When Apollo 15 astronaut David Scott did his famous freefall experiment on the Moon, he dropped a falcon feather from a height of about 1.6 meters. Assuming a gravitational acceleration of 1.6 m/s2 on the Moon, about how long did it take the feather to drop to the surface?

Answers

Answer 1

The time taken for the feather to drop to the surface, given that the gravitational acceleration is 1.6 m/s², is 1.4 s

How do I determine the time?

From motion under gravity, we understood that height and time are related according to the follwing formula:

h = ½gt²

Where

h is the heightg is the acceleration due to gravityt is the time

Using the above formula, we can obtain the time taken for the feather to drop to the surface. Details below:

Height (h) = 1.6 metersGravitational acceleration (g) = 1.6 m/s²Time taken (t) = ?

h = ½gt²

1.6 = ½ × 1.6 × t²

1.6 = 0.8 × t²

Divide both side by 0.8

t² = 1.6 / 0.8

Take the square root of both side

t = √(1.6 / 0.8)

t = 1.4 s

Thus, the time take is 1.4 s

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Related Questions



a) While riding a chair life to the top of a hill, a 54.8
kg skier gains a total of 4.22 x 10^5 J of gravitational
potential energy. Calculate the vertical distance the skier has traveled.

Answers

Vertical distance from the point of observation on the Earth's surface to the point being measured. Altitude: Vertical distance from mean sea level to the point being measured.

What is the formula of vertical distance?To calculate vertical distance, square the total distance, subtract the square of the horizontal distance from that result, then take the square root of this number.Gravitational potential energy is the energy possessed by a falling object due to virtue of its position.And we can think of the vertical distance as the change in and the horizontal distance as the change in . So, by the end of this lesson, what we hope you'll be able to do is find the horizontal or vertical distance between two points on the coordinate plane and find side lengths of shapes in the coordinate plane.All vertical lines are in the form x=a, where a is the x-intercept. To find the distance between two vertical lines, count the squares between the two lines. You can use this method for horizontal lines as well. All horizontal lines are in the form y=b, where b is the y-intercept.

gravitational potential energy = mass * acceleration due to gravity * height

gravitational potential energy = 55 * 9.8 * 370

gravitational potential energy = 539 * 370

gravitational potential energy = 199,430

Hence the total change in the skier's gravitational potential energy is 199,430Joules.

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If you catch the ruler 8.3 cm from the lower end, what is your reaction time?

Answers

Answer:

3*3-४3*74-7%**&-*%३;9८32&*7५३३6

a rocket flies directly upward with an initial velocity of 76.5 m/s. what is the maximum height the rocket will reach?

Answers

The maximum height the rocket will reach is 298.584m if its initial velocity is 76.5m/sec and it flies upwards.

We know that at highest point final velocity of the rocket will be 0m/sec.Now,we have initial velocity of rocket,final velocity of rocket,acceleration due to gravity.

We are taking upward direction as positive and downward direction as negative, due to that value of acceleration due to gravity is -9.8m/sec²

So,we can use third equation of motion which is given by

v² - u² =2aS

where v is the final velocity of rocket,

u is initial velocity of rocket

a is acceleration of the rocket

and S is the distance travelled by the rocket

We have v=0m/sec,u=76.6m/sec,a=9.8m/sec²,S=?

So,on putting the values,we get

=>(0)² - (76.5)² = 2 × (-9.8) × S

=>S=(76.5)² / 19.6

=>S=5852.25/19.6

=>S=298.584m

Hence, maximum height attained by rocket  is 298.584m.

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Describe the forces acting on a car as it moves along a level highway in still air at a constant speed.

Answers

Newton’s First Law !

a student conducts an experiment in which an object is released from rest and falls to the floor. in the experiment, frictional forces cannot be neglected. the student uses experimental data to create two graphs. figure 1 is a graph of kinetic energy of the object as a function of time. figure 2 is a graph of the object-earth system’s gravitational potential energy as a function of time. how should the student use one or both graphs to determine how much the total mechanical energy changes after 5s ?

Answers

The required change in after 5 seconds Mechanical energy is 0.6J.

What is gravitational potential energy?

Gravitational potential energy is the energy that an article has because of its situation in the gravitational field. The most well-known use of gravitational potential energy is for objects close to the outer layer of the Earth, where gravitational speed increase can be accepted consistent at around 9.8 m/s2. Since the no point of the gravitational likely energy anytime can be picked (like picking the no point of the direction framework), the possible energy at level h over that point is equivalent to the work expected to lift Become. Move an item up to that level with no net change in active energy. Since the power expected to lift it is equivalent to its weight, it follows that the gravitational potential energy is equivalent to its weight duplicated by the level lifted.

