What number is 20% of 80

Answers

Answer 1

Answer:

16

Step-by-step explanation:

a trick that helps with percentages

if its 20% of 80, multiply 20 and 80 and then divide that by 100 so 1600 divided by 100. 16. hope this helps!!


Related Questions

Please select the best answer from the choices provided ASAP

Answers

Answer:

c

Step-by-step explanation:

I think the correct answer is C

Please help! It's due today!

Expand (3a-2b^3)^2

Answers

Answer:

9a²-12ab³+4b⁶

Step-by-step explanation:

use FOIL to solve

f-first

o-outer

i-inner

l-last

Answer: 4b^6 - 12ab^3 + 9a^2

yw

can i get some help!!

Answers

yes u can get help what is it?

Answer:

Yeah i can  help you ,but the picture u have uploaded is blank.

pls upload again.

Step-by-step explanation:

Pls mark BRAINLIEST

Solve the system of equations -x+6y=2 and -3x+y=-11 by combining the equations.

Answers

X=4,,,,,,,,,,,,,,,,,,,,,,,,,,y=1,,,,,,,,,
Combine (5-i)+3i

Answer this question( need less then 5 minutes) 15 = t - 25 t=

Answers

Answer: t=40

Step-by-step explanation:

To work out t on its own you have to do the inverse of takeaway which is add so it is 15+25=40.

What is the correct answer?

Answers

Answer:

F

Step-by-step explanation:

The answer to your question is F

help me with this geometey question !! thanks!​

Answers

Answer:

A=542

Step-by-step explanation:

none, sorry

Answer: 542 ft.^2

Steps:

2(l*w) + 2(l*h) + 2(w*h)

2(13*7) + 2(13*9) + 2(7*9)

2(91) + 2(117) + 2(63)

182 + 234 + 126

=542

Please answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

Answers

Add the ratios together:

5 + 2 + 1 = 8

Divide the length of NQ by that:

24/8 = 3

Multiply the ratio of NO by that/l

The ratio of NO is 5, 5 x 3 = 15

NO = 15

A local boutique marks up all merchandise by 45%. If she purchases a dress wholesale for $28, what will be the sale price at her boutique? Help please

Answers

Answer:

45+28

Step-by-step explanation:

the

Find the mean of the set of data.
6, 8, 6, 6, 8, 6, 3, 8, 3, 8.

Answers

Answer:

Hellothe mean of the data =

= 6+8+6+6+8+6+3+8++3+8

10

= 62

10

= 6.2

Step-by-step explanation:

thanks pls mark as brainliest

Beth is buying 2.6 pounds of coffee beans. If the coffee costs 6.79 per pound, how much will she pay? Round to the nearest cent..

Answers

Answer:

$17.65

Step-by-step explanation:

hope this helped!!

When two rays have a common _________, they form a(n) _________.
A
vertex, angle

B
angle, vertex

C
angle, line segment

D
vertex, line segment

(this is for 7th grade by the way)

Answers

The answer is A, vertex, angle

—Evidence—
•] the two rays are connected at a common endpoint, called a vertex. This forms the angle. An angle is named by points on the rays.
The answer is A hope that helps!

Karla has spent $39 on food. She bought milk, cheese, and meat. The milk cost half as much as the cheese and the meat cost four times as much as the cheese. Which equation would help you find the cost of the cheese?

Let c = the amount spent on cheese

Click on the correct answer:

1)C+ 4c/5c=39

2)C+2c + 4c = 39

3)C+.5c + 4c = 39

4)C(.5c+ 4c) = 39

This is part of "Using Linear Equations to Solve Problems:Application" on Edmentum.​

Answers

Answer:

i think the answer is 3)C+.5c + 4c = 39

Step-by-step explanation:

Sophia bought snacks for her team's practice. She bought a bag of popcorn for $1.98
and a 10-pack of juice bottles. The total cost before tax was $12.48. Write and solve
an equation which can be used to determine j, how much each bottle of juice costs?

