What is the difference between centrifugal force and centripetal force???

Answer:

Boiling water - The heat passes from the burner into the pot, heating the water at the bottom. Then, this hot water rises and cooler water moves down to replace it, causing a circular motion. Radiator - Puts warm air out at the top and draws in cooler air at the bottom.

Answer:

The astronauts will simply have to fire the rocket engines again to keep moving. The spacecraft will keep coasting at the same speed and in the same direction. The spacecraft will slow down until it comes to a complete stop. ... Its speed will be constant except for very slow changes that are part of its orbital motion.

Explanation:

Answer:

In MeV: 10.674 × 10^(34) MeV

In TeV: 10.674 × 10^(28) TeV

Explanation:

We are given that;

1.78 × 10^(-36) kg = 1 eV

We are now told that the blue whale has an average mass of 1.90 × 10^(5) kg

Thus, converting this mass of the blue whale to eV, we have;

(1.90 × 10^(5) × 1)/(1.78 × 10^(-36)) = 10.674 × 10^(40) eV

Now, converting to mega electron volts;

From conversions;

1 eV = 10^(-6) MeV

Thus,

10.674 × 10^(40) eV will be;

(10.674 × 10^(40) × 10^(-6))/1 = 10.674 × 10^(34) MeV

Also, converting to Tera electron Volts;

From conversion, we know that;

1 eV = 10^(-12) TeV

Thus;

10.674 × 10^(40) eV will give;

(10.674 × 10^(40) × 10^(-12))/1 = 10.674 × 10^(28) TeV

Answer:

a. DNA storage

Explanation:

Answer:

20.7 cm³

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 20 cm³

Initial temperature (T1) = 5 °C

Initial pressure (P1) = 760 mm Hg

Final temperature (T2) = 30 °C

Final pressure (P2) = 800 mm Hg

Final volume (V2) =?

Next we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

Temperature (K) = Temperature (°C) + 273

Initial temperature (T1) = 5 °C

Initial temperature (T1) = 5 °C + 273 = 278 K.

Final temperature (T2) = 30 °C

Final temperature (T2) = 30 °C + 273 = 303 K.

Finally, we shall determine the new volume of the gas as follow:

Initial volume (V1) = 20 cm³

Initial temperature (T1) = 278 K

Initial pressure (P1) = 760 mm Hg

Final temperature (T2) = 303 K

Final pressure (P2) = 800 mm Hg

Final volume (V2) =?

P1V1/T1 = P2V2/T2

760 × 20 /278 = 800 × V2/303

Cross multiply

278 × 800 × V2 = 760 × 20 × 303

Divide both side by 278 × 800

V2 = (760 × 20 × 303) / (278 × 800)

V2 = 20.7 cm³

Therefore, the new volume of the gas is 20.7 cm³

Explanation:

Assume that the rock has a constant density,

then the density = volume/mass = 0.25g/cm^3.

Answer:

4 g/cm^3

Explanation:

Density can be found by dividing the mass by the volume.

d=m/v

We know that the mass of the rock is 24 gram. We also know the volume of the rock is 6 cubic centimeters.

m=24 g

v= 6 cm^3

Substitute the values into the formula and divide.

d= 24 g / 6 cm^3

d= 4 g/cm^3

The density of the rock is 4 grams per cubic centimeter.

copper wire is the example of superconductor

Answer:

Take the numbers and fill them in graph.

Plot time as X and speed as Y and afterward join then like a line graph.

Explanation:

Given that,

The x-component is 8 m/s east and y-component is 14.5 m/s North.

(a) As both x and y components are perpendicular to each other. Their resultant is given by :

[tex]R=\sqrt{x^2+y^2} \\\\R=\sqrt{(8)^2+(14.5)^2} \\\\R=16.56\ m/s[/tex]

(b) Let [tex]\theta[/tex] is the resultant vector. So,

[tex]\tan\theta=\dfrac{y}{x}\\\\\theta=\tan^{-1}(\dfrac{y}{x})\\\\\theta=\tan^{-1}(\dfrac{14.5}{8})\\\\\theta=61.11^{\circ}[/tex]

Hence, the resultant is 16.56 m/s and the angle of the resultant vector is 61.11 degrees.

Answer:

2m 4m2Explanation:rteji3ujnrej

1. .134

2. 22.34

3. 330

4. 4350

Answer:

The train stopped for 3 seconds.

Explanation:

D on edge

My answer to the question is Velocity.

Answer:

Explanation:

In this problem, we are going to solve for the average speed and average velocity for the entrire trip made by the dolphin.

