What is the answer to this problem?

What Is The Answer To This Problem?

Answers

Answer 1

Answer:

0.5 if rounded to the nearest tenth

Step-by-step explanation:

What Is The Answer To This Problem?

Related Questions

A space shuttle is made using a scale of 1 inch : 12 feet. If the actual space shuttle has a height of 84 feet, then the model is ____ inches tall.

Answers

Answer:

7 in.

Step-by-step explanation:

1 in - - > 12 ft

x in - - > 84 ft

----------------------

12*x=84 - - >x=7in

What type of data display is shown below?
Student Grades
60
69
99
82
92
60
70
HA
100
80
90
O A. Histogram
O B. Box-and-whisker plot
C. Stem-and-leaf plot
O D. Scatterplot

Answers

The answer would be stem and leaf plot

Answer:

B) Box-and-Whisker plot

please please please help


find the median

72 82 92 93 94 97 98 102


find the median

53 59 64 65 65 66 67 69

find the mean absolute deviation (MAD)

72
82
93
98
102
97
92
94

find the mean absolute deviation (MAD)

53 59 64 65 65 66 67 69

Answers

Answer:

median = 93.5

median = 65

MAD = 7.125

MAD = 3.75

Step-by-step explanation:

The median is the middle value when the values of the data set are placed in order from smallest to largest.

Data set:  72 82 92 93 94 97 98 102

As the number of values in the data set is even, the median is the mean of the middle two values.

[tex]\implies \sf median=\dfrac{93+94}{2}=93.5[/tex]

Data set: 53 59 64 65 65 66 67 69

As the number of values in the data set is even, the median is the mean of the middle two values.  

[tex]\implies \sf median=\dfrac{65+65}{2}=65[/tex]

To find the Mean Absolute Deviation (MAD):

1. calculate the mean (by summing the data values and dividing by the number of values)

2. Subtract the mean from each value in the data set and take the absolute value of each result.

3. Sum the absolute values from step 2.

4. Divide by the number of values.

Data set: 72, 82, 93, 98, 102, 97, 92, 94

[tex]\sf Mean=\dfrac{72+82+93+98+102+97+92+94}{8}=91.25[/tex]

|72 - 91.25| = 19.25

|82 - 91.25| = 9.25

|93 - 91.25| = 1.75

|98 - 91.25| = 6.75

|102 - 91.25| = 10.75

|97 - 91.25| = 5.75

|92 - 91.25| = 0.75

|94 - 91.25| = 2.75

Sum of absolute values = 57

[tex]\sf MAD=\dfrac{57}{8}=7.125[/tex]

Data set: 53 59 64 65 65 66 67 69

[tex]\sf Mean=\dfrac{53 +59+ 64+ 65+ 65+ 66+ 67+ 69}{8}=63.5[/tex]

|53 - 63.5| = 10.5

|59 - 63.5| = 4.5

|64 - 63.5| = 0.5

|65 - 63.5| = 1.5

|65 - 63.5| = 1.5

|66 - 63.5| = 2.5

|67 - 63.5| = 3.5

|69 - 63.5| = 5.5

Sum of absolute values = 30

[tex]\sf MAD=\dfrac{30}{8}=3.75[/tex]

Which is greater, (1/2)⁴² or (1/2)⁴⁵? Why?​

Answers

Answer:

1/2^42 because the 45 will be dividing it b half 3 more times

Step-by-step explanation:

What is my answer the missing numbers

Answers

The answers supposed to be

y = 2

I’m not entirely sure if it’s gonna work typing it in though

I need help with this ​

Answers

9514 1404 393

Answer:

x = 32y = 51

Step-by-step explanation:

Angle U = angle N = 180° -142° -24° = 14°

The expression for angle U tells us the value of x.

  2x -50 = 14

  x -25 = 7 . . . . . divide by 2

  x = 32 . . . . . . . .add 25

__

The measure of side SU is the same as that for side PN.

  13 = (2x -y)

  y = 2x -13 = 2(32) -13 . . . . solve for y, substitute for x

  y = 51

Find the measure of Angle I.

