Answer:
Fit test
Explanation:
it's on the automotive technology sight : )
11. Technician A says that gasoline storage containers should be painted red. Technician B says that any metal container may be used for gasoline storage. Who is correct? Name only Both A and B nor B
OTHER QUESTIONS LOOK AT PIC ABOVE PLS ANSWER ALL
Explanation:
1. Both a and b only
2. A only
3. B only
4.Neither a or b
A reversible refrigerator operates between a low temperature reservoir at TL and a high temperature reservoir at TH . Its coefficient of performance is given by
Answer
TL/TH- TL
Because we know that power coefficient is. = QL/QH-QL
=so using this for performance we have
=>Perf= TL/(TH-TL)
In mechanics of materials, the bending stress of a beam in bending can be determined by the equation σ = MyIwhere expressed in terms of SI base units M is the bending moment in Newton-meters (N-m), y is the distance from the neutral axis in meters (m), and I is the moment of inertia in meters to the fourth power (m4). The bending stress σ has the same units as those of:_____.a) pressure.b) density.c) force.d) spring constant.
Answer:
Explanation:
In mechanics of materials, the bending stress of a beam in bending can be determined by the equation
Two technicians are discussing a starter that clicks once when turning the key to the crank position. Technician A says that it could be caused by worn solenoid contacts. Technician B says it could be caused by an open ignition switch. Who is correct?
A. Technician A
B. Technician B
C. Both Technicians A and B
D. Neither Technician A nor B
Answer:
Technician A is correct.
Two technicians are discussing a starter that clicks once when turning the key to the crank position. Technician A is correct. The correct option is A.
What is a starter?An electromagnet known as a starter solenoid is activated to turn on an internal combustion engine's starter motor. The starter solenoid then connects two contacts or metal points as the key is turned.
The starter motor receives electrical currents from the ignition through the solenoid in this way. This sets off a series of electrical reactions that ultimately start the combustion engine. The multifunctional crankshaft position sensor regulates ignition timing, measures RPM, and determines relative engine speed.
The solenoid is likely defective, and the starter may sustain serious damage as a result, if the starter engages but does not disengage when you release the key.
Therefore, the correct option is A. Technician A.
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Technician A says ASE certification is mandatory in all 50 states before performing an automotive repair for pay. Technician B says automotive training programs must be reviewed every 3 years to be recertified. Who is correct?
Answer:
Technicians A is correct
Explanation:
According to ASE ( Automotive service excellence) "Certification credentials are valid for five years. If it has been five years or more since you took a test, it’s time to register for the corresponding Recertification Test. The five-year requirement ensures certified professionals are current in this rapidly changing industry."
This counters the claim of technician B who say the programs must be reviewed every three years , and ASE sends you reminders before your credentials expire.
1. Gas Metal Arc Welding is also known as
welding.
Answer: metal inert gas (MIG) welding
Explanation:
Gas metal arc welding (GMAW), also called metal inert gas (MIG) welding, is an arc welding process in which the heat for melting the metal is generated by an electric arc between a consumable electrode and the metal (Fig.
Which of the following is a safety device meant to protect an operator from the point of operation?
Answer:
machine guarding
Explanation:
Machine guarding protects an operator from the point of operation.
The correct area in sq. Inches and sq. Feet is: Select one: a. 966.76 sq. Inches and 8.056 sq. Feet b. 96.676 sq. Inches and 8.056 sq. Feet c. 96.676 sq. Inches and 0.671 sq. Feet
Answer:
c. 96.676 sq. Inches and 0.671 sq. Feet
Explanation:
From the list of the given option, we are told to chose the correct area in sq. inches that correspond to sq. Feet.
If we recall from the knowledge of our conversion table that,
1 sq feet = 144 sq inches
Then, let's confirm if the option were true.
a. 966.76 sq. Inches and 8.056 sq. Feet
Assuming
if 1 sq feet = 8.056
in sq inches, we have ( 8.056 × 144 ) sq inches
= 1160.064 sq. inches
So, 1160.064 sq. inches is equal to 8.056 sq. Feet. Then option 1 is wrong
b. 96.676 sq. Inches and 8.056 sq. Feet
if 1 sq feet = 8.056
in sq inches, we have ( 8.056 × 144 ) sq inches
= 1160.064 sq. inches
So, 1160.064 sq. inches is equal to 8.056 sq. Feet. Then option 2 is wrong/
c. 96.676 sq. Inches and 0.671 sq. Feet
if 1 sq feet = 0.671
in sq inches, we have ( 0.671 × 144 ) sq inches
= 96.624 sq. Inches which is closely equal to 96.676 sq. Inches
Therefore, this is the correct answer as it proves that 96.676 sq. Inches = 0.671 sq. Feet
MATLAB can solve a variety of engineering problems including those requiring simulating differential equations and iterative numerical calculations.A. TrueB. False
Answer:
A. True
Explanation:
MATLAB may be defined as a programming platform that is designed specifically for the engineers as well as the scientists to carry out different analysis and researches.
