What is the length of Line segment H A? 7 units 8 units 24 units 48 units

Answer:

5.291 * 10^4

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Answer:

40 m

Step-by-step explanation:

158 · 2.54 = 401.32

401.32/100 = 40.132

40.132 ≈ 40

Answer:

[tex]95 - \frac{3}{4} [/tex]

[tex] = \frac{95}{1} - \frac{3}{4} [/tex]

[tex] = \frac{380}{4} - \frac{3}{4} [/tex]

[tex] = \frac{380 - 3}{4} [/tex]

[tex] = \frac{377}{4} [/tex]

[tex] = 376\frac{1}{4} [/tex]

Answer:

d=23.43

Step-by-step explanation:

Given data

A(-6,8)

X1=-6

Y1=8

B(12, - 7)

X2=12

Y2=-7

The expression for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²

Substitute

d=√((12+6)²+(-7-8)²

d=√((18)²+(-15)²

d=√324+225

d=√549

d=23.43

I assume you meant to say "a differentiable function f has the values ..." and not g.

Since f is differentiable, the mean value theorem holds, so you can approximate

f ' (2.5) ≈ (f (2.6) - f (2.4)) / (2.6 - 2.4) = (24 - 18) / (0.2) = 30

Answer:

[tex]116^o[/tex]

Step-by-step explanation:

All triangles equal [tex]180^o[/tex]. Therefore, in order to find the value of [tex]x^o[/tex], all you will have to do is subtract [tex]64^o[/tex] from [tex]180^o[/tex].

[tex]180^o-64^o=116^o[/tex]

[tex]x^o=116^o[/tex]

Answer:

The answer is below

Step-by-step explanation:

Similar triangle are triangles with the same shape, equal pair of corresponding angles. Also they have the same ratio of the corresponding sides.

From the diagram attached, we can see that triangle ABC and triangle CEF are similar triangles. Hence:

AB/BC = CF/EF

Given that BC = 1 km = 1000 m, CF = 2 m - 1.5 m = 0.5 m, EF = 2.5 m.

Hence:

AB/1000 = 0.5/2.5

AB = (0.5/2.5) * 1000 = 200 m

The height of the building = AB + height of Steve = 200 m + 2 m

The height of the building = 202 m

Answer:

False

Step-by-step explanation:

If you see closely, Angle 3 is slightly smaller than Angle 6''

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

1003.4375

Step-by-step explanation:

16055/16 is 1003.4375

I assume that the equation you mean is below:

[tex] \large \boxed{w + \frac{ {w}^{2} }{3} = 0}[/tex]

To find roots for this equation, we have to get rid of the denominator. We can do by multiplying both sides by 3.

[tex] \large{w(3) + \frac{ {w}^{2} }{3} (3) = 0(3)} \\ \large{3w + {w}^{2} = 0}[/tex]

Factor w-term out (common factor)

[tex] \large{w(3 + w) = 0} \\ \large{w = 0 \: \: \: or \: \: \: 3 + w = 0} \\ \large{w = 0, - 3}[/tex]

Answer

Answer:

I'll setup the problem and you can compute the answer

Step-by-step explanation:

The formula for simple:

I = P*r*t

I = interest

P = loan amount

r = interest rate per period (period = days)

n = number of periods

P = 10,170

r = .0764/365

t = 272

Answer:

0.75 points per minute

Step-by-step explanation:

9/12 is 0.75

Answer:

does not have a solution because √-0.75 ≠ R

Step-by-step explanation:

x^2 - 5x + (5/2)^2 = -7

x^2 - 5x + 6.25 = -7 + 6.25

(x - 2.5)^2 = -0.75

(x - 2.5) = √-0.75

does not have a solution because √-0.75 ≠ R

Answer:

x = (1/2)(5 ± i√3)

Step-by-step explanation:

x² - 5x + 7 = 0

subtract 7 from both sides

x² - 5x = -7

Use half the x coefficent, -5/2, as the complete the square term

(x - 5/2)² = -7 + (-5/2)²

(x - 5/2)² = -7 + 25/4

(x - 5/2)² = -3/4

Take the square root of both sides

x - 5/2 = ±(√-3) / 2

x - 5/2 = ±(i√3) / 2

Add 5/2 to both sides

x = 5/2 ± (i√3) / 2

factor out 1/2

x = (1/2)(5 ± i√3)

Answer:

120 [tex]{ft}^{3}[/tex]

Step-by-step explanation:

To find the volume of a rectangular prism, multiply the lengths of all of the sides

3 x 5 x 8 = Ans --> 3 x 40 = Ans -->120 = Ans

Therefore, the volume of the rectangular prism is 120 [tex]{ft}^{3}[/tex]

Answer:

Step-by-step explanation:

a= 2qr^3 quotent 6p^2

Answer:

Approximately 46.29 feet

Step-by-step explanation:

Answer:

The answer would be E, the tire makes 700 revolutions in 2 minutes.

Step-by-step explanation:

One revolution is equal to the circumference of the tire :

[tex]C = 2\pi r = 2(1)(\frac{22}{7} ) = \frac{44}{7}[/tex]

The car travels at 2,200 feet per minute. To calculate the number of revolutions, divide the speed by the circumference.

[tex]2,200[/tex] ÷ [tex]\frac{44}{7}[/tex] = 350

This means that in 1 minute the tire makes 350 revolutions. To find out how many revolutions the tire would make for 2 minutes you simply multiply by 2.

350*2 = 700

So the answer would be E, the tire makes 700 revolutions in 2 minutes. Hope this helps, please mark brainliest!

I.)

1.) 7N = 50

2.) 35 - 16 = N

3.) 2P + 8 = 24

4.) R/5 = 9

5.) 30 - 10 = 20

II.)

1.) Twinity increased by eight times N

2.) D decreased by eleven

3.) The quotient of X and nine is K

4.) Five times X

5.) Three times a decreased by 5 is thirteen

6.) Nothing

7N = 50

35 - 16 = N

2P + 8 = 24

R/5 = 9

30 - 10 = 20

Twenty increased by eight times N

D decreased by eleven

The quotient of X and nine is K

Five times X

Three times a decreased by 5 is thirteen

Answer:

Terry has 1500 sweets.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the number of sweets Terry has.

y is the number of sweets Alex has.

If Terry gives 30% of his sweets to Alex,they will have the same number of sweets.

This means that:

[tex](1 - 0.3)x = y + 0.3x[/tex]

[tex]0.7x = y + 0.3x[/tex]

[tex]y = 0.4x[/tex]

If Terry gives 750 of his sweets to Alex,then Alex will have 80% more sweets than Terry.

This means that:

[tex]y + 750 = 1.8(x-750)[/tex]

We want to find x, and since [tex]y = 0.4x[/tex]

[tex]y + 750 = 1.8x - 1350[/tex]

[tex]0.4x + 750 = 1.8x - 1350[/tex]

[tex]1.4x = 2100[/tex]

[tex]x = \frac{2100}{1.4}[/tex]

[tex]x = 1500[/tex]

Terry has 1500 sweets.

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines :  y = √x, y = 2, x = 0.

a) The x-axis

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) [tex]\int\limits^2_0 {ph} \, dy[/tex]

     = [tex]( 2\pi ) \int\limits^2_0 {y.y^2} \, dy[/tex]  

∴ Vol = 8π

b) The line y = 2  ( using the shell method )

p = 2 - y

h = y^2

vol = ( 2π ) [tex]\int\limits^2_0 {ph} \, dy[/tex]

     = [tex]( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy[/tex]

     = ( 2π ) * [ 2/3 * y^3  - y^4 / 4 ] ²₀

∴ Vol  = 8/3 π

c) The y-axis  ( using shell method )

h = 2-y  = h = 2 - √x

p = x

vol = [tex](2\pi ) \int\limits^4_0 {ph} \, dx[/tex]

     = [tex](2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx[/tex]

     = ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

d) The line x = -1    (using shell method )

p = 1 + x

h = 2√x

vol = [tex](2\pi ) \int\limits^4_0 {ph} \, dx[/tex]

Hence   vol = 176/15 π

attached below is the graphical representation of P and h

Answer:

18.28 m

Step-by-step explanation:

Given the flower garden in the question :

The shape is composite and can be divided into 2 semicirles and rectangle

The perimeter of a semicircle is the Circumference of the semicircle = πr

Hence, 2 semicirles = 2πr

Radius of semicircle = 2/2 = 1

Perimeter = 2 * 3.14 * 1² = 2 * 3.14 * 1 = 6.28 m

The perimeter of rectangle; length and width are 6m and 2 m respectively :

Perimeter of rectangle = 2(l + w) = 2(4+2) = 2(6) = 12m

Tve perimeter of garden = 6.28 + 12 = 18.28 m

Answer:

5 hour and 25 mins

Step-by-step explanation:

Answer:

[tex]h = 7.69cm[/tex]

Step-by-step explanation:

Given

[tex]Volume = 455cm^3[/tex]

[tex]l = h[/tex]

Where:

[tex]h \to height[/tex]

[tex]l \to base\ length[/tex]

Required

The height

The volume is calculated as:

[tex]Volume = l^2 * h[/tex]

This gives:

[tex]Volume = h^2 * h[/tex]

[tex]Volume = h^3[/tex]

Rewrite as:

[tex]h^3 =Volume[/tex]

So, we have:

[tex]h^3 = 455cm^3[/tex]

Take cube roots

[tex]h = \sqrt[3]{455cm^3}[/tex]

[tex]h = 7.69cm[/tex] --- approximated

Answer:

The desired data-set is: {12,12,12,12,12,12,12}

Step-by-step explanation:

n = 7

Data set of 7 elements.

x = 12

Mean of 12

S = 0

Standard deviation of 0.

Desired data-set:

Since the desired standard deviation is 0, all the elements in the data-set will be the same. Since the mean is 12, all elements is 12. 7 elements.

The desired data-set is: {12,12,12,12,12,12,12}