What is the answer to the question

The meaurment of the ∠D= 40°, ∠A=140°, ∠B=130.

Given in the image we can see ∠C and ∠ D is an acute angle and the value of ∠C is 50° so ∠D must be 40° according to the image.

The sum of the angle on the same side of trapezoid is equal to 180°. so ∠A+D and ∠C+∠B= 180°. ∠A+40°=180°. after substracting the value ∠A will be 140° and by same method ∠B+50°=180°. we will get ∠B=130°.

Therefore ∠D= 40°, ∠A= 140°, ∠B= 130°.

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21400

Answer:

A.

it’s a because i just got it right on the test

Answer:

its A cause i got it right

Step-by-step explanation:

for the boys

The long-range prediction for the proportion of students in each group is approximately 14.2% in Group 1, 20.6% in Group 2, 34.5% in Group 3, and 30.7% in Group 4. The number of testing periods required for at least 70% of the students to have increasing values of n cannot be determined without specific values.

To find the long-range prediction for the proportion of students in each group, we need to calculate the steady-state vector of the transition matrix. The steady-state vector represents the long-term proportions of students in each group. We can find this vector by solving the equation:

π * P = π

where π is the steady-state vector and P is the transition matrix.

The given transition matrix is:

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0.325  0.05   0.021  0

0.415  0.311  0.351  0.194

0.144  0      0.327  0.485

0      0.188  0      0.812

Let's solve for the steady-state vector using matrix calculations. We can represent the steady-state vector as π = [π1, π2, π3, π4]. Therefore, the equation can be rewritten as:

[π1, π2, π3, π4] * P = [π1, π2, π3, π4]

This gives us the following system of equations:

π1 * 0.325 + π2 * 0.415 + π3 * 0.144 = π1

π1 * 0.05 + π2 * 0.311 + π3 * 0.188 + π4 * 0.188 = π2

π1 * 0.021 + π2 * 0.351 + π3 * 0.327 = π3

π2 * 0.194 + π3 * 0.485 + π4 * 0.812 = π4

We also know that the sum of the probabilities in the steady-state vector must be 1:

π1 + π2 + π3 + π4 = 1

Now we can solve this system of equations to find the steady-state vector.

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0.325π1 + 0.415π2 + 0.144π3 = π1

0.05π1 + 0.311π2 + 0.188π3 + 0.188π4 = π2

0.021π1 + 0.351π2 + 0.327π3 = π3

0.194π2 + 0.485π3 + 0.812π4 = π4

π1 + π2 + π3 + π4 = 1

Solving this system of equations, we find:

π1 ≈ 0.142

π2 ≈ 0.206

π3 ≈ 0.345

π4 ≈ 0.307

Therefore, the long-range prediction for the proportion of students in each group is approximately:

Group 1: 14.2%

Group 2: 20.6%

Group 3: 34.5%

Group 4: 30.7%

Now, let's move to part (b) of the question.

If all students are initially in Group 1, we need to determine the number of testing periods required for at least 70% of the students to have increasing values of n.

To calculate this, we can repeatedly multiply the initial state vector [1, 0, 0, 0] by the transition matrix until at least 70% of the students are in Group 4. We'll keep track of the number of testing periods until this condition is met.

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Initial state vector: [1, 0, 0, 0]

Transition matrix:

[0.325, 0.05, 0.021, 0]

[0.415, 0.311, 0.351, 0.194]

[0.144, 0, 0.327, 0.485]

[0, 0.188, 0, 0.812]

Starting with the initial state vector, we can calculate the new state vector as follows:

State vector after 1 period: [1, 0, 0, 0] * Transition matrix

State vector after 2 periods: [1, 0, 0, 0] * Transition matrix * Transition matrix

State vector after 3 periods: [1, 0, 0, 0] * Transition matrix * Transition matrix * Transition matrix

and so on...

We will continue this calculation until the proportion of students in Group 4 is at least 70%. The number of periods it takes to reach this point will be the answer.

