What is x3+y3+z3? I need help please.

Answer:

a. (11) (24x) (2526xx)

11×24x=264x

264x ×2526x²

= 666864 =6.7×10⁵x²

Step-by-step explanation:

b. the product of a and b is not equal because the the numbers are the same except for 42 in question b. which makes them not to be equal

Explanation:

The perimeter is 48 mm. We divide that by 4 to find the side length of the square, since each side is the same length.

48/4 = 12

Each side is 12 mm long.

This means the area of this square is 12^2 = 12*12 = 144 square mm

Answer:

The simplified version of this equation is -3x - 12.

Step-by-step explanation:

To simplify this equation, distribute -3 to both x and 4.

-3(x+4) = -3x -12

Answer:

-3x-12 as an expression

Step-by-step explanation:

To solve this problem, we need to distribute!

Multiply -3 by both the x and the 4

When we do this, we get:

-3x and -12

Note: when you multiply a positive by a negative, you get a negative so it turns into a negative number

Note 2: When you see an x without a number in front of it, it becomes 1x. In this problem, that is why it is a -3x because -3 x 1 is -3

Hope this helps! :) Please award brainliest if possible!

Answer:

I'm gonna head with B forgive me I'd I'm wrong

Answer:

h (-5) = 41/4 or 10.25

h (-2) = -3

h (3) = 25/4 or 6.25

Step-by-step explanation:

h (-5) = 1/4(-5)^2 + 4

h (-5) = 1/4(25) + 4

h (-5) = 41/4 or 10.25

h (-2) = -3 (this is given to you in the function)

h (3) = 1/4 (3)^2 + 4

h (3) = 1/4(9) + 4

h (3) = 25/4 or 6.25

Answer: I think the answer b

Step-by-step explanation:

The cost function for Julia's clothing store per month is 14.60n +970

A function is defined as a relation between a set of inputs having one output each.

Given that, Julia is opening a clothing store. She plans to start by selling sweatshirts. It costs her $10.50 for each sweatshirt, $4 per box for the shirts, and $0.10 a bag. Julia also spends $900 on rent, $40 on electricity, and $30 on advertising each month.

There are two types of cost Julia have,

The variable cost that is not fixed and depend on how many shirts she's making, = $10.50+$4 +$0.10 = $14.60

Let she makes n shirts, so cost = $14.60n

And the second one is fixed cost that is cost she is spending on rent, electricity and advertising, = $900+$40+$30 = $970

Therefore, cost = 14.60n +970

Hence, the cost function for Julia's clothing store per month is 14.60n +970

For more references on functions, click;

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Answer:

A, the first option, 49 square cm

Step-by-step explanation:

[] To know

-> A squares sides are all the same size

-> The area of a square can be found by finding L * W

[] Solving

-> We can use the points given to solve for one side, EF, of the square

-> Both the x coordinates are the same, so we can subtract the y values as they are on the same line.

6 - -1 = 6 + 1 = 7

-> Now for the area

7 * 7 = 49 square cm

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

Answer:

area = 6.5 square units

Step-by-step explanation:

Use the area of a triangle in coordinate geometry formula:

[tex]\triangle GHI =\frac{1}{2} |x_1(y_2- y_3) + x_2(y_3 -y_1) + x_3(y_1 -y_2)|[/tex]

where [tex](x_1,y_1)=(-8,-8) \ \ \ \ (x_2,y_2)=(-6,-7) \ \ \ \ (x_3,y_3)=(-9,-2)[/tex]

      [tex]\triangle GHI =\frac{1}{2} |x_1(y_2- y_3) + x_2(y_3 -y_1) + x_3(y_1 -y_2)|[/tex]

[tex]\implies \triangle GHI =\frac{1}{2} |-8(-7+2) -6(-2 +8) -9(-8 +7)|[/tex]

[tex]\implies \triangle GHI =\frac{1}{2} |40 -36 +9|[/tex]

[tex]\implies \triangle GHI =6.5[/tex]

Answer:

Here's a answer to your question.

Answer:

6 grapples

Step-by-step explanation:

x = number of wins

y = number of ties

y = 15 - x

48 = 5x + 2y

48 = 5x + 2(15 - x)

48 = 5x + 30 - 2x

48 = 3x + 30

18 = 3x

x = 6

The number of grapples that Jeremy win will be 6.

The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.

A relationship between two or more parameters that, when shown on a graph, produces a linear model. The degree of the variable will be one.

Sensei's Judo Club has a competition for the students.

Let x be the number of wins and y be the number of ties.

If you win a grappling match, you are awarded 5 points.

