Statement A. The sun is located at one focus is true about the foci of a planet in an elliptical orbit (option A).
What is an elliptical orbit?An elliptical orbit can be defined as any movement of a celestial body in which the attained object (for example a planet around its star) moves in an eccentric manner or oval-shaped way, which is a feature of the planets in the solar systems including the Earth planet.
The movement of a planet in an elliptical orbit is called an ellipse, while two points that are selected chosen at the start site are known as foci in such orbits.
Therefore, with this data, we can see that an elliptical orbit is an excentric movement of a celestial body such as the earth's planet around the sun, and foci are called to fixed points located inside this orbit.
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Two springs are attached side by side to a box of mass that is resting on a frictionless horizontal surface as shown in the figure. The springs have force constants of 1 and 2. Determine an expression that describes the period of the motion of the box attached to this combination of springs. Assume that the box does not rotate, so the amount of stretch or compression for each spring is the same.
Answer: 4+5z (x) + 9
Explanation:
So I got this by... I don't really know, but this might be the right answer..
Box A of mass m sits on the floor of an elevator with box B of mass 2 m on top of it, as shown the figure above. The elevator is moving upward and slowing down. F_A is the magnitude of the force exerted on box A by box B, F_B is the magnitude of the force exerted on box B by box A, and F_g is the magnitude of the gravitational force exerted on box {B}. Which of the following ranks the forces in order of increasing magnitude?
Box A of mass m sits on the floor of an elevator with box B of mass 2 m on top of it, in this case option b) would be correct in order of increasing magnitude.
What is magnitude?
Magnitude is a term used in physics to describe an object's maximal size and direction. Scalar and vector quantities both use magnitude as a common factor. We are aware that scalar quantities are those that have just magnitude by definition. Those quantities with both magnitude and direction are considered vector quantities.
There are different ways in which magnitude can be used. Some of them are:
Magnitude of earthquakeMagnitude of charge on an electronMagnitude of forceMagnitude of displacementMagnitude of gravitational forceAn earthquake's size is measured in terms of its length, breadth, and width. It is calculated based on the earthquake's actual size. A single magnitude is thought to exist for an earthquake. Due to variables including the type of surface material and distance from the epicentre, the magnitude of the shaking brought on by the earthquake varies depending on where it occurs.
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A light ray strikes the surface of crown glass (n = 1.520), at a 25° angle with respect to the normal from air(n = 1.000293), and leaves the glass, returning to the air. Determine the angle at which the light refracts when it leaves the glass.
16.14° is the angle of refraction of the light when it leaves the glass.
What is angle of refraction?Snell's law states that the angle of refraction, θr, is proportional to the angle of incidence, θi and the ratio of the refractive indices of the two media that comprise the interface. The angle θr=θi and no refraction occur when the mediums have equal refractive indices.
Given that,
The glass has an index of refraction (n₁) = 1.52
Air has an index of refraction (n₂) = 1.000293.
According to Snell's law:
n₂/n₁ = sin θ₁ / sin θ₂
or, 1.000293 / 1.52 = sin θ₁ / sin (25°)
or, 0.6581 = sin θ₁ / 0.42262
or, 0.2781 = sin θ₁
or, θ₁ = sin⁻¹ (0.2781)
or, θ₁ = 16.15°
So, 16.15° is the angle of refraction of the light when it leaves the glass.
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A 4.5-kg, three legged stool supports a 65-kg person. If each leg of the stool has a cross-sectional diameter of 2.6 cm and the weight of the person is evenly distributed, determine the pressure exerted on the floor by each leg.
The pressure exerted on the floor by each leg is 427832.0079 Pa.
F = mg
F = (4.5 + 65) × 9.8
F= 681.1 N
This force is evenly distributed on the three leg
radius, r = d/2
= 2.6 / 2
= 1.3 cm = 0.013 m
Total cross sectional area of the three legs, A = 3×π×[tex]r^{2}[/tex]
A = 3 × 3.14 × [tex]0.013^{2}[/tex]
A = 0.00159 [tex]m^{2}[/tex]
Pressure due to weight,
P = Weight/A
P = 681.1/ 0.00159
P = 427832.0079 Pa
Hence, the pressure exerted on the floor by each leg is 427832.0079 Pa.
