Titration is the process of determining the amount of a substance in a solution by measuring the volume of a solution with a known concentration that is required to react with it. The answer to the given question is option d) 5.25.
In the titration of a weak base with a strong acid, the pH at the half-equivalence point can be calculated as follows: At the half-equivalence point, we have equal moles of the weak base and the strong acid. As a result, we get a solution that contains the weak base, its conjugate acid, and water. In the solution, there is an equilibrium between the weak base and its conjugate acid. This equilibrium has an acid dissociation constant, Ka. It's given by:
Ka = [H+][A–]/[HA]
The pKa is calculated by taking the negative logarithm of Ka:
pKa = -log(Ka)
At the half-equivalence point, [HA] = [A–] and the expression for pKa becomes:
pKa = -log([H+])
Therefore, the pH at the half-equivalence point is:
pH = 1/2 (pKb + pKa)
Given that pKb = 7.95 for the weak base, we can calculate the pKa:
pKw = 14 (at 25°C)
pKw = pKa + pKb
14 = pKa + 7.95
pKa = 6.05
Therefore, the pH at the half-equivalence point is:
pH = 1/2 (7.95 + 6.05)
pH = 1/2 (14)
pH = 7
At the half-equivalence point, the pH of the solution is equal to 7. Therefore, option d) 5.25 is incorrect.
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For the following equilibrium, BaSO4(s) = Ba² + (aq) + S0 - (aq) if HCl is added, how will the quantities of each species change? Select the correct answer below: [Ba2+] increases, (so-1 decreases, mass of solid decreases O [Ba? +1 decreases, (so 1 decreases, mass of solid decreases [Ba? increases, so increases, mass of solid increases [Ba²+] decreases, (so increases, mass of solid increases
Adding HCl to the equilibrium BaSO4(s) ⇌ Ba²+(aq) + SO4²-(aq) will result in an increase in [Ba²+] and a decrease in [SO4²-]. The mass of the solid BaSO4 will also decrease.
When HCl is added, it dissociates into H+ and Cl- ions. The H+ ions react with the SO4²- ions from the dissociation of BaSO4, forming HSO4- ions and shifting the equilibrium to the right. As a result, more Ba²+ ions are released into the solution, leading to an increase in [Ba²+]. On the other hand, the decrease in [SO4²-] occurs because some of the SO4²- ions combine with H+ ions to form HSO4-. Since the equilibrium is being driven towards the products, the concentration of Ba²+ increases, [SO4²-] decreases, and the mass of the solid BaSO4 decreases.
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if 4.10 grams of chromium is heated with 9.30 grams of chlorine what mass of chromium(III) chloride is produced?
Answer:
4.1g of Cr will make (317/104) x 4.1 = 12.5g of CrCl3
The diagram shows a large, eroded rock tower found in Southern Utah.
Which most likely caused the erosion?
C sunlight
O A animals
D. water
B. plants
For the reaction
2S(s)+ 3O2\rightarrow 2SO3(g)
how many moles of SO3 can be produced from 6.0 g O2 and excess S?
Group of answer choices
none of these
0.28 mol SO3
4.0 mol SO3
0.25 mol SO3
0.13 mol SO3
To determine the number of moles of SO3 produced, we need to use the stoichiometry of the balanced equation.
The balanced equation tells us that 3 moles of O2 react with 2 moles of S to produce 2 moles of SO3. Therefore, the molar ratio between O2 and SO3 is 3:2.
To find the moles of SO3 produced from 6.0 g of O2, we need to convert the mass of O2 to moles using its molar mass. The molar mass of O2 is approximately 32 g/mol.
Moles of O2 = mass of O2 / molar mass of O2
Moles of O2 = 6.0 g / 32 g/mol
Moles of O2 = 0.1875 mol
Using the molar ratio, we can calculate the moles of SO3 produced:
Moles of SO3 = (0.1875 mol O2) x (2 mol SO3 / 3 mol O2)
Moles of SO3 = 0.125 mol
Therefore, the correct answer is 0.13 mol SO3.