Answers

Answer:

j = $1.05

Step-by-step explanation:

($12.48 - $1.98) / 10 = j

(Total cost - popcorn cost) / number of juice boxes = cost of one juice box

Answer:

10j+1.98=12.48

j= 1.05

Step-by-step explanation:

Can you help please I am struggling thank you

Answers

Answer:

m<ADC = 107

Step-by-step explanation:

You need to know three things to solve this problem.

1) Opposite angles of an inscribed quadrilateral are supplementary.

2) The measure of an inscribed angle is half the measure of its subtended arc.

3) The sum of the measures of all the arcs of a circle is 360 deg.

From 1) we get:

m<A + m<C = 180

72 + m<C = 180

m<C = 108

From 2) we get:

m<C = (1/2)m(arc)BAD

108 = (1/2)[m(arc)AB + m(arc)AD]

216 = m(arc)AB + 122

m(arc)AB = 94

From 3) we get:

m(arc)AB + m(arc)BC + m(arc)CD + m(arc)DA = 360

94 + 120 + m(arc)CD + 122 = 360

m(arc)CD = 24

From 2) we get:

m<ADC = (1/2)m(arc)ABC

m<ADC = (1/2)[m(arc)AB + m(arc)BC]

m<ADC = (1/2)[94 + 120]

m<ADC = 107

US_
Diagram NOT
accurately draw
(x + 1)cm
(3 - x) cm
(2x + 5) cm
The diagram shows a cuboid of volume V cm3
(a) Show that V = 15 + 16x - x (squared) - 2x (cubed)

Answers

Answer:

Step-by-step explanation:

Length of the cuboid = ((2x + 5) cm

Width of the cuboid = (3 - x) cm

Height of the cuboid = (2x + 5) cm

Since, volume of the cuboid = Length × Width × Height

                                               = (2x + 5)(3 - x)(x + 1)

                                               = [2x(3 - x) + 5(3 - x)](x + 1)

                                               = (6x - 2x² + 15 - 5x)(x + 1)

                                               = (-2x² + x + 15)(x + 1)

                                               = x(-2x² + x + 15) + 1(-2x² + x + 15)

                                               = -2x³ + x² + 15x - 2x² + x + 15

                                               = -2x³ - x² + 16x + 15

                                               ≈ 15 + 16x - x² - 2x³

Mr. Snyder begins traveling east on Interstate 90 from Spokane with a full tank of gasoline. His car has a 15-gallon gas tank and gets 30 miles per gallon during highway travel. Let m = the number of miles Mr. Snyder has driven Let g = the number of gallons of gas remaining in his tank Select in the letter of the equation that describes the relationship between the number of miles Mr. Snyder has traveled and the number of gallons remaining in his gas tank.

Answers

Answer:

[tex]g = 15 - \frac{1}{30}m[/tex]

Step-by-step explanation:

Given

[tex]Initial = 15[/tex]

[tex]mpg = 30[/tex] --- miles per gallon

Required

Determine an equation for this trip

First we have to get the number of gallons per mile from [tex]mpg = 30[/tex]

[tex]\frac{miles}{gallon}=30[/tex]

Inverse the equation

[tex]\frac{gallon}{miles}=\frac{1}{30}[/tex]

This represents the rate in gallons/mile

So, the equation is:

[tex]g= Initial - Rate * m[/tex]

[tex]g= 15 - \frac{1}{30} * m[/tex]

[tex]g= 15 - \frac{1}{30}m[/tex]

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

A population of 470 animals decreases at an annual rate of 12%.

a.f(x)=470(1.88)x

b.f(x)=470(0.12)x

c.f(x)=470(0.88)x

d.f(x)=470(1.12)x

Answers

Answer:

C. f(x) = 470(0.88)ˣ

Step-by-step explanation:

Initial number =  470Decrease rate = 12%   ⇒ 100% - 12% = 88%   ⇒ 0.88 times

Required equation:

f(x) = 470(0.88)ˣ

Correct choice is C

I NEED ANSWERS ASAP!!! PLEASE

Answers

Answer:

10 in by 48 in

Step-by-step explanation:

The volume (V) of a rectangular solid is calculated as

V = Ah ( A is the area of the base and h the height )

Here h = 3 and V = 1440 , then

3A = 1440 ( divide both sides by 3 )