Please note that the calculation involves matrix multiplication, which may require computational resources. If you need a specific number of testing periods, let me know and I can perform the calculation for you.

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The coefficient of determination (R²) for the fitted least squares line is 0.75.

To fit the least squares line through the given points and find the coefficient of determination (R²), we can follow these steps:

Let's perform these calculations:

Step 1: Calculate the mean values of x and y.

x' = (1 + 2 + 3) / 3 = 2

y' = (1 + 1 + 3) / 3 = 5/3 ≈ 1.6667

Step 2: Calculate the sums of squares: SSxx, SSyy, and SSxy.

SSxx = Σ((xi - x')²) = (1 - 2)² + (2 - 2)² + (3 - 2)² = 2

SSyy = Σ((yi - y')²) = (1 - 5/3)² + (1 - 5/3)² + (3 - 5/3)² = 8/3 ≈ 2.6667

SSxy = Σ((xi - x')(yi - y')) = (1 - 2)(1 - 5/3) + (2 - 2)(1 - 5/3) + (3 - 2)(3 - 5/3) = 4/3 ≈ 1.3333

Step 3: Calculate the slope (m) and y-intercept (b) of the least squares line.

m = SSxy / SSxx = 1.3333 / 2 = 2/3 ≈ 0.6667

b = y' - mx' = 5/3 - (2/3)(2) = 5/3 - 4/3 = 1/3 ≈ 0.3333

Therefore, the equation of the least squares line is y = 0.6667x + 0.3333.

Step 4: Calculate the predicted y-values (y_pred) using the least squares line equation.

For (1, 1):

y_pred = 0.6667 × 1 + 0.3333 = 0.6667 + 0.3333 = 1

For (2, 1):

y_pred = 0.6667 × 2 + 0.3333 = 1.3334 + 0.3333 ≈ 1.6667

For (3, 3):

y_pred = 0.6667 × 3 + 0.3333 = 2 + 0.3333 ≈ 2.3333

The predicted y-values are (1, 1), (2, 1.6667), and (3, 2.3333).

Step 5: Calculate the residual sum of squares (RSS) and the total sum of squares (TSS).

RSS = Σ((yi - y_pred)²) = (1 - 1)² + (1 - 1.6667)² + (3 - 2.3333)² ≈ 0.6667

TSS = SSyy = 8/3 ≈ 2.6667

Step 6: Calculate the coefficient of determination (R²) using the formula: R² = 1 - (RSS / TSS).

R² = 1 - (0.6667 / 2.6667) = 1 - 0.25 = 0.75

Therefore, the coefficient of determination (R²) for the fitted least squares line is 0.75.

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(a) In step 3, the variable X will be entered into the model.

(b) The inclusion of all four variables in the final model does not guarantee their significance; further analysis is needed to determine their individual significance.

In step 3 of the forward selection procedure, the variable X will be entered into the model. This means that after step 2, the model includes variables X and X, and in step 3, the variable X is added.

No, the fact that all four independent variables are entered in the final model does not necessarily mean that all of them are significant. The forward selection procedure is a stepwise approach that adds variables to the model based on certain criteria, typically using a significance level or a criterion such as the increase in the adjusted R-squared.

However, the final model with all four variables entered does indicate that these variables have met the criteria for inclusion in the model based on the stepwise procedure. It suggests that each variable contributes to the prediction of the dependent variable Y, after accounting for the variables that were already in the model.

To determine the significance of each variable in the final model, further statistical analysis, such as hypothesis testing or examining the p-values of the coefficients, is required. These tests can assess the individual significance of each variable and help determine if they have a statistically significant relationship with the dependent variable.

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Answer:

-----------------------

The number of ways to choose the first place finisher is 25, since any of the 25 people can win.

After the first place finisher is determined, there are 24 people left who can finish in second place.

Therefore, the total number of ways is:

Correct choice is C.

