What is the radius of a force?

Answers

Answer 1

Answer:

this kind of force is proportional directly to the speed of the object and inversely to the radius of the curved path. Therefore, Hence, the force becomes 2.25 times the original force.

Explanation:


Related Questions

Calculate change in height of a 2kg ball moving a speed of 10m/s up a frictionless ramp until it stops

Answers

The change in the height of the object is 5.1 m.

Conservation of mechanical energy

The principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.

The change in the height of the object is calculated by applying the principle of conservation of mechanical energy as follows;

P.E = K.E

[tex]mg \Delta h = \frac{1}{2} mv^2\\\\g \Delta h = \frac{1}{2}v^2\\\\\Delta h = \frac{v^2}{2g} \\\\\Delta h = \frac{(10)^2}{2(9.8)} \\\\\Delta h = 5.1 \ m[/tex]

Thus, the change in the height of the object is 5.1 m.

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If a green ball is rolled from an initial position of 2m and travels to a final
position of 10m - what distance does it travel? (just type the number, no
need for units).

Answers

Answer:

10m-2m = 8m

8

Hope this helps!

this is the question on the attachment

Answers

Explanation:

a) to allow for the metal tracks to expand on hot days.

reason:- as you have seen in summer the sunlight fall on these tracks and make the metal expand and fill that gaps.

hope this helps you

have a great day :)

Two spheres carry a charge of 1x10^-7 C. Their centers are separated by 0.7m. Calculate the magnitude of the force between the two charged objects.
Write your answer in scientific notation using one significant figure

PLEASE HELP ME

Answers

We have that the  force between  the two charged objects is mathematically given as

F=2.349N

Magnitude of the force between  two charged objects.

Question Parameters:

Two spheres carry a charge of 1x10^-7 C.

Their centers are separated by 0.7m.

Generally the equation for the Force  is mathematically given as

[tex]F=\frac{q1q2}{4*\pi e*r}[/tex]

Therefore

[tex]F=\frac{(1e-7)^2}{9e9*0.7}[/tex]

F=2.349N

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Explain why friction becomes desirable and undesirable

Answers

Answer:

A friction is very much desirable to stop the body from its moving condition. ... If the friction is more between the block and inclined surface then a large force is required to push the block on the plane.

Explanation:

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The period of a .75 m pendulum is _s

Answers

Hi there!

We can use the following equation for the period of a pendulum:

[tex]\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}[/tex]

T = Period (s)
L = length of simple pendulum (.75 m)

g = acceleration due to gravity (9.8 m/s²)

Plug in the values:

[tex]T = 2\pi \sqrt{\frac{.75}{9.8}} = \boxed{1.738 s}[/tex]

What is the effect of clouds on the "output" of a Solar PV module?

Answers

Answer:

What is the effect of clouds on the "output" of a Solar PV module?

Clouds do impact photovoltaic panels. The quantity of power your photovoltaic panels can produce is directly dependent on the level of light they receive. ... They will see complete direct sunlight “plus” reflected light from the clouds! They will drink in more energy than they could on a cloudless day!

Explanation:

I hope it will help you...

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What do you mean by escape speed at a place?​

Answers

In celestial mechanics, escape velocity or escape speed is the minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a primary body, thus reaching an infinite distance from it.

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The lightbulb of a flashlight creates light and heat, both of which are forms of
energy. What is the source of the energy?
A. Elastic potential energy stored in the molecules of the flashlight
B. Chemical potential energy stored in the ions of the battery
C. Kinetic energy of the electrons flowing through the lightbulb
O D. Gravitational potential energy stored in Earth's gravitational field

Answers

Answer:

B

Explanation:

If a driver brings a car traveling at 22m/s to a full stop in 2.0 s with an acceleration of -8 m/s2 then how far did the car travel while braking?