According to question:

Mechanical energy = kinetic energy + Potential energy

So, After 5 seconds

Mechanical energy = 0.6 + 0

Mechanical energy =  0.6 J

Thus, change in Mechanical energy is 0.6J.

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a car and a truck are each traveling at 20.0 m/s, and the car is 25 m behind the truck. the car driver decides to pass the truck, and he steps on the gas, producing an acceleration of 3.0 m/s2 . (a) how long will it be before the car is alongside the truck? (b) how fast will the car be moving relative to the truck when they are side by side? (c) how far will the car travel while reaching the truck? (d) how far will the truck travel in the same time?

Answers

a) It will travel 4.082 seconds before the car is alongside the truck

b)The car be moving at a speed of 12.246 m/s relative to the truck when they are side by side

c)The distance travelled by car is 106.64 m

d)The distance travelled by truck is 81.64 m

What is meant by relative motion?

The motion of one body when compared to another which is considered to be fixed is known as relative motion.

Initial velocity of the car ,u₁ = 20.0 m/s

Initial velocity of the truck ,u₂ = 20.0 m/s

Initially the distance between the truck and the car, d = 25 m

acceleration of the car,a₁ =  3.0 m/s²

a)  For the car to reach the truck in a time interval( t ) , the distance travelled by car in that time( s₁ ) should be 25m more than the distance travelled by the truck in the same time interval( s₂ )

⇒ s₁ = 25 + s₂                      

    u₁t+ 1/2a₁t² = 25 + u₂t +0        ( by eqn of motion , s = ut + 1/2at²)

    20t + 1/2 * 3 * t² = 25 + 20t

     1/2 * 3 * t² = 25

     t² = 50/3

   t = √50/3

   t = 4.082 s

Therfore, It will travel 4.082 seconds before the car is alongside the truck

b)   Time taken for them to reach side by side ,t = 4.082 s

     velocity of car at that instance , v₁ =u₁ +  a₁t

                                                          v₁ = 20 + 3 (4.082)

                                                              = 20 + 12.246

   ∴ v₁ =32.246 m/s

    relative velocity to the truck ,v₁₂ = v₁ - u₁  

                                                         = 32.246- 20

                                                         = 12.246 m/s

Therefore the car be moving at a speed of 12.246 m/s relative to the truck when they are side by side?

c)  Distance travelled by car , s₁ = u₁t + 1/2a₁t²

                                                  =  20 (4.082) + 1/2 * 3 * (4.082)²

                                                   = 81.64 + 25

                                                    =106.64 m

Therfore the distance travelled by car is 106.64 m

d) Distance travelled by  the truck , s₂ = u₂t

                                                              = 20(4.082)

                                                             = 81.64 m

Therfore the distance travelled by truck is 81.64 m

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the diagram shows an athlete crossing the finishing line in a race. as she crosses the finishing line, her speed is 10 m/s. she slows down to a speed of 4 m/s.

a)the mass of the athlete is 71 kg. calculate the impulse applied to her as she slows down.

Answers

Answer:

The impulse applied to the athlete as she slows down is 28 N*s.

Explanation:

To calculate the impulse applied to the athlete as she slows down, we can use the equation:

impulse = force * time

Since the force applied to the athlete is equal to her mass times her acceleration, we can also express the impulse as:

impulse = mass * (vf - vi) / time

Plugging in the values given in the question, we get:

impulse = 71 kg * (4 m/s - 10 m/s) / time

Solving for impulse, we get:

impulse = 28 N*s

Therefore, the impulse applied to the athlete as she slows down is 28 N*s.

you may have noticed that when you compress a bicycle pump, the body of the pump gets warmer. a) what is the sign of

Answers

The sign of q, or the heat transfer, for the process of compressing the air in a bicycle pump, is positive. This means that heat is being transferred into the system, in this case, the air in the pump.

When a gas is compressed, the molecules collide more frequently and with greater force, which increases the temperature of the gas. This increase in temperature is due to the transfer of heat from the surroundings (in this case, the body of the pump) into the gas.

The sign of q can be determined using the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

If heat is added to the system, q is positive, and if heat is removed from the system, q is negative. In the case of compressing the air in a bicycle pump, the internal energy of the system (the air in the pump) increases, which means that q is positive.