A = 480 in²

The area of a rectangle = length × breadth

From the give options

10 × 48 = 480 ← is the only option

CAN SOMEONE PLEASE FIND THE VOLUME AND SURFACE AREA OF THIS FIGURE.

and round to the nearest hundredth

Answers

Answer:

Volume = 1659.84Surface area = 1205.36

Step-by-step explanation:

Volume for triangular prism = 1/2 * b * l * h

we are given the length and the height but not the base.

since it is a right triangle we can use the Pythagorean theorem a^2 + b^2 = c^2

13.3^2 + b^2 = 20.5^2

176.89 + b^2 = 420.25

b^2 = 243.36

b = [tex]\sqrt{243.36}[/tex] = 15.6

1/2 (15.6)(13.3)(16) = 1659.84

Front: 15.6 x 13.3 = 207.48

Back: 15.6 x 13.3 = 207.48

Left: 15.6 x 16 = 249.6

Right: 13.3 x 16 = 212.8

Bottom: 20.5 x 16 = 328

207.48 + 207.48 + 249.6 + 212.8 + 328 = 1205.36

In a school, 30% of the students arrived by private car, 15 travel by taxi and the remainder walk to school. If the school has a population of 230, how many more students walk to school than arrives by car?

Answers

Answer:

57.5 students

Step-by-step explanation:

Given that

The 30% students would be arrived by private car

So 15% would be travelled by taxi

And, the remaining i.e. 55% would be walk to school

Since the population of the school is 230

So by car, the students would be

= 230 × 0.30

= 69

By walk, the students would be

= 230 × 0.55  

= 126.50

Now the more students would be

= 126.50 - 69

= 57.5 students



A student is standing next to a vertical flagpole. The top of the student's shadow

coincides with the top of the flagpole's shadow as shown.

not to scale

The student is 62 inches tall. The student estimates that the distance from the flagpole

to the point where the student is standing is between 21 and 22 feet. The student also

estimates that the length of the student's shadow is between 7 and 7 feet.

Based on the given information, what are the least and greatest possible heights, in

feet, of the flagpole? Explain how you arrived at your answers.

Answers

Answer:

The least possible height of the flagpole is 227.33 inches and the greatest possible height is 248 inches

Step-by-step explanation:

Given

See attachment for the system

Required

Determine the least and greatest heights of the flagpole

From the question, we have:

[tex]AB = 7\ to\ 7\frac{1}{2} ft[/tex]

[tex]BE =62in[/tex]

[tex]BC = 20\ to\ 21ft[/tex]

Convert AB and BC to feet (multiply by 12)

[tex]AB = 84in\ to\ 90in[/tex]

[tex]BC = 240in\ to\ 252in[/tex]

The height of the flagpole is represented as: CD

To calculate CD, we make use of the following equivalent ratios:

[tex]CD : AC = BE : AB[/tex]

Express as fraction

[tex]\frac{CD }{ AC } = \frac{BE }{ AB}[/tex]

Make CD the subject

[tex]CD = \frac{BE }{ AB} * AC[/tex]

From the attachment:

[tex]AC = AB + BC[/tex]

Where:

[tex]AB = 84in\ to\ 90in[/tex]

[tex]BC = 240in\ to\ 252in[/tex]

The possible values of AC are:

[tex]AC = 84 + 240 =324in[/tex]

[tex]AC = 84 + 252 =336in[/tex]

[tex]BC = 90 + 240 = 330in[/tex]

[tex]AC = 90 + 252 =342in[/tex]

So:

[tex]CD = \frac{BE }{ AB} * AC[/tex]

[tex]BE =62in[/tex]

When AC = 324 ; AB = 84

[tex]CD = \frac{62}{84} * 324[/tex]

[tex]CD = \frac{62* 324}{84}[/tex]

[tex]CD = \frac{20088}{84}[/tex]

[tex]CD = 239.14in[/tex]

When AC = 336 ; AB = 84

[tex]CD = \frac{62}{84} * 336[/tex]

[tex]CD = \frac{62* 336}{84}[/tex]

[tex]CD = \frac{20832}{84}[/tex]

[tex]CD = 248in[/tex]

When AC = 330 ; AB = 90

[tex]CD = \frac{62}{90} * 330[/tex]

[tex]CD = \frac{62 * 330}{90}[/tex]

[tex]CD = \frac{20460}{90}[/tex]

[tex]CD = 227.33in[/tex]

When AC = 342 ; AB = 90

[tex]CD = \frac{62}{90} * 342[/tex]

[tex]CD = \frac{62* 342}{90}[/tex]

[tex]CD = \frac{21204}{90}[/tex]

[tex]CD = 235.6in[/tex]

So, we have:

[tex]CD = 239.14in[/tex]

[tex]CD = 248in[/tex]

[tex]CD = 227.33in[/tex]

[tex]CD = 235.6in[/tex]

The least possible height of the flagpole is 227.33 inches and the greatest possible height is 248 inches

The given range of the length of the shadow and distance of the student

from the tree of between 7 and [tex]7\frac{1}{2}[/tex] feet and 21 and 22 feet gives;

The greatest possible height of the flagpole in feet ≈ 21.8 feet

The least possible height of the flagpole in feet = 19.3 feet

How can the height of the tree be calculated?

Height of the student = 62 inches = [tex]5\frac{1}{6}[/tex] feet

Distance of the flagpole to the student = 21 to 22 feet = 252 to 264 inches

Length of the student's shadow = Between 7 and [tex]\mathbf{7\frac{1}{2}}[/tex] feet = Between 84 and 90 inches

Required:

The least and greatest height of the flagpole.

Solution;

By using similar triangles formed by the student and the flagpole, we

have;

[tex]\dfrac{Height \ of \ the \ student}{Length\ of \ the \ student's \ shadow} = \mathbf{\dfrac{Height \ of \ the \ flagpole}{Length\ of \ the \ flagpole's \ shadow}}[/tex]

Which gives;

[tex]\dfrac{62}{84 \ or \ 90} =\mathbf{ \dfrac{h}{252+(84 \ or \ 90) \ or \ 264 + (84 \ or \ 90)}}[/tex]

Based on the method of cross multiplication, h will be the greatest

possible value, when we have, the largest possible value for the

denominator on the right hand side and the least possible value for the

denominator on the left hand side of the equation, and vice versa.

Which gives;

[tex]\dfrac{62}{90} = \mathbf{\dfrac{h_{min}}{252 + 84}}[/tex]

[tex]h_{min} \ in \ feet = \mathbf{\dfrac{\dfrac{62}{90} \times (252 + 84)}{12}} \approx 19.3[/tex]

The least possible height of the flagpole in feet, [tex]h_{min}[/tex] ≈ 19.3 feet

Similarly. we have;

[tex]\dfrac{62}{84} = \mathbf{\dfrac{h_{max}}{264 + 90}}[/tex]

Which gives;

[tex]h_{max} = \dfrac{62}{84} \times (264 + 90) \approx 261.3[/tex]

[tex]h_{max} \ in \ feet \approx \dfrac{261.3}{12} \approx\mathbf{ 21.8}[/tex]

The greatest possible height of the flagpole in feet, [tex]h_{max}[/tex] ≈ 21.8 feet

Learn more about the characteristics of similar triangles here:

https://brainly.com/question/10703692

question 9 working out plzzz

Answers

One central on a 1:50 000

Answer:

Here is the answer key!

https://2fv5d843v9w22sxtto1ibxtu-wpengine.netdna-ssl.com/wp-content/uploads/2015/12/Ratio-H-Speed-Distance-Time-Rates-of-Change-v2-SOLUTIONS.pdf

Step-by-step explanation:

Three-fifths of the students in a room are girls. One-third of the girls have blond hair. One-half of the boys have brown hair. What fraction of all the students are girls with blond hair?

Answers

Answer:

1/5

*I'm sorry if I got it wrong, but if not I hope this helps!*

Step-by-step explanation:

since 3/5 of the students are girls, and 1/3 of the girls have blonde hair, to find what fraction of all the girls have blond hair, we would multiply 3/5(1/3)

3/5(1/3)=3/15=1/5

therefore, 1/5 of all the students are girls with blond hair

Will someone help me

Answers

Answer:

1.one solution

2.no solution

3.ifinitly many

Step-by-step explanation:

Answer:

1, one solution

2, no solution

3, infinitely many solution

Please Help

Which of the following is a continuous random variable?

A. X= number of incoming flights at the local airport

B. T=winning time in the man's 100 meter dash at the 2016 Olympics

C. P=number of points scored by Stephen curry in a game

D.H=The number of hats sold on Tuesday

Answers

I assume it’s A because there will always be incoming flights at a local airport whereas the other options are limited and can’t be changed

Answer:

option A

Step-by-step explanation:

because it is not limited to anything while option b is limited to the men's hundred meter dash and 2016, and to the Olympics

C is limited to one game and stephen curry

D is limited to tuesday

since option a isn't confined to one day, person, or specific event there can be endless numbers assigned to the variable

PLEASE ANSWER ALL BIG REWARD
Dilations involve ________ the scale factor and the pre–image ordered pair(s)? *
adding
dividing
subtracting
multiplying
All dilations produce _______. *
similar figures
vertical figures
congruent figures
supplementary figures
The rule to describe a dilation is written in _________. *
a list
scale factor
arrow notation
slope-intercept form
Which of the rules below would create a reduction/compression? *
(x, y) (–3x, –3y)
(x, y) (3.2x, 3.2y)
(x, y) (x + 9, y + 9)
(x, y) (0.23x, 0.23y)
Which of the following rules below do NOT represent a dilation? *
(x, y) --> (2x, 4y)
(x, y) --> (–8x, –8y)
(x, y) --> (1/2x, 1/2y)
(x, y) --> (3x, 3y)
(x, y) --> (1.2x, 1.2y)
In the diagram below, triangle ABC will be dilated with the origin as the center of dilation by a scale factor of 1/2. What will be the coordinates of A'? *
Captionless Image
(0, 3/2)
(12, 6)
(3, – 3/2)
(–1, –5/2)
A line segment with endpoints D (–6, –5) and E (3, –4) is dilated by a scale factor of 2. Which statement below is true? *
The line segment has become longer with endpoints D' (-12, -10) and E' (6 -8).
The line segment has become shorter with endpoints D' (-12, -10) and E' (6 -8).
The line segment has become longer with endpoints D' (-3, -5/2) and E' (3/2, -2).
The line segment stays the same length with endpoints D' (-3, -5/2) and E' (3/2, -2).
Write a rule to describe the dilation below. *
Captionless Image
(x, y)→ (1/2x, 1/2y)
(x, y)→ (1/3x, 1/3y)
(x, y)→ (3x, 3y)
(x, y)→ (2x, 2y)
If the scale factor k = 1/9 the resulting dilation will be a/an *
enlargement
reduction
If the scale factor k = 3 the resulting dilation will be a/an *
enlargement
reduction

Answers

Answer:

multiplying similar figures scale factor (x, y) (–3x, –3y) and (x, y) (0.23x, 0.23y) (x, y) --> (2x, 4y) Need diagramA. The line segment has become longer with endpoints D' (-12, -10) and E' (6 -8).Need imageReductionEnlargement

good luck, i hope this helps :)

Please help with this

Answers

Answer:

What is your question?

______________________________

Please rate my answer and say thanks!

Plz help me with this
Find The Product of:
[tex] \sqrt[3]{2} \times \sqrt[6]{5} [/tex]

Answers

Answer:

Step-by-step explanation:

You can find the cube root of 2 and multiply it by the 6th root of 5.

cube root(2) = 2^(1/3) = 1.2599

6th root of (5) = 0.7418

Product = 1.2599 * 0.7418 = .9346

You need a key that will do fractional powers. Look around on your calculator for ^ that key y^x  or x^y.

Using one of those keys, you would put in 2 ^ 0.33333333 =

If your calculator does not have this key (I recommend you buy one that does. They are less than 10 dollars), then you can use the calculator on windows.

Find the solution set for this equation.
y2 + 2y = 0
comma.
Separate the two values with a comma.

Answers

Answer:
y= 0,-2

Hope this helps!
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