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A gas sample at 40° C occupies a volume of 3.22 L. If the temperature is raised to 55°C, what will the volume be, assuming the pressure remains constant?
Answer:
3.374L
Explanation:
According to Charle's Law:
V1/T1=V2/T2 (At constant pressure and moles)
where V=Volume and T=Temperature.
The temperature must be in kelvin.
K=C°+273
T1=40+273=313K
T2=55+273=328K
By applying the formula, we get:
3.22/313=V2/328
V2=(3.22*328)/313
V2=3.374L
compute the equilibrium constant for the spontaneous reaction between sn2 (aq) and fe(s) . express your answer using two significant figures.
The equilibrium constant for the given reaction is 0.93 (to two significant figures). Hence, the answer is 0.93.
Given, spontaneous reaction between Sn2(aq) and Fe(s) is:Sn2(aq) + Fe(s) → Sn(s) + Fe2+(aq)The standard reduction potentials for Sn2+(aq) and Fe2+(aq) are given as:Sn2+(aq) + 2e- → Sn(s); E°red = -0.14 VFe2+(aq) + 2e- → Fe(s); E°red = -0.44 VThe cell potential (E°cell) for the spontaneous reaction can be calculated using the formula: E°cell = E°reduction at cathode - E°reduction at anodeE°cell = E°red of Fe2+ - E°red of Sn2+E°cell = (-0.44 V) - (-0.14 V)E°cell = -0.3 VThe standard equilibrium constant (K°) can be calculated using the relation: ΔG° = -RTlnK°Here, ΔG° is the change in Gibbs free energy for the reaction, R is the gas constant, and T is the temperature in Kelvin.Assuming T = 298 K, we can use R = 8.314 J/mol*K.ΔG° = -nFE°cellHere, n is the number of electrons transferred in the reaction and F is the Faraday constant (96485 C/mol).n = 2 for the given reaction.ΔG° = -2 * 96485 C/mol * (-0.3 V)ΔG° = 58.32 kJ/molSubstituting the values of R, T, and ΔG° in the equation ΔG° = -RTlnK°, we get:lnK° = -ΔG°/RTlnK° = -(58.32 kJ/mol) / (8.314 J/mol*K * 298 K)lnK° = -0.0737K° = e-lnK°K° = e0.0737K° = 0.93The equilibrium constant for the given reaction is 0.93 (to two significant figures). Hence, the answer is 0.93.
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the formulas of three important acids and three important bases and describe their uses.
Answer:
18929eu9sisjwiejwjxjjejxme
How is enthalpy related to the spontaneity of a reaction?
A. AH=0 contributes to spontaneity.
B. AH<0 contributes to spontaneity.
C. AH> 0 contributes to spontaneity.
D. AH does not affect spontaneity.
Answer:
D
Explanation:
Gibb's free energy change(∆G) and Standard electrode potential of electrochemical (Ecell) determine the spontaneity of a reaction.
when ∆G > 0, the reaction is not spontaneous
∆G < 0, the reaction is spontaneous
∆G = 0, the reaction is in equilibrium
when Ecell > 0, the redox reaction is spontaneous
Ecell < 0, the redox reaction is not spontaneous
Ecell = 0, the redox reaction is in equilibrium.
ΔH < 0 contributes to spontaneity.
What is a spontaneous reaction?A spontaneous reaction is one that takes place naturally under a certain set of circumstances. The general entropy, or chaos, of the system increases in the presence of spontaneous reactions.How can we determine if a reaction is spontaneous or not?We can determine it by calculating Gibb's free energy.