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The question is -

You may have noticed that when you compress the air in a bicycle pump, the body of the pump gets warmer. What is the sign of q for this process?

A 60-kilogram runner has 1920 joules of kinetic energy. At what speed is she running?.

Answers

When an object is moved by a force at a constant speed over a rough, horizontal surface, the work against friction results in an increase in the object's

(1) Momentum (2) (2) Powerful potential (3) Translational Kinetic power (4) internal drive 4. The kinetic energy of a runner weighing 60.0 kg is 1920 joules. How fast is she running? Kinetic Power According to classical physics, kinetic energy (KE) is determined by multiplying the mass of an item by the square of its velocity, or 1/2*m. For instance, the kinetic energy of a mass of 10 kg traveling at a speed of 5 meters per second (v = 5 m/s) is equal to 125 joules, or (1/2 * 10 kg) * 5 m/s 2.

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What is maximum loading capacity?

Answers

The maximum amount of weight that we can load on a vehicle is known as maximum loading capacity.

The maximum loading capacity of any vehicle can be define as that maximum value of the weight of the body that we can load on the vehicle without damaging any part of the vehicle.

The maximum loading capacity of the vehicle is decided by doing certain experiments and observation by the makers and the manufacturers of the parts of the vehicle.

To avoid accidents and unfortunate events the maximum loading capacity is always higher than the prescribed limit of weight for the vehicle.

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By measuring the potential energy of an object relative to the ground, and the object's mass, you can calculate its speed when it hits the ground. Explain why you can do this.

Answers

Given that gravitational potential energy can become kinetic energy upon impact, you can determine the speed.

Total energy can be preserved in this way.

Kinetic and potential energy are equivalent.

We can calculate the velocity from this.

In this manner, we may observe the potential energy becoming kinetic energy.

A doubling in height will lead to a doubling in gravitational potential energy since an object's gravitational potential energy is directly proportionate to its height above the zero point. The gravitational potential energy will triple with a tripling of height.

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a force f is exerted on a 5 kg block to move it across a rough surface, as shown above. the magnitude of the force is initially 5 n, and the block moves at a constant velocity. while the block is moving, the force is instantaneously increased to 12 n. how much kinetic energy does the block now gain as it moves a distance of 2 m?

Answers

Right-left = ma, 5-friction=0 ,friction = 5,Work Net = change of kinetic energy,Fx-fx= change of kinetic energy,12 (2) - 5 (2) = change of kinetic energy,24-10 = change of kinetic energy.

Which one of the following scenarios involves the object's kinetic energy decreasing?

When a baseball is thrown at such an angle and is traveling upward, its kinetic energy will decrease because gravity is working against the ball's motion to slow it down and change it from kinetic energy to potential energy.

Which one of the following best illustrates how the Earth-book system's overall mechanical energy changed?

Because the author's kinetic energy does not change when it is brought to the table, the total mechanical force remains constant.

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Which forces could be used to conduct a simple experiment that tests the effect of force on an object?

Answers

Answer: electrostatic force

Explanation:

electrostatic forces pull or push on objects without touching them, which is how when you rub some materials together they can result in something called a 'charge', being moved from point A to point B.

can somebody answer this

Answers

Based on the given diagram that contains four items with a predefined mass, it is stated that the four items which are: sponge, glass, eraser and steel are submerged in water for 30 minutes, when they are all brough out, the item that would likely have an increase in weight is the sponge.

What is Weight?

This refers to the term that is used to describe and define the force exerted by gravity on an object. The gravitational force acting on the item is referred to as weight in several common textbooks. Some people refer to weight as a scalar quantity that measures the gravitational force's strength.

Hence, it can be seen that a sponge is a foamy material that absorbs water, unlike the other materials and this is the material that would feature an increase in weight after being submerged in water for 30 minutes.


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What is the frequency symbol?

Answers

Answer: f

Explanation:

It's just 'f'

Two blocks X andY of weights 8 N and 2 N
respectively are suspended by two strings as
shown. A downward force of 4 N is applied to Y.
Find the tensions T1 and T2 in the two strings.

Answers

Explanation:

are A and B really the only options ?

because they are wrong.

on T1 everything hangs : x and y and the additional 4 N.

T1 = 8 + 2 + 4 = 14 N

on T2 only the weight of y and the additional 4 N pull down.