Answers

Answer:

I think 5?................

NO LINKS OR WILL BE REPORTED
The table below shows the numbers of tickets sold at a carnival and the amounts of money in dollars collected Cost of Carnival Tickets

Number of Tickets. Amount $ Collected.
5 $15
10. $30
15. $45
20. $60
25. $75
Which equation represents the relationship
A y = x + 10
B y = 5x
C y = x + 15
D y = 3x​

Answers

The answer is D. Call number of tickets is ‘x’ and amount $ collected is ‘y’. If x=5, y=3x5=15.

One earthquake has MMS magnitude 3.2. If a second earthquake has 390 times as much energy (earth
movement) as the first, find the magnitude of the second quake.

Answers

Section 4.6 Exponential and Logarithmic Models
While we have explored some basic applications of exponential and logarithmic functions, in this section we explore some important applications in more depth.
Radioactive Decay
In an earlier section, we discussed radioactive decay – the idea that radioactive isotopes change over time. One of the common terms associated with radioactive decay is half- life.
Half Life
The half-life of a radioactive isotope is the time it takes for half the substance to decay.
Given the basic exponential growth/decay equation h(t) = abt , half-life can be found by solving for when half the original amount remains; by solving 1 a = a(b)t , or more
2
simply 1 = bt . Notice how the initial amount is irrelevant when solving for half-life. 2
Example 1
Bismuth-210 is an isotope that decays by about 13% each day. What is the half-life of Bismuth-210?
We were not given a starting quantity, so we could either make up a value or use an unknown constant to represent the starting amount. To show that starting quantity does not affect the result, let us denote the initial quantity by the constant a. Then the decay of Bismuth-210 can be described by the equation Q(d) = a(0.87)d .
To find the half-life, we want to determine when the remaining quantity is half the original: 1a. Solving,
2
1 a = a(0.87)d 2
1 = 0.87d 2
1 d log2=log(0.87 )
Divide by a,
Take the log of both sides Usetheexponentpropertyoflogs

The table shows the probability distribution of siblings of students in a high
school with 1500 students. What is the expected value for the number of
siblings of a randomly chosen student?
Number of siblings
0
1
2
3
4
5
Probability
0.18
0.65
0.09
0.05
0.02
0.01
A. 1.08
B. 2.5
C. 1.11
D. 1.29

Answers

Answer:

Step-by-step explanation:

1.11

The expected value for the number of siblings of a randomly chosen student is 1.11.

The correct answer is C. 1.11.

To calculate the expected value for the number of siblings of a randomly chosen student, we need to multiply each possible number of siblings by its corresponding probability and sum up the results.

Expected Value = (0 x 0.18) + (1 x 0.65) + (2 x 0.09) + (3 x 0.05) + (4 x 0.02) + (5 x 0.01)

Expected Value = 0 + 0.65 + 0.18 + 0.15 + 0.08 + 0.05

Expected Value = 1.11

Therefore, the expected value for the number of siblings of a randomly chosen student is 1.11.

Learn more about Probability here:

https://brainly.com/question/31828911

#SPJ5

PLEASE HELP ME!!!!!!!!!ASAP!!!!!

Write down three integers, all less than 25, whose range is 8 and mean is 11.

Answers

Answer:

11,15,7

Step-by-step explanation:

11+15+7=33 33/3=11 the mean

then 15-7=8 the range

The cost, C, to rent a car for d days is shown in the table. Days (d) Cost (C) 2 $105 4. $195 5 $240 6 $285​

Write an equation that represents this function

Answers

Answer:

C = 45d + 15

Step-by-step explanation:

105= (45 x 2) + 15

The equation represents the condition of the function as a linear function. Then the linear equation is C = 45d + 15.

What is the linear system?

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

The cost, C, to rent a car for d days is shown in the table.

Days (d) Cost (C)

  2         $105

  4         $195

  5         $240

  6         $285​

Then the linear equation of the given table will be

Let d be the number of days and C be the total cost.