How do we calculate Gibb's free energy?It is calculated by the formula:
ΔG = ΔH - TΔS
ΔG is the change in Gibb's free energy,ΔH is the change in the enthalpyΔS is the change in entropy.How does ΔG tells if a reaction is spontaneous or not?If ∆G > 0, the reaction is not a spontaneous reaction∆G < 0, the reaction is a spontaneous reaction∆G = 0, the reaction is in equilibriumHow does ΔH contribute to the spontaneity of the reaction?For a reaction to be a spontaneous reaction, ∆G < 0.Consider a reaction, ΔG will be calculated as ΔH - TΔSIf ∆H < 0 then the ΔH - TΔS will be a lesser value ( more negative) than it would have been when ∆H = 0 or ∆H > 0.Therefore ∆H < 0 contributes to spontaneity.To learn more about ΔH, spontaneous reaction, enthalpy, and entropy here,
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When we celebrate a new year we are really celebrating what?
HELP ME! is iodine solution polar, non-polar, or ionic?
Please don't attach links, i will report you
Answer:
Since the iodine-iodine bond is a pure covalent bond, iodine is a non-polar molecule. The electronegativity difference between the two Iodine atoms is zero.
does this help???
92.12 kJ of heat is required to convert 58.40 g of gold from liquid to gas phase. What is the heat of vaporization of gold in J/g?
Answer:
The heat of vaporization of the gold sample is 1577.397 joules per gram.
Explanation:
The latent heat of vaporization of gold ([tex]h_{v}[/tex]), in kilojoules per gram, is the heat required by a unit mass of gold to transform the material from liquid to gas:
[tex]h_{v} = \frac{E}{m}[/tex] (1)
Where:
[tex]E[/tex] - Energy required for vaporization, in joules.
[tex]m[/tex] - Mass, in grams.
If we know that [tex]E = 92120\,J[/tex] and [tex]m = 58.40\,g[/tex], then the heat of vaporization of the gold sample is:
[tex]h_{v} = \frac{E}{m}[/tex]
[tex]h_{v} = 1577.397\,\frac{J}{g}[/tex]
The heat of vaporization of the gold sample is 1577.397 joules per gram.
Enthalpy of
CH4(g) + 2NO2(g) -> N2(g) + CO2(g) + 2H2O(l)
Answer:
-177.9 kJ.
Explanation:
Use Hess's law. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1269.8 kJ We need to get rid of the Ca and O2 in the equations, so we need to change the equations so that they're on both sides so they "cancel" out, similar to a system of equations. I changed the second equation. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ The sign changes in the second equation above since the reaction changed direction. Next, we need to multiply the first equation by two in order to get the coefficients of the Ca and O2 to match those in the second equation. We also multiply the enthalpy of the first equation by 2. 2Ca(s) + 2CO2(g) + O2(g) → 2CaCO3(s) ΔH = -1625.6 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ Now we add the two equations. The O2 and 2Ca "cancel" since they're on opposite sides of the arrow. Think of it more mathematically. We add the two enthalpies and get 2CaO(s) + 2CO2(g) → 2CaCO3(s) and ΔH = -355.8 kJ. Finally divide by two to get the given equation: CaO(s) + CO2(g) → CaCO3(s) and ΔH = -177.9 kJ.
Which of these would be found in a wetland?
Mrs. Cornell and vultures
Cattails and salamanders
Maple trees and cats
Oak trees and squirrels
Answer:
jwjsjdjdhdvjeiejjrjrje
A 0.330 gram sample of an unknown, monoprotic acid (the molar ratio between acid and base is 1-to-1) was dissolved in 50.0 mL of water and titrated to equivalence point with 22.00 mL of 0.150 M NaOH. Determine the molar mass of the the unknown aci
The molar mass of the unknown monoprotic acid will be approximately 100 g/mol.
To determine the molar mass of unknown monoprotic acid, we will use the concept of stoichiometry.
First, let's calculate the number of moles of NaOH used in the titration:
Moles of NaOH = concentration of NaOH × volume of NaOH used
= 0.150 mol/L × 0.02200 L
= 0.00330 mol
Since the acid and base have a 1-to-1 molar ratio, the number of moles of the unknown acid is also 0.00330 mol.
