Answer:
if not sure sorry hope someone helps u❤️
The strength of the electric field 0. 5 m from a 6 µC charge is _______ N/C. (Use k = 8. 99 × 109 N•meters squared per Coulomb squared and round answer to the nearest whole number. ) 215760 539400 697976 512356.
The strength of the electric field at a distance of 0.5 m from a 6 μC punctual charge is 143,840 N/C.
We want to calculate the strength of the electric field 0.5 m (r) from a 6 μC charge (Q).
What is the electric field?The electric field (E) is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.
We can calculate the electric field at some distance from a punctual charge using the following formula.
E = (k × Q) / r²
E = [(8.99 × 10⁹ N.m².C²) × (4 × 10⁻⁶ C)] / (0.5 m)² ≈ 143,840 N/C
where,
k is the Coulomb's law constant.The strength of the electric field at a distance of 0.5 m from a 6 μC punctual charge is 143,840 N/C.
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IT'S SCIENCE
Answer:
1. A and C are balanced forces as all the forces get cancelled by the opposite and equal force.
2. B and D as in B the Net force is 5N to the right and in D the Net force is 20N to the right.
3. This would be all the unbalance forces which are B and D
4. B would be moving 5N to the right and D would move 20N to the right.
write two example in which chemical energy is converted into heat energy
Answer:
batteries in an electric heater, a nuclear power plant
Explanation:
sorry if it wrong g
Which key phrase below would imply that an object has no (0) initial velocity?
1) smoothly
2) in motion
3) backwards
4) from rest
5) uniformly
I assume number 4.
The key phrase which describes zero (0) initial velocity is from rest.
When the velocity of an object at initial time is zero (0), it implies that the change in the displacement of the object with time is zero
[tex]v= \frac{\Delta x}{\Delta t} \\\\v_0 = 0[/tex]
Generally, when an starts its motion from rest, the initial velocity of the object will be zero. As the object acquires more momentum, the velocity increases with time.
Thus, we can conclude that the key phrase which describes zero (0) initial velocity is from rest.
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A 12 volt car battery produces more current than a 1.5 volt battery for a TV remote because
A. The TV remote has a greater difference in electric potential energy
B. The car battery has more kinetic energy
C. The TV remote has more kinetic energy
D. The car battery has a greater difference in electric potential energy
A 12 volt car battery will produces more current than a 1.5 volt battery for a TV remote because the car battery has a greater difference in electric potential energy than a 1.5 Volt battery. The correct answer is D
The potential difference between any two point in a circuit is the work done when one coulomb of charge moves from one point to the other. Potential difference is a kind of electrical pressure difference between two point.
The difference in electric potential in a 12 Volt battery is greater than the difference in electric potential in a 1.5 Volt battery.
According to Ohm's law, Voltage supplied is proportional to current produced. That is, V = lR. Where R = resistance.
A 12 volt car battery will produces more current than a 1.5 volt battery for a TV remote because the car battery has a greater difference in electric potential energy than a 1.5 Volt battery.
Therefore, the correct answer is the option D
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how is pure salt obtained from the sea water ?describe in brief
Answer:
Evaporation
Explanation:
Evaporation
Answer:
Salt from sea water is obtained by the process of evaporation. ... The sea water evaporates due to the sun's heat and solid salt is left behind. The left salt is collected and refined to get purified salt. Hence, salt is obtained from sea water by evaporation.
What does a larger interquartile range mean.
Taking Earth to be a perfect sphere, find the linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation. The 32nd parallel north is a circle of latitude that is 32 degrees north of the Earth's equatorial plane. Take the Earth's radius to be 6,371,000 m
The linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s
We find the linear speed of a point on the 32nd parallel from v = rω where r = radius of 32nd parallel north = Rcos32° (since it is the radius of the small circle at the 32nd parallel) where R = radius of earth = 6,371,000 m and ω = angular speed of the earth = 2π/T where T = period of earth = 24h = 24 × 60 × 60 s = 86400 s.
So, v = rω
v = Rcos32° × 2π/T
v = 2πRcos32°/T
substituting the values of the variables into the equation, we have
v = 2πRcos32°/T
v = 2π × 6,371,000 m × cos32°/86400 s.
v = 2π × 6,371,000 m × 0.8480/86400 s.
v = 33947512.5035 m/86400 s
v = 392.91 m/s
So, the linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s
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In which scenario below does the ball have more gravitational potential energy when sitting at the top. Why?
The B figure has got more gravitational potential energy because gravity can draw it up straight rather than in a fashion (A) that would leave it with less room to travel.
What is Gravitational Potential Energy?The work (energy exchanged) per mass that would be required to transport an object to a point from a set reference location is the gravitational attraction at that location. It mimics the electric potential, with mass acting as the charge. There is a negative potential at any finite distance because the benchmark location, where the potential is zero, is conventionally indefinitely far from any mass.