T2 = y + 4 = 2 + 4 = 6 N

Guidlines for replenishing fuel during endurance events includeA. consume 30 to 60 grams of carbohydrate per hrB. use only one type of carbohydrate to avoid gastrointestinal upsetC. use a protein supplement every 30 minsD. avoid fluid during exercise

Answers

The recommended range for refueling for endurance races is 30 to 60 grams of carbohydrates each hour.

The following are suggestions for refueling while exercising. Use a fat supplement every 30 minutes, and stay away from fluids while working out. During endurance activities, good hydration habits should be followed. eating liquids to make up for fluid lost during exercise and drinking freely for the 24 hours before to an event. Maintaining performance, preventing injury, and maintaining hydrate all depend on replacing lost salt from exercise. To figure out how much salt is lost during training, you don't need a sophisticated lab test. You ought to be able to avoid the dangers of sodium losses if you go by these recommendations and experiment to see what works.

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What are the formulas to calculate energy wavelength and frequency?

Answers

Energy (E) is related to wavelength (λ) and frequency (ν) according to the equation E=hν, where h is Planck’s constant (6.626 × 10-34 J-s).

What is wavelentgh?

Wavelength is the distance between two successive peaks or troughs of a wave, such as light, sound, or other forms of energy. It is measured in meters or nanometers and is related to the frequency of the wave, as the frequency is inversely proportional to the wavelength. Wavelength can also be used to describe the physical size of an object, such as a particle or cell.
The equation for calculating wavelength (λ) is λ=c/ν, where c is the speed of light (3.0 × 10⁸ m/s). The equation for calculating frequency (ν) is ν=c/λ. Therefore, the formulas for calculating energy wavelength and frequency are:
Energy (E) = hν
Wavelength (λ) = c/ν
Frequency (ν) = c/λ
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a 1.00 102 -kg block is resting on a horizontal frictionless surface and is attached to a horizontal spring whose spring constant is 124 n/m. the block is shoved parallel to the spring axis and is given an initial speed of 8.00 m/s, while the spring is initially unstrained. what is the amplitude of the resulting simple harmonic motion?

Answers

The amplitude of the resulting simple harmonic motion will be A=0.07184M

As M (Mass) =1X10^-2

K (constant) =124 n/m (newton/ meter)

u (initial speed) =8 m/s     at x=0

A=?  

we have, e=1/2kx^2+1/2mu^2

but E=1/2KA^2

=1/2KA^2=1/2KX^2+1/2MU^2

1/2KA^2=1/2MU^2

A^2=M/KU^2=A=(M/K)U

A=(√1X10^-2)/124)(8)=0.0718

A=0.07184M  

or            

A=71.84X10^-3M  

A wave's amplitude is the separation between its starting point and its maximum displacement. Frequency is the quantity of waves that pass past a given place each second. Period: the amount of time required for a wave cycle to end.

It speaks about the greatest deviation an object in periodic motion can exhibit from equilibrium. A pendulum, for instance, swings past its equilibrium point (straight down), then swings to a maximum distance from the centre.

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a shot-putter accelerates a 5 kg shot put from rest to 11.2 m/s in a distance of .5 m. find the following: what is the work done on the shot put? what is the force exerted by the shot-putter? what power did the shot putter use?

Answers

(a) The work done by the shot-putter is 313.6 J.

(b) The force exerted by the shot-putter is 627.2 N.

(c) The power used by the shot putter is 7024.6 Watt.

What is the work done by the shot-putter?

The work done by the shot-putter is equal to the change in the kinetic energy of the shot-put.

W = ΔK.E

W = ¹/₂m(v² - u²)

where;

m is the mass of the shot-putv is the final velocity of the shot-putu is the initial velocity of the shot-put = 0 (since it started from rest)

W = ¹/₂m(v² - 0)

W = ¹/₂mv²

W = ¹/₂(5)(11.2)²

W = 313.6 J

The force exerted by the shot-putter is calculated as follows;

W = Fd

where;

F is the applied forced is the displacement of the shot-put

F = W / d

F = ( 313.6 J ) / (0.5 m)

F = 627.2 N

The power used by the shot putter is calculated as follows;

P = Fv

P = (627.2 N) x (11.2 m/s)

P = 7,024.6 Watt

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How do you calculate ammeter reading?

Answers

Voltmeters are typically connected in parallel because they have high resistance, while ammeters are typically connected in series to measure current since they have low resistance and the voltage drop would be minimal.