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Please help me with this
You want to use a pendulum clock on the moon gm = 1.625 m
s2 .
a) What length should the pendulum have in order for it to have a period of T = 1.00s? [6pt.]
b) Now you need a clock for your trip into interstellar space. A pendulum clock won’t work, even while
moving with a constant velocity. Why? [3pt.]
c) You then decide to create a clock from a spring and an object with a mass m = 655g. What is the amplitude of the spring if it has a maximum velocity of vmax = 0.5ms , and a period of T = 1.00s?
[8pt.]
(a) T = 4.12 cm.
(b) T ∝ [tex]\sqrt{m}[/tex], time period doesn't depends on velocity. Thus, a pendulum clock wouldn't work.
(c) A = 0.0795 m
What is pendulum clock?Pendulum clocks were the main timekeeping devices used in 18th and 19th-century houses, industries, offices, and train stations for scheduling daily activities, shifts at work, and public transit. Their increased precision enabled the quicker pace of living required for the Industrial Revolution.
(a)
[tex]g_m[/tex] = 1.625 m/sec²
T = 1 sec
T = 2Π × [tex]\sqrt{l/g}[/tex]
or, T = 2Π × [tex]\sqrt{l/1.625}[/tex]
or, T = 1.625 × [4 × (3.19)²]
or, T = 0.0412 m
or, T = 4.12 cm.
(b)
T ∝ [tex]\sqrt{l}[/tex] and T = 2Π × [tex]\sqrt{m/k}[/tex]
or, T ∝ [tex]\sqrt{1/g}[/tex] then, T ∝ [tex]\sqrt{m}[/tex]
So, time period doesn't depends on velocity. Thus, a pendulum clock wouldn't work.
(c)
m = 655 gm = 0.655 kg
V(max) = 0.5 m/sec
T = 1 sec
A = ?
V(max) = A × ω
or, V(max) = A × (2Π/T)
or, 0.5 = A × (2Π/ 1)
or, A = 0.0795 m
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A gas at a pressure of 2.00 atm undergoes a quasistatic isobaric expansion from 3.00 to 5.00 L. How much work is done by the gas?
The work done by the gas is 405.2 J.
What is the work done by the gas?The work done by the gas at the constant pressure is calculated by applying the following equation.
W = PΔV
W = P ( V₂ - V₁)
Where;
V₂ is the final volume of the gasV₁ is the initial volume of the gasP is the pressure of the gasThe given parameters include the following;
final volume of the gas = 5 L
initial volume of the gas = 3 L
constant pressure of the gas = 2 atm
The work done by the gas is calculated as follows;
W = 2 atm ( 5 L - 3 L )
W = 4 atm.L
1 atm.L = 101.3 J
4 atm.L = ?
= 405.2 J
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In what direction and at what point does the buoyant force on a body due to liquid act?
At the center of buoyancy, the buoyant force operates in an upward, vertical direction.
What kind of force is buoyant, for instance?Here are a few real-world instances of the buoyant force. Iceberg drifting on the sea, a boat traveling down a river An individual wearing a life jacket floating in the water, a ship sailing the seas, a helium balloon soaring into the sky, etc. The density has a direct relationship with the buoyant force.
What generates the force of buoyancy?The fluid's pressure on the object is what creates the buoyant force. The net upward force results from the fact that the pressure on the bottom of an item is always greater than the force on the top since pressure rises as depth increases. Whether an object sinks or floats, the buoyant force always exists.
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A disk between vertebrae in the spine is subjected to a shearing force of 530 N. Find its shear deformation in meters, taking it to have the shear modulus of 1 109 N/m2. The disk is equivalent to a solid cylinder 0.700 cm high and 3.80 cm in diameter.
The disk is equivalent to a solid cylinder 0.700 cm high and 3.80 cm in diameter. The shear deformation is .∆x=3.34×10⁻⁶ m.
What is deformation?Deformation refers to the change in size or shape of and object whereas displacements are the absolute change in to the position of a point on the the object. Deflections is the relative changes in external displacements in an object.
The shear deformation is .
Given that,
Shearing force F = 600 nm
Shear modulus S=1×10⁹ n/m²
length = 0.700 cm
diameter = 4.00 cm
We need to find the shear deformation
Using formula of shear modulus
S=Flo/A ∆x
∆x=Flo/(rd²/4)S
∆x=4Flo/(rd²/)S
Put the value into the formula
∆x=4×600×0.700×10²/3.14×1×10⁹×(4.00×10²)
∆x=3.34×10⁻⁶ m
Hence, The shear deformation is .∆x=3.34×10⁻⁶m
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hydrogen molecules, with a molar mass of 2.016 g/mol, in a certain gas have an rms speed of 390 m/s. a)What is the temperature of this gas, in kelvins?
The temperature of hydrogen molecules with a molar mass of 2.016 g/mol in a certain gas have an rms speed of 390 m/s in kelvins is 3.01K.
The RMS speed of gas molecules is the measure of the speed of the particles in a gas. It is the average squared velocity of molecules in a gas.
The formula for rms speed as follows
Vrms = √3*K*T / m
where
K = Boltzmann constant
T = temperature
m = mass of the gas molecules
to find T, the formula can be rearranged like this
T = m*v²rms / 3k
Now, let's find the mass of hydrogen molecules
m = molecular weight / avogadro's number
molecular weight = 2.016 g/mol
avogadro's number = 6.022 * 10^23
m = (2.016 g/mol / 6.022 * 10^23) * 10^-3 kg / mol
= 3.347 * 10^-27 kg
Next, we want to find the temperature of this gas.
T = m* v²rms / 3k
m = 3.347 * 10^-27 kg
k = 1.38 * 10^-23 J/K
Vrms = 390 m/s
T = (3.347 * 10^-27 kg) * (390 m/s)² / 3 * (1.38 * 10^-23 J/K)
= 12.3K (rounded)
Therefore, the temperature of this gas is 12.3Kelvins.
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Electrical stimulation of the brain (ESB) is used on humans during brain surgery to map out ___________.
d. the brain and critical structures
Electrical stimulation of the brain (ESB) is used on humans during the brain surgery used to map out the brain and critical structures.
Surgical operation is a medical distinctiveness that makes use of operative manual and instrumental techniques on a person to research or deal with a pathological circumstance together with a disorder or damage, to help improve physical characteristics, and appearance, or to repair undesirable ruptured areas.
A patient may additionally have surgical treatment to in addition discover the situation for the motive of prognosis. cast off or repair diseased tissues or organs.
Sushruta is the father of surgical operations. If the history of science is traced back to its origin, it likely starts from an unmarked technology of ancient instances.
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a van of mass 2000 kg is travelling at 10 m/s calculate its kinetic energy. If its speed increases to 20m/s by how much does its kinetic energy increases
The increase in the kinetic energy was found to be 300000 J
define kinetic energy ?
The energy an item has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort while slowing down from its current pace to a condition of rest. Formally, a kinetic energy is any term that contains a derivative with respect to time in the Lagrangian of a system.
kinetic energy was mentioned as ⇒1/2(m)v^2
kinetic energy =1/2(m)v^2
=1/2x2000x(10)^2
=100000 J
=1/2(m)v^2
=1/2x2000x(20)^2
=400000 J
therefore the increase in the kinetic energy was 400000-100000=300000 J
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Eli wanders around the park. First he walks north 4 meters to the swings. Then he walks south
2.5 meters to the bench to take a break. If he spends 600 seconds doing these things...
What is the distance traveled?
Answer: total distance traveled = 6.5 m
Explanation:
Important to note the difference between displacement and distance. Distance is the total length of the path taken: 4 + 2.5 = 6.5 m
Displacement is the distance from the point of origin to the ending point:
4 - 2.5 = 1.5 m
The question asked for the DISTANCE, so the answer is 6.5 m
There are three general types of spectra: continuous, emission, and absorption. Each is characterized by a different distribution of the wavelengths (i.e., colors) of radiation. Sort the images of the three types of spectra into the appropriate bins.
Each type of spectrum is unique in the way the wavelengths (colors) of light are distributed. The continuous spectrum shows a continuum of all the colors, whereas the emission spectra show only specific lines of emitted color. The absorption spectra show only small black ranges where specific colors have been absorbed away.
There are three general types of spectra: continuous, emission, and absorption. The image drag are:
Continuous
Image 1 (full spectrum)
Emission
Image 2 (mostly dark)
Image 5 (mostly dark)
Absorption
Image 3 (full with lines)
Image 4 (full with lines)
What is the spectrum above about?The distribution of light's wavelengths (or colors) differs for each type of spectrum. While the emission spectra only display individual lines of emitted color, the continuous spectrum displays a continuum of all hues. Only tiny black ranges where particular colors have been taken away are seen in the absorption spectrum.
From the image attached:
A hot, high-density light source generates a continuous spectrum.A hot, low-density light source generates an emission spectrum.A hot, high-density light source passing through a cold, low-density medium results in an absorption spectrum.Learn more about continuous spectrum from
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short-wave (visible and ultraviolet) radiation that reflects off the earth's surface is absorbed by the lower atmosphere and heats it up, a process otherwise known as the greenhouse effect.
The statement "short-wave (visible and ultraviolet) radiation that reflects off the Earth's surface is absorbed by the lower atmosphere and heats it up, a process otherwise known as the greenhouse effect" is true.
How does the greenhouse effect work?Solаr energy аbsorbed аt Eаrth’s surfаce is rаdiаted bаck into the аtmosphere аs heаt. Аs the heаt mаkes its wаy through the аtmosphere аnd bаck out to spаce, greenhouse gаses аbsorb much of it. Greenhouse gаses аre more complex thаn other gаs molecules in the аtmosphere, with а structure thаt cаn аbsorb heаt. They rаdiаte the heаt bаck to the Eаrth's surfаce, to аnother greenhouse gаs molecule, or out to spаce.
Eаrth is constаntly bombаrded with enormous аmounts of rаdiаtion, primаrily from the sun. This solаr rаdiаtion strikes the Eаrth's аtmosphere in the form of visible light, plus ultrаviolet (UV), infrаred (IR) аnd other types of rаdiаtion thаt аre invisible to the humаn eye. UV rаdiаtion hаs а shorter wаvelength аnd а higher energy level thаn visible light, while IR rаdiаtion hаs а longer wаvelength аnd а weаker energy level.
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a young girl from the kayan people wears a neck ring made of brass. it looks as if there are 21 individual rings but the ring is actually one continuous length of brass fashioned (bent) into a coil. the height of the brass coil is 12 cm and its average circumferences is 40 cm. neck rings are usually only removed to be replaced with a bigger one as the girls grows. however, we can estimate the mass of this neck ring without removing it.
b. the coil has a height of 12 cm and the coil has 21 turns. calculate the radius of the brass in cm.
The radius of the brass is determined as 0.091 cm.
What is the radius of the brass?
The radius of the brass is calculated by applying the equation for the circumference of a circle.
Mathematically, the equation for the circumference of a circle is given as;
C = 2πr
where;
r is the radius of the circleC is the circumference of the circleFor the given number of turns of the coil and the height of the coil, the radius of the brass is calculated as follows;
( 2πr ) N = h
where;
N is the number of turns of the brass coil = 21 turnsh is the height of the brass coil, = 12 cm( 2πr ) N = h
( 2πr ) ( 21 ) = 12
42πr = 12
r = 12 / 42π
r = 0.091 cm
Thus, the radius of the brass is a function of height of the brass and the number of turns of the brass.
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The road runner was being chased and outsmart the coyote. He ran past the road runner an fell straight down off a cliff. He fell with the same acceleration as gravity (9.8). Calculate his displacement if he fell for 4 seconds
The displacement of the runner after four seconds is 78.4 m.
What is the displacement after 4 seconds?We know that in this case, we are dealing with a case of an object that has a motion under gravity. We are told that the road runner an fell straight down off a cliff. The fact that we have been told that the runner just fell down the cliff means that the initial velocity of the runner would have to be taken in this context as zero since the runner was dropped from a height as shown.
Acceleration of the runner (g) = 9.8 m/s^2
Initial velocity of the runner (u) = 0 m/s
Time take (t) = 4 seconds
We then have;
h = ut + 1/2gt^2
If we then know that the initial velocity of the person is zero, then we have;
h = 1/2gt^2
h = 0.5 * 9.8 * (4)^2
h = 78.4 m
The height is 78.4 m.
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The black hole in the galaxy M87 has a mass of about 3 billion solar masses. Let us assume that most of that mass flowed into the black hole through an acretion disk that radiated 10% of the mass-energy passing through it. (a) In that case, what would be the total amount of energy radiated by the accretion disk during the history of the black hole? (b) What would be the average luminosity (in solar luminosities) of the accretion disk, if it that energy over a period of 10 billion years? (c) How does that average huminosity compare with the luminosity of the Milky Way?
Despite being only 38 billion kilometers (24 billion miles) big, that black hole contains a mass equivalent to six and a half billion Suns. It was the first black hole that had been directly pictured.
Which black hole is in M87?We need to know the black hole's mass, brightness, and energy-radiation timescale in order to calculate the total energy emitted by the accretion disk during the course of its existence. Using Einstein's equation for general relativity, we can determine the black hole's mass.
Then, using the Stefan-Boltzmann formula, we may utilize that knowledge to determine the luminosity of the accretion disk. Finally, we may utilize that knowledge to determine how long it will emit energy given its luminosity. The entire energy emitted by the accretion disk throughout the black hole's existence comes from the mass-energy that passes through it. The accretion disk's brightness is W/m2, on average.
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A circular rod of cross-sectional area 100 mm2 has a tensile force of 100 kN applied to it. The stress in the rod is:
According to the question the tensile stress of circular rod is 3142.85M Pa
What is an instance of tensile strength?The minimum tensile stress (force per unit area) required to break the material is how it is represented. The material has a tensile strength of 1,000 pounds of force, for instance, if a metal rod with a cross - sections of one square inch can bear a pulling force of 1,000 pounds but snaps with further pressure.
Briefing:
Tensile stress = Tensile load /Cross section area
Given load = 100kn = 100*10^3 = 10^5N
Area = 100πmm^2
Tensile Stress = 3142.85M Pa
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Peter and Nancy leave their office in Sacramento at the same time. Peter drives north on I-5 at a speed of 72 miles per hour. Nancy drives south on I-5 at a speed of 76 miles per hour. How long will it take them to be 330 miles apart?
2.2 hours long will it take them to be 330 miles apart.
They are separating at (72+76) = 148 miles per hour relative to each other, so they will take (330miles/148miles per hour)
[tex]330/148=2.2[/tex]
What are the distance problems?
Distance problems are word problems that involve the distance an object will travel at a certain average rate for a given period of time. Things to watch out for: Make sure that you change the units when necessary.
How do you solve distance-time problems?
To work out speed, divide the distance of the journey by the time it took to travel, so speed = distance divided by time. To calculate time, divide the distance by speed. To get the distance, multiply the speed by time. You may see these equations simplified as s=d/t, where s is speed, d is distance, and t is time.
Thus, it takes 2.2 hours for them to be 330 miles apart.
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a 300 g mass hangs vertically from a spring. a spring elongation of 11 cm is recorded. calculate the spring constant k in newtons per meter (n/m). (make sure to use the right si units for the mass and elongation)
The spring constant (K) is 2.67n/m when 300 g mass hangs vertically from a spring.
What is Spring?A spring is a material that may be bent by an external force before resuming its original shape.
What is the Spring constant?Now, the force required for every unit of spring extension is known as the "Spring constant." Knowing the spring constant makes it simple to calculate the amount of force needed to bend the spring.
Hooke's law states that F = -KX.
Calculations:
Given,
Mass = 300g = 0.3kg
Spring elongation = x = 11cm = 1.1m
Spring constant = k =?
Kx= mg
K = mg/x
K = (0.3 * 9.81) / 1.1m
K = 2.67n/m.
Hence, the spring constant (K) is 2.67n/m when 300 g mass hangs vertically from a spring.
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Physics question, vectors
The typical canoeist can paddle at about 2.6 knots, or 3 mph (ca. 5 km/h), when paddling without stopping and in calm, quiet water. Obviously, the length of time depends on the weather, the person's health, and the speed of the canoe.
What speed of canoe with respect to water and shore?The typical canoeist can paddle at about 2.6 knots, or 3 mph (ca. 5 km/h), when paddling without stopping and in calm, quiet water. Obviously, the length of time depends on the weather, the person's health, and the speed of the canoe.
Therefore, When the medium is deepest, water waves propagate more quickly. Water waves will therefore slow down as they go from deep to shallow water.
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An 15-cm-long bicycle crank arm, with a pedal at one end, is attached to a 25-cm-diameter sprocket, the toothed disk around which the chain moves. A cyclist riding this bike increases her pedaling rate from 65 rpm to 91 rpm in 11 s .
A) What is the tangential acceleration of the pedal?
B)What length of chain passes over the top of the sprocket during this interval? Need units as well
The tangential acceleration and length of chain of rocket is 0.5708 and 9.4m respectively.
Any object's rotational motion experiences tangential acceleration, which is the rate at which the tangential velocity varies. When an object is moving, it behaves in a tangential direction. When an object is moving in a circle, the tangential velocity also operates in the same direction. Only when an object follows a circular path does tangential acceleration take place. In cases where the body is rotating more quickly, it is positive; in cases where it is slowing down, it is negative; and in cases where the body is rotating uniformly throughout the orbit, it is zero.Initial angular velocity, w = 65rpm = 65(rad/s = 6.594rad/s
Final angular velocity, w = 91rpm = 91(rad/s = 9.734rad/s
time taken, t= 11s
Then let total radians covered in this much time be 0 and angular acceleration be a, using equations of motion.
a). 9.734 6.59 and 0.2854rad/s
= (9.734)(6.594) +2(0.2854)/3
A=0.5708
b).Then radius of sprocket R= diameter/2= (25/2)cm E =12.5cm
Then length of chain passes over the top of sprocket in this intervalis
r= (0-12.5m)(89/ 821)
r=9.4m
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A proton (charge 1.602 * 10-19) moves a distance of d
= 0.59 m from point A to point B in a straight line inside a linear accelerator. The electric field of the accelerator is uniform and has a magnitude of 15 MN/C.
What is the electric force on the proton?
F=
What is the work done on the proton?
W=
What is the potential difference between the points A and B?
Vab=
A proton (charge 1.602 * 10-19) moves a distance of d= 0.59 m from point A to point B in a straight line inside a linear accelerator. The electric field of the accelerator is uniform and has a magnitude of 15 MN/C.
i.) The expression for the force on proton is,
F=qE
(1.6⋅10−19 )(1.5⋅10 7)
=2.4⋅10 −12 N
Thus, the force on the proton is 2.4⋅10 −12 N.
ii) The expression for the work done by the field is,
W=qEd
(1.6⋅10 −19)(1.5⋅10 7 )(0.5)
=1.2⋅10 −12J
iii) The expression for the potential difference is,
U=Ed
=(1.5⋅10 7) (0.5)
=0.75⋅10 7 V
Electric potential of a system of point charges?
A point charge's electric potential is V=kQ/r. Electric field is a vector while electric potential is a scalar.
What is the electric potential at a point distance?
Electric potential at point P, located at a distance of r=R2 from the center, where R is the radius of an evenly charged shell with a density of surface charges.
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Can you summarize what it takes to make an object change direction ill report if you steal my point and put the wrong answer
Answer: The only way for the object to change its motion is if an external unbalanced force acts on it.
Explanation:
Newton's First Law of Motion (aka Law of Inertia) states:
An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
Velocity is a VECTOR, so it has both magnitude (size) and direction. The magnitude of the velocity of an object in motion (its speed) can stay the same, but if it changes direction, its velocity has changed. The only way for the object to change its direction of motion is if an external unbalanced force acts on it.
A box moves down one ramp and up another ramp along the path shown in the image. Between which two points does the box gain potential energy as it travels?
Points 3 and 4.
Points 1 and 2.
Points 1 and 3.
Points 2 and 3.
The box gains potential energy as it travels between points 3 and 4 according to the figure.
What is potential energy?The energy held within an object is known as potential energy. There are several different types of potential energy, including gravitational potential energy, elastic potential energy, and electric potential energy.
Here, the energy that an object possesses as a result of its position in relation to other objects is referred to as its gravitational potential energy.
When the box travels from point 3 to point 4, its height increases, that's why, the box gains potential energy as it travels between points 3 and 4.
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if a 0.08kg cell phone falls of a table at 15 m/s then what is its kinetic energy right before it hits the ground?
The Kinetic energy of the cell phone of mass 0.08 kg is 9 J.
What is kinetic energy?Kinetic energy is the energy of a body in motion.
To calculate the kinetic energy of the cell phone, we use the formula below.
Formula:
K.E = mv²/2............. Equation 1Where:
K.E = Kinetic energy of the cell phonem = Mass of the cell phonev = Velocity of the cell phoneFrom the question,
Given:
m = 0.08 kgv = 15 m/sSubstitute these values into equation 1
K.E = 0.08×15²/2K.E = 9 JHence, the Kinetic energy of the cell phone is 9 J.
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Two boxes with different masses slide down a ramp from the same initial height. Assuming friction is 0, which statement correctly describes the energy of the boxes when they are halfway down the ramp?
Each box has one-half the kinetic energy it had at the top of the ramp.
Both boxes have the same amount of kinetic energy as each other.
Each box has one-half the potential energy it had at the top of the ramp.
Both boxes have the same amount of potential energy as each other.
Both boxes have the same amount of kinetic energy as each other (option- b) is correct.
How does the mechanical energy in the system change as a result of friction?If no energy is lost through friction, the system's mechanical energy stays constant. When the speed picks up, the energy would change into kinetic energy. Providing there is no energy loss from friction, the system's mechanical energy increases.
The potential energy of an object falls while its kinetic energy rises. The increase in kinetic energy exactly offsets the decrease in potential energy. The idea of work is another crucial one.
Some kinetic energy is converted into heat energy when friction occurs between two surfaces that are moving over one another.
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A 10.5 kg board 6.00 m long is
supported by two sawhorses, one at each end. A 4.45 kg saw sits on the board 1.80 m from the left end. Find the upward force that the LEFT sawhorse exerts on the board.
Answer: Omitting g for weigh because problem omits g
Taking torque about left sawhorse
Mr * 6 = 3 * 10.5 + 4.45 * 1.8 = 31.5 + 8.0 = 39.5
Mr = 39.5 / 6 = 6.60 mass exerted upward by right sawhorse
6.6 + Ml = 10.5 + 4.45 balancing upward and downward mass
Ml = 8.4 kg upward force (kg) exerted by left sawhorse
Check: take torque about right end
8.4 * 6 = 3 * 10.5 + 4.45 * 4.2
50.4 = 31.5 + 18.7 = 50.2 balances within rounding error
The upward force that the left sawhorse exerts on the board is 164 N.
What is meant by torque ?Torque is defined as the rotational analogue of force. It is the cross product of force and the perpendicular distance.
Here,
Mass of the board, m₁ = 10.5 kg
Length of the board, L = 6 m
Torque of the board, τ₁ = m₁g x r₁
τ₁ = 10.5 x 9.8 x (6/2)
τ₁ = 308.7 Nm
Mass of the saw, m₂ = 4.45 kg
Length of the saw, r₂ = 6 - 1.8 = 4.2 m
Torque of the saw, τ₂ = m₂g x r₂
τ₂ = 4.45 x 9.8 x 4.2
τ₂ = 183.2 Nm
So,
Torque on the left saw = Torque on the board + torque on the saw
τ' = 308.7 + 183.2
τ' = 491.9
Therefore force exerted by the left saw, F = τ'/(L/2) = 491.9/3
F = 164 N
Hence,
The upward force that the left sawhorse exerts on the board is 164 N.
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Read the definitions then match it with the correct force.
This image is an example of Newton's ___Law of Motion.
Here in this scenario, this image is an example of Newton's first Law of Motion.
What is newton's law of motion?
The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact. The following is a paraphrasing of these laws:
Unless a force acts upon a body, it remains at rest or in continual straight-line motion.When a force acts on a body, the force is equal to the time rate at which the body's momentum changes.When two bodies exert force on one another, the direction and amount of the force are opposed.Isaac Newton first identified the three laws of motion in his 1687 book Philosophies Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy).
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For many years Colonel John P. Stapp, USAF, held the world's land speed record. On March 19.1954, he rode a rocket-propelled sled that moved down a track at a speed of 632 mi/h . He and the sled were safely brought to rest in 1.40 s (Fig. P2.31). Determine (a) the negative acceleration he experienced and (b) the distance he traveled during this negative acceleration.
The negative acceleration and distance is 451.42m/s² and 175.55m.
When an object experiences negative acceleration, its velocity changes in a negative direction, which can indicate that it is moving either slower or faster.
As a vector quantity that denotes both magnitude and direction, the term "acceleration" is used in physics to describe a change in an object's velocity.
Positive velocity, which is also a vector, makes something move more slowly than something experiencing negative acceleration. An object that has both negative acceleration and velocity, however, is actually moving faster.
a]. Negative Acceleration = dv/dt
a=632/1.40=451.42m/s²
b]. distance= speed x time
d=632x 5/18=175.55m
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