Which answer correctly describes the grey lines in this Hering illusion? (Optical Illusions Lesson)

A close-up of a fanDescription automatically generated with low confidence



Question 1 options:

The grey lines are bent.


The grey lines are straight.


The grey lines are curly.


The grey lines are a figment of my imagination.

Answer:

d) observers in different reference frames will measure time and distance differently

This is a uniform rectilinear motion (MRU) exercise.

We get the data:

d = ?, v = 55 km/h, t = 2 hr

To calculate the distance, multiply the speed by the time.

d = v * t

The distance traveled is 110 km.

The balloon will rise the most on Wednesday due to high temperature that will increase the thermal energy of the balloon and cause it to rise higher.

The average daily temperature of the different days is calculated as follows;

Monday = (4 + 18 + 22)/3 = 14.67 ⁰C

Tuesday = (6 + 19 + 24)/3 = 16.3 ⁰C

Wednesday = (10 + 20 + 25)/3 = 18.3 ⁰C

The average daily temperature of Wednesday is the greatest.

The balloon will rise the most on Wednesday due to high temperature that will increase the thermal energy of the balloon and cause it to rise higher.

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The Answer Is Displacement  

The two factors that may affect the forces exerted by the pieces of tape are  the charge on the tape and distance between them.

The effect of one of the factors could be tested by altering the distance and calculating the forces between them.

A force is the push or pull which make a body to move or stop it.

a. When two objects are kept apart. they are always attracted when uncharged kept at any distance.

When the objects are charged, the force will be attractive or repulsive.

The distance between those charged objects increase or decrease in strength depending on the distance between them.

Thus, the two factors that may affect the forces exerted by the pieces of tape are the magnitude of charge on the tape and distance between them.

b. By increasing the distance between the tapes, we can find the strength of forces.

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This experiment help us understand their behavior as well as how the people will cop up with the rules and regulation the society wants to apply on them

In a two-week simulation of a prison setting, the Stanford prison experiment was meant to look at the impact of situational factors on participants' responses and behaviors.

Hence, this experiment allows us to better understand their behavior, as well as how individuals will respond to the laws and regulations imposed by society.

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The mass of the string is 0.515 kg.

Given that:

To solve for the mass of the string,

Therefore, the mass would be[tex]15.9*0.03242= 0.515448= 0.515[kg][/tex]

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Water can rise from the roots to the tops of trees due to capillary action. The correct option is A.

It is the phenomenon by which the liquid rises or falls in a very small diameter tube.

In plants. its roots have very thin diameter tubes which are not visible to the eye. But the water reached to the plants through these tube to every single part of the plant i.e. from root to the fruits.

So, water can rise from the roots to the tops of trees due to capillary action.

Thus, the correct option is A.

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The statement that is not true about in

terms of what to consider when judging eye witness accounts is the type of crime and how the witness saw the incident.

Judgement is a decree, or decision or conclusion on a subject matter when there is an offence or someone did wat is wrong . It can be to vindicate and to punish for a crime.

Therefore, The statement that is not true about in terms of what to consider when judging eye witness accounts is the type of crime and how the witness saw the incident

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Answer:

F = 750N

Explanation:

We know that F(force) = mass(m) × acceleration(a)

And that Acceleration(a) = velocity(V) ÷ time(t)

So we'll first calculate the acceleration

a = V = 8m/s = 1m/s²

     t        8

Next we'll calculate the force

F = ma = 750kg × 1m/s² = 750N

Explanation:

formula is given by

h/mv

where h is 6.626 × 10 ^-34

and c = 3 × 10^8

m = mass

by plugging in the values in the formula, the de Brogile wavelength is equal to 7.6424 × 10^(-15)

would appreciate a brainliest :)

Let's see

Use snells law

[tex]\\ \rm\Rrightarrow \dfrac{n_1}{n_2}=\dfrac{sini}{sinr}[/tex]

[tex]\\ \rm\Rrightarrow \mu=\dfrac{sin30}{sin19.9}[/tex]

[tex]\\ \rm\Rrightarrow \mu=0.5/0.34[/tex]

[tex]\\ \rm\Rrightarrow \mu=1.47[/tex]

It may be glass

Answer:

Usual speed: [tex]500\; {\rm km \cdot h^{-1}}[/tex].

Explanation:

Let the usual duration of the trip be [tex]t[/tex] hours ([tex]t > 0[/tex].) The actual duration of this trip would be [tex](t - (1/2))[/tex] hours.

The usual speed would be:

[tex]\begin{aligned}\frac{1500}{t}\end{aligned}[/tex].

The actual speed would be:

[tex]\begin{aligned}\frac{1500}{t - (1/2)}\end{aligned}[/tex].

The actual speed is [tex]100\; {\rm km \cdot h^{-1}}[/tex] greater than the usual speed. In other words:

[tex]\begin{aligned}\frac{1500}{t - (1/2)} - \frac{1500}{t} = 100\end{aligned}[/tex].