Answers

Answer:

v=u + at

0= 22 + a*2

a = -22/2 = -11 m/s^2

The car's acceleration is -11 m/s^2

V^2 = u^2 + 2as

022^2 + 2*(-11)s

s = 22^2/22 = 22m

The car will travel 22 m before stopping.

Explanation:

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On the periodic table, the elements known as noble gases are found in

Answers

Answer:

The noble gases are located in the 18th group of the periodic table.

What is the acceleration of the object?

Answers

30 because v1 - v2 is 30 v1 is 40 v2 is 10

According to newton second law of motion what is force equal to

Answers

Answer:

According to Newton, "Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration."

Force = mass x acceleration

Answer: According to Newton’s Second Law of physics, the force is equal to the mass of the object times the acceleration. The force acting on an object would be equal to the mass of an object times its acceleration... This means the more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration

Car 1 brakes to a stop on a dry road. Car 2 does the same thing, at the same speed, on a road where it has been raining. Explain how the following will be different for car 2: a) braking distance, b) thinking distance and c) stopping distance.

Answers

Answer: car 1 is going how fast

Explanation: no need to answer without speed I won't know distance.

how do you work this out​

Answers

Answer:

A= v-u/t

= 8m/s - 18m/s ÷ 100s

= - 0.1m/s^2

Hope this helps!

I need help algebra in physics

Answers

Answer:

A: 0.26

Explanation:

using my friend account again
HELP ME PLIS

Answers

The answer is x = 118

Using the angle addition postulate, you can see that 55 + 63 is equivalent to 118

what is the kinetic energy of a sky diver with a mass of 60.0 kg falling at a terminal velocity of 40.0 ms?

Answers

Answer:

48,000 J

Explanation:

m = 60.0 kg

v = 40.0 m/s

kinetic energy = mv^2/2 = 60*40^2/2 = 48,000 J

What is that force that simply pushes bodies through the planet's gravitational field​

Answers

Answer:

Actually, it is not a force. It is a velocity attained by the bodies hence escaping through the gravitational field.

This velocity is called escape velocity.

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Answer:

Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun. Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity, which is 9.8 m/s2 on Earth. The gravitational force between two bodies is directly proportional to the product of the masses of those bodies and is inversely proportional to the square of the distance between them.

Hope this helped! Have a nice day!

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If a yellow ball is rolled with an average speed of 5 m/s, how far will it travel
in 5 seconds? (just type the number, no need for units).
*

Answers

25m

Explanation:
5m/s if 5 seconds pass then 5 • 5, you get 25m
Hope this helps!

Which example is a simple machine?

1. ramp

2. bicycle

3. car

4. steering wheel system of a boat

Answers

Answer:

Ramp

Explanation:

All of the other things are fairly complex, bikes have to be made with multiple parts so do cars and steering wheels are another part of a boat, a ramp usually consists of two or fewer parts making it the simplest.

A ball with a weight of 15 N is thrown striaght up into the air with an initial speed of 14 m/s. What is the maximum height it will achieve above its starting position

Answers

Answer:

10m above initial height

Explanation:

let acceleration due to gravity = 9.8 m/s/s

v final = v initial - time • gravity

0 = 14m/s - t • 9.8m/s/s

t = 1.43 seconds to reach max height

distance = 1/2 • acceleration • time^2

distance = 1/2 • 9.8 • 1.43^2

distance = 10 meters above initial height

A new company is making security cameras. These security cameras will be different than other security cameras because instead of detecting motion, they will detect body heat.
What type of electromagnetic wave will the camera detect?
A
gamma ray
B
infrared
C
microwave
D
radio wave

Answers

Answer:

b

Explanation:

Light passes through a single slit of width 8.77 x 10-6 m. The second (m = 2 diffraction minimum occurs at an angle of 5.62º. What is the wavelength of the light IN NANOMETERS?​

Answers

Answer:

429.424

Explanation:

Trust :)

The wavelength of the light passing through the single slit is approximately 429 nanometers.