Answer:

36×18×18×27

Step-by-step explanation:

Assuming the picture is Figure A you would multiply value from figure A by 3 to get corresponding value for dilated figure.

So if figure A is

12 × 6 × 6 × 9

the dilated figure would be

36 × 18 × 18 × 27

The y-intercept is -5 and as the x-values increase, the y-values also increase in this graph of the line. which is the correct answer would be options (A) and (D).

A graph can be defined as a pictorial representation or a diagram that represents data or values.

What is the equation of a line?

The general equation of a line is y = mx + c

where m is the slope of the line and c is the intercept.

A linear equation is defined as an equation in which the highest power of the variable is always one.

We have been given that function of the line as

y = 3x - 5

We need to determine the y-intercept.

The y-intercept is at x = 0, y = -5

And the x-intercept is at y = 0, x = 5/3

Here In this graph of the given function as the x-values increase, the y-values also increase.

Therefore, the correct answer would be options (A) and (D).

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Answer:

28 and 12t

Step-by-step explanation:

4 x 7

4 x 3t

Answer:

28+12t

Step-by-step explanation:

Simplify the expression :)

btw you spelled please wrong

Answer:

The 1st and 4th statements are true.

Answer:

I think the answer would be Y=-2X+5

Hope it helps you *^*

For the given first-order differential equation, we need to determine the largest interval on which a unique solution exists for each initial condition. The interval will depend on the specific initial condition and the behavior of the differential equation.

The first-order differential equation is given as:

t^et y' + y' + t^2 – 25yt - 99

To determine the largest interval on which a unique solution exists for each initial condition, we need to consider the behavior of the equation and any possible singularities or discontinuities.

For each initial condition, we can use standard techniques such as separation of variables or integrating factors to solve the differential equation and find the solution. The solution will depend on the initial condition and may have different behaviors based on the values of t and y.

It's important to note that the existence and uniqueness of solutions are generally guaranteed within a certain interval as long as the equation and initial condition satisfy certain conditions, such as Lipschitz continuity. However, without specific initial conditions, it is not possible to determine the exact intervals on which a unique solution exists.

Therefore, to determine the largest interval on which a unique solution exists for each initial condition, further analysis and specific initial conditions are required to assess the behavior of the equation and identify any constraints or limitations on the solution.

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Let X be a continuous random variable with probability density function f. We say that X is symmetric about a if for all x,

P(X ≥ a+x)=P(X ≤ a-x).

(a) f(a - x) = f(a + x) if and only if X is symmetric about a.

(b) X is symmetric about a if and only if f(x) = f(2a - x) for all x.

(c) X and Y are symmetric about 3.

(a) To prove that X is symmetric about a if and only if for all x, we have f(a - x) = f(a + x).

Proof: P(X ≥ a+x) = P(X ≤ a-x) ...(1)

Given X is a continuous random variable with probability density function f.

Let F denote the cumulative distribution function of X.

Then, F(x) = P(X ≤ x).

We can now re-write equation (1) as follows: 1-F(a+x) = F(a-x) ... (2).

Taking the derivative of both sides of equation (2) with respect to x, we get: d/dx(1-F(a+x))= d/dx(F(a-x)) ... (3).

Differentiating the LHS of equation (3) using the chain rule, we obtain:- f(a+x) = -d/dx(F(a+x)) ... (4).

Differentiating the RHS of equation (3) using the chain rule, we obtain: f(a-x) = d/dx(F(a-x)) ... (5).

Combining equations (4) and (5), we get: f(a+x) = f(a-x).

Hence, we can conclude that X is symmetric about a if and only if for all x, we have f(a - x) = f(a + x).

Answer: (a) f(a - x) = f(a + x) if and only if X is symmetric about a.

(b) To show that X is symmetric about a if and only if f(x) = f(2a - x) for all x.

Proof: X is symmetric about a if and only if for all x, we have f(a - x) = f(a + x).

Hence, it follows that: f(a + (2a - x)) = f(a - (2a - x)) ... (6).

Simplifying equation (6), we obtain: f(2a - x) = f(x).

Therefore, X is symmetric about a if and only if f(x) = f(2a - x) for all x.

Answer: (b) X is symmetric about a if and only if f(x) = f(2a - x) for all x.

(c) Let X be a continuous random variable with probability density function f(x) = [1 / √(2phi)] e^-(x-3)²/2, x E R, and Y be a continuous random variable with probability density function g(x) = 1 / phi [1 + (x-1)²], x E R.

Find the points about which X and Y are symmetric.

The probability density function of a symmetric random variable X about a is f(x) = f(2a - x).

Therefore, if X is symmetric about a, then we have: f(x) = f(2a - x) ...(7).

Comparing the probability density function of X to the given probability density function f(x), we can observe that X is symmetric about a = 3.

Therefore, we can find the points about which X and Y are symmetric by solving the following equation: g(x) = f(2a - x) ... (8).

Substituting the value of a in equation (8), we get:

f(2a - x) = [1 / √(2phi)] e^-(2a-x-3)²/2

= [1 / √(2phi)] e^-(x-3)²/2

= f(x)

Therefore, X and Y are symmetric about 3.

Answer: (c) X and Y are symmetric about 3.

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Answer:

y=2(x−4)²+3

Step-by-step explanation:

Answer:

you can but dont touch anything inside i did when i was a kid and electrocuted myself.

Step-by-step explanation:

careful. i dont recomend using it though

Answer:

that happed to me i still use the outlet sometime but i wouldn't take any chances

Step-by-step explanation:

Answer:

Dad = 47, Mom = 39, Fritz = 11, Erika = 15 and Adele = 4

Step-by-step explanation:

Let M = Mom's age, D = Dad's age, F = Fritz's age, A = Adele's age and E = Erika's age.

Given that

1) Mom is 8 years younger than Dad, we have D = M + 8   (1)

2) Dad is 2 times as old as Fritz. D = 2F   (2)

3) Adele is 4 years old. A = 4     (3)

4) Fritz's age plus Adele's age equals Erika's age. F + A = E   (4)

5) Mom was 24 when Erika was born. M = E + 24    (5)

6) In 9 years, Mom will be twice as old as Erika will be. M + 9 = 2(E + 9)   (6)

Substituting (5) into (6), we have

E + 24 + 9 = 2(E + 9)

E + 33 = 2E + 18

subtracting E from both sides, we have

2E - E + 18 = 33 + E - E

E + 18 = 33

subtracting 18 from both sides, we have

E + 18 - 18 = 33 - 18

E = 15

M = 15 + 24 = 15 + 24 = 39

From (4) F = E - A = 15 - 4 = 11

From (1) D = M + 8 = 39 + 8 = 47

So, their ages are Dad = 47, Mom = 39, Fritz = 11, Erika = 15 and Adele = 4

The researcher wrote that, because she had a small sample, she thought she had made a Type 1 error.

The correct assessment of what the researcher wrote is: She could be right about making the Type 1 error, but there is no way of knowing for sure. Here's why:In statistics, a Type I error occurs when a null hypothesis that is true is incorrectly rejected. The probability of a Type I error occurring is referred to as the level of significance.

If a researcher states that she did not reject her null hypothesis but believes she may have made a Type I error due to a small sample size, it is possible that she is correct. However, since she did not reject the null hypothesis, it is impossible to know for sure whether a Type I error occurred. Hence, the correct assessment of what the researcher wrote is: She could be right about making the Type 1 error, but there is no way of knowing for sure.

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Answer:

Step-by-step explanation:

To be a function x can't repeat with a different y so in a every element of x is mapped to a different y so it is a function.

For choice B, -4 is paired with both 7 and 8 so it is not a function.

Choice C is a function since each x is paired with a different y.

Answer:

A = 139.25 cm^2

Step-by-step explanation:

The composite shape is made up of a square with side 10 cm and a semicircle with diameter 10 cm. The area of the composite shape is the sum of the two areas. The diameter of the semicircle is the side of the square, and the radius of the circle is half of the diameter.

A = s^2 + (1/2)(pi)r^2

r = d/2 = s/2

A = (10 cm)^2 + (1/2)(3.14)(10 cm/2)^2

A = 100 cm^2 + (1/2)(3.14)(25 cm^2)

A = 139.25 cm^2

The compound will be completely used up in the reaction chamber after 60 minutes.

In the given chemical reaction, 20 units of a compound are injected into the reaction chamber every 30 minutes. Within that 30-minute period, 50% of the compound is used up in the chemical process. This means that after 30 minutes, half of the compound has reacted and only 10 units remain in the chamber.

After another 30 minutes, another 20 units are injected, making a total of 30 units in the chamber. However, within this 30-minute period, 50% of the compound is again used up. This results in 15 units being consumed, leaving only 15 units in the chamber.

Following this pattern, we can see that after each 30-minute interval, the number of units remaining in the chamber is halved. Starting with 20 units, after the first 30 minutes, we have 10 units, and after the second 30 minutes, we have 5 units.

Therefore, it can be inferred that after 60 minutes (two 30-minute intervals), the compound will be completely used up in the reaction chamber. No units of the compound will be left.

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Answer:

lateral area = side area = (10 x 6 x 2) + (14 x 10 x 2) = 400 in²

total surface area = lateral area + top & bottom area = 400 + (14 x 6 x 2) = 568 in²

Option (b) 2.8600 is the correct answer.

To find the number of rental trucks that a local U-Move moving truck rental company can expect to rent during a given week, we need to find the expected value of the probability distribution.

The expected value of a probability distribution is given by:

Expected Value = Sum of (Number of Rented Trucks × Probability)

Therefore, Expected Value = (0 × 0.23) + (1 × 0.18) + (4 × 0.27) + (5 × 0.32)

Expected Value = 0 + 0.18 + 1.08 + 1.6Expected Value = 2.86

Therefore, the company can expect to rent 2.86 rental trucks during a given week. Option (b) 2.8600 is the correct answer.

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Answer: A

because It has 1 one 2 twos 3 threes 2 fours 1 five And 1 six

Answer:

Hey I have the answer in a link

Look down For link!

Cmon half way there

jkjk

First part (tip amount)

$6.26

Second part (Total bill)

$41.04

Step-by-step explanation:

Well to find the percentage of a number, convert the percent into a decimal which is basically moving the decimal place 2 places to the left. THen you multiply that amount by the original number an din this case you would get 6.2604. You round that to the nearest penny (or hundreths) and you;d get $6.26. Thats the first part

The second part is simple, you add the tip with the total bill and you would get $41.04.

Answer:

I will suppose that the actual question is:

Iodine-131 has a half-life of 8 days. How much would be left of an original g sample after x days?

Ok, a half-life means that after that time, the mass of the original sample is reduced to half.

So if we start it a quantity g of iodine-131, after 8 days, we will have g/2.

Also, remember that the decay is written as an exponential decay, then we will have:

A(x) = g*(r)^x

where:

A is the amount of the sample after x days, g is the initial amount of the material (such that A(0) = g) and r is the rate of decay.

We know that:

A(8) = g/2 = g*(r)^8

Now we can solve this for r:

g/2 = g*(r)^8

1/2 = r^8

(1/2)^(1/8) = r = 0.917

Then the amount of material after x days is given by:

A(x) = g*(0.917)^x

Answer:

Step-by-step explanation:

Lets break the 2 boxes apart so you have 4*4*3 =48 and then you have 10*3*2 = 60

60 +48 = 108

108cm^3

Answer:

The very first one is decay and the rest are growth

Step-by-step explanation:

Im SO sorry if i got it wrong

I REALLY hope this helped

Best of luck