Simplify this equation and solve for [tex]t[/tex] ([tex]t > 0[/tex]):

[tex]\begin{aligned}\frac{15}{t - (1/2)} - \frac{15}{t} = 1\end{aligned}[/tex].

[tex]\begin{aligned}15\, t - 15\, \left(t - \frac{1}{2}\right) = t^{2} - \frac{1}{2}\, t\end{aligned}[/tex].

[tex]\begin{aligned}t^{2} - \frac{1}{2}\, t - \frac{15}{2} = 0\end{aligned}[/tex].

[tex]2\, t^{2} - t - 15 = 0[/tex].

[tex](2\, t + 5)\, (t - 3) = 0[/tex].

Since [tex]t > 0[/tex], the only possible value for [tex]t[/tex] would be [tex]t = 3[/tex].

Thus, the usual duration of this trip would be [tex]3\; {\rm h}[/tex]. The usual speed of this trip would be:

[tex]\begin{aligned}v &= \frac{s}{t} = \frac{1500\; {\rm km}}{3\; {\rm h}} = 500\; {\rm km \cdot h^{-1}}\end{aligned}[/tex].

Answer:

electromagnetic waves

Answer:

[tex]64\; {\rm m}[/tex], assuming that the rollercoaster is not attached to the track.

Explanation:

Let [tex]r[/tex] denote the radius of the loop. The height of the top of the loop would be [tex]2\, r[/tex].

Let [tex]a[/tex] denote the acceleration of the rollercoaster. At any position in the loop, if the speed of the rollercoaster is [tex]v[/tex], the (centripetal) acceleration of the rollercoaster would be:

[tex]\displaystyle a = \frac{v^{2}}{r}[/tex].

Let [tex]m[/tex] denote the mass of the rollercoaster. The net force on the rollercoaster would then be:

[tex]\displaystyle F_\text{net} = m\, a = \frac{m\, v^{2}}{r}[/tex].

The rollercoaster would stay on the track (and goes around the loop without falling off) only if the normal force [tex]F_\text{normal}[/tex] between the track and the rollercoaster is non-negative. In other words: it is necessary that [tex]F_\text{normal} > 0[/tex] for the rollercoaster to stay on the track.

At the top of the loop, [tex]F_\text{normal}[/tex] and the weight of the rollercoaster [tex]m\, g[/tex] are in the same direction as the centripetal acceleration (downwards towards the center of the loop.) Hence:

[tex]F_\text{net} = F_\text{normal} + m\, g[/tex].

Let [tex]v_\text{top}[/tex] denote the speed of the rollercoaster at the top of the loop.

[tex]\begin{aligned} F_\text{normal} &= F_\text{net} - m\, g \\ &= \frac{m\, v_\text{top}^{2}}{r} - m\, g\end{aligned}[/tex].

If [tex]F_\text{normal} > 0[/tex] at the top of the loop, then:

[tex]\displaystyle \frac{m\, v_\text{top}^{2}}{r} - m\, g > 0[/tex].

[tex]\displaystyle v_{\text{top}}^{2} > g\, r[/tex].

At the same time, by the conservation of energy, the sum of the kinetic energy [tex]\text{KE}[/tex] and gravitational potential energy [tex]\text{GPE}[/tex] of the rollercoaster should stay the same during the entire ride. Assuming that [tex]\text{GPE}\![/tex] is [tex]0[/tex] at the bottom of the loop:

[tex]\begin{aligned}& \text{KE at the bottom}\\ &= \text{KE at the top} + \text{GPE at the top}\end{aligned}[/tex].

Let [tex]v_{0}[/tex] denote the speed of the rollercoaster at the bottom of the loop.

[tex]\begin{aligned}\text{KE at the bottom} = \frac{1}{2}\, m\, {v_{0}}^{2}\end{aligned}[/tex].

The speed of the rollercoaster at the top of the loop [tex]v_\text{top}[/tex] is at least [tex](g/r)[/tex]. Therefore:

[tex]\begin{aligned}& \text{KE at the top}= \frac{1}{2}\, m\, {v_{\text{top}}}^{2} > \frac{1}{2} \, m\, g\, r\end{aligned}[/tex].

Since the height of the loop is [tex]2\, r[/tex], the [tex]\text{GPE}[/tex] of the rollercoaster at the top of the loop would be:

[tex]\text{GPE at the top} = m\, g\, h = 2\, m\, g\, r[/tex].

Thus:

[tex]\begin{aligned} \frac{1}{2}\, m\, {v_{0}}^{2} &= \text{KE at the bottom}\\ &= \text{KE at the top} + \text{GPE at the top} \\ & > \frac{1}{2}\, m\, g\, r + \text{GPE at the top}\\ & = \frac{1}{2}\, m\, g\, r+ 2\, m\, g\, r \\ &= \frac{5}{2}\, m\, g\, r\end{aligned}[/tex].