MATLAB makes use of a desktop environment which is tuned for certain iterative analysis and the design processes with a programming language which expresses matrix as well as array mathematics directly.
Thus the answer is true.
Technician A says that latent heat is hidden heat and cannot be measured on a thermometer. Technician B says that latent heat is hidden heat that is required for a change of state of matter. Who is correct? a. A only b. B only c. Both A and B d. Neither A nor B
Answer: C
Both A and B are correct
Explanation:
Latent heat is the hidden heat.
Latent heat is the heat energy required to change one state of matter to another state of matter without change in temperature. For example, solid state to liquid state, or liquid state to gaseous state.
Thermometer can not detect the latent heat. That is why it is called hidden heat.
If Technician A says that latent heat is hidden heat and cannot be measured on a thermometer. And Technician B says that latent heat is hidden heat that is required for a change of state of matter, then we can therefore conclude that both Technician A and Technician B are correct.
How many cables enter the 2-gang wall switch box located next to the side garage door?
Answer:
According to the National Electric Code Paragraph 404 section 2, the cables entering into the 2-gang wall must be 4 in number and it must be fitted with a neutral conductor terminal as well.
Cheers
A power plant operates on a regenerative vapor power cycle with one open feedwater heater. Steam enters the first turbine stage at 12 MPa, 5608C and expands to 1 MPa, where some of the steam is extracted and diverted to the open feedwater heater operating at 1 MPa. The remaining steam expands through the second turbine stage to the condenser pressure of 6 kPa. Saturated liquid exits the open feedwater heater at 1 MPa. The net power output for the cycle is 330 MW. For isentropic processes in the turbines and pumps.
Determine:
a. the cycle thermal efficiency.
b. the mass flow rate into the first turbine stage, in kg/s.
c. the rate of entropy production in the open feedwater heater, in kW/K.
Answer:
a) 0.489
b) 54.42 kg/s
c) 247.36 kW/s
Explanation:
Note that all the initial enthalpy and entropy values were gotten from the tables.
See the attachment for calculations
2.1 What is the minimum number of pins required for a so-called dual-op-amp IC package, one containing two op amps? What is the number of pins required for a so-called quad-op-amp package, one containing four op amps?
Answer:
8 for dual-op-amp package, and 14 for quad-op-amp
Explanation;
This is because every op-amp has 2 input terminal 4 pns
So one output terminal that is 2 pins which are required for power
and the same for a minumum number of pins required by quad op amp which is 14
Design a first order active high pass filter with a hig.
Active Filters:
Active filters are made by using the active components i.e operational amplifiers.
Passive Filters:
Passive filters are made by using passive components i.e capacitor, resistor, and inductor.
Active High Pass Filter:
An active high pass filter is shown in attachment. When the input with the high frequency is applied then the capacitive reactance will be low and signal will pass. When input frequency will be low capacitive reactance will be high. So, It will not allow to pass the Signal.
Designing:
The cuttoff frequency of this filter is given below:
[tex]f = 1/2\pi RC[/tex]
It is always known the cutoff frequency of the required filter. Hence, by supposing R we can find the C for this active high pass filter.
Gain:
As this is non-inverting amplifier so, its gain will be
[tex]A = 1+ Ri/Rf[/tex]
Q1. Convert 200 km
hur
to inches/
ms
Answer:
2.187 inches
hope it would be helpful
Answer:
2.187 in.
Explanation:
A construction manager is looking for workers to build a series of walkways within a large garden apartment project. What type of
workmen should the manager employ?
Answer:
Casual workers
Explanation:
Casual workers are workers on a short-term employment contract that unlike non-permanent workers have restricted entitlement to benefits, little employment security, with the primary distinction of there being a lack of a stable connection or relationship between them and their employers for the to be referred to as employees.
What is the specific volume of oxygen at 40 psia and 80°F?
The wall is 15 ft high and consists of 2 x 4 in. studs, plastered on one side. On the other side there is 4-in. clay brick. Determine the average load in lb>ft of length of wall that the wall exerts on the floor.