To calculate the wavelength of the light passing through a single slit, we can use the formula for the diffraction of light:

w × sin(θ) = m ×λ

Where:

w is the width of the slit

θ is the angle of the diffraction minimum

m is the order of the diffraction minimum

λ is the wavelength of the light

Given:

Width of the slit (w) = 8.77 × 10^(-6) m

Angle of the diffraction minimum (θ) = 5.62º = 5.62° = 5.62 × π/180 radians

Order of the diffraction minimum (m) = 2

To solve for the wavelength (λ),  rearrange the formula:

λ = (w × sin(θ)) / m

Substituting the given values:

λ = (8.77 × 10^(-6) m × sin(5.62° × π/180)) / 2

Calculating this expression:

λ ≈ (8.77 × [tex]10^{(-6)[/tex] m × sin(0.098)) / 2

λ ≈ (8.77 ×[tex]10^{(-6)[/tex] m × 0.098) / 2

λ ≈ 4.29 ×[tex]10^{(-7)[/tex] m

To convert the wavelength to nanometers, we multiply by[tex]10^9[/tex]:

λ = 4.29 × [tex]10^{(-7)[/tex] m × 10^9 nm/m

λ ≈ 429 nm

Therefore, the wavelength of the light passing through the single slit is approximately 429 nanometers.

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A car engine burns gas at 495 K and exhausts to the air at 293 K if it ran at the highest possible efficiency and use 10,000 J of input heat how much he would it be rejected into the air? WILL GIVE BRAINLIEST​

Answers

Answer:

5,920 J

Explanation:

Lowest temperature T₂ = 293 K

Highest temperature T₁ = 495 K

Highest possible efficiency e = 1 - T₂/T₁ = 1 - 293/495 = 0.408

Input heat Q₁ = 10,000 J

Find output heat Q₂

e = 1 - Q₂/Q₁

0.408 = 1 - Q₂/10,000

Q₂/10,000 = 1 - 0.408 = 0.592

so

Q₂  = 10,000 x 0.592 = 5,920 J

How much work is done on a small car if 4250 N force is exerted to move it 83.5 m to the side of the road?

Answers

Answer:

354875 J

Explanation:

The equation for Work is:

[tex]Work=Force*Distance[/tex]

We can plug in the given values into the equation:

[tex]Work=4250N*83.5m=354875J[/tex]

A 10 N force is applied to a 2 kg mass, how fast will it be going in 10 sec?

Answers

Answer:

v = 50 ms^1

Explanation:

We know:

F = 10N

m = 2kg

t = 10 sec

F=ma

10 = 2*a

5=a

a = 5 ms^2

Now,

a=v/t

5 = v/10

50 = v

v = 50 ms^1

Physics Unit 5 CA - Conservation of

1. A student is pushing a car toward a gas station. They exert a constant force of 100 N
on the car for 40 m bring the car from rest to 5 m/s. What is the mass of the car?

Answers

Answer:

160 kg

Explanation:

f = ma

100 = m * a

a = v/t

v = distanc/time

dist = 40m

time = 8 sec

v = 40/8

a = 40/(64)= 5/8

m = 100*8/5= 160 kg

how can i plot a graph?​

Answers

Answer:

so you have your boxes go by tens on the x-axis okay which is the one going straight up then the second number goes by 5's is your y-axis. 30,6 so 30 is your x and 6 is your y. start at 0,0 which is the little corner piece. find 30 on x and then go over 6 and that's it!

Explanation:

Calculate the speed of a 5 kg object that possesses 20 J of kinetic energy KE=1/2
mv2
2.83 m/s/s
2.83 m/s
2 m/s
4 m/s

Answers

Answer:

2.83 m/s

Explanation:

m = 5 kg,

KE = 20 J

KE = mv^2/2

20 = 5*v^2/2

5*v^2 = 40

v^2 = 8

v = [tex]\sqrt{8}[/tex] = 2.83 m/s

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