Given data

speed v= 2 m/s

time t= 24s

the distance travelled by the dolphin is

speed= distance/time

distance= speed*time

distance= 2*24

distance= 48m

now the dolpine made a reverse and covered this 48m in 8s to return to it initial position

the speed it took is

speed= distance/time

speed= 48/8

speed= 6m/s

It average speed is the total distance divided by the total time taken

average speed= (48+48)/(24+8)= 96/32= 3m/s

average speed= 3 m/s

it average velocity is the sum of the initial and final velocity is divided by 2 to find the average

(2+6)/2= 8/2= 4m/s

average velocity is 4m/s

Answer:

180

Explanation:

4m/s x 45s=180m

Answer:

very complex

Explanation:

The answer is D very complex

Answer:

E = 27 J

Explanation:

It is given that,

Mass of a kitten is 1.5 kg

Initially, it was at a height of 1.8 m refrigerator and finally jumps to a 0.9 m height counter.

We need to find the kitten's gravitational  potential energy on top of the counter. Potential energy is possessed due to the position of an object. It can be given by :

[tex]E=mgh[/tex]

g is acceleration due to gravity

[tex]E=1.5\ kg\times 10\ m/s^2\times 1.8\ m\\E=27\ J[/tex]

So, the kitten's gravitational  potential energy on top of the counter is 27 J.

The interest in a pile of free bricks on Craigslist varies based on the needs and preferences of individuals in the local area, and posting clear details about the quantity, condition, and pickup arrangements can attract potentially interested parties.

Craigslist is an online classified advertising platform where users can post and find a wide range of listings for various goods, services, housing, jobs, and more. It operates on a local level, allowing individuals to connect within their specific geographic regions.

Interest in a pile of bricks on Craigslist would depend on the specific needs and preferences of individuals in the local area. While some people may find value in acquiring free bricks for construction or DIY projects, others may not have any use for them. It is difficult to predict the level of interest without knowing the specific context, location, and local demand for such materials. Posting the offer on Craigslist and providing clear details about the quantity, condition, and pickup arrangements can help attract potentially interested parties.

Therefore, Interest in a free pile of bricks on Craigslist depends on local individuals' needs and preferences, and posting clear details can attract potentially interested parties.

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#SPJ6

Answer:

I'm in college and i'm a senior so i will graduate this year.

Explanation:

At this point in the story, Beasy has driven his car (2+6+4) = 12 km.

He is parked at the thrift store, (2+4) = 6 km East and 6 km North of his starting point.

As the crow flies, the thrift store is √(6km² + 6km²) in a straight line from the starting point.

That's √(72 km²) , which works out to 8.485 km .  When rounded to the nearest whole km, he can phone up his wife and tell her he's "eight kilometers from home can you hear me now ?".

Displacement is a vector, so to answer the question completely, we also need to state its direction.

The angle from home to the thrift store, relative to East, is arctan(6km/6km).

That's 45 degrees.  

The full displacement vector is 8.485 km Northeast.

From the question, Beasy drives 2km East and 6 km North. He then drives 4 km East of the first errand. An illustrative diagram is shown in the attachment below.

From the diagram S is the starting starting point, C is coffee shop and T is the thrift store.

The displacement of the car from the starting point is giving by /TS/ in the diagram. To calculate /TS/, consider the right-angled triangle TSQ, /TS/ is the hypotenuse.

From The Pythagorean theorem, in a right-angled triangle, the square of the longest side (hypotenuse) equals sum of the squares of the other two sides.

That is,

/TS/² = /SQ/² + /TQ/²

But /TQ/ = /CP/ = 6km

and /SQ/ = /SP/ + /PQ/

/SP/ = 2 km, /PQ/ = 4 km

∴ /SQ/ = 2 km + 4 km

/SQ/ = 6 km

Hence,

/TS/² = 6² + 6²

/TS/² = 36 + 36

/TS/² = 72

/TS/ = [tex]\sqrt{72}[/tex]

/TS/ = 8.485 km

/TS/ ≅ 8 km ( to the nearest km)

Hence, the displacement of the car from the starting point rounded to the nearest km is 8 km.

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Complete Question

A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.

Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.

Express your answer as two numbers separated by a comma. Be careful with your signs.

Answer:

The value is  [tex]dT  =  ( -0.3,  0.8)[/tex]

Explanation:

From the question we are told that

   The first displacement is  [tex]dN  =  0.900 \  due  \  North[/tex] i.e positive  y-axis

   The  second displacement is  [tex]dW =  0.300 \  miles  \  due \  west[/tex] i.e negative  x-axis

   The final displacement is  [tex]dS =  0.100 \  miles \ due \ south[/tex] i.e  negative  y-axis

Generally dW in component for is  

      [tex]dW =  (-0.3 ,  0)[/tex]  

Generally the  total displacement of the student is mathematically represented as

     [tex]dT  =  ( -0.3,  (0.90 - 0.10))[/tex]

      [tex]dT  =  ( -0.3,  0.8)[/tex]

Answer:

Explanation:

If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s,we ae to find the time taken for the ball to drop. To do that we will use the equation of motion v = u + gt

v is the final velocity = 30m/s

u is the initial velocity = 0m/s (the object drops from rest)

g is the acceleration due to gravity = 9.81m/s²

time is the time taken

Substituting the given parameters into the formula;

30 = 0 + (9.81)t

30 = 9.81t

t = 30/9.81

t = 3.06secs

Hence it will take the object 3.06secs in free fall

Answer:

Tension in the chains - In a chain drive, technically, you have a closed-chain (which has no end) going around 2 pulley or gears; looking closely you have 2 parallel chains going in opposite direction. If kept in horizontal direction, the one below the other is the slack side and the other the tight side. The tension on the upper or tight side is more than the slack side. So you need to keep in mind to keep your chain drive tight so that there is no loss or rotation or lags.

Sizes of the pulley/gear - The chain will be warped around a pair of pulley or gear. The sizes of these pulley/gear will also determine the efficiency of the chain drive (consider one big and one small)

Number of pulley/gear - If the number of pulley/gear is more and chain wrapped on it with little complexity will result in decrease in efficiency because of extra tension.

Length of the chain drive - You cannot have much too long chain drive. It will make your slack side more heavy because the end are further away. You have to apply more power and possibilities of lag increases decreasing efficiency. In an ideal situation, this won't happen, but this world isn't ideal.

Friction between chains & pulley/gear - If you have studied gears (involving its teeth), you will come to know that there is friction offered on the two meeting surfaces.

Angle of contact - This would have been explained better with a diagram. Although, if you are familiar with the terms you won't have difficulty understanding. Angle of contact is the angle the chain forms with the pulley/gear at the point of contact with the center of the pulley. The angle of contact should not be too small, or else the things will be slippery.

Explanation:

Answer:

f block on edge 2020

Explanation:

hope this helps:)

Answer:

The mass of a single paper  is approximately 0.047 lb/paper which in SI Units is approximately 21.77  g/paper

Explanation:

The given information on the size and the weight of paper are;

The mass of a box of 500 sheets of paper = 24 lb

The number of sheets in the paper = 500 sheets

The dimensions of the paper = 17 in. × 22 in., which is equivalent to  43.18 cm × 55.88 cm

The mass of a single paper = The mass of the box of paper/(The number of sheets of paper present in the box)

The mass of a single paper = 24 lb/500 = 0.047 lb/paper

Given that 1 lb = 453.6 g, we have;

0.047 lb/paper = 0.047 lb/paper×453.6 g/(lb) = 21.77  g/paper

The mass of a single paper  = 0.047 lb/paper = 21.77  g/paper.

Answer:

5.349g

Explanation:

The other post forgot about the differing answer. They wanted the answer for 21.59cm*27.94cm. when they get that 0.047=43.18cm*55.88cm we can set a ratio;

0.047/43.18*55.88=X/21.59*27.94=0.01179

then we do the same;

0.01179lb(453.6g/1lb)=5.349

(*the number is bigger but we have 4 sig figs*)

Answer:

13.069 g/cm^3

Explanation:

to get density, simply divide the mass by the volume. Your equation would look like this; p=562/43

'P' represents density in this equation. Never forget to add your units!

Hope this helps!

Answer: Because a compound is formed by at least two elements, and here we have only one.

Explanation:

A compound is defined as:

"A substance that is formed when two or more elements are chemical bonded together"

And in this case, we have two hydrogen atoms bonded together, so we have the bond, but there is only one element, and we need to have at least two elements to have a compound.

Two hydrogen atoms bonded together are not considered a compound.

A compound is formed when two are more different elements form a chemical bond with each other and make a substance.

For any substance to be categorized as a compound it is necessary that it contains at least two different elements.

A substance that is formed by the chemical combination or bonding of the atoms of the same element is not considered a compound.

In the given case we have two hydrogen atoms bonded together, which is very clear that the substance contains the atoms of the same element bonded together.

Therefore it can not be considered a compound.

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Answer:

the body has descended a height (4a)

Explanation:

This exercise should use the acceleration given in the graph, but unfortunately the graph is not loaded, but we can build it, using the law of universal gravitation and the fact that you indicate that the movement is near the surface of the planet

           F = m a

f

orce is gravitational force

           G M m / r² = m a

           a = G M / r²

where G is the universal constant of gravitation, M the mass planet and r the distance from the center of the planet of radius R to the body, if we measure the height of the body from the surface of the planet (y), we can write

           r = R + y

for which

           a = G M/R²     (1+ y/R)⁻²

if we use y«R we can expand the function in series

           a = (G M /R²)   (1 -2 y/R - 2 (-2-1) /2!   y² / R² +…)

as the height is small we can neglect the quadratic term and in many cases even the linear term, for this exercise we will remain only constant therefore the acceleration is constant

           a = G M / R²

from this moment we can use the relations of motion with constant acceleration for the exercise

a) they ask us for the position for t = 2s

            y = y₀ + v₀ t - a t²

as the body is released v₀ = 0

            y-y₀ = - a t²

            y-y₀ = - a 2²

             y-y₀ = - a 4

therefore  

therefore the body has descended a height (4a) where a is the acceleration of the planet's gravity