Next, let's calculate the molar mass of the unknown acid:
Molar mass of the unknown acid = mass of the unknown acid / moles of the unknown acid
We are given the mass of the unknown acid as 0.330 grams and the moles of the unknown acid as 0.00330 mol.
Molar mass = 0.330 g / 0.00330 mol
= 100 g/mol
Therefore, the molar mass is 100 g/mol.
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please help I'm stuck
7. Which of the following correctly defines an acid-base reaction?
a. redox reaction
b. neutralization reaction
C. combustion reaction
d. hydrolysis reaction
Answer:
b
Explanation:
What is the goal of mitosis? Of meiosis?
How are organisms classified as Eukarya different from organisms classified as Archaea and Bacteria?
A)They are all multicellular.
B)They all produce their own food.
C) They all reproduce sexually.
D) They all have membrane-bound nuclei
Answer: D
Explanation: The Eukarya differ from the Archea and Bacteria in that their cells are eukaryotic, meaning they contain a membrane enclosed nucleus and other membrane enclosed organelles.
Eukarya is different from organisms classified as Archaea and Bacteria because Eukarya have membrane-bound nuclei. Therefore, option (D) is correct.
How does the classification of Eukarya differ from Archaea?The type of cell of the organism can be classified into three domains. First is the bacteria which have no nucleus present in cells. Then Archaea have no nucleus in the cells but they have a different cell wall than bacteria. Then Eukarya have a nucleus in them.
The domains of Archaea and Bacteria are both composed entirely of small, single-celled organisms but they also have differences. All are composed of prokaryotic cells, which are nucleus-less cells. T
All the cells in the Eukarya domain contain their genetic material or DNA within the nucleus. Four classes make up the Eukarya domain: Plantae, Fungi, Animalia, and Protista.
Therefore, the domain of the Eukarya is different from organisms classified as Archaea and Bacteria as Eukarya have membrane-bound nuclei.
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In the following molecules, the primary intermolecular attractive force is
Answer:
Dipole-dipole
Explanation:
a 900 w carbon-dioxide laser emits light with a wavelength of 10μm into a 3.0-mm-diameter laser beam.
The 900 W carbon-dioxide laser emits light with a wavelength of 10 μm into a 3.0 mm diameter laser beam. This means that the laser is producing a high-power output in the infrared region of the electromagnetic spectrum.
The wavelength of 10 μm corresponds to the mid-infrared range, which is commonly used in various applications such as industrial cutting and welding, medical procedures, and scientific research.
The 3.0 mm diameter laser beam represents the spatial profile of the laser output. It indicates that the laser beam has a relatively small cross-sectional area, allowing for focused and concentrated energy delivery.
The combination of a high-power output and a specific wavelength allows the carbon-dioxide laser to efficiently perform tasks that require precision and controlled energy deposition, making it suitable for a wide range of industrial and scientific applications.
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a 0.0280 m solution of an organic acid has an [h ] of 1.60×10-3 m .Using the values above, calculate the pH of the solution. What is the percent ionization of the acid? Calculate the Ka value of the acid.
The pH of the solution is 2.80, the percent ionization of the acid is 5.71%, and the Ka value of the acid is 9.14 × 10-5.
A.0280 M solution of an organic acid has an [H] of 1.60×10-3 M.Using the values above, the pH of the solution, the percent ionization of the acid, and the Ka value of the acid are given below:pH of the solution: The formula for calculating the pH of a solution is as follows:pH = -log[H] = -log[1.60 × 10-3] = 2.80Percent ionization of the acid:Percent ionization is given by the following formula:Percent ionization = ( [H+]/[HA] ) × 100 = (1.60 × 10-3/0.0280) × 100 = 5.71%Ka value of the acid:The formula for calculating the Ka value of an acid is as follows:Ka = [H+]2 / [HA]Ka = [1.60 × 10-3]2 / [0.0280]Ka = 9.14 × 10-5Hence, the pH of the solution is 2.80, the percent ionization of the acid is 5.71%, and the Ka value of the acid is 9.14 × 10-5.
