What is the per capita GDP of China? Be sure to indicate the calendar year that this information represents.

Answer:

2

Explanation:

From the formula R=(ro)A/l resistance depends on the length of the wire, the area of the wire(thickness) and the resistivity(ro) which depends on the material and temperature.

Answer:

I think you might have forgotten to post the problems

Answer:

[tex]X_t=2.17391304*10^{-4}[/tex]

[tex]X_r=2.89855072*10^{-4}[/tex]

[tex]e_t=0.0026[/tex]

[tex]e_r=0.0035[/tex]

Explanation:

From the question we are told that:

Dimension [tex]12*12[/tex]

Thickness [tex]l_t=5mm=5*10^-3[/tex]

Normal tensile force on top side [tex]F_t= 15kN[/tex]

Normal tensile force on right side  [tex]F_r= 20kN[/tex]

Elastic modulus, [tex]E=115Gpap=>115*10^9[/tex]

Generally the equation for Normal Strain X is mathematically given by

 [tex]X=\frac{Force}{Area*E}[/tex]

Therefore

For Top

 [tex]X_t=\frac{Force_t}{Area*E}[/tex]

Where

 [tex]Area=L*B*T[/tex]

 [tex]Area=12*10^{-2}*5*10^{-3}[/tex]

 [tex]Area=6*10^{-4}[/tex]  

 [tex]X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}[/tex]

 [tex]X_t=2.17391304*10^{-4}[/tex]

For Right side[tex]X_r=\frac{Force_r}{Area*E}[/tex]

Where

Area=L*B*T

 [tex]Area=12*10^{-2}*5*10^{-3}[/tex]

 [tex]Area=6*10^{-4}[/tex]  

 [tex]X_r=2.89855072*10^{-4}[/tex]

 [tex]X_r=2.89855072*10^{-4}[/tex]

Generally the equation for elongation is mathematically given by

 [tex]e=strain *12[/tex]

For top

 [tex]e_t=2.17391304*10^{-4}*12[/tex]

 [tex]e_t=0.0026[/tex]

For Right

 [tex]e_r=2.89855072*10^{-4} *12[/tex]

 [tex]e_r=0.0035[/tex]

Answer:

The block will float with its axis vertical.

Explanation:

For it to float, the upward force on the cylindrical block must be equal to the weight of an equal volume of water. Also, this upward force must be greater than or equal to the weight of the cylindrical block for it to float.

So, weight of cylindrical block, W = specific weight × volume

specific weight = 7500 N/m³

volume = πd²h/4 where d = diameter of block and h = height of block

volume = π(1 m)² × 1 m/4 = π/4 m³ = 0.7854 m³

W = 7500 N/m³ × 0.7854 m³ = 5890.5 N

Since the density of water = 1000 kg/m³, its specific weight W' = 1000 kg/m³ × 9.8 m/s² = 9800 N/m³

Since the volume of the cylinder = volume of water displaced, the weight of water displaced W' = upward force = specific weight of water × volume of water displaced =  9800 N/m³ × 0.7854 m³ = 7696.92 N

Since W' = 7696.92 N > W = 5890.5 N, the block will float with its axis vertical since the upward force is greater than the weight of the cylindrical block.

Complete Question:

Problem 8 Determine the horsepower required to compress 1 lbm/min of ethylene oxide from 70 °F and 1 atm to 250 psia. The compressor has an efficiency of 75%. The molar heat capacity of ethylene oxide is given by

C_p=10.03+0.0184T  C_p[=]Btu/lbmole- "F ; T[=] °F C,

Answer:

[tex]P'=0.377hp[/tex]

Explanation:

From the question we are told that:

Initial Temperature T_1=70 F

Final Temperature [tex]T_2=250pisa =114.94F[/tex]

Efficiency [tex]E=75\%=0.75[/tex]

Generally the equation for Work-done  is mathematically given by

 [tex]W=\int C_pT[/tex]

 [tex]W=10.03(114.94-70 )+0.0184((114.94)^2-70^2 )[/tex]

 [tex]W=527.21btu/ibmole[/tex]

 [tex]W=11.982btu/ibm[/tex]

Generally the equation for Efficiency  is mathematically given by

 [tex]E=\frac{isotropic Power}{Actual P'}[/tex]

 [tex]E=\frac{P}{P'}[/tex]

Since

Isotropic Power

  [tex]P=0.0167*11.982btu/ibm[/tex]

 [tex]P=0.2btu/s[/tex]

Therefore

 [tex]P'=\frac{0.2}{0.75}[/tex]

 [tex]P'=0266btu/s[/tex]

Since

 [tex]1btu/s=1.4148hp[/tex]

Therefore

 [tex]P'=0.377hp[/tex]

Answer:

The answer is "[tex]25\times 10^{-9}[/tex]".

Explanation:

Using formula:

[tex]f_c=\frac{1}{2\pi RC}\\\\w_c= 4 \frac{krad}{sec}\\\\w_c=2\pi fc\\\\R=w\\\\c=\frac{1}{w_c\ R}\\\\[/tex]

  [tex]=\frac{1}{4 \times 10^3 \times 10\times 10^3}\\\\=\frac{1}{40 \times 10^6 }\\\\=0.025 \times 10^{-6 }\\\\=25\times 10^{-9}[/tex]

Answer:

2.68

Explanation:

Percentage by Mass of each Aggregate :

Pa = 65% ; Pb = 35%;

Bulk Specific gravity of each aggregate :

Ga = 2.45 ; Gb = 3.25

Gsb = (Pa + Pb) / (Pa/Ga + Pb/Gb)

Gsb = (65 + 35) / (65/2.45 + 35/3.25)

Gsb = (65 + 35) / 37.299843

Gsb = 100 / 37.299843

Gsb = 2.68

Answer:

B. rotor

Explanation:

The correct answer Is rotor because the others are part of a cars drivetrain

The drive train system exists as a critical element of a vehicle and the transmission exists as an integral part of the drive train. B rotors NOT part of a car's drive train.

A drive train exists not really a single part of your car – it's a set of drive train components that interact with the engine to drive the wheels and different regions of the vehicle to thrust it into motion. These components often contain the transmission, differential, driveshaft, axles, CV joints, and wheels.

Therefore, the correct answer is option B rotors.

To learn more about the part of a car's drive train

https://brainly.com/question/14362401

#SPJ2

Answer:

Safety First, Safety Always. Safety stands out as a core value for the oil and natural gas industry, embedded in every process and decision for operations. The oil and natural gas industry and the federal government are working together to continuously improve the safety of offshore operations. ...

Answer:

5,465.4165939453

Explanation:

formula

A=P(1+r/n)^n(t)

p=1000

r=0.09

n=4

t=5

Answer:

At the threads due to shear.

Explanation:

Given :

The allowable tensile stress = 207 MPa

The allowable shear stress = 103 MPa

If a tensile force is applied, the maximum shear stress occurs at the threads of  the bolt. The bolt is most likely to fail at the critical section. The critical cross section is the section having the minimum cross sectional area.

The portion of the bolt having threads has the minimum cross sectional area.

So when the bolt is applied with a tensile force, failure is most likely to take place at the threads due to the shearing force.

Answer:

[tex]GM<0[/tex]

So the bouy does not float with its axis vertical

Explanation:

From the question we are told that:

Diameter [tex]d=2m[/tex]

Length [tex]l=2.5m[/tex]

Weight [tex]W=22kN[/tex]

Specific weight of sea water [tex]\mu= 10.25kN/m^3[/tex]

Generally the equation for weight of cylinder is mathematically given by

Weight of cylinder = buoyancy Force

[tex]W=(pwg)Vd[/tex]

Where

[tex]V_d=\pi/4(d)^2y[/tex]

Therefore

[tex]22*10^3=10.25*10^3 *\pi/4(2)^2y\\\\\22*10^3=32201.3247y\\\\\y=1.5m[/tex]

Therefore

Center of Bouyance B

[tex]B=\frac{y}{2}=0.26m\\\\B=0.75[/tex]

Center of Gravity

[tex]G=\frac{I.B}{2}=2.6m[/tex]

Generally the equation for\BM is mathematically given by

[tex]BM=\frac{I}{vd}\\\\BM=\frac{3.142/64*2^4}{3.142/4*2^2*0.5215}\\\\BM=0.479m\\\\[/tex]

Therefore

[tex]BG=2.6-0.476\\\\BG=0.64m[/tex]

Therefore

[tex]GM=BM-BG\\\\GM=0.479m-0.64m\\\\GM=-0.161m\\\\[/tex]

Therefore

[tex]GM<0[/tex]

So the bouy does not float with its axis vertical

Answer:

volumetric flow rate = [tex]0.0251 m^3/s[/tex]

Velocity in pipe section 1 = [tex]6.513m/s[/tex]

velocity in pipe section 2 = 12.79 m/s

Explanation:

We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.

The density of water is = 997 kg/m³

density = mass/ volume

since we are given the mass, therefore, the  volume will be mass/density

25/997 = [tex]0.0251 m^3/s[/tex]

volumetric flow rate = [tex]0.0251 m^3/s[/tex]

Average velocity calculations:

Pipe section A:

cross-sectional area =

[tex]\pi \times d^2\\=\pi \times 0.07^2 = 3.85\times10^{-3}m^2[/tex]

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

[tex]velocity = 25/(997 \times 3.85\times10^{-3}) = 6.513m/s[/tex]

Pipe section B:

cross-sectional area =

[tex]\pi \times d^2\\=\pi \times 0.05^2= 1.96\times10^{-3}m^2[/tex]

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

[tex]velocity = 25/(997 \times 1.96\times10^{-3}) = 12.79m/s[/tex]

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Explanation:

mitski

Answer:

The generator delivers current of 500.11 A

Explanation:

Given the data in the question;

mechanical energy delivered to the generator = 1500 hp

efficiency η = 80.0 %

terminal potential difference of the generator = 1790 V

we know that;

1 hp = 746 W

so

the mechanical energy delivered to the generator will be

Generator Input = ( 1500 × 746 )W = 1119000 W

So the generator output will be;

Generator Output = Generator Input × η

we substitute

Generator Output = 1119000 W × 80.0 %

Generator Output = 1119000 W × 0.8

Generator Output = 895200 W

So the Current will be;

[tex]I[/tex] = Generator Output / terminal potential difference of the generator

we substitute

[tex]I[/tex] =  895200 W / 1790 V

[tex]I[/tex] =  500.11 A

Therefore, The generator delivers current of 500.11 A

Answer:

isn't it summer? sjsushsiansudndd

Answer:

Both

Explanation:

Because of water, fuel does not burn completely. This brings about water fumes that are white in color and looks like white smoke. If engine is cold and water is heating, it leads to steam formation like water vapor. The white times are because of not firing properly in the heated engine. Technician A is right.

Blue fine is caused by this scoring. It is also caused by dirty oil. Technician b is right too

Answer:

The maximum length of a surface flaw that is possible without fracture is

[tex]2.806 \times 10^{-4} m[/tex]

Explanation:

The given values are,

σ=1.65 MPa

γs=0.60 J/m2

E= 2.0 GPa

The maximum possible length is calculated as:

[tex]\begin{gathered}a=\frac{2 E \gamma_{s}}{\pi \sigma^{2}}=\frac{(2)\left(2 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}\right)(0.60 \mathrm{~N} / \mathrm{m})}{\pi\left(1.65\times 10^{6} \mathrm{~N} / \mathrm{m}^{2}\right)^{2}} \\=2.806 \times 10^{-4} \mathrm{~m}\end{gathered}[/tex]

The maximum length of a surface flaw that is possible without fracture is

[tex]2.806 \times 10^{-4} m[/tex]

Answer:

The International Building Code (IBC) is a model code that provides minimum requirements to safeguard the public health, safety and general welfare of the occupants of new and existing buildings and structures.

Explanation:

Answer:

The answer is "22.501,-22.899"

Explanation:

Just as in the previous problems find the angle the velocity makes with the  x-axis and radius of curvature.

[tex]x= 2t^2 + 3t — 1\\\\y=5t-2\\\\x=4t+3\\\\y=5\\\\\tan \alpha (t = 1) =\frac{y}{x}=\frac{5}{4+3}=\frac{5}{7} \to alpha=35.54^{\circ}\\\\[/tex]

For the radius of curvature, we can use the expression from the last two  problems, but first express the position and derivatives as y(x).

[tex]y(x)=2(\frac{y+2}{5})^2+3(\frac{y+2}{5})-1=\frac{1}{25}(2y^2+23y+13)\\\\y'(x)=\frac{1}{25}(4y+23)\\\\y''(x)=\frac{4}{25}\\\\\rho(t=1)=\frac{[1+(\frac{dy}{dx})^2]^{\frac{3}{2}}}{\frac{d^2y}{dx^2}}=\frac{(1+(\frac{35}{25})^2)^{\frac{3}{2}}}{4}25=31.828[/tex]

The position for the center of the radius of curvature [tex]\vec{r}[/tex], (finding this expression is easy and is left as an exercise for the reader.)

[tex]\to \vec{r} = \hat{x}(x + \rho \sin \alpha) + \hat{y}(y- \rho \cos \alpha)\\\\= (4 + 18.501, 3-25.899)\\\\=(22.501, -22.899)[/tex]

Answer:

Rock and orange juice

Explanation:

The mystery matter to be submerged in water must be a solid, therefore we can eliminate the Lemonade and Milk, and Orange juice and Helium, as these pairs do not contain solids. The graduated cylinder is used to measure the volume of a liquid, therefore the only remaining option is Rock and Orange Juice.

Answer:

16Gpa < 30 Gpa

there would be no fracture

Explanation:

fracture can occur if the maximum strength at the top of the biggest flaw is more than the theoretical fracture

to get the theoretical strength =

e/10 = 300/10

= 30 Gpa

we get the magnitude at the buggest flaw

= 2σ√a/ρt

σ = 800

ρτ = 0.0015

a= 0.3/2

[tex]=2*800\sqrt{\frac{\frac{0.3}{2} }{0.0015} }[/tex]

= [tex]=2*800*\sqrt{100} \\=2*800*10\\=16000MPa[/tex]

= 16Gpa < 30 Gpa

the fracture is not going to happen given that the maximum strenght is smaller than the theoretical fracture strength.

Answer:

26.02 ft

86.7690 ft/min

Explanation:

After 3 steps

0.75³(2.0 thickness)

T = 0.84375

W = (1+0.03)³10

= 10.92727 inches

A To get length

2.0 x 10 x 12 x12 = 0.84375 x 10.92727x lf

= 2880 = 9.21988Lf

Lf = 2880/9.21988

= 312.368 inches

Convert to feet

322.368 x 0.0833

= 26.02 ft

B.

= 2 x 10 x 40 = 0.84375 x 10.92727 x vf

800 = 9.21988vf

Vf = 800/9.21988

Vf = 86.7690 ft/min