet × 5 feet  = 125  feet³

Hence, the volume of box having dimension 5 feet, 5 feet, 5 feet is 125  feet³

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CosA-[1+sin2A]1/2
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Answer:

[tex]\frac{cosA-(1+sin2A)^{\frac{1}{2} } }{sinA-(1+sin2A)^{\frac{1}{2} } } =tanA[/tex]

Step-by-step explanation:

Step(I):-

Given

    [tex]\frac{cosA-(1+sin2A)^{\frac{1}{2} } }{sinA-(1+sin2A)^{\frac{1}{2} } }[/tex]    

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  =  [tex]\frac{cosA-(1+sin2A)^{\frac{1}{2} } }{sinA-(1+sin2A)^{\frac{1}{2} } }[/tex]

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= [tex]\frac{cosA-(sinx +cosx)^{2} )^{\frac{1}{2} } }{sinA-(sinx+cos x)^2){\frac{1}{2} } }[/tex]

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= [tex]\frac{cosA-(sinA+cosA)}{sinA-(sinA+cosA)}[/tex]

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