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How is oxide different from a neutral oxygen atom
Answer: The main difference between oxide and oxygen is that oxide is a chemical compound with at least one oxygen atom while oxygen is an element whose atomic number is 8.
Explanation: let me know if it was right or wrong
please help me with these questions, im not understanding :(
Answer:
this is all the answers i hope you have a good day
Explanation:
may i please have a branlliests
Consider the equilibrium system described by the chemical reaction below, which has a value of Kc equal to 1.79 at a certain temperature. If a reaction mixture initially contains 0.050 M H2S and 0.050 M SO2, what will the equilibrium concentration of H20 be? 2 H2S(g) + SO2(g) ⇄ 3 S(s) + 2 H2O(g)
Equilibrium is a state of a reversible chemical reaction where the rates of forward and reverse reactions become equal, which results in the concentration of reactants and products being constant.
The chemical equation of the system described above is:2 H2S(g) + SO2(g) ⇄ 3 S(s) + 2 H2O(g)This system has an equilibrium constant (Kc) equal to 1.79 at a certain temperature. When the reaction mixture initially contains 0.050 M H2S and 0.050 M SO2, the equilibrium concentration of H2O can be found out as follows:As per the given equation, the mole ratio of H2S to H2O is 2:2 or 1:1. Therefore, the initial concentration of H2O is zero.The initial concentration of H2S is 0.050 M.Therefore, according to the equilibrium constant expression for this reaction, we can say that:[tex]\begin{align*}{K_c}&=\frac{\mathrm{[S]^3[ H_2O]^2}}{\mathrm{[ H_2S]^2[SO_2]}} \\ \\{1.79}&=\frac{\mathrm{(0.0.0.050)^2 [H_2O]^2}}{\mathrm{(0.050)^2 (0.050)}} \\ \\{1.79} \times \mathrm{(0.050)^3}&= \mathrm{[H_2O]^2} \\ \\{\mathrm{[H_2O]}}&= \sqrt{\mathrm{1.79} \times \mathrm{(0.050)^3}} \\ \\{\mathrm{[H_2O]}}&= \mathrm{0.027\ M} \end{align*}[/tex]Thus, the equilibrium concentration of H2O is 0.027 M.
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Which of the following are conjugate acid/base pairs? Select all that apply.
a. NaCl and NaOH
b. HCl and Cl-
c. H2SO4 and SO42-
d. H3PO4and H2PO4-
e. H2CO3 and CO32
The following are conjugate acid/base pairs:
HCl and Cl-.H2SO4 and SO42-.H3PO4 and H2PO4-.H2CO3 and CO32-.
Explanation:
In the acid-base reaction, the acid donates the proton (H+) while the base receives the proton. The substance that loses its proton becomes a conjugate base while the substance that gains a proton becomes the conjugate acid.
The conjugate acid/base pairs differ by one proton (H+).
NaCl and NaOH are not conjugate acid/base pairs as they are not acids or bases. NaOH is a strong base while NaCl is a neutral salt.
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balance
A FeS2 + B O2 → C Fe2O3 + D SO2 *
Answer:
4FeS2 + 6O2 > 2Fe2O3 + 8SO2
Explanation:
what were the advantages and disadvantages of each measuring device?
To assess the advantages and disadvantages of different measuring devices, specific devices need to be mentioned. Without specific devices, a comprehensive analysis of their advantages and disadvantages is not possible.
The advantages and disadvantages of measuring devices vary depending on the specific device and its application. Different devices have unique features and limitations that affect their accuracy, precision, ease of use, and suitability for different measurements. For example, consider two commonly used measuring devices: a ruler and a digital caliper. A ruler, while simple and inexpensive, may have limitations in terms of precision and accuracy due to human error in reading the markings. On the other hand, a digital caliper offers higher precision and accuracy, as it provides digital readouts and can measure small distances with greater precision. However, digital calipers may be more expensive and require batteries for operation.