Then the equation will be

x + y = 15

y = 15 - x

If you tie, you are awarded 2 points.

Jeremy grappled 15 times and his score was 48 points.

Then the equation will be

5x + 2y = 48

Put the value of y in the above equation. Then we have

5x + 2(15 - x) = 48

5x + 30 - 2x = 48

3x = 18

x = 6

The number of grapples that Jeremy win will be 6.

More about the solution of the equation link is given below.

https://brainly.com/question/545403

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[tex]volume \: = \frac{1}{3} \times base \: area \: \times \: height \\ [/tex]

Thus :

[tex]80 = \frac{1}{3} \times 24 \times h \\ [/tex]

[tex]h = \frac{80 \times 3}{24} \\ [/tex]

[tex]h = \frac{240}{24} \\ [/tex]

[tex]h = \frac{24 \times 10}{24} \\ [/tex]

[tex]h = 10 \: cm[/tex]

Thus the last option is the correct answer.

Answer:

x = 11

Step-by-step explanation:

Since the 2 triangles are exact replicas of each other, we see the angle for this is 54 from the first triangle, and that 4x+10 is the angle as well.

So we set up the equation:

[tex]4x+10=54\\4x=44\\x=11[/tex]

[tex]\bold{Heya}[/tex] ~

✰ [tex]\sf{Solve~for~x}[/tex] ✰

[tex]\sf{19x~=~361}[/tex]

[tex]\huge \boxed {\underline{Explanation}}[/tex]

—————————————

[tex]\sf{19x~=~361}[/tex]

[tex]\sf{Divide~both~sides~by~19}[/tex]

[tex]\sf{\frac{19x}{19}~=~\frac{361}{19}[/tex].

[tex]\sf{Simplify}[/tex]

[tex]\sf{x~=~19}[/tex]

Hope It Helps ! ~

#LearnWithBrainly

[tex]\underline{Answer~:}[/tex]

Jace •᎑•

Answer:

2.2      Solve  :    3x-20 = 0

Add  20  to both sides of the equation :

                     3x = 20

Divide both sides of the equation by 3:

                    x = 20/3 = 6.667

x = 20/3 = 6.667

Answer:

C) 471

Step-by-step explanation:

Surface area for a cylinder formula:

SA = 2πrh + 2πr²

Given:

r = 5

h = 10

Work:

SA = 2πrh + 2πr²

SA = 2(3.14)(5)(10) + 2(3.14)(5²)

SA = 314 + 2(3.14)(25)

SA = 314 + 157

SA = 471

Answer:

a conjecture is a conclusion made on incomplete information

Step-by-step explanation:

so in saying that, it can be true or false because conjecture can be used with true information thats not fully been proved yet/ verified

hope I helped

Answer:

no

Step-by-step explanation:

because 8 isnt a perfect square

Answer:

rate 72 mph; current 16 mph

Step-by-step explanation:

to find the rate of the boat and the current we can model the equation like this

let r = rate

let c = current

8(r - c) = 464

6(r + c) = 540

8r - 8c = 464

6r + 6c = 540

r - c = 58

r + c = 90

then you could use elimination to find r

2r = 148

r = 74

the rate is 74 mph

then plug it in

the current is 16 mph

Answer: 240mph

Step-by-step explanation:

Answer:

23° and 157°

Step-by-step explanation:

Let n represent the smaller angle then the larger angle would be...

n+134

Supplementary angles add up to 180 degrees. We can use this information to set up an equation...

n+n+134=180

Combine like terms

2n+134=180

Subtract 134 from both sides

2n=46

Divide both sides by 2

n=23

n+134=157

23° and 157°

Answer:

The coral reef grows 266 cm in 14 weeks.

Step-by-step explanation:

Lets convert 0.19 meters to centimeters.

1m= 100cm

0.19m×100= 19 cm

It grows 19 cm every week, so:

[tex]\frac{1w}{19 cm} *14 =\frac{14w}{x= 266 cm}[/tex]

So, the coral reef grows 266 cm in 14 weeks.

Hope this helps!