How to read ammeter reading?Ammeter resistance is typically in the range of 0.5 ohm.However, when we connect as indicated, 10 ohm and 0.5 ohm are in parallel, resulting in a 40 amp current in the ammeter and a 2 amp current in the 10 ohm resistor. As a result, the ammeter will read 40 amp even if only 2 amp of current is flowing through the 10 ohm resistance.An ammeter is a device used to gauge the current flowing through a circuit. Amperes are units used to measure electric currents, therefore the name. The ammeter is connected in series  with the circuit being used to measure the current for direct measurement.

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Why do water particles drift in a spiral shape in the direction of wave propagation?

Answers

Spiral waves in excitable systems decay to drifting defects if forced by high-frequency wave trains

What is the value of threshold voltage in 180nm technology node?

Answers

The threshold voltages for NMOS transistors in the 180 nm technology are Vth,r = 0.592 V and Vth,n = 0.068 V.

What does technology with a 180 nm mean?

Leading semiconductor firms, first with TSMC and Fujitsu, then Sony, Toshiba, Intel, AMD, Texas Instruments, and IBM, commercialized the 180 nm process, a MOSFET (CMOS) semiconductor process technology, between 1998 and 2000.

What is Threshold voltage?

The Threshold voltage at which a sizable current begins to flow from the source to the drain is referred to as the threshold voltage.

A thin inversion layer that separates the insulating from the real body of a transistor is typically used to build a threshold voltage. The region's surface is covered with tiny holes that are positively charged, and when electricity is applied, the particles in these spaces are repelled.

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What are the 3 wavelengths?

Answers

Violet electromagnetic radiation- The wavelength is 400 nm. Red electromagnetic radiation- The wavelength is 750 nm. Infrared electromagnetic radiation- The wavelength is 1000 nm.

Which three primary electromagnetic waves are there?

Although they are made using various techniques and are discovered in various ways, they are not essentially distinct from one another.Electromagnetic radiation includes radio waves, gamma rays, visible light, and all other components of the electromagnetic spectrum.

What wave has the longest wavelength out of the three?

These include microwaves, X-rays, gamma rays, infrared waves, radio waves, visible rays, and infrared, X-ray, and microwave waves.Gamma rays have the smallest wavelength as well as the shortest frequency of the seven electromagnetic waves, while radio waves have had the longest wavelength as well as the longest frequency.

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In the meeting of the Gram Sabha so far, what are the problems that are being discussed? What sort of solutions is being suggested?

Answers

Answer:

The problems discussed in the meeting of the Gram Sabha are: (i) Construction and maintenance of village roads and waterways, constructions of culverts on them and planting of trees, maintenance and repair of public wells, tanks and pits

Explanation:

Piping water from the Suru river and making an overhead tank in the villages.

(ii) Deepening the handpumps and cleaning the wells.

(iii) Conserving water and recharging it.

(iv) Name of Om Prakash should be in the BPL list.

An ice skater is spinning with her arms out and is not being acted upon by an external torque. a. When she pulls her arms in close to her body what happens to her angular momentum? b. When she pulls her arms in, what happens to her moment of inertia? c. What happens to her angular speed when she pulls her arms in? d. What happens to her rotational kinetic energy when she pulls her arms in?

Answers

When the ice skater pulls her arms in close to her body, her angular momentum remains the same because it is a conserved quantity. When the ice skater pulls her arms in, her moment of inertia decreases. When the ice skater pulls her arms in, her angular speed increases. When the ice skater pulls her arms in, her rotational kinetic energy increases.

When the ice skater pulls her arms in close to her body, her angular momentum remains the same because it is a conserved quantity. Angular momentum is defined as the product of the moment of inertia and the angular velocity of an object, and it is conserved as long as there is no external torque acting on the object. In this case, since the ice skater is not being acted upon by an external torque, her angular momentum will not change when she pulls her arms in.

When the ice skater pulls her arms in, her moment of inertia decreases. The moment of inertia of an object is a measure of its resistance to changes in its rotational motion, and it is directly proportional to the mass of the object and the distance of the mass from the axis of rotation. When the ice skater pulls her arms in, she reduces the distance of her mass from the axis of rotation, which decreases her moment of inertia.

When the ice skater pulls her arms in, her angular speed increases. This is because the decrease in her moment of inertia leads to an increase in her angular velocity, according to the equation:

ω = L / I

where ω is the angular velocity, L is the angular momentum, and I is the moment of inertia.