[tex]\rm C - 285 = \dfrac{285-240}{6-5} (d-6)\\\\C - 285 = 45d - 270\\\\45d - C = -15 \\\\C - 45d = 15[/tex]

More about the linear system link is given below.

https://brainly.com/question/20379472

Helpppppppppppppppppppp

Answers

Answer:

192.5 m²

Step-by-step explanation:

The formula for calculating the area if a circle

= πr²

Find the area of the larger circle first, then subtract the area of the smaller circle.

The area of the larger circle

= π×(21÷2)²

= 346.4 m² (rounded to the nearest tenth)

The radius of the smaller circle

= 21÷2 - 3.5

= 7 m

The area of the smaller circle

= π×7²

= 153.9 m² (rounded to the nearest tenth)

The area of the shaded region

= 346.4 - 153.9

= 192.5 m²


Which expression is equivalent to 3m(x) - 5n(x), if m(x) = 6x2 + 3x - 5 and n(x) = 2x2 + 7x - 1?

Answers

Answer:

8x^2 - 26x - 10

Step-by-step explanation:

3(6x2 + 3x - 5 ) = 18x^2 + 9 -15

5(2x2 + 7x - 1) = 10x^2 + 35 - 5

18^2 - 10x^2 = 8x^2

9x - 35x = - 26x

-15 -(-5) = -10

final answer = 8x^2 - 26x - 10

Find the probability that a randomly selected point within the circle falls in the red shaded area (square). Round to the nearest tenth of a percent.​

Answers

Answer:

probability of selecting the square is 63.7% approximately

Step-by-step explanation:

First of all, the probability of the point of choice is within the red square can be obtained with this formula

probability = expected outcome / total number of possible outcomes

In this case, we are not dealing with discrete values which can be counted. instead, we are dealing with areas.

We are to go about this problem by finding the area of the internal square and dividing it by the area of the circle.

Area of the square

Area of the square = [tex]l^2[/tex]

where length = [tex]4\sqrt{2}[/tex]

Area = [tex](4\sqrt{2}) ^2 = 32cm^2[/tex]

Area of the circle

Area of the circle = [tex]\pi r^2[/tex]

area of circle =[tex]\pi \times 4^2 =50.26cm^2[/tex]

Probablity of selecting the square =

32/50.26 = 0.6366

To express this as a percentage, we multiply our answer by 100.

This will give us 0.6366 X 100 = 63.7% approximately

Is 35.336 an irrational number?
yes or no

Answers

Yes , that’s ur answer , ur welcomeee

Answer:

No

Step-by-step explanation:

Hello, 35.336 is would not be an irrational number because irrational numbers are messy numbers that go on forever like 3.14159..... A rational number is a number with clean numbers like 1.222222....., 35.336, ect. I hope this helped you!

Y(2.5+7)+y-2
10.5y-2

Answers

Answer:

−200y − 2

Step-by-step explanation:

y(2.5 + 7) + y −210.5y − 2

=9.5y + y + −210.5y + −2

=(9.5y+ y + −210.5y) + (−2)

−200y − 2

Mark me brainllest

HELP! Does the pythagorean theorem work for every triangle or just for right triangles?

a. everytriangle

b. only right triangles

Answers

Answer:

This is so easy!

ONLY RIGHT TRIANGLES

Did you really ask this question?

Tip: You should learn the basics first.

Please help (no links) or i will report you i just need answers

Answers

Answer:

Both are TRUE

Step-by-step explanation:

✔️The statement, "angles 1 and 5 are corresponding angles" is TRUE.

Rationale/reason:

Angles that have corners that match are called corresponding angles. Angles 1 and 5 are angles found in the corners that match each other. Therefore, they are corresponding.

✔️The statement, "Angle 6 is congruent to angle 4" is TRUE.

Rationale/reason:

When two lines that are parallel is crossed by a transversal, the alternate interior angles formed are congruent to each other.

Angles 4 and 6 are interior angles that alternate each other along the transversal. Therefore they are congruent to each other.

Use the net to find the surface area of the prism.



360 in2

480 in2

408 in2

432 in2

NO LINKS

Answers

Answer:

96 in.²

Step-by-step explanation:

Surface Area of the prism = 2(area of the 2 equal triangles) + area of rectangle A + rectangle B + rectangle C

✔️Area of the two triangles with the following dimensions:

height = 3 in.

base = 4 in.

Area = 2(½*4*3) = 12 in.²

✔️Area of rectangle A = L*W

L = 7 in

W = 5 in

Area of rectangle A = 7*5 = 35 in.²

✔️Area of rectangle B = L*W

L = 7 in

W = 4 in

Area of rectangle B = 7*4 = 28 in.²

✔️Area of rectangle C = L*W

L = 7 in

W = 3 in

Area of rectangle C = 7*3 = 21 in.²

✔️surface area of the prism = 12 + 35 + 28 + 21 = 96 in.²

A store pays $35 for a fish tank. The markup is 20%. What is the selling price?

Answers

The selling price is $42

14. If a woman is just about to ski down a steep mountain, She estimates the
angle of depression from where she is now to the flag at the bottom of the
course to be 24". She knows that she is 800 feet higher than the base of the
course. How long is the path that she will ski? (Round to the nearest foot)

Answers

It’s ah me mariooooki

Upon studying low bids for shipping contracts, a microcomputer manufacturing company finds that intrastate contracts have low bids that are uniformly distributed between 22 and 31, in units of thousands of dollars. Find the probability that the low bid on the next intrastate shipping contract is in excess of $28,000.

Answers

Answer:

0.111

Step-by-step explanation:

It is given that a manufacturing company found out that the intrastate contracts having a low bid which are [tex]$\text{uniformly}$[/tex] distributed between [tex]$22$[/tex]  and [tex]$31$[/tex] [tex]$\text{units of thousands}$[/tex] of dollars.

Therefore, the probability that a low bid on the [tex]$\text{next intrastate}$[/tex] shipping contract is in excess of [tex]$\$ 28,000$[/tex] is given by :

P(x ≥ 30) = 1 - P(X ≤ 30)

              [tex]$=1-\frac{30-22}{31-22}$[/tex]

             [tex]$=1-\frac{8}{9}$[/tex]

             [tex]$=\frac{1}{9}$[/tex]

            = 0.111

Which ordered pair
describes a point
with location in the
second quadrant?
A. (-6, -5)
B. (-6, 5)
C. (6, 5)
D. (6, -5)

Answers

Answer:

B)  (-6,5)

Step-by-step explanation:

Quadrant I:  (+,+)

Quadrant II: (-,+)

Quadrant III: (-,-)

Quadrant IV: (+,-)

When electricity (the flow of electrons) is passed through a solution, it causes an oxidation-reduction (redox) reaction to occur. If the solution contains a metal cation such as Ag+, the flow of electrons will reduce the silver ion, causing solid silver to plate onto the electrode. The amount of metal plated depends on the number of electrons passed. The total charge of a mole of electrons is 96, 485 coulombs (C) and 1 ampere = 1 coulomb/second (C/s).
What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.
How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)? Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

a. 135 g

b. 60.6 min

Step-by-step explanation:

a. What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.

The chemical equation for the reaction is given below

Cu²⁺(aq) + 2e⁻ → Cu(s)

We find the number of moles of Cu that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 28.5 A and t = time = 4.00 h = 4.00 × 60 min/h × 60 s/min = ‭14,400‬ s

So, n = It/F = 28.5 A × ‭14,400‬ s/96485 C/mol = ‭410,400‬ C/96485 C/mol = 4.254 mol

Since 2 moles of electrons deposits 1 mol of Cu, then 4.254 mol of electrons deposits 4.254 mol × 1 mol of Cu/2 mol = 2.127 mol of Cu

Now, number of moles of Cu = n' = m/M where m = mass of copper and M = molar mass of Cu = 63.546 g/mol

So, m = n'M

= 2.127 mol × 63.546 g/mol

= 135.15 g

≅ 135 g to 3 significant figures

b. How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)?