Answer:

the volume should be 2/15

[tex]\Large{\underline{\underline{{\mathfrak{{\bigstar}\:Answer}}}}}\\\\[/tex]

[tex]\bf{1.\:\:x^{2}+4x+1=0}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{-4{\underline{+}}\sqrt{4^{2}-4\times1\times1}}{2\times1}}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{-4{\underline{+}}\sqrt{16-4}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{-4{\underline{+}}\sqrt{12}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{4{\underline{+}}2\sqrt{3}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-2-\sqrt{3}\:,\:x_{2}= -2+\sqrt{3}}\\\\\\[/tex]

[tex]\bf{2.\:\:x^{2}-9x+14=0}[/tex]

[tex]\longrightarrow\:\:\sf{x^{2}-2x-7x+14=0}[/tex]

[tex]\longrightarrow\:\:\sf{x\times (x-2)-7(x-2)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=2\:,\:x_{2}=7}\\\\\\[/tex]

[tex]\bf{3.\:\:x^{2}+8x+2=22}[/tex]

[tex]\longrightarrow\:\:\sf{x^{2}+8x+2-22=0}[/tex]

[tex]\longrightarrow\:\:\sf{x(x+10)-2(x+10)=0}[/tex]

[tex]\longrightarrow\:\:\sf{(x+10)(x-2)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-10\:,\:x_{2}=2}\\\\\\[/tex]

[tex]\bf{4.\:\:x^{2}+8x+7=0}[/tex]

[tex]\longrightarrow\:\:\sf{x^{2}+7x+x+7=0}[/tex]

[tex]\longrightarrow\:\:\sf{x(x+7)+x+7=0}[/tex]

[tex]\longrightarrow\:\:\sf{(x+7)(x+1)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-7\:,\:x_{2}=1}\\\\\\[/tex]

[tex]\bf{5.\:\:x^{2}-10x+25=9}[/tex]

[tex]\longrightarrow\:\:\sf{(x-5)^{2}=9}[/tex]

[tex]\longrightarrow\:\:\sf{x-5={\underline{+}}3}[/tex]

[tex]\longrightarrow\:\:\sf{x-5=-3 \: ; \:x-5=3}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=2\:,\:x_{2}=8}\\\\\\[/tex]

[tex]\bf{6.\:\:x^{2}-10x+16=0}[/tex]

[tex]\longrightarrow\:\:\sf{x^{2}-2x-8x+16=0}[/tex]

[tex]\longrightarrow\:\:\sf{(x-2)(x-8)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x-2=0\:;\:x-8=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=2\:,\:x_{2}=8}\\\\\\[/tex]

[tex]\bf{7.\:\:2x^{2}+7x-4=0}[/tex]

[tex]\longrightarrow\:\:\sf{2x(x+4)-(x-4)=0}[/tex]

[tex]\longrightarrow\:\:\sf{(x+4)((2x-1)=0}[/tex]

[tex]\longrightarrow\:\:\sf{x+4=0\:;\:2x-1=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-4\:,\:x_{2}=\dfrac{1}{2}}\\\\\\[/tex]

[tex]\bf{8.\:\:x^{2}-2x+3=0}[/tex]

[tex]\longrightarrow\:\:\sf{x=\dfrac{-(-2){\underline{+}}\sqrt{(-2)^{2}-4\times 1\times 3}}{2\times1}}[/tex]

[tex]\longrightarrow\:\:\sf{\dfrac{2{\underline{+}}\sqrt{4-12}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{\dfrac{2{\underline{+}}\sqrt{-8}}{2}}[/tex]

[tex]\longrightarrow\:\:\sf{x \notin {\mathbb{R}}}\\\\\\[/tex]

[tex]\bf{9.\:\:3x^{2}+8x+5=0}[/tex]

[tex]\longrightarrow\:\:\sf{x(3x+5)+3x+5=0}[/tex]

[tex]\longrightarrow\:\:\sf{(3x+5)(x+1)=0}[/tex]

[tex]\longrightarrow\:\:\sf{3x+5=0\:;\:x+1=0}[/tex]

[tex]\longrightarrow\:\:\sf{x_{1}=-\dfrac{5}{3}\:,\:x_{2}=-1}\\\\\\[/tex]

[tex]\bf{10.\:\:{\mathbb{\red{1}}}\:\:}[/tex]:')

The solutions are listed below:

(i) [tex]x = -2\pm \sqrt{3}[/tex], (ii) [tex]x = \frac{9}{2}\pm \frac{5}{2}[/tex], (iii) [tex]x = -4 \pm 6[/tex], (iv) [tex]x = -4\pm 3[/tex], (v) [tex]x = -5\pm 3[/tex], (vi) [tex]x = 5 \pm 3[/tex], (vii) [tex]x = -\frac{7}{4}\pm \frac{9}{4}[/tex], (viii) [tex]x = 1 \pm i\sqrt{2}[/tex], (ix) [tex]x = -\frac{4}{3}\pm \frac{1}{3}[/tex], (x) 1. I do not celebrate Valentine's day at all.

Completing the square consists in applying algebraic operations to transform part of the second order polynomial into a perfect square trinomial and simplify the resulting expression. Now we proceed to present the corresponding solutions:

(i) [tex]x^{2}+4\cdot x + 1 = 0[/tex]

[tex]x^{2}+4\cdot x +4 = 3[/tex]

[tex](x+2)^{2} = 3[/tex]

[tex]x+2 = \pm \sqrt{3}[/tex]

[tex]x = -2\pm \sqrt{3}[/tex]

(ii) [tex]x^{2}-9\cdot x + 14 = 0[/tex]

[tex]x^{2}-9\cdot x + 14+\frac{25}{4} = \frac{25}{4}[/tex]

[tex]x^{2}-9\cdot x +\frac{81}{4} = \frac{25}{4}[/tex]

[tex]\left(x-\frac{9}{2} \right)^{2} = \frac{25}{4}[/tex]

[tex]x -\frac{9}{2} = \pm \frac{5}{2}[/tex]

[tex]x = \frac{9}{2}\pm \frac{5}{2}[/tex]

(iii) [tex]x^{2}+8\cdot x + 2 = 22[/tex]

[tex]x^{2}+8\cdot x +16 = 36[/tex]

[tex](x+4)^{2} = 36[/tex]

[tex]x+4 = \pm 6[/tex]

[tex]x = -4 \pm 6[/tex]

(iv) [tex]x^{2}+8\cdot x + 7 = 0[/tex]

[tex]x^{2}+8\cdot x + 16 = 9[/tex]

[tex](x+4)^{2} = 9[/tex]

[tex]x+4 = \pm 3[/tex]

[tex]x = -4\pm 3[/tex]

(v) [tex]x^{2}+10\cdot x + 25 = 9[/tex]

[tex](x+5)^{2} = 9[/tex]

[tex]x+5 = \pm 3[/tex]

[tex]x = -5\pm 3[/tex]

(vi) [tex]x^{2}-10\cdot x + 16 = 0[/tex]

[tex]x^{2}-10\cdot x + 25 = 9[/tex]

[tex](x-5)^{2} = 9[/tex]

[tex]x-5 = \pm 3[/tex]

[tex]x = 5 \pm 3[/tex]

(vii) [tex]2\cdot x^{2} + 7\cdot x - 4 = 0[/tex]

[tex]x^{2}+\frac{7}{2}\cdot x -2 = 0[/tex]

[tex]x^{2} + \frac{7}{2}\cdot x -2 +\frac{81}{16} = \frac{81}{16}[/tex]

[tex]x^{2}+\frac{7}{2}\cdot x +\frac{49}{16} = \frac{81}{16}[/tex]

[tex]\left(x+\frac{7}{4} \right)^{2} = \frac{81}{16}[/tex]

[tex]x + \frac{7}{4} = \pm \frac{9}{4}[/tex]

[tex]x = -\frac{7}{4}\pm \frac{9}{4}[/tex]

(viii) [tex]x^{2}-2\cdot x + 3 = 0[/tex]

[tex]x^{2}-2\cdot x + 1 + 2 = 0[/tex]

[tex](x-1)^{2} = -2[/tex]

[tex]x-1 = \pm \sqrt{-2}[/tex]

[tex]x = 1 \pm i\sqrt{2}[/tex]

(ix) [tex]3\cdot x^{2} + 8\cdot x + 5 = 0[/tex]

[tex]x^{2}+\frac{8}{3}\cdot x +\frac{5}{3} = 0[/tex]

[tex]x^{2}+\frac{8}{3}\cdot x +\frac{5}{3}+\frac{1}{9} = \frac{1}{9}[/tex]

[tex]x^{2}+\frac{8}{3}\cdot x + \frac{16}{9} = \frac{1}{9}[/tex]

[tex]\left(x+\frac{4}{3} \right)^{2} = \frac{1}{9}[/tex]

[tex]x + \frac{4}{3} = \pm \frac{1}{3}[/tex]

[tex]x = -\frac{4}{3}\pm \frac{1}{3}[/tex]

(x) 1. I do not celebrate Valentine's day at all.

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Answer:

im pretty sure its -3/2

Step-by-step explanation:

since you have to do rise over run and your falling 3 so its a negative 3 and you always run right so its run 2 so then its -3/2 if its not that sorry

Answer:

1212=1212=

33weeks=33we2ks33weeks=33we2ks

weeks=we2ksweeks=we2ks

1616=we2ks1616=we2ks

Step-by-step explanation:

simplificar 16161616.

1212=1212=

33weeks=33we2ks33weeks=33we2ks

weeks=we2ksweeks=we2ks

1616=we2ks1616=we2ks

Answer:

all sides have different lengths

and the third angle measures 90⁰

And

Now

bigger angle has bigger side.

So the order is