The subject of potential theory is based on the gravitational potential, sometimes referred to as the Newtonian potential in mathematics. The electrostatic and popular throughout the world fields produced by ellipsoidal bodies that are uniformly charged or polarized can also be resolved using this method.
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The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at 3. The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at atmospheric pressure, would have to be admitted into the space to cause the column of the mercury
to drop to 59 cm?
The ideal gas equation and the pressure in barometer allows us to find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:
The variation of the volume is: ΔV = 7.67 cm³
Pressure is defined by the relationship between force and area.
P = F / A
The ideal gas equation establishes a relationship between pressure, volume, and temperature of an ideal gas.
PV = nR T
Where P is pressure, V is volume, and T is temperature.
Let's write this equation for two points assuming that the temperature has not changed.
P₀ V₀ = P₁ V₁
V₁ = [tex]\frac{P_o}{P_1} \ V_o[/tex] (1)
The subscript "o" is used for the start point and the subscript "1" for the end point.
The pressure in a barometer is:
P = ρ g y
They indicate the initial height of the barometer y₀=75 cm, the distance from empty space y'₀ = 9 cm and the final height of the barometer y₁ = 59 cm.
The volume of the cylinder is
V = π r² y
Let's calculate the initial volume.
V₀ = π 1 9
V₀ = 28.27 cm³
We substitute in equation 1.
V₁ = [tex]\frac{\rho \ g \ y_o}{\rho \ g \ y_1} \ V_o[/tex]
V₁ = [tex]\frac{y_o}{y_1} \ V_o[/tex]
Let's calculate.
V₁ = [tex]\frac{75}{59} \ 27.27[/tex]
V₁ = 35.94 cm³
The volume to be incremented is
ΔV = V₁ - V₀
ΔV = 35.94 - 28.27
ΔV = 7.67 cm³
Using the ideal gas equation and the pressure in barometer we can find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:
The change of the volume is: ΔV = 7.67 cm³
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If Corolla does 1,800,000 Joules of work in a 400 meter race, how much average force was applied through that distance?
Answer:
4500 NExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
To find the force applied we make force the subject in the formula above
That's
[tex]f = \frac{w}{d} \\ [/tex]
w is the workdone
d is the distance
From the question we have
[tex]f = \frac{1800000}{400} = \frac{18000}{4} = 4500\\ [/tex]
We have the final answer as
4500 NHope this helps you
HELP
How much heat energy is required to raise the temperature of 37.5g of water from 23.0°C to 55.2°C? The specific heat for water is 4.184 J/g°C. (Include your calculation to receive credit.)
Answer: 5.05 J
Explanation:
Qcalorimeter: m*c* ΔT --> (37.5g)*(4.184J/g ° C)*(55.2 °C – 23.0 °C) Qcalorimeter: 5.05 J
According to specific heat capacity, 5.052 kJ of heat energy is required to raise the temperature of 37.5 g of water from 23.0°C to 55.2°C.
What is specific heat capacity?Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.
It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.
It is given by the formula ,
Q=mcΔT
Substitution in above formula, givesQ= 37.5×4.184×32.2=5052.18 J or 5.052 kJ.
Thus , 5.052 kJ of heat energy is required to raise the temperature of 37.5g of water from 23.0°C to 55.2°C.
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What type of energy transfer causes a sunburn?
Radiation, because particles of hot air move in space
Radiation, because electromagnetic waves transfer heat
Conduction, because hot air comes in contact with the skin
Conduction, because invisible light carries heat from the sun
Pacificaly what is the right answer A? B? C? or D? which one
Answer:
radiation
Explanation:
Answer:
B is most likely forgive me if im wrong
Explanation:
why do we believe 90 percent of the mass of the milky way is in the form of dark matter?
Answer:
The orbital speeds of stars far from the galactic center are surprisingly high, suggesting that these stars are feeling gravitational effects from unseen matter in the halo.
Physics Physics Physics - 10
Answer:Pulley , Wheel and axle , Screw , wedge , Incline
Explanation:
Answer: below .
Explanation:
Pulley , Wheel , axle , Screw , wedge , Incline
HOPE IT HELPS YOU .PLEASE GIVE BRAINLIEST .THANKS .
A bullet of mass 6.00 gg is fired horizontally into a wooden block of mass 1.20 kgkg resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.190. The bullet remains embedded in the block, which is observed to slide a distance 0.270 mm along the surface before stopping.
(a) What was teh initial speed of the bullet?(b) What kind of collision took place between the bullet and the block? Explain your answer comparing the values of the kinetic energy before and after the collision.(c) Calculate the impulse of the block from the moment just after the impact to his final position. Analyze the result.
Answer:
A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.230 m along the surface before stopping.
Explanation:
In what part of the electromagnetic spectrum do the biggest telescopes on earth operate?.
Explanation:
Notice it says above that the largest optical telescopes in the world are reflectors. Optical telescopes collect visible light. Even larger telescopes are built to collect light at longer wavelengths radio waves.
How does water temperature affect density?
2. What are the challenges of wind energy that causes decrease in the electrical production?
3. Give two solutions:
1. Modification in the structure of the turbine
2. Modification in the function of the turbine.
4. You must estimate the cost in each solution, and which one is more affordable and efficient for the municipality to go for.
5. You must make sure that there is minimal energy loss.
Levelized production cost is a big challenge in the production of wind energy.
The main challenge in the production of wind energy is the high production cost. It has to minimize the Levelized Production Cost (LPC) which is the ratio between energy production cost and economic lifetime. This problem can be solved by doing modification in the structure of the turbine as well as we must ensure minimal energy loss.
The modification in the structure can produce more electrical energy and reduce the energy loss also provides more profit to the company so we can conclude that levelized production cost is a big challenge in the production of wind energy.
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a race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this time
find distance and acceleration
FAST PLEASE !!
Answer:
-1.2×10^2 m
I hope this helps you
what is heliocentric?
Answer:
having or representing the sun as the centre, as in the accepted astronomical model of the solar system.
Explanation:
Heliocentrism is the astronomical model in which the Earth and planets revolve around the Sun at the center of the Universe. Historically, heliocentrism was opposed to geocentrism, which placed the Earth at the center.
In motion pictures, what do you call the lens manipulation where the focus quickly changes from one subject to the next in a motion picture
Answer:
A film transition is a technique used in the post-production process of film editing and video editing by which scenes or shots are combined. Most commonly this is through a normal cut to the next shot. Most films will also include selective use of other transitions, usually to convey a tone or mood, suggest the passage of time, or separate parts of the story. These other transitions may include dissolves, L cuts, fades (usually to black), match cuts, and wipes.
Explanation:
Describe at least two similarities between untraviolet rays and microwaves
A feather drops in a vacuum. What is the feather's final velocity if it falls for 3.48s?
A. -34.1 m/s
B. 59.3 m/s
C. -59.3 m/s
D. 34.1 m/s
Answer:
34.104
Explanation:
the time * acceleration = final velocity.
so 3.48s * 9.8m/s (gravity) = 34.1 m/s
Can Hotspots can be found at the edges of tectonic plates?
Answer:
No.
Explanation:
Hot spots don't appear at the barriers of tectonic plates, instead, they originate at hot centres known as mantle plumes. Mantle plumes exist below the tectonic plates and may develop a string of volcanoes on the Earths surface.
A new tube is used each time a blood sample is tested.Explain why valid results are only obtained if each tube is identical
Valid results are only obtained if each tube is identical because; effective comparison of the tested blood each time can only be achieved if the testing model is constant in which case each tube is identical.
Discussion:
During scientific tests such as that described in the question; it is important to keep all parameters of testing constant.
This is so because, the utmost motive of the testing model is to draw comparison. It is on this note that valid results are only obtained if each tube is identical.
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Omar rubs a balloon with wool, giving the balloon a
charge of -8.9x10-14 C. What is the force between
the balloon and a metal sphere that is charged to
25 C and is 2 km away?
Answer:
-8.9×10-14=-89-14=-103°C
25°C=2km
-103°C=? Less
=-103/25×2km
=-8.24km
A 1300-kg car is traveling with a speed of 16.0 m/s. What is the magnitude of the horizontal net force that is required to bring the car to a halt in a distance of 38.9 m?
Answer:
F=ma,a=0.329m/second squared,m=1300kg,F=1300*0.329=4277N
A 50-kg girl lifts a 1-kg box vertically upward a distance of 0.5 meter. How
much work is done on the box?
Answer:
Given mass = 2kg, height = 10m,g = 9.8.
We know that Work done W = FD
= > W = (mg)(D)
= > W = (2 * 9.8)(10)
= > W = 196 Joules.
Explanation:
Yan :).
The launch speed of a projectile is three times the speed it has at its maximum height.what is the elevation angle at launch?
Answer:
Given: a projectile of initial launch velocity(V) and launch angle ∅ and no air resistance. At the maximum height, the projectile would have a zero contribution of speed from the vertical component(Vy) Therefore, if we say Vx=Vcos∅ is the only speed the projectile has at the instant of maximum height then we can replace Vx with 1/5V and write 1/5V=Vcos∅. Solving for the the launch angle ∅, gives Inverse Cos(1/5)=78.5 degrees.