Answer:
645 lb/ft
Explanation:
The height of the wall = 15 ft
For the 2 x 4 in. studs:
The minimum dead load for a 2 x 4 in. studs (from table 1-3) = 4 psf = 4 lb/ft²
Therefore for a 15 ft tall wall, the dead load for a 2 x 4 in. studs = 15 ft × 4 lb/ft² = 60 lb/ft
For the 4 in. clay brick:
The minimum dead load for a 4 in. clay brick (from table 1-3) = 39 psf = 39 lb/ft²
Therefore for a 15 ft tall wall, the dead load for a 4 in. clay brick = 15 ft × 39 lb/ft² = 585 lb/ft
Therefore the average load = load for the 4 in. clay brick + load for the 2 x 4 in. studs = 585 lb/ft + 60 lb/ft = 645 lb/ft
ule
5. Safety and environmental training is important in keeping employees safe and free from injuries and illness.
A True
B) False
Answer:
true
Explanation:
The statement "Safety and environmental training are important in keeping employees safe and free from injuries and illness" is definitely true.
What is Injury?Injury may be characterized as a circumstance of being damaged or injured due to any physical means. This activity impacts the overall health and fitness of an individual.
Employees are working in their respective fields on the basis of their educational background, skills, and interests. But the fact that is common to all forms of employees is safety and security.
This safety prevents the employees from being injured and ill with the help of some crucial safety and environmental training in their respective trades. This approach by their company is beneficial for maintaining the health of their employees as well as the growth of the company.
Therefore, the statement "Safety and environmental training are important in keeping employees safe and free from injuries and illness" is definitely true.
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2.24 Carbon dioxide (CO2) gas in a piston-cylinder assembly undergoes three processes in series that begin and end at the same state (a cycle). Process 1-2: Expansion from state 1 where p1 = 10 bar, V1 = 1 m3, to state 2 where V2 = 4 m3. During the process, pressure and pV1.5 volume are related by = constant. Process 2-3: Constant volume heating to state 3 where p3 = 10 bar. Process 3-1: Constant pressure compression to state 1. Sketch the processes on p –V coordinates and evaluate the work for each process, in kJ. What is the net work for the cycle, in kJ?
Answer:
Explanation:
Given that:
From process 1 → 2
[tex]P_1 = 10 bar \\ \\ V_1 = 1 m^3 \\ \\ V_2 = 4 m^3[/tex]
[tex]PV^{1.5} = \ constant[/tex]
[tex]\gamma = 1.5[/tex]
Process 2 → 3
The volume is constant i.e [tex]V_2 =V_3 = 4m^3[/tex]
[tex]P_3 = 10 \ bar[/tex]
Process 3 → 1
P = constant i.e the compression from state 1
Now, to start with 1 → 2
[tex]P_1V_1^{1.5} = P_2V_2^{1.5}[/tex]
[tex]P_2 = P_1 (\dfrac{V_1}{V_2})^{1.5}[/tex]
[tex]P_2 = 10 \times (\dfrac{1}{4})^{1.5}[/tex]
[tex]P_2 =1.25[/tex]
The work-done for the process 1 → 2 through adiabatic expansion is:
[tex]W = \dfrac{1}{1-\gamma}[P_2V_2-P_1V_1][/tex]
We know that 1 bar = [tex]10^5 \ N/m^2[/tex]
∴
[tex]W = \dfrac{1}{1-1.5}[1.25 \times 10^5 \times 4- 10 \times 10^5 \times 1][/tex]
[tex]W =1000000 \ J[/tex]
[tex]W_{1 \to 2} = 1000 kJ[/tex]
For process 2 → 3
Since V is constant
Thus:
W = PΔV = 0
[tex]W_{2 \to 3} = 0[/tex]
For process 3 → 1
W = PΔV
[tex]W _{3 \to 1} = P_3(V_1-V_3)[/tex]
[tex]W _{3 \to 1} = 10 \times 10^5 (1-4)[/tex]
[tex]W _{3 \to 1} = 10 \times 10^5 (-3)[/tex]
[tex]W _{3 \to 1} = -3 \times 10^6 \ J[/tex]
[tex]W _{3 \to 1} = -3000 \ kJ[/tex]
The net work-done now for the entire system is :
[tex]W_{net} = W_{1 \to 2} + W_{2 \to 3 } + W_{ 3 \to 1 }[/tex]
[tex]W_{net} = (1000 + 0 + (-3000)) \ kJ[/tex]
[tex]W_{net} =-2000 \ kJ[/tex]
The sketch of the processes on p -V coordinates can be found in the image attached below.