When the ice skater pulls her arms in, her rotational kinetic energy increases. This is because the rotational kinetic energy of an object is directly proportional to its moment of inertia and its angular velocity squared, according to the equation:

Krot = (1/2) * I * ω^2

Therefore, when the ice skater's moment of inertia decreases and her angular velocity increases, her rotational kinetic energy will also increase.

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What are genetic diseases give one example?

Answers

A genetic disease is an example, such as sickle cell anemia. The organelles that house our genes are called chromosomes. Chromosome disorders include Down syndrome.

What causes genetic illness?

A genetic disorder is a condition that is wholly or partially brought on by a deviation from the typical DNA sequence.

What exactly are genetic illnesses?

Genetic illnesses result from changes or anomalies in an organism's genome. A gene mutation can affect one or more genes, leading to a genetic disorder. Changes in chromosomal structure or number may also be to blame. Genes are the basic unit of heredity.

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A 600-kilogram space vehicle travels at 4. 8 meters per second along the level surface of mars. If the magnitude of the gravitational field strength on the surface of mars is 3. 7 newtons per kilogram, the magnitude of the normal force acting on the vehicle is.

Answers

The magnitude of the normal force acting on the vehicle in mars is 2,220 N

The mass of the vehicle = 600 kg

The speed at which the space vehicle travels = 4.8 m/s

The gravitational field strength = 3.7 N/kg

The magnitude of the force acting on the vehicle can be found using the formula,

                  F = mg

where F is the force acting on the vehicle

          m is the mass of the vehicle

          g is the gravitational strength.

Let us substitute the known values in the above equation, we get

               F = 600 x 3.7

                  = 2,220 N

Therefore, the force acting on the vehicle is 2,220 N

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Is waste a Scope 3 emission?

Answers

The Greenhouse Gas Protocol defines scope 3 emissions from waste as emissions from the disposal and treatment of all waste streams produced as a result of the operations of the institution, including the treatment of both solid waste and wastewater.

Waste: Is it an emission?

Methane emissions from solid waste decomposition in landfills, biological treatment of solid wastes, waste incineration and burning, wastewater treatment and discharge, and other sources are examples of waste emissions.

What does a scope 3 carbon and mission look like?

Although they emanate from sources that the company does not own or control, scope 3 emissions are a byproduct of corporate operations. The extraction and manufacturing of purchased materials and the transfer of purchased fuels are two examples of activities in scope 3.

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the (nonconservative) force propelling a 1.50 x 103 kg car up a mountain road does 4.70 x 106 j of work on the car. the car starts from rest at sea level and has a speed of 27.0 m/s at an altitude of 2.00 x 102 m above sea level. calculate the work done on the car by the combined forces of friction and air resistance, both of which are nonconservative forces.

Answers

Work done by friction and air resistance -780,000 Joules. Since the work done by the combined forces of friction and air resistance is negative, this means that these forces are doing negative work on the car, which means that they are slowing the car down.

The work done on the car by the force propelling it up the mountain road is given by W = Fd, where F is the force and d is the distance over which the force is applied. Since the force is nonconservative, the work it does on the car is not equal to the change in the car's kinetic energy. Instead, the work done by the force propelling the car is equal to the change in the car's potential energy plus the work done by the nonconservative forces of friction and air resistance.

To find the work done by the combined forces of friction and air resistance, we can use the following equation:

Work done by friction and air resistance = change in kinetic energy - change in potential energy

We can find the change in the car's kinetic energy by subtracting its initial kinetic energy (0 Joules, since it starts from rest) from its final kinetic energy. The final kinetic energy of the car is given by

[tex]KE = \frac{1}{2} mv^2[/tex]

where m is the mass of the car and v is its speed. Plugging in the values, we get:

[tex]KE = (1/2)(1.50 * 103 kg)(27.0 m/s)^2 = 2.16 * 105[/tex] joule

The change in the car's potential energy can be found by subtracting its initial potential energy (which is 0 Joules at sea level) from its final potential energy. The final potential energy of the car is given by

PE = mgh,

where m is the mass of the car, g is the acceleration due to gravity, and h is the height of the car above the ground. Plugging in the values, we get:

PE = (1.50 x 103 kg)(9.8 m/s²)(2.00 x 102 m) = 2.94 x 105 Joules

Substituting these values into the equation above, we get:

Work done by friction and air resistance = (2.16 x 105 Joules) - (2.94 x 105 Joules) = -780,000 Joules

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