Other factors to consider when evaluating measuring devices include durability, range of measurements, calibration requirements, ease of calibration, portability, and the specific needs of the measurement task at hand. To provide a more detailed analysis, it would be helpful to specify the measuring devices being compared.
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A combustion reaction is a common reaction used to produce energy. Write a combustion reaction for the combustion of ethanol, C₂H5OH. View Available Hint(s) C,HyOH + 3 Oz → 2 CO, + 3 H,O C₂H5OH(
Combustion reaction is a common reaction used to produce energy. The reaction that describes the combustion of ethanol, C₂H5OH is as follows:
C₂H5OH + 3O₂ → 2CO₂ + 3H₂O
The energy released by the combustion reaction is used to generate electricity or to power machines and vehicles.
This reaction is a chemical process in which a fuel reacts with oxygen to produce heat and light energy. Ethanol is a colorless liquid with a formula of C₂H₅OH. It is an important biofuel and is commonly used as a fuel additive to gasoline. In the combustion process, ethanol reacts with oxygen to produce carbon dioxide and water vapor.Combustion reactions are exothermic reactions that release energy in the form of heat and light. They are commonly used in engines and power plants to produce energy from fuels. The energy released by the combustion reaction is used to generate electricity or to power machines and vehicles.
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enzymes act as catalysts because they: group of answer choices decrease the enthalpy of the products. increase the entropy of the products.
Enzymes act as catalysts because they decrease the activation energy required to initiate a chemical reaction.
Why enzymes are considered as catalysts?Enzymes are molecules that accelerate chemical reactions by lowering the energy barrier (activation energy) for the transition state of the reaction. Enzymes bind to substrates, which are the reactants of the reaction.
The binding of the substrate to the enzyme lowers the energy required to transition the reactants to the transition state. This results in the lowering of activation energy that is required for a reaction to proceed
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During strenuous exercise, lactic acid builds up in muscle tissues. In a 1.00 M aqueous solution, 2.94% of lactic acid is ionized. What is the value of Ka for lactic acid?
The value of Ka for lactic acid is approximately 0.0303. To find the value of Ka for lactic acid, we can use the ionization percentage and the initial concentration of the acid.
Given that 2.94% of lactic acid is ionized in a 1.00 M solution, we can calculate the concentration of the ionized form ([tex]CH_{3}CH(OH)COO-[/tex]) by multiplying the ionization percentage by the initial concentration of the acid: [[tex]CH_{3}CH(OH)COO-[/tex]] = 2.94% × 1.00 M = 0.0294 M
Since lactic acid ([tex]CH_{3}CH(OH)COO-[/tex]) is a monoprotic acid, the concentration of the undissociated form is equal to the initial concentration minus the concentration of the ionized form: [[tex]CH_{3}CH(OH)COOH[/tex]] = 1.00 M - 0.0294 M = 0.9706 M
The equilibrium expression for the ionization of lactic acid can be written as: Ka = [[tex]CH_{3}CH(OH)COO-[/tex]] / [[tex]CH_{3}CH(OH)COOH[/tex]]
Substituting the values, we get: Ka = 0.0294 M / 0.9706 M = 0.0303
Therefore, the value of Ka for lactic acid is approximately 0.0303.
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What is the proper disposal of all chemicals in this reaction? Briefly explain any hazards associated with barium nitrate and silver nitrate
Barium nitrate is toxic if ingested or inhaled, while silver nitrate is corrosive and can cause severe skin and eye irritation.
Barium nitrate is toxic if ingested or inhaled, posing risks to the respiratory, cardiovascular, and nervous systems. It can also harm aquatic life if released into water bodies. Silver nitrate is corrosive and can cause severe irritation and burns to the skin and eyes. To properly dispose of these chemicals, consult local waste management authorities for specific guidelines. Follow any recommended neutralization procedures, use suitable containers for storage, and label them clearly with the contents and hazards. Engage a licensed waste disposal company or hazardous waste facility to ensure proper collection and disposal. Adhering to local regulations and best practices is crucial to minimize the environmental and health risks associated with these chemicals.
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