A) The work done for each process are :
Process (1 - 2) = 1000 kJ Process (2 - 3) = 0 kJ process (3 - 1) = -3000 kJB) The net work for the cycle = -2000 kJ
Given Data :
For process (1 -2) For process ( 2 - 3 ) process ( 3 - 1 )
P₁ = 10 bar P₃ = 10 bar constant pressure compression
V₁ = 1 m³ constant volume heating
V₂ = 4 m³
PV[tex]^{1.5}[/tex] = constant
A) Determine work done for each process
Calculate work done for process (1 - 2)
W₁ ₋ ₂ = [tex]\frac{P_{1}V_{1} - P_{2}V_{2} }{n -1 }[/tex] * 100
= [ ( 10*1 ) - ( 1.25 * 4 ) ] / 1.5 - 1
= [ 10 - 5 ] / 0.5
= 10 * 100 = 1000 kJ
Calculate work done for process ( 2-3 )
given that there is constant volume heating
W₂₋₃ = 0 kJ
Calculate work done for process ( 3-1)
W₃₋₁ = P ( Δ V ) given that p = constant
= 10 * 100 ( -3 )
= - 3000 kJ
B) The net work for the cycle
W₁ ₋ ₂ + W₂₋₃ + W₃₋₁
= 1000 kJ + 0 kJ + - 3000 kJ
= - 2000 kJ
Hence we can conclude that the ) The work done for each process are :
Process (1 - 2) = 1000 kJ Process (2 - 3) = 0 kJ process (3 - 1) = -3000 kJand The net work for the cycle = -2000 kJ
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Attached below is the P-V sketch of the process
A rocket is shot straight up from the earth with a net acceleration (= acceleration by the rocket engine - gravitational pullback) of 7m/sec during the initial stage of flight until the engine cut out at t = 10 sec. How high will it go, air resistance neglected?
Answer:
599.7 m
approximately 600 m
Explanation:
initial speed of the rocket = 0
net acceleration upwards = 7 m/s^2
the engine cuts out 10 sec after take off
maximum height reached = ?
we neglect air resistance
To get the velocity of the rocket at the point where the engine cuts off, we use the equation
v = u + at
where
v is the velocity at this point where the engine stops = ?
u is the initial velocity of the rocket from rest = 0 m/s
a is the net acceleration upwards = 7 m/s^2
t is the time the engine runs = 10 s
substituting, we have
v = 0 + (7 x 10)
v = 70 m/s
to get the distance from the ground to this point, we use the equation
[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as
where
v is the final velocity at the the height where the engine is cut out = 70 m/s
u is the initial speed at the ground = 0 m/s
a is the net acceleration on the rocket = 7 m/s^2
s is the distance from the ground to this point
substituting, we have
[tex]70^{2}[/tex] = [tex]0^{2}[/tex] + 2(7 x s)
4900 = 14s
s = 4900/14 = 350 m
After this point when the engine cuts out, the rocket experiences an acceleration proportional to the acceleration due to gravity 9.81 m/s^2 downwards, and slows down gradually before coming to a stop at the maximum height.
To get this height, we use the equation
[tex]v^{2}[/tex] = [tex]u^{2}[/tex] - 2gs (the negative sign is due to the downward direction of the acceleration g)
where
v is the final velocity at the maximum height = 0 m/s (it comes to a stop)
u is the speed at the instance that the engine is cut out = 70 m/s
g is the acceleration due to gravity = 9.81 m/s^2
s is the distance from this point to the maximum height
substituting values, we have
[tex]0^{2}[/tex] = [tex]70^{2}[/tex] - 2(9.81 x s)
0 = 4900 - 19.62s
4900 = 19.62s
s = 4900/19.62 = 249.7 m
The maximum height that will be reached = 350 m + 249.7 m = 599.7 m
approximately 600 m
procedure of calculator programming
Answer:
I wrote this on my own so hope I helps!
Explanation:
The most basic calculations are addition, subtraction, multiplication, and division. The more transistors an integrated circuit has, the more advanced mathematical functions it can perform. ... Thus, when you input numbers into a calculator, the integrated circuit converts those numbers to binary strings of 0s and 1s.
this is what I know :)
hope it helps
A hemispherical container, 26 inches in diameter, is filled with a liquid at 20C and weighed. The liquid weight is found to be 1617 ounces.Required:a. What is the density of the fluid, in kg/m³? b. What fluid might this be? Assume standard gravity, g = 9.807 m/s².
Answer:
The answer is below
Explanation:
a) Density is the ratio mass of a substance to the total volume it occupies. The SI unit of density is kg/m³. The formula for density is:
Density = mass / volume
1 ounce = 0.0283495 kg
1 inch = 0.0254 m
The mass of liquid = 1617 ounces = [tex]1617\ ounce * 0.0283495\frac{kg}{ounce} =45.84\ kg[/tex]
diameter of container (d) = 26 inches = [tex]26\ inches*0.0254\frac{m}{inch}=0.66\ m[/tex]
Radius = d/2 = 0.66/2 = 0.33 m
The volume of a hemisphere = (2/3)πr³
Volume = [tex]\frac{2}{3}*\pi*(0.33)^3 =0.075\ m^3[/tex]
Density = mass / volume = 45.84 kg / 0.075 m³ = 609.04 kg/m³
b) Specific weight = density × acceleration due to gravity = 609.04 kg/m³ × 9.807 m/s² = 5972.83 N/m³
B.1-7 Given w=x- jy, determine:
(a) Re(e")
(b) Im(e")
Answer:
a
Explanation:
because it a year yea yea
Unsafe sites may use your personal information for criminal activities.
Answer:
True ! Unsafe sites may use our personal information for criminal activities .
True ! Unsafe sites may use our personal information for criminal activities .
What are criminal activities?
"Criminal Activities" should be required pre-"The Hateful Eight" viewing for anyone who's either forgotten or taken for granted Quentin Tarantino's gifts as a filmmaker.
Director Jackie Earle Haley's "Criminal Activities" is the worst kind of Tarantino clone, one with no gas in the tank, and no clue about how to pull off Tarantino's swagger.
So much of "Criminal Activities," a dizzyingly convoluted hostage drama, feels like a grim hang-out comedy as scripted by undergrad college film students.
Therefore, True ! Unsafe sites may use our personal information for criminal activities.
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some connecting rods have ____ to help lubricate the cylinder wall or piston pin.
Answer:
some connecting rods have spit holes
Some connecting rods have crankshaft to help lubricate the cylinder wall or piston pin.
What are crankshaft?A crankshaft is a mechanical component that converts reciprocating motion in a piston engine into rotational motion.
The crankshaft is a rotating shaft with one or more crankpins that drive the pistons via the connecting rods.
Reduced fuel economy is one issue you'll face if your car's crankshaft isn't working properly. The reason for this is that your vehicle's fuel injectors will not efficiently direct gas to the engine.
The connecting rods' big ends are lubricated with oil that travels up an oilway drilled through the crankshaft.
From the main bearings to the big end bearings, oil is pushed. It will lubricate the cylinder walls in some engines by passing through a passage drilled in the connecting rod.
Thus, the answer is crankshaft.
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a. Draw the logic gate implementation for the Boolean function F = W X(Y + Z).b. Write the DeMorgan equivalent Boolean statement in part (a) and draw its logic gate schematic.
Answer:
DeMorgan equivalent :
F = B + C
F' = ⁻B⁻+⁻C⁻ = ⁻BC⁻
Explanation:
Attached below is the logic gate implementation diagram and the DeMorgan equivalent Boolean statement as requested in part A and B
The steady, surface temperature of a lake changes from point to point and is given to you as a function T(x, y) (assume the surface of the lake is in the (x,y) plane). If you attach a thermometer to a boat and take a path across the lake surface defined by the trajectory (x(t), y(t)) = (bi(t), b2(t)), find an expression for the rate of change of the thermometer temperature in terms of the lake temperature.
Answer:
[tex]\frac{To - T}{To - T_{infinity} } = 1 - e^{\frac{-bast}{mc} }[/tex]
Explanation:
Attached below is the detailed expression
Given function : T(x,y)
assuming surface of the lake is in (x,y) plane
path across the lake surface = (x(t), y(t)) = ( bi(t), b2(t))
In other to find an expression we have to make some assumptions
What is the hardest part of thermodynamics?
Answer:
I would say that the hardest part about learning Thermodynamics is the generality and abstractness of it all.
Explanation:
Name four major categories of automotive parts and systems.
Answer:
The major systems of an automobile are the engine, fuel system, exhaust system, cooling system, lubrication system, electrical system, transmission, and the chassis. The chassis includes the wheels and tires, the brakes, the suspension system, and the body.
Explanation: