What property was applied to solve the equation below? 0. 36 x = negative 1. 8 0. 36 (divided by 0. 36) x = negative 1. 8 (divided by 0. 36) x = negative 5 Addition Property of Equality Subtraction Property of Equality Multiplication Property of Equality Division Property of Equality.

Answers

Answer 1

The property of equality applied to solve the equation is division property of Equality.

What is the property of equality?

Property of equality says that by performing any mathematical operation, of both sides of an expression does not change the original value of the equation.

The equation given in the problem is,

[tex]0.36 x = -1. 8[/tex]

This equation is solved further by dividing both side of the expression with decimal number 0.36 as,

[tex]\dfrac{0.36}{0.36}x = -\dfrac{1. 8}{0.36}\\x=-5[/tex]

Here, the division operation is performed both sides of the equation to solve the equation. This does not change the original value of the equation and gives the value of unknown number.

Thus, the property of equality applied to solve the equation is division property of Equality.

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Related Questions


I am really confused and need help.

Answers

Answer:

The 3rd, 4th, and 6th are correct but I'm not sure if the second would be correct as well.

Step-by-step explanation:

Fabiola’s dog is 5 pounds heavier than one-third of the weight of Luisa’s dog. Fabiola’s dog weighs 23 pounds. Use the diagram to write an equation to represent the dogs’ weights. Let f represent the weight of Luisa’s dog.

A long rectangle is the top section. 2 smaller rectangles are the bottom section.

The top section represents
.
The bottom section represents
.
The equation is
.

Answers

Let us rephrase this statement: Fabiola's dog weighs 5 pounds more than one-third of Luisa's dog. The dog that Fabiola owns weights 23 pounds.
This is the equation for Fabiola's dog's weight: 1/3f + 5 = 23

I have no understanding what the diagram means.

PLEASE HELP ME!!

A line has this equation: 5y+x=-40
Write an equation for the perpendicular line that passes through the point (1, 10)

Answers

Answer:

look it up go to demos

Step-by-step explanation:

hi pls help it’s pretty simple i think

Answers

Answer:

The radicals is the name of the sign we use in roots. The numerator is the power of the exponential, and the denominator is the power of the root.

So we take the radical:

√((-4)^2/7)

And move the denominator to the place where we list the root's power:

7√((-4)2)

Do note you can remove the outermost parentheses if you were to extent the radical's top line, something like so:

_____

7√(-4)2

[tex]the \: answwr \: is \: 1.48 \: or \\ 7 \sqrt{( - 4) {}^{2} } [/tex]

# be careful #

A mole starts out in its burrow 5.1 feet below the surface of the ground. It digs straight up at a rate of 0.4 feet per minute.
How long does it take for the mole to reach a depth of -3.7 feet?
Enter your answer as a decimal in the box.

Answers

The mole approximately 3.5 minutes to reach a depth of -3.7 feet.

To determine how long it takes for the mole to reach a depth of -3.7 feet, we need to calculate the time it takes to cover the distance between its starting point and the target depth.

The mole is digging straight up at a rate of 0.4 feet per minute.

Since the target depth is negative, we can consider it as a negative displacement.

The distance the mole needs to travel can be calculated as follows:

Distance = Target depth - Starting depth

Distance = -3.7 feet - (-5.1 feet)

Distance = -3.7 feet + 5.1 feet

Distance = 1.4 feet

Now, we can calculate the time it takes for the mole to cover this distance using the formula:

Time = Distance / Speed

Time = 1.4 feet / 0.4 feet per minute

Time = 3.5 minutes

Therefore, the mole approximately 3.5 minutes to reach a depth of -3.7 feet.

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Consider the following expression.
Select all of the true statements below.
7a+3b+4

7a is a factor.

7a+3b is written as a sum of three terms.

7a and 4 are like terms.

7a is a coefficient.

4 is a constant.

None of these are true.

Answers

Answer:

None of these are constant

Answer: 4 is a constant.

Explanation:
A constant is the number in an equation without a variable, 4. A coefficient is the number before the variable, not with the variable, so 7 and 3 would be a coefficient but it says 7 and a are coefficients. 7a and 4 are not like terms because 4 doesn’t have the same variable as 7. 7a is obviously not a factor.

The coordinates of a rectangle are (-11,20), (-11,3), (-1,20), (-1,-3). Find the perimeter and the area of the rectangle.

Answers

Answer:

The perimeter of the rectangle is 54, and the area is 170.

Step-by-step explanation:

First, we must plug the coordinates into a graph (attached below).

[tex]l=10\\w=17[/tex]

Now, we must solve for the perimeter.

[tex]P=2(l+w)\\P=2(10+17)\\P=2*27\\P=54[/tex]

Lastly, we must solve for the area.

[tex]A=wl\\A=(17)(10)\\A=17*10\\A=170[/tex]

You're welcome!

5) The length of one side of a square is 12 meters. To the nearest tenth, find the length of a diagonal of the square.​

Answers

Answer:

17.0 meters

Step-by-step explanation:

The diagonal of a square is calculated as sqrt(2) x a, where a is the side

= sqrt (2) x 12 = approx. 16.97 (round to 17.0)

Hope this helps :)

HELP ILL GIVE YOU BRAINLIEST
Determine the absolute maximum value of the function f.

Answers

Answer: I think 7

Step-by-step explanation:

what is x

x/2 = (8 - 2x)/4

Answers

Answer:

x = 2

Step-by-step explanation:

x*(4) = (8-2x)*(2)

4x = -4x+16

+4x    +4x

8x = 16

x = 2

Answer:

x = 2

Step-by-step explanation:

Multiply to remove the fraction, then set equal to 0 and solve.

please i need the answer ​

Answers

1.) DBC

2.) EBA

3.) CBD=20
180-160=20

4.) CBD=60
3x=180
x=60

5.) Supplementary

help me with this math pls

Answers

If you’re trying to find one phases area then 20 x 6.5 if you are trying to find the whole figures area it’s 4(20x6.5)

Solve each system of equations using the elimination method

4x-y=-2
2x+y=2

Answers

x = 0

y = 2

Step-by-step explanation:

4x - y = -2

2x + y = 2

-------------- add the equations

6x = 0

x = 0

substitute x in equation 1

0 - y = -2

y = 2

Solve for xx. Round to the nearest tenth of a degree, if necessary.QRSx°2755Answer: x=x=

Answers

The measure of x is an illustration of the cosine trigonometry ratio

The measure of x to the nearest tenth of a degree is 58.7 degrees

How to calculate the measure of x

The measure of x is calculated using the following cosine ratio

[tex]\cos(x) = \frac{4.1}{7.9}[/tex]

Evaluate the quotient

[tex]\cos(x) = 0.5190[/tex]

Take the arccos of both sides of the equation

[tex]x = \cos^{-1}(0.5190)[/tex]

Evaluate the arccos(0.5190)

[tex]x = 58.73[/tex]

Approximate to the nearest tenth of a degree

[tex]x = 58.7[/tex]

Hence, the measure of x is 58.7 degrees

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Jake plans to make and sell wooden birdhouses. He plans to sell each birdhouse for $50, his income can be found using the equation I(x) = 50x, where x is the number of birdhouses he sells. It costs him $10 in materials for each birdhouse, so his expenses can be found using the equation E(x) = 10x. Use function operations to find an equation for his profit, P(x), and find his profit if he sells 20 birdhouses.

Answers

Answer:

290 Is the answer I answered it before

2 box plots. The number line goes from 175 to 450. For resort A, the whiskers range from 175 to 375, and the box ranges from 250 to 300. A line divides the box at 375. For Resort B, the whiskers range from 200 to 400, and the box ranges from 300 to 375. A line divides the box at 325. Kevin wanted to go snowboarding for his vacation. He looked up annual snowfall of both resorts over a ten-year period to determine which resort would have the better snowfall. Compare the two box plots and use the drop-down menus to determine where Kevin should plan to go for vacation. What is the approximate median snowfall at Resort A? What is the approximate median snowfall at Resort B?.

Answers

Box plot 5 important descriptive measures about data that they represent.

The median snowfall for Resort B is greater than the median for Resort A

The interquartile range has higher values for Resort A than for Resort B.

Resort B has more snowfall overall than Resort A does.

How does a boxplot show the data points?

A box plot has 5 data descriptions.

The leftmost whisker shows the minimum value in the data.

The rightmost whisker shows the maximum value in the data.

The leftmost line in the box shows the first quartile.

The middle line shows the median, also called the second quartile.

The last line of the box shows the third quartile.

How to find the interquartile range?

IQR(interquartile range)  is the difference between the third and first quartile.

Inferring the information each box plot describe, we get:

Case 1: For resort A:

Wisker's minimum value = minimum value for resort A = 175

Maximum value = 375

Box's minimum value = First quartile = 250

Box's maximum value = Third quartile = 300

First quartile = 250 < Median = Second quartile < 300 = third quartile

Thus, 250 < Median for resort A < 300

IQR = Third quartile - first quartile = 300 - 250 = 50

Range of values = Max - min = 375 - 175 = 200

Case 2: For resort B:

Wisker's minimum value = minimum value for resort B = 200

Maximum value = 400

Box's minimum value = First quartile = 300

Box's maximum value = Third quartile = 325

First quartile = 300 < Median = Second quartile < 375 = third quartile

Thus, 300 < Median for resort B < 375

IQR = Third quartile - first quartile = 325 - 300 = 25

Range of values= Max - min = 400 - 200

Thus, it is visible that:

Median for resort A < 300 < Median for resort B

or

Median for resort A < Median for resort B.

and

IQR for resort A = 50 > IQR for resort B = 25

and

Both have the same variation as both ranges are the same, which is the interval of values assumed for both resorts.

Hence, Minimum, maximum, first, and third quartile all are smaller for resort A, thus, Resort B has more snowfall overall than Resort A does.

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What is the approximate median snowfall at Resort A?

✔ 275 inches

What is the approximate median snowfall at Resort B?

✔ 325 inches

Which point is located at (2, -3)?

Answers

Point K because its x-coordinate is at 2 and its y-coordinate is at -3.

A) Point K

Answer:

Point K

Step-by-step explanation:

Remember, in a rectangular coordinate plane, every point is shown as (x, y)

x is moving left and right while y moves up and down. Looking at the point provided, (2, -3).

x = 2

A positive x value means the point will be shifted to the right, while the number 2 tells you to shift to the right 2 units.

y = -3

A negative y value means the point will be shifted down, while the number -3 tells you to shift down 3 units.

Now, looking at the graph, starting at (0, 0), move to the right 2 units and move down 3 units. The point resting at this point is Point K.

show the linear graph obtained by joining the following points is a staright line. (6,-3),(6,1)and(6,6)

Answers

Points be

A(6,-3)B(6,1)C(6,6)

Slope of AB:-

[tex]\\ \tt\hookrightarrow m=\dfrac{1+3}{6-6}=\dfrac{4}{0}=\infty[/tex]

Slope of BC

[tex]\\ \tt\hookrightarrow m=\dfrac{6-1}{0}=\infty[/tex]

As

Slope of AB=Slope of BC

A,B,C are colinear.

5x+3y=15
x+2y= -5 solve for x and y

Answers

Answer:

x=-3/5y+3

Step-by-step explanation:

Let's solve for x.

5x+3y=15

Step 1: Add -3y to both sides.

5x+3y+−3y=15+−3y

5x=−3y+15

Step 2: Divide both sides by 5.

5x/5 = -3y+15/5

Answer

x=-3/5y+3

can 3 meters and 2 km be expresses as a ratio.

Answers

yes 2km is 2000 meters
3:2000
it cannot be simplified

Answer:

yes, you can just write it as 3m : 2km

Step-by-step explanation:

I don't know if this is completely right, but I know you can also turn 3m into km by multiplying it by 1000, (because there are 1000 m in every km) and then solve because 3000km/2km = 1500km

So to solve would be 1500 km. I hope the first answer is right though. Did I help? Let me know in the comments

What is n in n:44 = 7:11?

Answers

Answer:

n = 28

Step-by-step explanation:

hope this helps :)

[tex]\frac{n}{44} =\frac{7}{11} \\\\11n=308\\n=\frac{308}{11} \\n=28[/tex]

Find the volume of a sphere with a radius of x – 1.

Answers

-2.52 this is the answer because y=md+b

The amount of region enclosed by a plane closed figure is calles

Answers

Answer:

The amount of region enclosed by a plane-closed figure is called its Area. Hence, correct answer is Area.

FROM

SURAJ SAINI

Need answer as soon as possible

Answers

Answer:

adding all like terms the answer will be:

[tex]\frac{3}{8} x + \frac{1}{2} y + \frac{3}{8}[/tex]

Step-by-step explanation:

Answer:

sec answer

[tex] \frac{3}{8} x + \frac{1}{2} y + \frac{3}{8} [/tex]

Which of the statements about the following quadratic equation is true? 6x2 - 8 = 4x2 7x.

Answers

Answer:

2(−2x^28+3x^2−4)=0

Step-by-step explanation:

this is your answer factored. but i will you the real answer after you tell me all the other options

Answer:

Step-by-step explanation:

A store owner asks each person to write “Yes” or “No” on a slip of paper as they leave, secretly writing down whether they were happy with their experience. At the end of the day, the owner selects 12 slips at random and looks at them.

These were the results:
yes, yes, yes, no, yes, no, yes, yes, no, yes, no, yes

a. Estimate the proportion of all shoppers who were happy with their experience that day.

Answers

Answer:

2/3

Step-by-step explanation:

Probability=number of favourable outcomes/number of possible outcomes

P(customers who were happy with their experience)= 8/12 = 2/3

two-third of total customers (12 people) were happy with their experiences.

The following rectangle has area 16.4icm² and length 8.207cm. Work out its width, xcm. Area = 16.41 cm x cm 8.207cm​

Answers

I’m a little confused by the question at the end, but from the first two sentences, I think I’ve got it. If not, leave a comment and I can help further. So to find the width of this rectangle, you only need to divide the area by the length. As to find the area, it’s length x width. Kind of like the width is x and you are trying to get w separate from 8.207. (16.4)/(8.207). This comes out to be 1.99829414 cm. Hope this helps!

will give u 20 points brainlist

Answers

Answer:

once a plats grew in 2 weeks he was 12 weeks old and he grew by 10 to 60 height lead and and he gained 140 to 155 fat

Step-by-step explanation:

Hello! can someone help with these questions? I provided photos of the triangles below.

1. Determine which sides correspond with each angle in triangle ABC below.
a. angle XYZ corresponds with side length ____
b. angle ZXY corresponds with side length ____
c. angle YZX corresponds with side length ___

2. Determine which angles correspond with each side in the triangle below.
__
a. side length KL corresponds with angle ___
__
b. side length LJ corresponds with angle ___
__
c. side length JK corresponds with angle ___

thanks for any help!

Answers

The sides that correspond to each angle in triangle ABC are:

Angle XYZ corresponds with side length YZAngle ZXY corresponds with side length XZAngle YZX corresponds with side length YX

The angles correspond with each side in the triangle are:

Side length KL corresponds with angle KSide length LJ corresponds with angle JSide length JK corresponds with angle L

How to determine the corresponding sides

The corresponding sides are segments located at the same relative position of an angle.

So, the corresponding sides of the angles are:

Side YZ & angle XYZ, Side XZ & angle ZXY, and Side YX and angle YZX

How to determine the corresponding angles

On the other hand, the corresponding angles are segments located at the same relative position of the sides.

So, the corresponding angles of the sides are:

Side KL & angle K, Side LJ & angle J, and Side JK and angle L

Read more about corresponding sides and angles at:

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someone pls help me..

Answers

Answer:

[tex]32x^2 \sqrt[3]{2x} - 8x^3[/tex]

Step-by-step explanation:

[tex]\hookrightarrow 4x\sqrt[3]{4x^2}\left(2\sqrt[3]{32x^2}-x^3\sqrt{2x}\right)[/tex]

[tex]\hookrightarrow 8x\sqrt[3]{32x^2 } \sqrt[3]{4x^2} -4x^2 \sqrt[3]{4x^2} \sqrt[3]{2x}[/tex]

[tex]\hookrightarrow 2^5\sqrt[3]{2}x^{\frac{7}{3}}-2^2\cdot \:2^{\frac{2}{3}}\sqrt[3]{2}x^3[/tex]

[tex]\hookrightarrow 32\sqrt[3]{2}x^{\frac{7}{3}}-4\cdot \:2^{\frac{2}{3}}\sqrt[3]{2}x^3[/tex]

[tex]\hookrightarrow 32x^2 \sqrt[3]{2x} - 8x^3[/tex]

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