In other words:

[tex]\displaystyle \frac{1}{2}\, m\, {v_{0}}^{2} > \frac{5}{2}\, m\, g\, r[/tex].

Rearrange and simplify to obtain a bound on [tex]r[/tex]:

[tex]\begin{aligned} r < \frac{(1/2)\, m\, {v_{0}}^{2}}{(5/2)\, m\, g}\end{aligned}[/tex].

[tex]\begin{aligned} r < \frac{{v_{0}}^{2}}{5\, g}\end{aligned}[/tex].

Given that [tex]v_{0} = 40\; {\rm m\cdot s^{-1}[/tex] and [tex]g = 10\; {\rm N \cdot kg^{-1}} = 10\; {\rm m\cdot s^{-2}[/tex]:

[tex]\begin{aligned} r & < \frac{{v_{0}}^{2}}{5\, g} \\ &= \frac{(40\; {\rm m\cdot s^{-1}})^{2}}{5 \times (10\; {\rm m\cdot s^{-2}})} \\ &= 32\; {\rm m}\end{aligned}[/tex].

Hence, the radius of this loop is at most [tex]32\; {\rm m}[/tex], such that the height of the top of this loop is at most [tex]2 \times 32\; {\rm m} = 64\; {\rm m}[/tex].

Answer:

Active energy is a characteristic of Kinetic energy

The planets of the solar system has the orbiting time.

Mercury-  88 days, Venus-225 days, Earth- 365 days, Mars-687 days, Jupiter- 12 years, Saturn- 29 years, Uranus-  84 years, Neptune- 165 years, Pluto- 248 years.

Solar system consists of all the planets and the most importantly the center of the solar system is Sun.

Sun is the main focus of the solar system. It emits high temperature light rays on the planets which in turn emit lights and be visible.

Outer planets take longer to orbit the sun because the gravitational pull is weaker as shown in the inverse square law.

The outer planets very far away from the Sun, means that they have more distance to cover in their orbit.

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Unguarded live parts operating at 30,000 volts located above a working space must be elevated at least 9.5' above the working space.

The voltage is the potential difference between the end of the conductor.
The place where electricity supply wires and power stations are present, the lives must protected. They must live far above the working space.

Thus, it must be 9.5' above the working space.

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Answer:

At the critical angle the angle of refraction (outside the medium) is 90°

Ni sin θ = Na sin 90° = 1    assuming outside medium is air

sin θ = 1 / Ni            where Ni is the refractive of the medium involved

Frictional force is reduced in smooth surfaces but is large in rough surfaces.

Force is defined as an agent which causes a change in the motion or state of an object.

Forces are of two types:

Contact forces include frictional force.

Frictional forces refers to the force which acts between two surfaces in contact by opposing the relative motion of one over the other

Frictional force depends on the nature of surfaces in contact where rough surfaces produce greater frictional force than smooth surfaces.

Therefore, frictional force is reduced in smooth surfaces but is large in rough surfaces.

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Answer:

When the car crashes, there is no unbalanced force acting on the person, so they continue forward (Newton's First Law). The person moves against the seat belt, exerting a force on it.

Answer:

5 meters

Explanation:

4  and  3   are legs of a right triangle with the hypotenuse = displacement

Use Pythagorean theorem

4 ^2 + 3^2 = (displacement)^2

displacement = 5 m

The displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.

Displacement is change in the position of an object. It can be described as the shortest distance between the initial and final position of an object.

The displacement of the object is calculated as follows;

d² = 4² + 3²

d² = 25

d = 5 m

Thus, the displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.

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Answer:

Continental polar Cp

Explanation:

The horizontal force be to keep the sled moving at constant velocity is 392 N.

The horizontal force applied to the sled to prevent it from moving is calculated from Newton's second law of motion.

F - Ff = ma

where;

at constant velocity, a = 0

F - μmg = m(0)

F - μmg  = 0

F = μmg

F = 0.2 x 200 x 9.8

F = 392 N

Thus, the horizontal force be to keep the sled moving at constant velocity is 392 N.

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There are two systems that contain only the fundamental frequency and they are the systems C and D.

The term fundamental frequency refers to the lowest frequency of a vibrating body. It does not include the overtones or the harmonics.

From the image shown in the question, there are two systems that contain only the fundamental frequency and they are the systems C and D.

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Answer:

missing mass has been converted to energy according to Einstein mass energy equation

The 2.7 x 10^17 J of energy is produced when 3.0 kg mass disappears.

According to Einstein's equation, the energy produced when mass is converted to energy is proportional to the mass of the substance.

The Einstein equation is given as:

[tex]E = mc^{2}[/tex]

Mass = 3 kg

c = 3.0 × 10^8

[tex]E = 3 × (3.0 × 10^{8})^{2} = 2.7 \times 10^{17}[/tex]

Therefore, 2.7 x 10^17 J of energy is produced when 3.0 kg mass disappears.

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