Mathematics College

What is the value of k?

2k+9=7−3k


k=−2

k=−0.4

k = 2

k = 3.2

Answers

Answer 1

Answer:

k = -0.4

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

2k + 9 = 7 - 3k

Step 2: Solve for k

[Addition Property of Equality] Add 3k on both sides:                                  5k + 9 = 7[Subtraction Property of Equality] Subtract 9 on both sides:                        5k = -2[Division Property of Equality] Divide 5 on both sides:                                 k = -0.4

Related Questions

Don’t answer on this or ur sus

Answers

>:)

heheheheheheheherhehehehreh

13 12 28 candy bars and 42 packs of gum were put in gift bags. The same number of candy bars and the same number of packs of gum were put in each bag. What is the greatest number of gift bags that could be made? ​

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Answer:

Step-by-step explanation:

which one is this a b c d e the thing on the side dosent matter

Answers

Answer:

21.5m²

Step-by-step explanation:

Area for a square: LxW = A

10x10=100m²

Area for a circle: pi r² = A

pi(5)²=78.5m²

Find the difference:

100m²-78.5m² = 21.5m²

7x - 3= -3 + 7x find x​

Answers

I think x equals either 0 or 1 cause if you solved for x you would just end up with 0=0 so I think it would be x=0

Solve. −2x−35=87 Enter your answer in the box. x =

Answers

Hello there! I am Grace Rosalia (SilentNature), and I hope my answer will help you! :)

-2x-35=-87

-2x=-87+35

-2x=-52

Divide both sides by -2 to isolate x:

x=26

Hope this helps you! :)

~Just a joyful teen

[tex]SilentNature[/tex]

The solution of the given equation is x = -21.

How to solve a linear equation?

A linear equation can be solved by equating the LHS and RHS of the equation following some basic rules such as by adding or subtracting the same numbers on both sides and similarly, doing division and multiplication with the same numbers.

The given equation can be solved as follows,

−2x − 35 = 87

=> -2x = -35 + 87

=> -2x = 42

=>  x = -42/2

       = -21

Hence, the value of x for the given equation is -21.

To know more about linear equation click on,

https://brainly.com/question/11897796

#SPJ2

Sorry its blurry but please answer fast!!!!!

Answers

Answer:

i know 14 and 15 are true but not sure about 12 sry

Step-by-step explanation:

Calvin works at a pizza place making pizzas. If he is working alone, he can make an average of 15 3/4 per hour. If he works with his friend Megan, he tends to get distracted, and his rate falls by 1/2 per hour. How many pizzas can Calvin make in a 8- hour shift with Megan?

Explain the operations that will be needed to solve this problem, ans then solve it.

Answers

The fraction 1/2 converts to 0.50 in decimal form.

The mixed number 15 & 3/4 is the same as 15.75

If Calvin is distracted, then he makes 15.75-0.50 = 15.25 pizzas per hour on average.

Multiply by 8 to find the total number of pizzas possible.

8*15.25 = 122

Answer: Calvin can make 122 pizzas overall if he is distracted

Calvin can make 122 pizzas in an 8-hour shift with Megan.

Since Calvin works at a pizza place making pizzas, and if he is working alone, he can make an average of 15 3/4 per hour, but if he works with his friend Megan, he tends to get distracted, and his rate falls by 1/2 per hour, to determine how many pizzas can Calvin make in a 8-hour shift with Megan, the following calculation must be performed:

Rate of pizzas made x number of hours = Total number of pizzas (15 3/4 - 1/2) x 8 = X (15.75 - 0.5) x 8 = X 15.25 x 8 = X 122 = X

Therefore, Calvin can make 122 pizzas in an 8-hour shift with Megan.

Learn more in https://brainly.com/question/14963327

Please help I don’t understand it

Answers

The constant is 3.

This is because when x=1, y=3 and when x=2, y=6 so that is a constant change over each interval as seen in the graph which is 3 :)

(-8r^2s^-8)(-3r^-7s^8)

Answers

24r^−5s^0 would be your answer

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