The chemical equation for the reaction is given below

Au⁺(aq) + e⁻ → Au(s)

We need to find the number of moles of Au in 37.1 g

So, number of moles of Au = n = m/M where m = mass of gold = 37.1 g and M = molar mass of Au = 196.97 g/mol

So, n = m/M = 37.1 g/196.97 g/mol = 0.188 mol

Since 1 mol of Au is deposited  by 1 moles of electrons, then 0.188 mol of Au deposits 0.188 mol of Au × 1 mol of electrons/1 mol of Au = 0.188 mol of electrons

We find the time it takes to deposit 0.188 mol of electrons that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 5.00 A and t = time

So, t = nF/It

= 0.188 mol × 96485 C/mol ÷ 5.00 A

= ‭18173.30‬ C/5.00 A

= 3634.66 s

= 3634.66 s × 1min/60 s

= 60.58 min

≅ 60.6 min to 3 significant figures

An investor wants to invest up to $100,000 as follows:

X amount into a Certificate of Deposit (CD) that yields an expected annual return of 1% with a risk index of 1,
Y amount into a Bond with an expected annual return of 3% and a risk index of 4,
Z amount into a Stock with an expected annual return of 7% and a risk index of 8.
The investor’s objective is to maximize the total expected annual return of the investment.

However, to be prudent, the investor requires that:
The fraction of the total investment in X must be at least 20%.
The fraction of the total investment in Z must not exceed 50%.
The combined portfolio risk index must not exceed 5.

Required:
a. Set up this investment problem as a linear program, which has 3 variables, 3 basic constraints, and 4 special constraints.
b. Use an LP software to find the maximum expected annual return in dollars and the dollar values of X, Y, and Z for this best investment.
c. From the software solution, show the values of the dual variables for the four special constraints.

Answers

Answer:

a-The Linear Model is as follows:

[tex]X+Y+Z\leq 100,000\\{0.001X}\geq 20\\{0.001Z}\leq 50\\0.00001X+0.00004Y+0.00008Z\leq5\\X\geq0\\Y\geq0\\Z\geq0[/tex]

b-The values are

X=$33,333.33

Y=$16,666.67

Z=$50,000.00

Leading to a total expected return of $4333.33.

c-The values of constraints are as follows

X+Y+Z=33333.33+16666.67+50000=100,000

X=33%, Y is 16.67% and Z is 50%

Risk component of X is 0.33

Risk component of Y is 0.66

Risk component of Z is 4.00

Step-by-step explanation:

a

From the conditions, the first special constraint is the total amount which is that the sum of investments must not be  more than the total available amount of $100,000 so

[tex]X+Y+Z\leq 100,000[/tex]

The second special constraint is that the percentage of X must be at least 20% So

[tex]\dfrac{X}{100,000}\times100 \geq20\\\dfrac{X}{1000} \geq20\\{0.001X}\geq 20[/tex]

The third special constraint is that the fraction of total investment of Z must not exceed 50% So

[tex]\dfrac{Z}{100,000}\times100 \leq50\\\dfrac{Z}{1000}\leq 50\\0.001Z\leq50[/tex]

The fourth special constraint is that the combined portfolio risk index must not exceed 5 so

[tex]\dfrac{X}{100,000}\times1+\dfrac{Y}{100,000}\times4+\dfrac{Z}{100,000}\times8\leq5\\0.00001X+0.00004X+0.00008Z\leq5[/tex]

As the investments cannot be negative so three basic constraints are

[tex]X\geq0\\Y\geq0\\Z\geq0[/tex]

The maximization function is given as

[tex]f(X,Y,Z)=\dfrac{X}{X+Y+Z}\times1\%+\dfrac{Y}{X+Y+Z}\times3\%+\dfrac{Z}{X+Y+Z}\times7\%\\f(X,Y,Z)=\dfrac{X}{X+Y+Z}\times0.01+\dfrac{Y}{X+Y+Z}\times0.03+\dfrac{Z}{X+Y+Z}\times0.07[/tex]

b

By using an LP solver with BigM method the solution is as follows:

X=$33,333.33

Y=$16,666.67

Z=$50,000.00

Leading to a total expected return of $4333.33.

c

The values of constraints are as follows

X+Y+Z=33333.33+16666.67+50000=100,000

X=33%, Y is 16.67% and Z is 50%

Risk component of X is 0.33

Risk component of Y is 0.66

Risk component of Z is 4.00

Tino and Ramona are planning to go to Washington, D. C. for 4 days. The travel options are shown below. Which travel option is the most expensive?

