Answer:A rear disc/drum parking brake uses the inside of each rear wheel hub and rotor assembly as a parking brake drum
Explanation:
The interior of each rear wheel hub and rotor assembly serves as a parking brake drum in a rear disc/drum parking brake.
What is a brake drum?A drum brake is a type of brake that relies on friction created by a set of shoes or pads pressing outward against a rotating cylinder-shaped part known as a brake drum.
Drum brakes are commonly used to describe brakes in which shoes press against the inner surface of the drum.
Drum brakes provide consistent braking force regardless of whether the vehicle is moving forward or backward.
This is due to the fact that drum brakes produce the same braking force in both directions. This type is typically found on passenger car rear brakes.
Thus, in a rear disc/drum parking brake, the interior of each rear wheel hub and rotor assembly serves as a parking brake drum.
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A 500-km, 500-kV, 60-Hz, uncompensated three-phase line has a positivesequence series impedance. z = 5 0.03 1 + j 0.35 V/km and a positive sequence shunt admittance y = j4.4*10^26 S/km. Calculate:(a) Zc, (b) (gl), (c) the exact ABCD parameters for this line.
Answer:
A) 282.34 - j 12.08 Ω
B) 0.0266 + j 0.621 / unit
C)
A = 0.812 < 1.09° per unit
B = 164.6 < 85.42°Ω
C = 2.061 * 10^-3 < 90.32° s
D = 0.812 < 1.09° per unit
Explanation:
Given data :
Z ( impedance ) = 0.03 i + j 0.35 Ω/km
positive sequence shunt admittance ( Y ) = j4.4*10^-6 S/km
A) calculate Zc
Zc = [tex]\sqrt{\frac{z}{y} }[/tex] = [tex]\sqrt{\frac{0.03 i + j 0.35}{j4.4*10^-6 } }[/tex]
= [tex]\sqrt{79837.128< 4.899^o}[/tex] = 282.6 < -2.45°
hence Zc = 282.34 - j 12.08 Ω
B) Calculate gl
gl = [tex]\sqrt{zy} * d[/tex]
d = 500
z = 0.03 i + j 0.35
y = j4.4*10^-6 S/km
gl = [tex]\sqrt{0.03 i + j 0.35* j4.4*10^-6} * 500[/tex]
= [tex]\sqrt{1.5456*10^{-6} < 175.1^0} * 500[/tex]
= 0.622 < 87.55 °
gl = 0.0266 + j 0.621 / unit
C) exact ABCD parameters for this line
A = cos h (gl) . per unit = 0.812 < 1.09° per unit ( as calculated )
B = Zc sin h (gl) Ω = 164.6 < 85.42°Ω ( as calculated )
C = 1/Zc sin h (gl) s = 2.061 * 10^-3 < 90.32° s ( as calculated )
D = cos h (gl) . per unit = 0.812 < 1.09° per unit ( as calculated )
where : cos h (gl) = [tex]\frac{e^{gl} + e^{-gl} }{2}[/tex]
sin h (gl) = [tex]\frac{e^{gl}-e^{-gl} }{2}[/tex]
Calculate the "exact" alkalinity of the water in Problem 3-2 if the pH is 9.43.
Calculate the "approximate" alkalinity (in mg/L as CaCO3 ) of a water containing 120 mg/L of bicarbonate ion and 15 mg/L of carbonate ion.
Answer:
A) approximate alkalinity = 123.361 mg/l
B) exact alkalinity = 124.708 mg/l
Explanation:
Given data :
A) determine approximate alkalinity first
Bicarbonate ion = 120 mg/l
carbonate ion = 15 mg/l
Approximate alkalinity = ( carbonate ion ) * 50/30 + ( bicarbonate ion ) * 50/61
= 15 * (50/30) + 120*( 50/61 ) = 123.361 mg/l as CaCO3
B) calculate the exact alkalinity of the water if the pH = 9.43
pH + pOH = 14
9.43 + pOH = 14. therefore pOH = 14 - 9.43 = 4.57
[OH^- ] = 10^-4.57 = 2.692*10^-5 moles/l
[ OH^- ] = 2.692*10^-5 * 179/mole * 10^3 mg/g = 0.458 mg/l
[ H^+ ] = 10^-9.43 * 1 * 10^3 = 3.7154 * 10^-7 mg/l
therefore the exact alkalinity can be calculated as
= ( approximate alkalinity ) + ( [ OH^- ] * 50/17 ) - ( [ H^+ ] * 50/1 )
= 123.361 + ( 0.458 * 50/17 ) - ( 3.7154 * 10^-7 * 50/1 )
= 124.708 mg/l
How does the wind affect the wildfire spread?
Answer: it spread by winds has a strong effect on fire behavior due to the fanning effect on the fire.Wind increases the supply of oxygen.
Explanation:
Fires need three things to occur in order to start and grow: oxygen, a spark/heat, and fuel. Wildfires in forests have plenty of fuel and heat is never really an issue, therefore the wind can cause a fire to continue and even spread faster. Wind will not only increase the fire's supply of oxygen, but it will also blow the fire in many different directions, now causing the flames to spread.
A total of 245 kip force is applied to a set of 10 similar bolts. If the spring constant of each bolt is 0.4 Mlb/in and that of members is 1.6 Mlbf/in. What is the net force in every bolt (Fb) if a preload equal to 40 kip was applied to the bolts?
Answer: The net force in every bolt is 44.9 kip
Explanation:
Given that;
External load applied = 245 kip
number of bolts n = 10
External Load shared by each bolt (P_E) = 245/10 = 24.5 kip
spring constant of the bolt Kb = 0.4 Mlb/in
spring constant of members Kc = 1.6 Mlb/in
combined stiffness factor C = Kb / (kb+kc) = 0.4 / ( 0.4 + 1.6) = 0.4 / 2 = 0.2 Mlb/in
Initial pre load Pi = 40 kip
now for Bolts; both pre load Pi and external load P_E are tensile in nature, therefore we add both of them
External Load on each bolt P_Eb = C × PE = 0.2 × 24.5 = 4.9 kip
So Total net Force on each bolt Fb = P_Eb + Pi
Fb = 4.9 kip + 40 kip
Fb = 44.9 kip
Therefore the net force in every bolt is 44.9 kip
"That whenever any Form of Government becomes destructive of these ends, it is the Right of the People to alter or to abolish it, and to institute new Government."
Answer: b. social contract
Explanation:
This text in the Declaration of Independence is influenced by John Locke's Social Contract theory which believes that people only enact a government that will keep them safe and secure to allow them pursue their daily lives with liberty.
If the government is unable to do that then the people have the right to overthrow such a government and institute a new one that will act in such a way as to bring them safety and happiness.
Answer:
Social Contract is right but the letter for mine was c whether the letter is different the social contract is correct.
Explanation: