What kind of cord is this no links please

Answer: Juvenile fish go through various stages between birth and adulthood. When they have developed to the point where they are capable of feeding themselves, the fish are called fry. When, in addition, they have developed scales and working fins, the transition to a juvenile fish is complete and it is called a fingerling.

According to the Question:

[tex]\footnotesize\implies F \propto [m]^x [v]^y [r]^z[/tex]

[tex]\footnotesize\implies F =k [m]^x [v]^y [r]^z \:...(i)[/tex]

Now, substituting Dimensions of each physical quantity in equation (I):

[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M^1L^0T^0]^x [M^0L^1T^{-1}]^y [M^0L^1T^0]^z[/tex]

[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M]^x [L]^{y + z} [T]^{ - y}[/tex]

On comparing the powers of LHS and RHS:

[tex]\implies \bf x = 1[/tex]

[tex]\implies - y = - 2[/tex]

[tex] \implies \bf y = 2[/tex]

[tex]\implies y + z = 1[/tex]

[tex]\implies z = 1 - 2[/tex]

[tex]\implies \bf z = - 1[/tex]

[tex]\footnotesize\implies F = [m]^x [v]^y [r]^z[/tex]

[tex]\footnotesize\implies F = [m]^1 [v]^2 [r]^{ - 1}[/tex]

[tex]\implies\footnotesize \underline{ \boxed{ \bf \red{ F = \frac{m {v}^{2} }{r} }}}[/tex]

An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.

An escalator used to lift people up from one floor to another, exerts a work (w) of 1.2 MJ in 1 minute (t).

In physics, power (P) is the amount of energy (w) transferred or converted per unit time (t).

[tex]P = \frac{w}{t} = \frac{1.2 \times 10^{6} J }{1min} = 1.2 \times 10^{6} W[/tex]

We can convert 1.2 × 10⁶ W to kW using the conversion factor 1 kW = 1000 W.

[tex]1.2 \times 10^{6} W \times \frac{1kW}{1000W} = 1200kW[/tex]

An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.

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Answer:

potentiometer is a device used to measure potential difference across the circuit

Answer:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

Explanation:

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Answer

Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.

Explanation:

The demand of cigarette is elastic so the government's cigarette-tax revenues would rise with a tax increase.

The demand of cigarette is elastic because of the addiction the people can buy the cigarette even at high prices and the government's cigarette-tax revenues would rise.

The demand for cigarettes is unitary elastic (−1.06) means that a 1% increase in the price of cigarette would reduce its consumption by 1.06% so we can conclude that the demand of the cigarette is elastic and the government revenues increases.

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Answer:

35N

Explanation:

force=mass×gravity

the mass is 5 and the gravity is 7 therefore:

force=7×5

=35N

I hope this helps

The one you lifted in front of you ( the flat piece of paper being holded horizontally ) goes down so slow. While the one being crumpled into a ball goes down fast. Subscribe to DreamfanBG for support.

Answer:

Answer below

Explanation:

The flat piece of paper just gently glided to the ground, as if it were a feather. It didn’t go down in a straight line, it swayed from side to side. The crumpled piece of paper seemed like it had more weight to it (although I know that it didn’t), and it fell way quicker than the flat piece of paper.

_____________________________________________________

(Hope this helps can I pls have brainlist (crown)☺️)

[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]

[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]

[tex] \sf \huge \red {\dag} Given[/tex]

[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]

[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]

We know that the formula of Pressure is

[tex]\sf \longmapsto \: Force/Area[/tex]

Let's start.

[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]

[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]

[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]

Answer:

625                                      GIVE ME BRAINLIEST ANSWER PLEASE

Explanation:

This question is based on pascal's Law.

So By Pascal's Law

=

therefore  =force on input piston =200N

                 = Force on output piston = 5000N

therefore after putting the values we get,

a)  = (25x 5000)/200

    = 625

b) area of the salve piston =  = 625

so  = 625/3.14 = 199

so     r =    = 14.10 cm

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder   is mathematically given as

[tex]dl=\frac{Flo}{yA}[/tex]

[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=1.19064778*10^-^4[/tex]

Generally the equation for brass cylinder   is mathematically given as

[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=2.43*10^{-4}[/tex]

Therefore Total change in length

[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]

[tex]dl'=3.621*10^{-4}m[/tex]

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Answer:

High water level during a tide is called High tide.

Low water level during a tide is called Low tide.

Answer:

B

Explanation:

I don't know but its b

Explanation:

thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat the flow of thermal energy

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Answer:

element ammmkkkv was a very good

The tension in the horizontal portion of the rope provided the blocks are not moving and the rope has negligible mass is 40 N

The tension in the rope is a pulling force that acts on the rope when the mass of 4kg is placed on each side of the two frictionless pulley.

According to Newton's second Law;

Force = (Tension) = mass × acceleration due to gravity

∴

We can say:

Tension = 4kg × 9.81 m/s²

Tension = 39.24 N

Tension = 40 N (to the nearest whole number)

Therefore, we can conclude that the tension in the horizontal portion of the rope is 40 N

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The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N

A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.

According  to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.

The centripetal force is the external force at work here and  It's the net force that propels the object in a circular motion.

Using the formula for calculating centripetal force:

[tex]\mathbf{F_c = mass (m) \times acceleration (a)}[/tex]

[tex]\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}[/tex]

[tex]\mathbf{F_c = 27 \ N}[/tex]

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Answer:

Explanation:

lThe mass of an object given only it's force and acceleration can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question

f = 195 N

a = 2.1 m/s

We have

[tex]m = \frac{195}{2.1 } = 92.857142... \\ [/tex]

We have the final answer as

Hope this helps you

Explanation:

The speedometer of a motor car showed the following speeds in km per hour at the ends of successive intervals of 3 secs. 38.9, 52.8, 64.4. 73.6, 80.9, 86.1, 90.0, 92.5 Plot the velocity – time graph in convenient units and find from the graph, (a) The distance covered while the speed increased from 80

Answer:

7.65 x 10^22kg

sorry if im wrong!

Answer:

0n

Explanation:

Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

Pressure is related to Force, Volume and Density thus :

[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]

Using dimensional analysis :

Substituting the dimension into the relation :

[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]

[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]

Equating the power ;

a + c = 1 - - - (1)

a + 3b - 3c = - 1 - - - (2)

-2a = - 2

a = - 2/-2

a = 1

From (1)

1 + c = 1

c = 1 - 1 = 0

c = 0

From (2) :

1 + 3b - 3(0) = - 1

1 + 3b = - 1

3b = - 2

b = - 2/3

Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

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The representation of pressure is:

[tex]P=FV^{-\frac{2}{3} }[/tex]

Given that:

Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:

[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]

Hence:-

2 = -2a

a = 1

a + c = 1

1 + c = 1

c = 0

a + 3b - 3c = -1

1 + 3b - 3(0) = -1

3b = -2b = -2/3

Hence the representation of pressure is:

[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]

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9) a) formula = h(ρ)g by default g=9.8m/s²

Pressure = 2×1000×9.8 = 19600Pa

b)

Answer:

Additionally, the initial horizontal velocity may be calculated by measuring the diameter d of the ball and dividing the result by the amount of time t required for the ball to pass across the photogate. Vo = d/t is the formula.

Initial vertical velocity is the vertical component of the initial velocity: v 0 y = sin 0 sin 0 = (30.0 m/s) sin 45° = 21.2 m/s

Explanation:

Hope it helps:)

we can observe its gravitational influence on visible matter.

Dark matter is a term used in astrophysics to refer to matter that corresponds to approximately 80% of the matter in the universe.

Dark matter is related to the motion of galaxies because visible matter makes up only a small part of the cluster and the galaxies show signs of being composed mainly of a halo of dark matter concentrated in their center.

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The density of the object is 5911.94 kg/m³

An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.

The buoyancy = weight of the object - weight in water

= 15 N - 13N

= 2 N

The buoyancy force can also be determined by using the expressed:

[tex]\mathbf{F_B = Volume (V) \times density ( \rho) \times g}[/tex]

[tex]\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }[/tex]

[tex]\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}[/tex]

volume (v) = 2.589 × 10⁻⁴m³

Recall that:

The mass of an object can be estimated by using the formula:

Weight = mass × gravity

mass = Weight / gravity

mass = 15/9.8

mass = 1.5306 kg

The density of the object can now be calculated using the relation

Density = mass/volume

Density = 1.5306 kg / 2.589 × 10⁻⁴m³

Density = 5911.94 kg/m³

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