Answers

Answer:

54 grams

Step-by-step explanation:

To hard to explain.

Answer: A

Step-by-step explanation: I am a big brain pro

Enter the number that belongs in the green box as you solve for P.

Answers

Answer:

2p=18

2p=2p the answer is p=9

Step-by-step explanation:

Lorenzo has a package that weighs 2 pounds.
He wants to check the weight of the package on a scale, but he only has weights that are measured in ounces.
Drag the weights into the box that will balance the scale. Each weight can be used once or not at all.

Answers

1 pound = 16 ounces

2 pounds = 32 ounces

4 + 12 + 16 = 32

Use the 4, 12 and 16 ounce weights.

Answer:

Solution given:

1 pound = 16 ounces

2 pounds = 32 ounces

we have 32=4×12×16

so

the 4, 12 and 16 are ounce weights.

An education researcher would like to test whether 2nd graders retain or lose knowledge during the summer when they are presumably not in school. She asks nine 2nd graders to take a comprehension exam at the end of the school year (May), and then asks those same students to come back after the summer (late August) to retake a different but equivalent exam, to see if their level of comprehension has changed. Using the data below, test this hypothesis using an alpha level of .05.
May August
90 100
65 80
78 92
50 60
89 90
92 98
75 70
90 96
65 87
a) What is the appropriate test? Is it a one or two tailed test?
b) State the null hypothesis (in words and using means).
c) State the alternative hypothesis (in words and using means).
d) Find the critical value.
e) Calculate the obtained value by hand. What does your decision mean?

Answers

Answer:

See step by step explanation

Step-by-step explanation:

From the problem statement, we understand that we need to investigate if 2nd graders RETAIN OR LOSE knowledge comparing information concerning two different months, therefore we are going to find out if the information gives us enough evidence of a difference in the two groups

a) The test should be a two tail-test

Sample sizes are small ( n₁ = n₂  = 9 ) which means we have to use  t-student test

b   and    c) Test Hypothesis:

For Null Hypothesis H₀,  we establish that the two means are equal, which in this case means that the two samples´ means are equal. And as Hypothesis alternative Hₐ that the H₀ is not true,  or that the samples mean are different.

Null Hypothesis     H₀             x₁  -  x₂   = 0   or    x₁  =  x₂

Alternative Hypothesis  Hₐ    x₁  -  x₂   ≠  0   or   x₁  ≠  x₂

d) Significance level α  = 0,05   then   α/2  = 0,025

then t(c)  with  α/2  =  0,025  and degree of freedom  

df =  n₁  +  n₂  - 2      df =  9 + 9 -2     df = 16

From t s-tudent table we find     t(c) =  2,12

e) Calculating:

x₁   and  σ₁

x₂  and  σ₂

σₓ  = [ ( n₁ - 1 )* σ₁² + ( n₂  - 1 )*σ₂² ]/ n₁ + n₂ - 2

Using a calculator:

x₁  =  77,11        σ₁  = 13,86

x₂  = 85,89      σ₂  = 12,74

σₓ  = [ ( 8*(13,86)² + 8*( 12,74 )² ] / 16

σₓ  =  (8* 192,1) + 8* ( 162,31) / 16

σₓ  = (1536,8 + 1298,48 ) / 16

σₓ  =  177,205

t(s) = ( x₁ - x₂ ) /√ σₓ²/ n₁  + σₓ²/ n₂

t(s) = ( 77,11 - 85,89 )/ (177,205)²/n₁ + (177,205)²/n₂

t(s) = - 8,78 / √3489,07 + 3489,07

t(s) = -8,78 / 83,54

t(s) =  - 0,11

Comparing  t(s) and  t(c)

|t(s)| < |t(c)|      

0,11 <  2,12

t(s) is in the acceptance region. We accept H₀

       

Other Questions
Here is a diagram and its corresponding equation. Find the solution to the equation and explain your reasoning 38 x+7 x+7 x+7 x+7 4(x + 7) = 38 Necesito estas palabras con el presente simplee :((( (-s -ies -es)sleepvisitSon con she y he What is the best reason for changing the slide order in a presentation?to make it easier to add slidesto make it easier to delete slidesto change the logical structure of the presentationto change the character and paragraph formatting of slidesanswer: C. to change the logical structure of the presentation Which gland would most likely have an issue with maintaining the breakdown of food?the thyroidthe thymusthe pancreasthe ovaries During the current month, Tomlin Company incurs the following manufacturing costs.(a) Purchased raw materials of $16,940 on account.(b) Incurred factory labor of $38,528. Of that amount, $32,281 relates to wages payable and $6,247 relates to payroll taxes payable.(c) Factory utilities of $3,108 are payable, prepaid factory property taxes of $2,008 have expired, and depreciation on the factory building is $8,322.Prepare journal entries for each type of manufacturing cost. (Credit account titles are automatically indented when amount is entered. Do not indent manually.)No. Account Titles and Explanation Debit Credit(a)(b)(c) What is the ph of H2SO4? A particle cannot generally be localized to distances much smaller than its de Broglie wavelength. This means that a slow neutron appears to be larger to a target particle than does a fast neutron, in the sense that the slow neutron will probably be found over a large volume of space. For a thermal neutron at room temperature (300 K), find (a) the linear momentum and (b) the de Broglie wavelength. Compare this effective neutron size with both nuclear and atomic dimensions. which statement best evaluates the effect of adding dialogue In the second version of the passage How many different types of fibers do muscles have? Hurry plzzzz i will give a brilliance if right fivefourthreetwo Jack and Jill are pushing a 3 kg object on a rough surface; the object accelerates at a rate of 5 m/s2. Calculate the force applied by the Jack knowing that Jill is pushing 4 N and the rough surface applies 2 N force on the box as friction force. I posted 2 question of this but nobody answered first answer gets brainliest and a thanks and 5 stars and 20 points and do all of them or half no links ASAP guessers will be reported Pls help I will give branlist answer on the best oneDont explain it just strait up give me the answer for 1,2 and 3 If right youll get brainliest Amy and Builders Corporation enter into a contract in which Amy agrees to deliver cement to Builders at a construction site. They neglect to include a price in the agreement. A court will a. determine a reasonable price for the cement and insert it into the contract. b. leave the parties in the position in which it found them. c. refuse to enforce the agreement. d. select the lowest quoted price for cement and insert it into the contract. Which of the following has the largest mass of carbon per gram?HCOCHCOHCHOHCHCHOH Density of iron is 800 kg per cubic meter . calculate the mass of iron contained by a 5 cubic meter of iron block . Also calculate it's relative density.. Write x^3- 7x + 7x^5 - 19 + x^2 in standard form.A. -19 + 7x5 - 7x + x3 + x2B. x3 7x + 7x5 19 + x20C. 7x5 + x3 + x2 - 7x - 19O D. -19 - 7x + x2 + x + 7x5 Write two numbers that multiply to the value on top and add to the value on bottom. -6060 -44 \times ++ the average length of a doves egg is 7 1/2 inches. the average length of a ravens egg is 6/10 inches. about how many more inches is the doves egg to the ravens A pair of weak earthquakes is modeled by a system of inequalities. One earthquake occurred roughly 20 km east and 14 km north of the center of Columbia, NC. The quake could be felt from 25 km away. A couple days later, another earthquake occurred 8 km west and 3 km north of the center of Columbia and could be felt from 14 km away. If Columbia is located at (0, 0) on a coordinate grid, the system of inequalities represents this scenario.StartLayout Enlarged left-brace first row (x minus 20) squared + (y minus 14) squared less-than-or-equal-to 625 second row (x + 8) squared + (y minus 3) squared less-than-or-equal-to 196 EndLayoutWhich location relative to Columbia felt both earthquakes?4 km west and 12 km south6 km west and 4 km north2 km east and 10 km north6 km east and 8 km north